Calculate the volume of 1 mole of a gas at exactly 20°C at a pressure of 101.35 kPa.

Calculate the volume of 1 mole of a gas at exactly 20°C at a pressure of 101.35 kPa.
by

1 Answer

Answer :

Calculate the volume of 1 mole of a gas at exactly 20°C at a pressure of 101.35 kPa.
by
selected by

Related questions

Standard air is the: a. Mass of 1 cubic meter of dry air at 20°C and atmospheric pressure b. Mass of a cubic meter of air at atmospheric conditions c. Volume of air at ambient temperature and atmospheric pressure d. Volume of 1 kg of dry air at 21°C and atmospheric pressure at sea level or 101.325 kPa e. Volume of 1 kg of air at 15°C and 100 kPa

Description : Standard air is the: a. Mass of 1 cubic meter of dry air at 20°C and atmospheric pressure b. Mass of a cubic meter of air at atmospheric conditions c. Volume of air at ambient temperature and atmospheric pressure ... pressure at sea level or 101.325 kPa e. Volume of 1 kg of air at 15°C and 100 kPa

Last Answer : Answer: D

1m3 of an ideal gas at 500 K and 1000 kPa expands reversibly to 5 times its initial volume in an insulated container. If the specific heat capacity (at constant pressure) of the gas is 21 J/mole . K, the final temperature will be (A) 35 K (B) 174 K (C) 274 K (D) 154 K

Description : 1m3 of an ideal gas at 500 K and 1000 kPa expands reversibly to 5 times its initial volume in an insulated container. If the specific heat capacity (at constant pressure) of the gas is 21 J/mole . K, the final temperature will be (A) 35 K (B) 174 K (C) 274 K (D) 154 K

Last Answer : (C) 274 K

A liquid mixture contains 30% o-xylene, 60% p-xylene and 10%. m￾xylene (all percentages in w/w). Which of the following statements would be true in respect of this mixture? (A) The mixture exhibits an azeotrope at 101.3 kPa (B) The composition of the mixture, in percent by volume is: o-xylene 30, p￾xylene 60. and m-xylene 10 (C) The composition of the mixture in mole percent is: o-xylene 30, p-xylene 60 and m-xyoene 10 (D) The mixture contain optical isomers

Description : A liquid mixture contains 30% o-xylene, 60% p-xylene and 10%. m￾xylene (all percentages in w/w). Which of the following statements would be true in respect of this mixture? (A) The mixture exhibits ... : o-xylene 30, p-xylene 60 and m-xyoene 10 (D) The mixture contain optical isomers

Last Answer : (A) The mixture exhibits an azeotrope at 101.3 kPa

The specific volume of air is expressed as the volume of: a. 1 kg of air at 101.325 kPa in cm3 b. 0.833 kg of air at standard pressure and temperature in m3 c. 1 kg of air at 101.325 kPa and 21 degrees Celsius in m3 d. 1 g of air occupied at any temperature and pressure e. 1 kg of air, regardless of temperature and pressure

Description : The specific volume of air is expressed as the volume of: a. 1 kg of air at 101.325 kPa in cm3 b. 0.833 kg of air at standard pressure and temperature in m3 c. 1 kg of air at 101.325 ... d. 1 g of air occupied at any temperature and pressure e. 1 kg of air, regardless of temperature and pressure

Last Answer : Answer: C

Calculate the number of molecules of methane in 0.50 m^3 of the gas at a pressure of 2.0 × 10^2 kPa and a temperature of exactly 300 K.

Description : Calculate the number of molecules of methane in 0.50 m^3 of the gas at a pressure of 2.0 × 10^2 kPa and a temperature of exactly 300 K.

Last Answer : Calculate the number of molecules of methane in 0.50 m3 of the gas at a pressure of 2.0 × 102 kPa and a temperature of exactly 300 K.

