In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?
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1 atm
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In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

Description : In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

Last Answer : 1 atm

Standard air is the: a. Mass of 1 cubic meter of dry air at 20°C and atmospheric pressure b. Mass of a cubic meter of air at atmospheric conditions c. Volume of air at ambient temperature and atmospheric pressure d. Volume of 1 kg of dry air at 21°C and atmospheric pressure at sea level or 101.325 kPa e. Volume of 1 kg of air at 15°C and 100 kPa

Description : Standard air is the: a. Mass of 1 cubic meter of dry air at 20°C and atmospheric pressure b. Mass of a cubic meter of air at atmospheric conditions c. Volume of air at ambient temperature and atmospheric pressure ... pressure at sea level or 101.325 kPa e. Volume of 1 kg of air at 15°C and 100 kPa

Last Answer : Answer: D

The maximum delivery pressure of compressors can be upto __________ atmospheres. (A) 10 (B) 100 (C) 250 (D) 1000

Description : The maximum delivery pressure of compressors can be upto __________ atmospheres. (A) 10 (B) 100 (C) 250 (D) 1000

Last Answer : (D) 1000

The specific volume of air is expressed as the volume of: a. 1 kg of air at 101.325 kPa in cm3 b. 0.833 kg of air at standard pressure and temperature in m3 c. 1 kg of air at 101.325 kPa and 21 degrees Celsius in m3 d. 1 g of air occupied at any temperature and pressure e. 1 kg of air, regardless of temperature and pressure

Description : The specific volume of air is expressed as the volume of: a. 1 kg of air at 101.325 kPa in cm3 b. 0.833 kg of air at standard pressure and temperature in m3 c. 1 kg of air at 101.325 ... d. 1 g of air occupied at any temperature and pressure e. 1 kg of air, regardless of temperature and pressure

Last Answer : Answer: C

How many molecules of an ideal gas are there in 22.414 liters at 10 atmospheres pressure and 0 degrees C?

Description : How many molecules of an ideal gas are there in 22.414 liters at 10 atmospheres pressure and 0 degrees C? 

Last Answer : ANSWER: 6.02 x 1024 (or accept 10 x AVAGADRO'S NUMBER) 

Unit for pressure used in weather maps is millibar. 1 millibar is equal to A. 1000 bar B. 100 kPa C. 100 Pa D. 1 atm

Description : Unit for pressure used in weather maps is millibar. 1 millibar is equal to A. 1000 bar B. 100 kPa C. 100 Pa D. 1 atm

Last Answer : 100 Pa

A rectangle-shaped open-to-sky tank of water has a length of 2 m and a width of 1 m. If the atmospheric pressure is assumed to be 100 kPa and thickness of the tank walls is assumed to be negligible, the force exerted by the atmosphere on the surface of water is A. 20 kN B. 50 kN C. 100 kN D. 200 kN

Description : A rectangle-shaped open-to-sky tank of water has a length of 2 m and a width of 1 m. If the atmospheric pressure is assumed to be 100 kPa and thickness of the tank walls is assumed to be negligible, the force exerted by ... of water is A. 20 kN B. 50 kN C. 100 kN D. 200 kN

Last Answer : 200 kN

The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Description : The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 14026.5 m³

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

Pick out the wrong statement: (A) Greater is the kinematic viscosity of the liquid, greater is the thickness of the boundary layer (B) Blowers develop a maximum pressure of 2 atmospheres (C) Friction losses in pipe fittings are generally expressed in terms of velocity heads (D) Fanning friction factor in case of turbulent flow of liquids in pipe depends upon relative roughness & Reynolds number

Description : Pick out the wrong statement: (A) Greater is the kinematic viscosity of the liquid, greater is the thickness of the boundary layer (B) Blowers develop a maximum pressure of 2 atmospheres ( ... factor in case of turbulent flow of liquids in pipe depends upon relative roughness & Reynolds number

Last Answer : (C) Friction losses in pipe fittings are generally expressed in terms of velocity heads

