What is the piece holding DNA together?

What is the piece holding DNA together?
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What is the weak bond holding the nucleic acids together in DNA? a. ionic bonds b. covalent bonds bonds c. polar bond d. hydrogen bond

Description : What is the weak bond holding the nucleic acids together in DNA? a. ionic bonds b. covalent bonds bonds c. polar bond d. hydrogen bond

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Description : 5-Match the following Robot part Function a. Manipulator arm 1. For holding a piece or tool b. Controllers 2. Move the manipulator arm and end effector c. Drives 3. Number of degrees of freedom of movement d. Gripper 4. Delivers commands to the ... -1 (C) a-3, b-2, c-4, d-1 (D) a-4, b-3, c-2, d-1

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Description : ‘Most federations that are formed by ‘holding together’ do not give equal power to its constituent units.’ Is it true for India ? Explain. -SST 10th

Last Answer : Yes, the above statement is true for India. (i) All states in the Indian Union do not have identical powers. Some states enjoy a special status. Jammu and Kashmir has its own Constitution. Many ... do not have the powers of a state. The central government has special powers in running these areas.

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Last Answer : Holding together: 1. when a large country divides it's powers Between the constituent States & National Government is known as Holding together Federation. 2. Central Government tends to be more ... units have equal power. 3. The example of such Countries are USA, Switzerland, and Australia.

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“Holding together federations” do not give equal power to its constituent units. -SST 10th

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Description : Which nuclear particles responsible for holding all nucleons together?

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Beams composed of more than one material, rigidly connected together so as to behave as one piece, are known as (A) Compound beams (B) Indeterminate beams (C) Determinate beams (D) Composite beams

Description : Beams composed of more than one material, rigidly connected together so as to behave as one  piece, are known as  (A) Compound beams  (B) Indeterminate beams  (C) Determinate beams  (D) Composite beams

Last Answer : (D) Composite beams

Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between the number of days taken by Ram and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Description : Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between ... and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Last Answer : Let the time taken by Ram, Suresh and Shilpa to finish the work alone be A, B and C respectively Therefore, 1/A + 1/B + 1/C = 1 Also it is given that, A = B/3 and C =B/2 3/B + 1/B + ... between the number of days taken by Ram and Shilpa, each working alone, to complete the work = 3-2 = 1 Answer: a)

8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days

Description : 8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men ... more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days 

Last Answer : 1 man = 2 women 8 men + 4 women = 20 women 2 day's work of 20 women = 20 × 6/1 = 20 × 2/x x =1/3 Remaining work = 1 – 1/3 = 2/3 Total number of females = 16 20 × 6/1 = 16 × x ÷2/ 3 x = 5 days Short Cut M1D1=M2D2+M3D3 10x6 =10x2 + 8 x 60-20= 8x x= 5 days Answer: c)

Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Description : Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6 

Last Answer : D 6 days before the completion of the work Rakchita left the work means in last 6 days only Shreya has worked alone So, in last 6 days worked done by Shreya = 6*1/42=6/42=1/7 So, the rest = 1-1/7 =6/7 So 6/7work was done by Rakchita and Shreya worked together=6/7*70/10 =420/70=6 days

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Description : Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Last Answer : C Karthik’s 1 day work : Raghu’s 1 day work = 2:1 (Karthik + Raghu)’s 1 day work = 1/42 Divide 1/42 in the ratio 2:1 Therefore karthick’s 1 day work = 1/42 * 2/3 =1/63 Hence karthik alone can finish the work in 63 days.

Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Description : Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Last Answer : D Work done by pranesh in 4 days = 1/60 *4 =1/15 Remaining work = 1-1/15 =(15 - 1)/15 =14/15 Now 14/15 work done by sarvesh in 28 days Whole work will be done by sarvesh in(28*15 /14) = 2* 15 =30 ... 's work = 1/60 + 1/30 = (1+2) /60 = 3/60 =1/20 Hence both will finish the work in 20 days

Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Description :  Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Last Answer : A Arfath’s 1 days work = 3 Deekshith 1 day’s work = 1 Arfath 1 day’s work : Deekshith 1 days work = 3:1 (Arfath + deekshith )’s 1 day’s work = 1/27 Divide 1/27 in the ratio 3:1 Arfath’s 1 days work = 1/27 *3/1 = 3/27 =1/9 Hence Arfath’s alone can finish the work in 9 days

M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Description : M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Last Answer : A Time taken by M to finish the work = 45 days. M's 1 day's work = 1/45 Time taken by N to finish the work = 40 days. N's 1 day's work = 1/40 (M + N)'s 1 day's work = (1/40+1/45) = ... be done by N in (55/72*40) days = 30and 5/9 days. Hence, the remaining work is done by B in 30 and 5/9 days.

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

Description : P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each ... finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 

Last Answer : B Time taken by (P + Q) to finish the job = 24days. (P + Q)'s 1 day's job = 1/24 Time taken by (Q +R) to finish the job = 30days. (Q + R)'s 1 day's job = 1/30 Time taken by (R + P) to finish the ... - {(P + Q)'s 1 day's job } = (1/20 -1/24)=1/120 Hence, R alone can finish the job in 120 days.

