What will be the pressure of a sample of 48.0 grams of oxygen gas in a glass container of volume 5.2 L at 25 and degC?

What will be the pressure of a sample of 48.0 grams of oxygen gas in a glass container of volume 5.2 L at 25 and degC?
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What will be the pressure of a sample of 48.0 grams of oxygen gas in a glass container of volume 5.2 L at 25 degrees Celsius?

Description : What will be the pressure of a sample of 48.0 grams of oxygen gas in a glass container of volume 5.2 L at 25 degrees Celsius?

Last Answer : PV = nRTP = pressure = ?V = volume = 5.2 Ln = moles of gas = 48 g x 1 mole/32 g = 1.5 moles O2 gasR = gas constant = 0.0821 L-atm/K-moleT = temperature in K = 25 + 273 = 298 KSolving for P = nRT/V = (1.5)(0.0821)(298)/5.2P = 7.0 atm (to 2 significant figures)

If there are 3 moles of hydrogen 6 moles of oxygen and 9 moles of helium in a 10 L vessel at 27 and degC the total pressure of the gas mixture will be?

Description : If there are 3 moles of hydrogen 6 moles of oxygen and 9 moles of helium in a 10 L vessel at 27 and degC the total pressure of the gas mixture will be?

Last Answer : What is the answer ?

If 48.0 g of O2 and 4.4 g of CO2 are placed in a 10.0 L container at 21c. what is the pressure of mixture of gases?

Description : If 48.0 g of O2 and 4.4 g of CO2 are placed in a 10.0 L container at 21c. what is the pressure of mixture of gases?

Last Answer : Need answer

Nitrogen gas is filled in a container of volume 2.32 L at 32°C and 4.7 atm pressure. Calculate the number of moles of the gas.

Description : Nitrogen gas is filled in a container of volume 2.32 L at 32°C and 4.7 atm pressure. Calculate the number of moles of the gas.

Last Answer : Nitrogen gas is filled in a container of volume 2.32 L at 32°C and 4.7 atm pressure. Calculate the number of moles of the gas.

A sample of NO experiences a change in pressure from 0.5734 atm to 5.1663 atm. If its new volume is 89.811 L, what was its original volume in liters ____ L?

Description : A sample of NO experiences a change in pressure from 0.5734 atm to 5.1663 atm. If its new volume is 89.811 L, what was its original volume in liters ____ L?

Last Answer : 809.2(Explanation): boyle's law of PV=PV for this problem. Plug in values we know, (the pressures and new volume) to get 0.5734V=(5.1663)(89.811). Now solve for V by dividing by 0.5734 on both sides. You get 809.1917846. Round to 4 sig figs to get 809.2.

The half-life of an isotope of an element is 5 days. The mass of a 10 gram sample of this isotope remaining after 20 days is: w) 0.312 grams x) 0.625 grams y) 1.25 grams z) 2.50 grams

Description : The half-life of an isotope of an element is 5 days. The mass of a 10 gram sample of this isotope remaining after 20 days is: w) 0.312 grams x) 0.625 grams y) 1.25 grams z) 2.50 grams

Last Answer : ANSWER: X -- 0.625 GRAMS

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

A 20 L container holds 0.650 mol of He gas at 37 °C at a pressure of 628.3 bar.

Description : A 20 L container holds 0.650 mol of He gas at 37 °C at a pressure of 628.3 bar.

Last Answer : A 20 L container holds 0.650 mol of He gas at 37°C at a pressure of 628.3 bar. What will be new ... and 1.25 mol of additional He gas was added to it?

For determining the moisture content of a soil sample, the following data is available Weight of container = 260 g, Weight of soil sample and = 320 g container, Weight of soil sample (dried) and = 310 g container. The moisture content of the soil sample, is (A) 15 % (B) 18 % (C) 20 % (D) 25 %

Description : For determining the moisture content of a soil sample, the following data is available Weight of container = 260 g, Weight of soil sample and = 320 g container, Weight of soil sample (dried) and = 310 g container. The moisture content of the soil sample, is (A) 15 % (B) 18 % (C) 20 % (D) 25 %

Last Answer : (C) 20 %

PROBLEM FA sample of soft saturated clay weighs 350 grams and has a volume of 205cc. After oven drying, the soil weighs 225 grams. Calculate the values of saturated unit weight, void ratio, porosity and specific gravity?

Description : PROBLEM FA sample of soft saturated clay weighs 350 grams and has a volume of 205cc. After oven drying, the soil weighs 225 grams. Calculate the values of saturated unit weight, void ratio, porosity and specific gravity?