At one atmosphere, a cylinder with movable piston contains 2,000 milliliters of gas. If the pressure is increased to 5 atmospheres and the temperature remains unchanged, what is the new volume of the gas? w) 10,000 milliliters x) 400 milliliters y) 1,000 milliliters z) 4,000 milliliters

Description : At one atmosphere, a cylinder with movable piston contains 2,000 milliliters of gas. If the pressure is increased to 5 atmospheres and the temperature remains unchanged, what is the new volume of the gas? w) 10,000 milliliters x) 400 milliliters y) 1,000 milliliters z) 4,000 milliliters

Last Answer : ANSWER: X -- 400 MILLILITERS

A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Last Answer : 2 x10^6 kJ

Calculate the number of molecules of methane in 0.50 m^3 of the gas at a pressure of 2.0 × 10^2 kPa and a temperature of exactly 300 K.

Description : Calculate the number of molecules of methane in 0.50 m^3 of the gas at a pressure of 2.0 × 10^2 kPa and a temperature of exactly 300 K.

Last Answer : Calculate the number of molecules of methane in 0.50 m3 of the gas at a pressure of 2.0 × 102 kPa and a temperature of exactly 300 K.

An air-water vapour mixture has a dry bulb temperature of 60°C and a dew point temperature of 40°C. The total pressure is 101.3 kPa and the vapour pressure of water at 40°C and 60°C are 7.30 kPa and 19.91 kPa respectively. The humidity of air sample expressed as kg of water vapour/kg of dry air is: (A) 0.048 (B) 0.079 (C) 0.122 (D) 0.152

Description : An air-water vapour mixture has a dry bulb temperature of 60°C and a dew point temperature of 40°C. The total pressure is 101.3 kPa and the vapour pressure of water at 40°C and 60°C are 7.30 kPa and 19.91 kPa respectively ... air is: (A) 0.048 (B) 0.079 (C) 0.122 (D) 0.152

Last Answer : (D) 0.152

A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Description : A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Last Answer : (B) 11.77 kPa

. A 0.5 m high bed made up of a 1 mm dia glass sphere (density 2500 kg/m3 ) is to be fluidised by water (density 1000 kg/m3 ). If at the point of incipient fluidisation, the bed voidage is 40%, the pressure drop across the bed is (A) 4.4 KPa (B) 2.94 KPa (C) 3.7 KPa (D) None of these

Description : . A 0.5 m high bed made up of a 1 mm dia glass sphere (density 2500 kg/m3 ) is to be fluidised by water (density 1000 kg/m3 ). If at the point of incipient fluidisation, the bed voidage is 40%, the pressure drop across the bed is (A) 4.4 KPa (B) 2.94 KPa (C) 3.7 KPa (D) None of these

Last Answer : (A) 4.4 KPa

At 60° C, vapour pressure of methanol and water are 84.562 kPa and 19.953 kPa respectively. An aqueous solution of methanol at 60° C exerts a pressure of 39.223 kPa; the liquid phase and vapour phase mole fractions of methanol are 0.1686 and 0.5714 respectively. Activity co-efficient of methanol is (A) 1.572 (B) 1.9398 (C) 3.389

Description : At 60° C, vapour pressure of methanol and water are 84.562 kPa and 19.953 kPa respectively. An aqueous solution of methanol at 60° C exerts a pressure of 39.223 kPa; the liquid phase and vapour phase mole ... respectively. Activity co-efficient of methanol is (A) 1.572 (B) 1.9398 (C) 3.389

Last Answer : (A) 1.572

A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is the partial pressure of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Description : A 0.064 kg of octane vapor (MW = 114) is mixed with0.91 kg of air (MW = 29.0) in the manifold of an Engine. The total pressure in the manifold is 86.1 kPa, and a temperature is 290 K. assume octane behaves ideally. What is ... of the air in the mixture in KPa?  a. 46.8  b. 48.6  c. 84.6  d. 64.8

