Working together, X and Y can do a piece of work in 12 days, Y and Z can do it in 15 days where as X and Z can do it in 20 days. Who is the most effci

Working together, X and Y can do a piece of work in 12 days, Y and Z can do it in 15 days where as X and Z can do it in 20 days. Who is the most effci
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Working together, X and Y can do a piece of work in 12 days, Y and Z can do it in 15 days where ... Z can do it in 20 days. Who is the most effcient?
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A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can they do it, all working together?

Description : A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can they do it, all working together?

Last Answer : A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can they do it, all working together?

X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Description : X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Last Answer : X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

Description : P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each ... finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 

Last Answer : B Time taken by (P + Q) to finish the job = 24days. (P + Q)'s 1 day's job = 1/24 Time taken by (Q +R) to finish the job = 30days. (Q + R)'s 1 day's job = 1/30 Time taken by (R + P) to finish the ... - {(P + Q)'s 1 day's job } = (1/20 -1/24)=1/120 Hence, R alone can finish the job in 120 days.

X, Y, Z are engaged to do a certain piece of work for Rs.8200.Y and Z are to execute 15/26 of the work together. Amount to be paid to X is A) 4287 B) 3469 C) 6124 D) 2865

Description : X, Y, Z are engaged to do a certain piece of work for Rs.8200.Y and Z are to execute 15/26 of the work together. Amount to be paid to X is A) 4287 B) 3469 C) 6124 D) 2865

Last Answer : Answer: B)  Y and Z are execute 15/26 of week Balance =1-15/26  11/26 of work completed by X  X’s share of revenue  =11/26 *8200  =Rs 3469

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Description : Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Last Answer : D Work done by pranesh in 4 days = 1/60 *4 =1/15 Remaining work = 1-1/15 =(15 - 1)/15 =14/15 Now 14/15 work done by sarvesh in 28 days Whole work will be done by sarvesh in(28*15 /14) = 2* 15 =30 ... 's work = 1/60 + 1/30 = (1+2) /60 = 3/60 =1/20 Hence both will finish the work in 20 days

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

A and B together can do a piece of work in 20 days, while B and C together can do the same work in 15 days. If A ,B and C together can finish this wor

Description : A and B together can do a piece of work in 20 days, while B and C together can do the same work in 15 days. If A ,B and C together can finish this wor

Last Answer : A and B together can do a piece of work in 20 days, while B and C together can do the same ... number of days in which B alone can finish the work.

X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Description : X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Last Answer : X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

X and Y can do a job in 24 days, Y & Z can do the same job in 36 days. X,Y,Z together can finish it in 18 days. X and Z together will do it in. a) 24 b) 36 c) 12 d) 26

Description : X and Y can do a job in 24 days, Y & Z can do the same job in 36 days. X,Y,Z together can finish it in 18 days. X and Z together will do it in. a) 24 b) 36 c) 12 d) 26

Last Answer : A (X+Y+Z) s 1 day work =1/18 (X+Y)'s 1 day work = 1/24 (Y+Z)'s 1 day work = 1/36 (X+Z)'s 1 day work = 2[X+Y+Z]'s 1 day work - [(X+Y)'s 1 day work + (Y+Z)'s 1 day work]= 2 [1/18]- (1/24 + ... /24 + 1/36) = 1/9 -1/24 - 1/36 =(8-3-2)/72 =3/72 = 1/24 So X & Z together will do the work in 24 days

The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the thre of them can complete the work in 24 days. In how man

Description : The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the thre of them can complete the work in 24 days. In how man

Last Answer : The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the ... days. In how many days can C alone complete it ?

A boy and his mother together can do a piece of work in 24 days while the day, working with his father, can complete it in 18 days. If the mother and

Description : A boy and his mother together can do a piece of work in 24 days while the day, working with his father, can complete it in 18 days. If the mother and

Last Answer : A boy and his mother together can do a piece of work in 24 days while the day, working with ... take to complete the job, if they work individually.

Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between the number of days taken by Ram and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Description : Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between ... and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Last Answer : Let the time taken by Ram, Suresh and Shilpa to finish the work alone be A, B and C respectively Therefore, 1/A + 1/B + 1/C = 1 Also it is given that, A = B/3 and C =B/2 3/B + 1/B + ... between the number of days taken by Ram and Shilpa, each working alone, to complete the work = 3-2 = 1 Answer: a)

8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days

Description : 8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men ... more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days 

Last Answer : 1 man = 2 women 8 men + 4 women = 20 women 2 day's work of 20 women = 20 × 6/1 = 20 × 2/x x =1/3 Remaining work = 1 – 1/3 = 2/3 Total number of females = 16 20 × 6/1 = 16 × x ÷2/ 3 x = 5 days Short Cut M1D1=M2D2+M3D3 10x6 =10x2 + 8 x 60-20= 8x x= 5 days Answer: c)

Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Description : Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Last Answer :  C Efficiency of Rubika = 16.666% Efficiency of sathya = 4.166% Total efficiency of rubika and sathya =(16+4) =20% Actual work 100/20=5 So, they can do actual work in 5 days So, 6 times work requires 30 days.

Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Description :  Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Last Answer : A Arfath’s 1 days work = 3 Deekshith 1 day’s work = 1 Arfath 1 day’s work : Deekshith 1 days work = 3:1 (Arfath + deekshith )’s 1 day’s work = 1/27 Divide 1/27 in the ratio 3:1 Arfath’s 1 days work = 1/27 *3/1 = 3/27 =1/9 Hence Arfath’s alone can finish the work in 9 days

A can do a piece of work in 20 days while B can do it in 30 days. Both of them start the work together and work for some time, then B leaves. If A com

Description : A can do a piece of work in 20 days while B can do it in 30 days. Both of them start the work together and work for some time, then B leaves. If A com

Last Answer : A can do a piece of work in 20 days while B can do it in 30 days. Both of them start ... then find the number of days for which they worked together.

X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Description : X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Last Answer : B Z alone can finish the work in 120 days. As given Z does half as much work as X and Y together => (X + Y) can do it in 60 days (X+ Y)s 1 days wok = 1/60. X's 1 days work : Y's 1 days Work = 1 ... (1/90) + (1/120) =(2+4+3)/360 =9/360 = 1/40 All the three together will finish it in 40 days

A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C

Description : A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C

Last Answer : A can complete a piece of work working along with B in 20 days. If he can complete the same work ... , then between B and C who is more efficient ?

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

Twenty workers can complete a piece of work in 30 days. After how many days should 5 workers leave the job so that the work is completed in 35 days? a) 5 days b) 10 days c) 15 days d) 20 days

Description : Twenty workers can complete a piece of work in 30 days. After how many days should 5 workers leave the job so that the work is completed in 35 days? a) 5 days b) 10 days c) 15 days d) 20 days

Last Answer : c) 15 days

8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, woman and one boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Description : 8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, ... boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Last Answer : A Efficiency of 8 men and 8 boys = 10% Efficiency of 9 women and 7boys = 10% Efficiency of 7 men and 6 women = 10% So, Efficiency of 15 men, 15women and 15boys = 30% So, efficiency of 1 man ... efficiency Efficiency of 1 man, 1 woman and 1 boy = 4% Required number of days = 100/4=25 days

What is considered to be the approximate difference in average temperature between the "little ice age" and today? w) 1 to 3 degrees centigrade x) 5 to 8 degrees centigrade y) 10 to 12 degrees centigrade z) 15 to 20 degrees centigrade

Description : What is considered to be the approximate difference in average temperature between the "little ice age" and today? w) 1 to 3 degrees centigrade x) 5 to 8 degrees centigrade y) 10 to 12 degrees centigrade z) 15 to 20 degrees centigrade

Last Answer : ANSWER: W -- 1 TO 3 DEGREES CENTIGRADE

A can do a work in 15 days and B in 20 days. If they work together for 4 days, then the fraction of work that is left is a) 7/15 b) 8/10 c) 8/15 d) 7/20

Description : A can do a work in 15 days and B in 20 days. If they work together for 4 days, then the fraction of work that is left is a) 7/15 b) 8/10 c) 8/15 d) 7/20

Last Answer : c) 8/15

Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Description : Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6 

Last Answer : D 6 days before the completion of the work Rakchita left the work means in last 6 days only Shreya has worked alone So, in last 6 days worked done by Shreya = 6*1/42=6/42=1/7 So, the rest = 1-1/7 =6/7 So 6/7work was done by Rakchita and Shreya worked together=6/7*70/10 =420/70=6 days

Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Description : Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Last Answer : C Karthik’s 1 day work : Raghu’s 1 day work = 2:1 (Karthik + Raghu)’s 1 day work = 1/42 Divide 1/42 in the ratio 2:1 Therefore karthick’s 1 day work = 1/42 * 2/3 =1/63 Hence karthik alone can finish the work in 63 days.

M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Description : M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Last Answer : A Time taken by M to finish the work = 45 days. M's 1 day's work = 1/45 Time taken by N to finish the work = 40 days. N's 1 day's work = 1/40 (M + N)'s 1 day's work = (1/40+1/45) = ... be done by N in (55/72*40) days = 30and 5/9 days. Hence, the remaining work is done by B in 30 and 5/9 days.