For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be (A) 6738.9 (B) 6753.5 (C) 7058.3 (D) 9000

Description : For water at 300°C, it has a vapour pressure 8592.7 kPa and fugacity 6738.9 kPa Under these conditions, one mole of water in liquid phase has a volume of 25.28 cm3 and that in vapour phase in 391.1 cm3.Fugacity of water (in kPa) at 9000 kPa will be (A) 6738.9 (B) 6753.5 (C) 7058.3 (D) 9000

Last Answer : (B) 6753.5

A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure becomes 2.9 kPa at 298 K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

Description : A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure ... K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

Last Answer : For a very dilute solution ∴ Molecular mass, MB = 34 g/mol.

Air initially at 101. 3 kPa and 40°C and with a relative humidity of 50%, is cooled at constant pressure to 30°C. The cooled air has a (A) Higher dew point (B) Higher absolute (specific) humidity (C) Higher relative humidity (D) Higher wet bulb temperature

Description : Air initially at 101. 3 kPa and 40°C and with a relative humidity of 50%, is cooled at constant pressure to 30°C. The cooled air has a (A) Higher dew point (B) Higher absolute (specific) humidity (C) Higher relative humidity (D) Higher wet bulb temperature

Last Answer : (C) Higher relative humidity

An air-water vapour mixture has a dry bulb temperature of 60°C and a dew point temperature of 40°C. The total pressure is 101.3 kPa and the vapour pressure of water at 40°C and 60°C are 7.30 kPa and 19.91 kPa respectively. The humidity of air sample expressed as kg of water vapour/kg of dry air is: (A) 0.048 (B) 0.079 (C) 0.122 (D) 0.152

Description : An air-water vapour mixture has a dry bulb temperature of 60°C and a dew point temperature of 40°C. The total pressure is 101.3 kPa and the vapour pressure of water at 40°C and 60°C are 7.30 kPa and 19.91 kPa respectively ... air is: (A) 0.048 (B) 0.079 (C) 0.122 (D) 0.152

Last Answer : (D) 0.152

Height of atmosphere, if atmospheric density is 1.29 kg m-3 and atmospheric pressure is 101 kPa, is A. 7839.4 m B. 7829.4 m C. 7849.4 m D. 7859.4 m

Description : Height of atmosphere, if atmospheric density is 1.29 kg m-3 and atmospheric pressure is 101 kPa, is A. 7839.4 m B. 7829.4 m C. 7849.4 m D. 7859.4 m

Last Answer : 7829.4 m

At 60° C, vapour pressure of methanol and water are 84.562 kPa and 19.953 kPa respectively. An aqueous solution of methanol at 60° C exerts a pressure of 39.223 kPa; the liquid phase and vapour phase mole fractions of methanol are 0.1686 and 0.5714 respectively. Activity co-efficient of methanol is (A) 1.572 (B) 1.9398 (C) 3.389

Description : At 60° C, vapour pressure of methanol and water are 84.562 kPa and 19.953 kPa respectively. An aqueous solution of methanol at 60° C exerts a pressure of 39.223 kPa; the liquid phase and vapour phase mole ... respectively. Activity co-efficient of methanol is (A) 1.572 (B) 1.9398 (C) 3.389

Last Answer : (A) 1.572

A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg

A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A → B. Assume the heat of reaction is - 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal to 50J/mole.K. The temperature rise after a conversion of 0.5 will be: (A) 5°C (B) 10°C (C) 20°C (D) 100°C

Description : A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A → B. Assume the heat of reaction is - 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal ... rise after a conversion of 0.5 will be: (A) 5°C (B) 10°C (C) 20°C (D) 100°C

Last Answer : (B) 10°C

At constant temperature the pressure of 22.4 dm^3 volume of an ideal gas was increased from 10^5 kPa to 210 kPa, New volume could be -

Description : At constant temperature the pressure of 22.4 dm^3 volume of an ideal gas was increased from 10^5 kPa to 210 kPa, New volume could be -

Last Answer : At constant temperature the pressure of 22.4 dm3 volume of an ideal gas was increased from 105 kPa to 210 kPa, New ... 2 dm3 c. 22.4 dm3 d. 5.6 dm3

When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

Description : When a gas of 3.4 moles occupies a volume of 40.6 L at 298 K what is the pressure of the gas in kPa?