Last Answer : 84.6

A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Description : A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Last Answer : 12 kJ

The pressure drop in a 30 cm diameter horizontal pipe is 60 kPa in distance of 15m. The wall shear stress in kPa is (a) 0.1 (b) 0.2 (c) 0.3 (d) 0.4

Description : The pressure drop in a 30 cm diameter horizontal pipe is 60 kPa in distance of 15m. The wall shear stress in kPa is (a) 0.1 (b) 0.2 (c) 0.3 (d) 0.4

Last Answer : (c) 0.3

What is the resulting concentration (in molL) of aqueous hydrochloric acid if 500 mL of its gaseous form at 300 K and 100 kPa will be dissolved in 100 mL pure water Use 8.314 kPaL(Kmol)?

Description : What is the resulting concentration (in molL) of aqueous hydrochloric acid if 500 mL of its gaseous form at 300 K and 100 kPa will be dissolved in 100 mL pure water Use 8.314 kPaL(Kmol)?

Last Answer : Feel Free to Answer

Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Description : Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Last Answer : -1384.7 kJ

What would happen if we replaced 20% of our atmosphere's nitrogen with neon?

Description : What would happen if we replaced 20% of our atmosphere's nitrogen with neon?

Last Answer : I would be like “Whoa!”

which of the following gases is not a significant ingredient of the jovian planet atmospheres? -General Knowledge

Description : which of the following gases is not a significant ingredient of the jovian planet atmospheres? -General Knowledge

Last Answer : Carbon dioxide is important in the terrestrial planet atmospheres, but not in the jovian planet atmospheres.

Why have the Jovian planets retained their atmospheres?

Description : Why have the Jovian planets retained their atmospheres?

Last Answer : Simply because the gas giants are so big that the force ofgravity is sufficient to retain the light gases.

Which gases are found in the atmospheres of the gas giantes?

Description : Which gases are found in the atmospheres of the gas giantes?

Last Answer : Hydrogren and helium

Which of the statements to about the Troposphere is not true? A. It contains 85-90% of the atmosphere’s mass B. It contains nearly all the water and oxygen of the atmosphere C. It is the zone which exhibits changes in condition of weather D. It is about 350 km thick (Answer)

Description : Which of the statements to about the Troposphere is not true? A. It contains 85-90% of the atmosphere’s mass B. It contains nearly all the water and oxygen of the atmosphere C. It is the zone which exhibits changes in condition of weather D. It is about 350 km thick (Answer)

Last Answer : D. It is about 350 km thick (Answer)

To what does the atmosphere's "greenhouse effect" refer to? w) the fact that ozone reflects ultraviolet radiation x) the fact that air prevents heat from leaving the earth y) the fact that clouds prevent sunlight from reaching the earth z) the fact that green plants use sunlight to produce food

Description : To what does the atmosphere's "greenhouse effect" refer to? w) the fact that ozone reflects ultraviolet radiation x) the fact that air prevents heat from leaving the earth y) the fact that clouds prevent sunlight from reaching the earth z) the fact that green plants use sunlight to produce food

Last Answer : ANSWER: X -- THE FACT THAT AIR PREVENTS HEAT FROM LEAVING THE EARTH 

if a gas has a gage pressure of 156 kpa, its absolute pressure is approximately -General Knowledge

Description : if a gas has a gage pressure of 156 kpa, its absolute pressure is approximately -General Knowledge

Last Answer : If a gas has a gage pressure of 156 kPa, its absolute pressure is approximately 256 kPa.

A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure becomes 2.9 kPa at 298 K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

Description : A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure ... K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

Last Answer : For a very dilute solution ∴ Molecular mass, MB = 34 g/mol.

The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Description : The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Last Answer : 400 mL(Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer

Calculate the volume of 1 mole of a gas at exactly 20°C at a pressure of 101.35 kPa.

Description : Calculate the volume of 1 mole of a gas at exactly 20°C at a pressure of 101.35 kPa.