Last Answer : {

A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Description : A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Last Answer : 130.08 {(10atm)(10)(32)/(0.0821) (300K)}

Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Last Answer : 1124 cal

Which of the following is the best example of law of conservation of mass? [NCERT 1975] (A) 12 g of carbon combines with 32 g of oxygen to form 44 g of CO2. (B) When 12 g of carbon is heated in a vacuum there is no change in mass. (C) A sample of air increases in volume when heated at constant pressure but its mass remains unaltered. (D) The weight of a piece of platinum is the same before and after heating in air.

Description : Which of the following is the best example of law of conservation of mass? [NCERT 1975] (A) 12 g of carbon combines with 32 g of oxygen to form 44 g of CO2. (B) When 12 g of carbon is ... mass remains unaltered. (D) The weight of a piece of platinum is the same before and after heating in air.

Last Answer : (A) 12 g of carbon combines with 32 g of oxygen to form 44 g of CO2.

1m3 of an ideal gas at 500 K and 1000 kPa expands reversibly to 5 times its initial volume in an insulated container. If the specific heat capacity (at constant pressure) of the gas is 21 J/mole . K, the final temperature will be (A) 35 K (B) 174 K (C) 274 K (D) 154 K

Description : 1m3 of an ideal gas at 500 K and 1000 kPa expands reversibly to 5 times its initial volume in an insulated container. If the specific heat capacity (at constant pressure) of the gas is 21 J/mole . K, the final temperature will be (A) 35 K (B) 174 K (C) 274 K (D) 154 K

Last Answer : (C) 274 K

2.6272 mol of Ne is held at 2.0999 atm and 653.33 °C. What is the volume of its container in liters ____ L?

Description : 2.6272 mol of Ne is held at 2.0999 atm and 653.33 °C. What is the volume of its container in liters ____ L?

Last Answer : 95.149(Explanation): use ideal gas law in full to solve for volume in liters. Plug in what we know (pressure, number of moles, and gas constant r which is always 0.0821, temperature in kelvin!!) to get ... Now divide both sides by 2.0999 to get V=95.14882035. Round to 5 sig figs to get 95.149

A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6.26, CO : 1.56, O2 : 3.91, H2O :15.66, N2 : 72.60 (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02 (C) CO2 : 6.39, CO : 1.60, O2 : 3.99, H2O:25.96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02

When the stopper is removed from a partly filled bottle containing solid and liquid acetic acid at 16.7 and degC a strong vinegar like odor is noticeable immediately. How many acetic acid phases must?

Description : When the stopper is removed from a partly filled bottle containing solid and liquid acetic acid at 16.7 and degC a strong vinegar like odor is noticeable immediately. How many acetic acid phases must?

Last Answer : When the stopper is removed from a partly filled bottlecontaining solid and liquid acetic acid at 16.7 °C, a strongvinegar like odor is noticeable immediately. How many acetic acidphases must be present in the bottle? Explain.

How much energy is required to raise the temperature of 3 kg of aluminum from 18 and degc to 23 and degc?

Description : How much energy is required to raise the temperature of 3 kg of aluminum from 18 and degc to 23 and degc?

Last Answer : What is the answer ?

What ideal gas is stored in a container at constant volume. If the temperature (T) were increased to 3T what would be the change in pressure (P)?

Description : What ideal gas is stored in a container at constant volume. If the temperature (T) were increased to 3T what would be the change in pressure (P)?

Last Answer : Feel Free to Answer

The temperature of a gas is held constant while its volume is reduced. The pressure the gas exerts on the walls of its container increases because its molecules: w) strike the container walls more often x) strike the container walls with higher speeds y) strike the container walls with greater force z) all of the above

Description : The temperature of a gas is held constant while its volume is reduced. The pressure the gas exerts on the walls of its container increases because its molecules: w) strike the container walls more ... walls with higher speeds y) strike the container walls with greater force z) all of the above

Last Answer : ANSWER: W -- STRIKE THE CONTAINER WALLS MORE OFTEN

If a 2% solution of sewage sample is incubated for 5 days at 20°C and the dissolved oxygen depletion was found to be 8 mg/l. The BOD of the sewage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l

Description : If a 2% solution of sewage sample is incubated for 5 days at 20°C and the dissolved oxygen depletion was found to be 8 mg/l. The BOD of the sewage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l

Last Answer : ANS: D

Which one of the following is largest? w) the number of molecules in 2 grams of hydrogen gas x) the number of molecules in 60 grams of lead sulfate y) the number of molecules in 20 liters of oxygen gas at standard temperature and pressure z) the population of the United States

Description : Which one of the following is largest? w) the number of molecules in 2 grams of hydrogen gas x) the number of molecules in 60 grams of lead sulfate y) the number of molecules in 20 liters of oxygen gas at standard temperature and pressure z) the population of the United States

Last Answer : ANSWER: A - THE NUMBER OF MOLECULES IN 2 GRAMS OF HYDROGEN GAS  

The temperature of O2 is changed from -48.03 °C to 235.59 °C. If its new volume is 29.164 L, what was its original volume in liters ______ L?