Last Answer : The pressure is 207,5 kPa.

A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Description : A gas is enclosed in a cylinder with a weighted piston as the top boundary. The gas is heated and expands from a volume of 0.04 m3 to 0.10 m3 at a constant pressure of 200 kPa. Find the work done on the system.  a. 5 kJ  b. 15 kJ  c. 10 kJ  d. 12 kJ

Last Answer : 12 kJ

The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Description : The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Last Answer : 400 mL(Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer

While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Description : While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Last Answer : 217.7 kPa

While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Description : While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Last Answer : 217.17 kpa

An automobile tire has a gauge pressure of 200 kpa at 0°C assuming no air leaks and no change of volume of the tire, what is the gauge pressure at 35ºC.  a. 298.645  b. 398.109  c. 291.167  d. 281.333 Pg = Pabs - Patm

Description : An automobile tire has a gauge pressure of 200 kpa at 0°C assuming no air leaks and no change of volume of the tire, what is the gauge pressure at 35ºC.  a. 298.645  b. 398.109  c. 291.167  d. 281.333 Pg = Pabs - Patm

Last Answer : 298.645

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Calculate the volume occupied by 10 mole of CO2 at STP.

Description : Calculate the volume occupied by 10 mole of CO2 at STP.

Last Answer : Ans. 1 mol of CO2 at STP = 22.7 L 10 mole of CO2 at STP = 22.7 x 10 =227 L

A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Last Answer : 2 x10^6 kJ

Convert :  a. Exactly 1.5 atm to pascals  b. 89 kPa to newton per square metre (N m^(-2)) 

Description : Convert :  a. Exactly 1.5 atm to pascals  b. 89 kPa to newton per square metre (N m^(-2)) 

Last Answer : Convert : a. Exactly 1.5 atm to pascals b. 89 kPa to newton per square metre (N m-2) ... -100°C to Kelvin e. 0.124 torr to standard atmosphere

One mole of a gas occupying `3dm^(3)` expands against a constant external pressure of 1 atm to a volume of 13 lit. The workdone is :-

Description : One mole of a gas occupying `3dm^(3)` expands against a constant external pressure of 1 atm to a volume of 13 lit. The workdone is :-

Last Answer : One mole of a gas occupying `3dm^(3)` expands against a constant external pressure of 1 atm to a volume of 13 lit. ... `dm^(3)` D. `-48` atm `dm^(3)`

if a gas has a gage pressure of 156 kpa, its absolute pressure is approximately -General Knowledge

Description : if a gas has a gage pressure of 156 kpa, its absolute pressure is approximately -General Knowledge

Last Answer : If a gas has a gage pressure of 156 kPa, its absolute pressure is approximately 256 kPa.

If a gas has an absolute pressure of 319 kPa its gage pressure is?

Description : If a gas has an absolute pressure of 319 kPa its gage pressure is?

Last Answer : Need answer

The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Description : The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 14026.5 m³

Calculate the pressure in atm of 1.0 mole of helium in a 2.0 dm^3 container at 20.0°C.

Description : Calculate the pressure in atm of 1.0 mole of helium in a 2.0 dm^3 container at 20.0°C.

Last Answer : Calculate the pressure in atm of 1.0 mole of helium in a 2.0 dm3 container at 20.0°C.

CPC include a) 51 orders & 158 Sections b) 101 orders & 511 Section c) 35 orders & 488 Sections d) None of these

Description : CPC include  a) 51 orders & 158 Sections b) 101 orders & 511 Section c) 35 orders & 488 Sections d) None of these

Last Answer : a) 51 orders & 158 Sections

CPC include a) 51 orders & 158 Sections b) 101 orders & 511 Section c) 35 orders & 488 Sections d) None of these

Description : CPC include  a) 51 orders & 158 Sections b) 101 orders & 511 Section c) 35 orders & 488 Sections d) None of these

Last Answer : (c) 2(17)