Last Answer : Calculate the volume of 1 mole of a gas at exactly 20°C at a pressure of 101.35 kPa.

At constant temperature the pressure of 22.4 dm^3 volume of an ideal gas was increased from 10^5 kPa to 210 kPa, New volume could be -

Description : At constant temperature the pressure of 22.4 dm^3 volume of an ideal gas was increased from 10^5 kPa to 210 kPa, New volume could be -

Last Answer : At constant temperature the pressure of 22.4 dm3 volume of an ideal gas was increased from 105 kPa to 210 kPa, New ... 2 dm3 c. 22.4 dm3 d. 5.6 dm3

When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

Description : When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

Last Answer : The pressure is 207,5 kPa.

If a gas has an absolute pressure of 319 kPa its gage pressure is?

Description : If a gas has an absolute pressure of 319 kPa its gage pressure is?

Last Answer : Need answer

Air initially at 101. 3 kPa and 40°C and with a relative humidity of 50%, is cooled at constant pressure to 30°C. The cooled air has a (A) Higher dew point (B) Higher absolute (specific) humidity (C) Higher relative humidity (D) Higher wet bulb temperature

Description : Air initially at 101. 3 kPa and 40°C and with a relative humidity of 50%, is cooled at constant pressure to 30°C. The cooled air has a (A) Higher dew point (B) Higher absolute (specific) humidity (C) Higher relative humidity (D) Higher wet bulb temperature

Last Answer : (C) Higher relative humidity

Height of atmosphere, if atmospheric density is 1.29 kg m-3 and atmospheric pressure is 101 kPa, is A. 7839.4 m B. 7829.4 m C. 7849.4 m D. 7859.4 m

Description : Height of atmosphere, if atmospheric density is 1.29 kg m-3 and atmospheric pressure is 101 kPa, is A. 7839.4 m B. 7829.4 m C. 7849.4 m D. 7859.4 m

Last Answer : 7829.4 m

For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be (A) 6738.9 (B) 6753.5 (C) 7058.3 (D) 9000

Description : For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be (A) 6738.9 (B) 6753.5 (C) 7058.3 (D) 9000

Last Answer : (B) 6753.5

1m3 of an ideal gas at 500 K and 1000 kPa expands reversibly to 5 times its initial volume in an insulated container. If the specific heat capacity (at constant pressure) of the gas is 21 J/mole . K, the final temperature will be (A) 35 K (B) 174 K (C) 274 K (D) 154 K

Description : 1m3 of an ideal gas at 500 K and 1000 kPa expands reversibly to 5 times its initial volume in an insulated container. If the specific heat capacity (at constant pressure) of the gas is 21 J/mole . K, the final temperature will be (A) 35 K (B) 174 K (C) 274 K (D) 154 K

Last Answer : (C) 274 K

The pressure at a point 4 m below the free surface of water is (A) 19.24 kPa (B) 29.24 kPa (C) 39.24 kPa (D) 49.24 kPa

Description : The pressure at a point 4 m below the free surface of water is (A) 19.24 kPa (B) 29.24 kPa (C) 39.24 kPa (D) 49.24 kPa

Last Answer : Answer: Option C

The pressure intensity in kN/m2 (or kPa) at any point in a liquid is (where w = Specific weight of liquid, and h = Depth of liquid from the surface) (A) w (B) wh (C) w/h (D) h/w

Description : The pressure intensity in kN/m2 (or kPa) at any point in a liquid is (where w = Specific weight of liquid, and h = Depth of liquid from the surface) (A) w (B) wh (C) w/h (D) h/w

Last Answer : Answer: Option B

While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Description : While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Last Answer : 217.7 kPa

While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Description : While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Last Answer : 217.17 kpa

A vacuum is connected to a tank reads 3kpa at a location w/ the barametric pressure reading is 75mmhg. Determined the P absolute in the tank  a. 70.658 kpa  b. 68 kpa  c. 58.78 kap  d. None of the above Pabs = Patm – Pvacuum