If the half-life of a radioisotope is 2 days, after how many days is the quantity reduced to 12.5% of its original amount? w) 4 days x) 6 days y) 8 days z) 10 days

Description : If the half-life of a radioisotope is 2 days, after how many days is the quantity reduced to 12.5% of its original amount? w) 4 days x) 6 days y) 8 days z) 10 days

Last Answer : ANSWER: X -- 6 DAYS

X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Description : X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : D Suppose the work was finished in a' days Then X's (a - 16) day's work + Y's (a - 24) days + Z's a days work = 1 (a-16)/72 + (a-24)/108 + a/144 =1 lcm of 72,108,144 is 432 (6(a-16) + 4( ... = 432 6a - 96 +4a - 96 =3a = 432 13a - 192 = 432 13a = 624 => a =48 Therefore Z worked in 48 days.

The half-life of an isotope of an element is 5 days. The mass of a 10 gram sample of this isotope remaining after 20 days is: w) 0.312 grams x) 0.625 grams y) 1.25 grams z) 2.50 grams

Description : The half-life of an isotope of an element is 5 days. The mass of a 10 gram sample of this isotope remaining after 20 days is: w) 0.312 grams x) 0.625 grams y) 1.25 grams z) 2.50 grams

Last Answer : ANSWER: X -- 0.625 GRAMS

Fifteen men can complete a piece of work in 10 days, working 8 hours per day. How many persons are required to complete double the work in 25 days, wo

Description : Fifteen men can complete a piece of work in 10 days, working 8 hours per day. How many persons are required to complete double the work in 25 days, wo

Last Answer : Fifteen men can complete a piece of work in 10 days, working 8 hours per day. How many persons are ... work in 25 days, working 6 hours per day ?

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

Two pipes can fill a tank in 20 and 24 minutes respectively and another pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank in gallons is: a)100 b)110 c)120 d)140

Description : Two pipes can fill a tank in 20 and 24 minutes respectively and another pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank in gallons is: a)100 b)110 c)120 d)140

Last Answer : c)120

Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days

Description : Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days 

Last Answer : B Nandhu's 1 day work = 1/10 Naren's 1 day work = 1/15 Abishek's 1 day work =1/30 Nandhu's 2 day's work =(1/10*2) =1/5 (nandhu + naren+abishek)'s 1 day work = 1/10+1/15+1/30 =3+2+1/30 =6/30 ... +1/5 = 2/5 Now 2/5 work is done in 3 days Whole work will be done in 3 *5/2 = 15/2 = 7.5 days

Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB(x))) Then, f(A+B) is equal to (A) {(0.5,12), (0.6,13), (1,14), (0.7,15), (0.7,16), (1,17), (1,18)} (B) {(0.5,12), (0.6,13), (1,14), (1,15), (1,16), (1,17), (1,18)} (C) {(0.3,12), (0.5,13), (0.5,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Description : Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB( ... ,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Last Answer : (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} 

3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Description :  3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Last Answer : C  Part filled in 4 hrs = 4/12 = 1/3 Remaining part = 2/3 (P+Q)’s 14 hrs work = 2/3 (P+Q)’s 1 hr work = 2/ 3 *14 = 1/21 R’s 1 hr work = (P+Q+R)’s 1 hr work – (P+Q)’s 1 hr work = 1/12 – 1/21 = 7-4/84 = 3/84 = 1/28 R alone can fill the tank in 28 hrs.

What is the approximate weight in pounds of the atmosphere on a 1 sq. ft. surface at sea level? w) 15 lbs. x) 1500 lbs. y) 2100 lbs. z) 20,000 lbs.

Description : What is the approximate weight in pounds of the atmosphere on a 1 sq. ft. surface at sea level? w) 15 lbs. x) 1500 lbs. y) 2100 lbs. z) 20,000 lbs. 

Last Answer : ANSWER: Y -- 2100 LBS.

In a business, X,Y and Z inversed Rs.20,000/-,Rs.30,000/- and Rs.40,000/- respectively. After 1 year X adds Rs.10000/- to the initial investment.Y and Z withdrew Rs.10000/- and Rs.15,000/- respectively. After 2 years the total profit is Rs.9900/-. What is X’s share?. A) 3000 B) 2700 C) 3600 D) 4000

Description : In a business, X,Y and Z inversed Rs.20,000/-,Rs.30,000/- and Rs.40,000/- respectively. After 1 year X adds Rs.10000/- to the initial investment.Y and Z withdrew Rs.10000/- and Rs.15,000/- respectively. After 2 years the total profit is Rs.9900/-. What is X’s share?. A) 3000 B) 2700 C) 3600 D) 4000

Last Answer : Answer: A)  X's Share = Rs.20000/- per first 1 year, Next year 10000/- added = Rs.20000/- 1 + Rs.30000/- 1 = Rs.50000/- Y's Share = Rs.30000/- per first 1 year, Next year 10000/- reduced = Rs.30000 ... /-  1 part------> Rs300/- Then, X's share is 10 parts = Rs.300/- 10 parts = Rs.3000/-

Vinay can do a work in 28 days. Vikram is 75% more efficient than vinay. The number of days taken by vikram to do the same piece of work. a) 12 days b) 14 days c) 16 days d) 18 days

Description : Vinay can do a work in 28 days. Vikram is 75% more efficient than vinay. The number of days taken by vikram to do the same piece of work.  a) 12 days b) 14 days c) 16 days d) 18 days

Last Answer : C Given a certain work done by vinay = 28 days Efficient percentage of vikram = 75% Ratio of time taken by vinay and vikram = 175 : 100 = 7:4 Suppose vikram takes ‘x’ days to do the work. 7:4 :: 28 : x 7x = 4*28 X= 4*28/7 X= 4*4 = 16 days So vikram takes 16 days to do the work.