Description : The temperature of O2 is changed from -48.03 °C to 235.59 °C. If its new volume is 29.164 L, what was its original volume in liters ______ L?

Last Answer : 12.90(Explanation): use charle's law for this one. V/T=V/T. we know the temperatures in both scenarios, and we're trying to solve for the volume in the beginning. Remember temperature in Kelvin! So, plug in ... Now, divide by 508.59 on both sides to get 12.90042093. Round to 4 sig figs, 12.90 DONE!

Walls of a cubical oven are of thickness l, and they are made of material of thermal conductivity k. The temperature inside the oven is 100°C and the inside heat transfer co-efficient is ‘3k/l’. If the wall temperature on the outside is held at 25°C, what is the inside wall temperature in degree centigrade?(A) 35.5 (B) 43.75 (C) 81.25 (D) 48.25

Description : Walls of a cubical oven are of thickness l, and they are made of material of thermal conductivity k. The temperature inside the oven is 100°C and the inside heat transfer co-efficient is 3k/l'. If the wall temperature ... wall temperature in degree centigrade? (A) 35.5 (B) 43.75 (C) 81.25 (D) 48.25

Last Answer : (C) 81.25

a gas has a pressure of 766.7 torr at a temperature of 10.0°C. the sample contains 2.35 moles of xenon. what is the volume of the gas in liters?

Description : a gas has a pressure of 766.7 torr at a temperature of 10.0°C. the sample contains 2.35 moles of xenon. what is the volume of the gas in liters?

Last Answer : Using PV=nRT, 10.0ºC = 283.15ºK, R = 62.36 L torr/mol KV= (nRT)/PV = (2.35m*(62.36 L torr/mol K)*283.15ºK)/766.7 TorrV = 54.12 L

Which of the following is TRUE of a sample of gas at a constant temperature when the pressure is doubled? w)the volume doubles x)the volume halves y)the volume remains the same

Description : Which of the following is TRUE of a sample of gas at a constant temperature when the pressure is doubled? w)the volume doubles x)the volume halves y)the volume remains the same

Last Answer : ANSWER: X -- THE VOLUME HALVES

A sample of gas has a volume of 210 cubic centimeters at a temperature of 250 degrees Kelvin. The temperature is raised to 500 degrees Kelvin while the pressure remains unchanged. What is the new volume of the gas.

Description : A sample of gas has a volume of 210 cubic centimeters at a temperature of 250 degrees Kelvin. The temperature is raised to 500 degrees Kelvin while the pressure remains unchanged. What is the new volume of the gas.

Last Answer : ANSWER: 420 CUBIC CENTIMETERS

The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. What does the pressure of the gas do?

Description : The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. What does the pressure of the gas do?

Last Answer : increases by a factor of eight

The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. What does the pressure of the gas do?

Description : The volume of a gas is reduced from 4 L to 0.5 L while the temperature is held constant. What does the pressure of the gas do?

Last Answer : increases by a factor of eight

A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal proportions. What is the value of x? a) 6 litres b) 10 litres c) 30 litres d) None of these

Description : A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal ... . What is the value of x? a) 6 litres b) 10 litres c) 30 litres d) None of these

Last Answer : C Another way for solving this sum is by choice The mixture of 60 litres has in it 24 litres of milk and 36 litres of water. (2 : 3 :: milk water) When you remove x litres from it, you ... have 30 litres of milk and 30 litres of water - i.e. milk and water are in equal proportion.

What is the molecular mass of a gas that effuses through a small hole at twice the rate as oxygen gas at the same temperature. (The molecular mass of O2 is 32.) w) 8.0 atomic mass units x) 16 atomic mass units y) 48 atomic mass units z) 64 atomic mass units

Description : What is the molecular mass of a gas that effuses through a small hole at twice the rate as oxygen gas at the same temperature. (The molecular mass of O2 is 32.) w) 8.0 atomic mass units x) 16 atomic mass units y) 48 atomic mass units z) 64 atomic mass units

Last Answer : ANSWER: W -- 8.0 ATOMIC MASS UNITS

The dimensions of a 35 litre forma for measuring aggregates by volume, are: (A) length 30 cm, breadth 25 cm, height 30 cm (B) length 39 cm, breadth 25 cm, height 32 cm (C) length 27 cm, breadth 27 cm, height 48 cm (D) length 220 cm, breadth 25 cm, height 40 cm

Description : The dimensions of a 35 litre forma for measuring aggregates by volume, are: (A) length 30 cm, breadth 25 cm, height 30 cm (B) length 39 cm, breadth 25 cm, height 32 cm (C) length 27 cm, breadth 27 cm, height 48 cm (D) length 220 cm, breadth 25 cm, height 40 cm

Last Answer : Answer: Option C

If a sample that originally contained grams of C14 has gone through two half-lives of decay how much C14 will be left?