Description : A vacuum is connected to a tank reads 3kpa at a location w/ the barametric pressure reading is 75mmhg. Determined the P absolute in the tank  a. 70.658 kpa  b. 68 kpa  c. 58.78 kap  d. None of the above Pabs = Patm – Pvacuum

Last Answer : 70.658 kpa

An automobile tire has a gauge pressure of 200 kpa at 0°C assuming no air leaks and no change of volume of the tire, what is the gauge pressure at 35ºC.  a. 298.645  b. 398.109  c. 291.167  d. 281.333 Pg = Pabs - Patm

Description : An automobile tire has a gauge pressure of 200 kpa at 0°C assuming no air leaks and no change of volume of the tire, what is the gauge pressure at 35ºC.  a. 298.645  b. 398.109  c. 291.167  d. 281.333 Pg = Pabs - Patm

Last Answer : 298.645

A pressure gage registers 50 psig in a region where the barometer is 14.25 psia. Find absolute pressure in psia, Pa. (Formula; p = patm+ pg)  a. 433 kPa  b. 443 kPa  c. 343 kPa  d. None of the above

Description : A pressure gage registers 50 psig in a region where the barometer is 14.25 psia. Find absolute pressure in psia, Pa. (Formula; p = patm+ pg)  a. 433 kPa  b. 443 kPa  c. 343 kPa  d. None of the above

Last Answer : 443 kPa

A 30-m vertical column of fluid (density 1878 kg/m3 ) is located where g= 9.65 mps2 . Find the pressure at the base of the column. (Formula: pg= gρhg/k )  a. 543680 N/m2  b. 543.68 kPa (gauge)  c. Both a & b  d. None of the above

Description : A 30-m vertical column of fluid (density 1878 kg/m3 ) is located where g= 9.65 mps2 . Find the pressure at the base of the column. (Formula: pg= gρhg/k )  a. 543680 N/m2  b. 543.68 kPa (gauge)  c. Both a & b  d. None of the above

Last Answer : Both a & b

The flow energy of 150 L of a fluid passing a boundary to a system is 110 kJ. Determine the pressure at this point  a. 733.33 kPa  b. 833.33 kPa  c. 933.33 kPa  d. 633.33 kPa

Description : The flow energy of 150 L of a fluid passing a boundary to a system is 110 kJ. Determine the pressure at this point  a. 733.33 kPa  b. 833.33 kPa  c. 933.33 kPa  d. 633.33 kPa

Last Answer : 733.33 kPa

A piezo-electric type pressure sensor has a sensitivity of 1 mV/kPa and a bandwidth of 300 Hz to 300 kHz.

Description : A piezo-electric type pressure sensor has a sensitivity of 1 mV/kPa and a bandwidth of 300 Hz to 300 kHz. For a constant (dc) pressure of 100 kPa, the steady state output of the sensor in millivolt is (A) 0 (B) 2 (C) 4 (D) 6

Last Answer : A piezo-electric type pressure sensor has a sensitivity of 1 mV/kPa and a bandwidth of 300 Hz to 300 kHz. For a constant (dc) pressure of 100 kPa, the steady state output of the sensor in millivolt is 0

Standard quantity of material per unit 5KG. Standard Price Rs 5 per KG. actual number of units 400 units. Actual quantity 2,200KG and price of material Rs 4.80 per kg. Calculate material price. a) 100(F) b) 500(A) c) 440(F) d) 600(F)

Description : Standard quantity of material per unit 5KG. Standard Price Rs 5 per KG. actual number of units 400 units. Actual quantity 2,200KG and price of material Rs 4.80 per kg. Calculate material price. a) 100(F) b) 500(A) c) 440(F) d) 600(F)

Last Answer : The standard quantity of material per unit is 5KG, so the standard quantity for 400 units would be: Standard quantity = 5KG/unit x 400 units = 2000KG The standard price per KG is Rs 5, so the ... material cost was lower than the standard material cost. Option (c) is the correct answer: 440(F).