Ten coulombs of positive charge are placed on an irregularly-shaped, solid piece of copper. Once the charge has stopped moving, the electric field inside the copper is: w) zero x) changes as one over the radius squared y) becomes smaller as you approach the center z) becomes larger as you approach the center

Description : Ten coulombs of positive charge are placed on an irregularly-shaped, solid piece of copper. Once the charge has stopped moving, the electric field inside the copper is: w) zero x) changes as one ... squared y) becomes smaller as you approach the center z) becomes larger as you approach the center

Last Answer : ANSWER: W -- ZERO

A COPPER strip is placed in one compartment of a voltaic cell and a wire connects this strip to a piece of metal in the other compartment through a voltmeter. If the voltmeter reads zero, the other piece of metal is: w) zinc x) mercury y) silver z) copper

Description : A COPPER strip is placed in one compartment of a voltaic cell and a wire connects this strip to a piece of metal in the other compartment through a voltmeter. If the voltmeter reads zero, the other piece of metal is: w) zinc x) mercury y) silver z) copper

Last Answer : ANSWER: Z -- COPPER

A cobalt chloride solution soaked into a piece of cotton can be used as an indicator for changes in humidity levels. Pink indicates a high-humidity environment and blue a low-humidity environment. What are these color changes caused by: w) The ionization and reduction of the cobalt plus two slash cobalt plus three couple. x) The vaporization and redeposition of cobalt chloride. y) The loss and readsorption of the cobalt's waters of hydration. z) This is an illustration of the Schrodinger principle.

Description : A cobalt chloride solution soaked into a piece of cotton can be used as an indicator for changes in humidity levels. Pink indicates a high-humidity environment and blue a low-humidity environment. What ... the cobalt's waters of hydration. z) This is an illustration of the Schrodinger principle.  

Last Answer : ANSWER: Y -- THE LOSS AND READSORPTION OF THE COBALT'S WATERS OF HYDRATION.

P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Last Answer : 2;

4 male and 6 female do a piece of work in 20 days while 6 male and 4 female can do the same work in16 days. In how many days can 4 male and 2 female do the work? a) 3 62/142 b) 2 18/124 c) 4 81/165 d) 1 67/133

Description : 4 male and 6 female do a piece of work in 20 days while 6 male and 4 female can do the same work in16 days. In how many days can 4 male and 2 female do the work? a) 3 62/142 b) 2 18/124 c) 4 81/165 d) 1 67/133

Last Answer : D Let 1 male's 1 day's work = x 1 female's 1 day's work = y Then 4x + 6y = 1/20 ---------->A 80x + 120y = 1 -----------1 6x + 4y = 1/16 ----------B 96x + 64y = ... (1/400) =132/200+1/200 = 133/200 So 4 male and 2 female together can finish the work in 200/133 = 1 67 /133 days

According to ---------- the managers and workers should work together as partners and of equal importance for the organizations success (a) X theory (b) Y theory ; (c) Z theory ; (d) 2 Factor theory

Description : According to ---------- the managers and workers should work together as partners and of equal importance for the organizations success (a) X theory (b) Y theory ; (c) Z theory ; (d) 2 Factor theory

Last Answer :  (c) Z theory ;

If a piece of metal at -20 degrees Celsius is added to an ice and water mixture in equilibrium at 0 degrees Celsius, the amount of ice will: w) Increase x) Remain the same y) Decrease

Description : If a piece of metal at -20 degrees Celsius is added to an ice and water mixture in equilibrium at 0 degrees Celsius, the amount of ice will: w) Increase x) Remain the same y) Decrease

Last Answer : ANSWER: W -- INCREASE

Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th

Description : Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th

Last Answer : Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they ... 5200 for their work, then find their individual shares.

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Description : Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Last Answer : A Rishwi can complete the work in (6*4) = 24 hrs Dhiviksha can complete the work in (4*5) = 20 hrs Rishwi's 1 hr work = 1/24 Dhiviksh's 1 hr work = 1/20(Rishwi and dhivikasha)'s 1 hr work = (1/24 ... fininsh the work in (120/11)hrs Number of days of 4 hrs each = 120/11*1/4 =120/44 =30/11 days