X, Y, Z are engaged to do a certain piece of work for Rs.8200.Y and Z are to execute 15/26 of the work together. Amount to be paid to X is A) 4287 B) 3469 C) 6124 D) 2865

Description : X, Y, Z are engaged to do a certain piece of work for Rs.8200.Y and Z are to execute 15/26 of the work together. Amount to be paid to X is A) 4287 B) 3469 C) 6124 D) 2865

Last Answer : Answer: B)  Y and Z are execute 15/26 of week Balance =1-15/26  11/26 of work completed by X  X’s share of revenue  =11/26 *8200  =Rs 3469

What is the oldest piece of complete DNA yet sequenced?

Description : What is the oldest piece of complete DNA yet sequenced?

Last Answer : answer: There is one problem that DNA studies of population movements within the past 10,000 years do not have: dating of the samples, as radiocarbon dating is considered to be accurate up to 50,000 years. ... if a sequence of that age has never been recovered. Wow, isn't this stuff incredible?? :)

What is a piece of DNA that codes for a particular protein?

Description : What is a piece of DNA that codes for a particular protein?

Last Answer : A piece of DNA that codes for a particular protein is called agene.

What is a piece of DNA that codes for a particular protein?

Description : What is a piece of DNA that codes for a particular protein?

Last Answer : A piece of DNA that codes for a particular protein is called agene.

What is antisense technology? (a) When a piece of RNA that is complementary in sequence is used to stop expression of a specific gene (b) RNA polymerase producing DNA (c) A cell displaying a foreign antigen used for synthesis of antigens (d) Production of somaclonal variants in tissue cultures

Description : What is antisense technology? (a) When a piece of RNA that is complementary in sequence is used to stop expression of a specific gene (b) RNA polymerase producing DNA (c) A cell displaying a foreign antigen used for synthesis of antigens (d) Production of somaclonal variants in tissue cultures

Last Answer : (a) When a piece of RNA that is complementary in sequence is used to stop expression of a specific gene

What forms to hold bivalent together so that DNA can duplicate chromosomes?

Description : What forms to hold bivalent together so that DNA can duplicate chromosomes?

Last Answer : Need answer

The two strands of the DNA double helix are held together by (a) Hydrogen bonds (b)C=C double bonds (c) Hydrophobic bonds (d) Peptide bonds

Description : The two strands of the DNA double helix are held together by (a) Hydrogen bonds (b)C=C double bonds (c) Hydrophobic bonds (d) Peptide bonds

Last Answer : Ans:(a)

The figure below shows three steps (A, B, C) of Polymerase Chain Reaction (PCR). Select the option giving correct identification together with what it represents? A. B. C ds DNA 3 5 5 3 5 3 5 3 5 3 5 3 5 5 3 3 5 3 5 3 Region to be amplified . (a) B - denaturation at a temperature of about 98°C separating the two DNA strands (b) A - denaturation at a temperature of about 50°C (c) C - extension in the presence of heat stable DNA polymerase (d) A - annealing with two sets of primers

Description : The figure below shows three steps (A, B, C) of Polymerase Chain Reaction (PCR). Select the option giving correct identification together with what it represents? A. B. C ds DNA 3 5 5 3 ... - extension in the presence of heat stable DNA polymerase (d) A - annealing with two sets of primers

Last Answer : (c) C - extension in the presence of heat stable DNA polymerase

True statements about the nucleic acid include: a. contains purine and pyrimidine which are bound together by covalent bonds b. there is always an equal concentration of purine and pyrimidine c. in RNA, thymine is replaced by uracil d. introns is more common than exons on the DNA e. the histones mark the excision site

Description : True statements about the nucleic acid include: a. contains purine and pyrimidine which are bound together by covalent bonds b. there is always an equal concentration of purine and pyrimidine c. in RNA, ... d. introns is more common than exons on the DNA e. the histones mark the excision site

Last Answer : there is always an equal concentration of purine and pyrimidine

The double helical structure of DNA is held together by (a) sulfur-sulfur linkages (b) peptide bonding (c) hydrogen bonding (d) glycosidic bonds

Description : The double helical structure of DNA is held together by (a) sulfur-sulfur linkages (b) peptide bonding (c) hydrogen bonding (d) glycosidic bonds

Last Answer : hydrogen bonding

The process of conjugation in bacteria requires that _____. a. Two Types Of Viruses Be Present. b. The Conjugating Bacteria Be Deprived Of Nutrients. c. Two Bacteria Exchange Dna. d. Two Live Bacteria Come Together.

Description : The process of conjugation in bacteria requires that _____. a. Two Types Of Viruses Be Present. b. The Conjugating Bacteria Be Deprived Of Nutrients. c. Two Bacteria Exchange Dna. d. Two Live Bacteria Come Together.

Last Answer : d. Two Live Bacteria Come Together.