Description : If a sample that originally contained grams of C14 has gone through two half-lives of decay how much C14 will be left?

Last Answer : 2.5

If a sample of pure sodium has a mass of 8.2 grams and sodium has an average atomic mass of 22.99 gmol how many sodium atoms are there in the sample?

Description : If a sample of pure sodium has a mass of 8.2 grams and sodium has an average atomic mass of 22.99 gmol how many sodium atoms are there in the sample?

Last Answer : Need answer

If the sample has 2 Grams of water vapor what would the relative humidity be?

Description : If the sample has 2 Grams of water vapor what would the relative humidity be?

Last Answer : What is the answer ?

If a sample that originally contained 10 grams of C14 has gone through two half-lives of decay, how much C14 will be left?

Description : If a sample that originally contained 10 grams of C14 has gone through two half-lives of decay, how much C14 will be left?

Last Answer : 2.5

The void ratio of a soil sample decreases from 1.50 to 1.25 when the pressure is increased from 25 tonnes/m2 to 50 tonnes/m2 , the coefficient of compressibility is (A) 0.01 (B) 0.02 (C) 0.05 (D) 0.001

Description : The void ratio of a soil sample decreases from 1.50 to 1.25 when the pressure is increased from 25 tonnes/m2 to 50 tonnes/m2 , the coefficient of compressibility is (A) 0.01 (B) 0.02 (C) 0.05 (D) 0.001

Last Answer : (A) 0.01

How many moles of carbon are in 48 grams of carbon w) 4 x) 3 y) 2 z) 1

Description : How many moles of carbon are in 48 grams of carbon w) 4 x) 3 y) 2 z) 1

Last Answer : ANSWER: W -- 4

In an isothermal process on an ideal gas, the pressure increases by 0.5 percent. The volume decreases by about __________ percent. (A) 0.25 (B) 0.5 (C) 0.75 (D) 1

Description : In an isothermal process on an ideal gas, the pressure increases by 0.5 percent. The volume decreases by about __________ percent. (A) 0.25 (B) 0.5 (C) 0.75 (D) 1

Last Answer : (B) 0.5

If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

2 If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Description : 2 If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L

Last Answer : B. 80 L

A gas has a temperature of 14 degrees C, and a volume of 4.5 L. If the temperature is raised to 29 degrees C and the pressure is not changed, what is the new volume of the gas?

Description : A gas has a temperature of 14 degrees C, and a volume of 4.5 L. If the temperature is raised to 29 degrees C and the pressure is not changed, what is the new volume of the gas?

Last Answer : V1/T1 = V2/T2 (Charles' Law) T is in Kelvin. Celsius temp plus 273.15 = K T1 = 14 +273 = 287 K T2 = 29 + 273 = 303 K 4.5 / 287 = V2 / 303 V2 = 4.75 L = 4.8 L

An ideal gas of volume 1liter and pressure 10 bar undergoes a quasistatic adiabatic expansion until the pressure drops to 1 bar. Assume γ to be 1.4 what is the final volume?  a. 3.18 l  b. 4.18 l  c. 5.18 l  d. 6.18 l

Description : An ideal gas of volume 1liter and pressure 10 bar undergoes a quasistatic adiabatic expansion until the pressure drops to 1 bar. Assume γ to be 1.4 what is the final volume?  a. 3.18 l  b. 4.18 l  c. 5.18 l  d. 6.18 l

Last Answer : 5.18 l

What would be the volume, in liters, of 11 grams of CO2 at standard temperature and pressure?

Description : What would be the volume, in liters, of 11 grams of CO2 at standard temperature and pressure?

Last Answer : ANSWER: 5.6 LITERS

3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 dayincubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l

Description : 3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 dayincubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l

Last Answer : ANS: C

When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

Description : When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

Last Answer : The pressure is 207,5 kPa.

How many 250 ml glasses can be filled from 2.5 l container of juice?

Description : How many 250 ml glasses can be filled from 2.5 l container of juice?

Last Answer : ten2.5 / 0.25 = 10

The volume of nitrogen gas Um (measured at STP) required to cover a sample of silica get with a mono-molecular layer is `129 cm^(3) g^(-1)` of gel. Ca

Description : The volume of nitrogen gas Um (measured at STP) required to cover a sample of silica get with a mono-molecular layer is `129 cm^(3) g^(-1)` of gel. Ca

Last Answer : The volume of nitrogen gas Um (measured at STP) required to cover a sample of silica get with a mono-molecular layer ... `16.2 xx 10^(-20) m^(2).`