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

Temperature and gage pressure maintained during the manufacture of cold SBR (styrene butadiene rubber) are (A) 5°C and 1 kgf/cm2 (B) - 20°C and 1 kgf/cm2 (C) 0°C and 1 kgf/cm2 (D) 0°C and 3 kgf/cm

Description : Temperature and gage pressure maintained during the manufacture of cold SBR (styrene butadiene rubber) are (A) 5°C and 1 kgf/cm2 (B) - 20°C and 1 kgf/cm2 (C) 0°C and 1 kgf/cm2 (D) 0°C and 3 kgf/cm

Last Answer : (A) 5°C and 1 kgf/cm

Normal temperature and pressure (N.T.P.) corresponds to (A) 0°C and 760 mm Hg (B) 15°C and 760 mm Hg (C) 20°C and 760 mm Hg (D) 0°C and 1 kgf/cm2

Description : Normal temperature and pressure (N.T.P.) corresponds to (A) 0°C and 760 mm Hg (B) 15°C and 760 mm Hg (C) 20°C and 760 mm Hg (D) 0°C and 1 kgf/cm2

Last Answer : (C) 20°C and 760 mm Hg

a gas has a pressure of 766.7 torr at a temperature of 10.0°C. the sample contains 2.35 moles of xenon. what is the volume of the gas in liters?

Description : a gas has a pressure of 766.7 torr at a temperature of 10.0°C. the sample contains 2.35 moles of xenon. what is the volume of the gas in liters?

Last Answer : Using PV=nRT, 10.0ºC = 283.15ºK, R = 62.36 L torr/mol KV= (nRT)/PV = (2.35m*(62.36 L torr/mol K)*283.15ºK)/766.7 TorrV = 54.12 L

Nitrogen gas is filled in a container of volume 2.32 L at 32°C and 4.7 atm pressure. Calculate the number of moles of the gas.

Description : Nitrogen gas is filled in a container of volume 2.32 L at 32°C and 4.7 atm pressure. Calculate the number of moles of the gas.

Last Answer : Nitrogen gas is filled in a container of volume 2.32 L at 32°C and 4.7 atm pressure. Calculate the number of moles of the gas.

Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 126m³

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Description : A cylinder contains oxygen at a pressure of 10 atm and a temperature of 300 K. The volume of the cylinder is 10 liters. What is the mass of the oxygen in grams? Molecular weight (MW) of oxygen is 32 g/mole?  a. 125.02  b. 130.08  c. 135.05  d. 120.04

Last Answer : 130.08 {(10atm)(10)(32)/(0.0821) (300K)}

Which of the following parameters is constant for a mole for most of the gases at a given temperature and pressure  (a) enthalpy  (b) volume  (c) mass  (d) entropy  (e) specific volume.

Description : Which of the following parameters is constant for a mole for most of the gases at a given temperature and pressure  (a) enthalpy  (b) volume  (c) mass  (d) entropy  (e) specific volume.

Last Answer : Answer : b

What is the volume of 1 mole of methane gas in proof temperature and condition ?

Description : What is the volume of 1 mole of methane gas in proof temperature and condition ?

Last Answer : The volume of 1 mole methane gas is 22.4 liters.

What is the volume of 1 mole of methane gas ?

Description : What is the volume of 1 mole of methane gas ?

Last Answer : The volume of 1 mole methane gas is 22.4 liters.

The workdone in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 litres to 20 litres at `25^(@)C` is

Description : The workdone in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 litres to 20 litres at `25^(@)C` is

Last Answer : The workdone in ergs for the reversible expansion of one mole of an ideal gas from a volume of 10 ... 0821xx298xx` log 0.5 D. `-2.303xx2xx298` log2

For the reversible isothermal expansion of one mole of an ideal gas at 300 K, from a volume of `10 dm^(3)` to `20 dm^(3), Delta H` is -

Description : For the reversible isothermal expansion of one mole of an ideal gas at 300 K, from a volume of `10 dm^(3)` to `20 dm^(3), Delta H` is -

Last Answer : For the reversible isothermal expansion of one mole of an ideal gas at 300 K, from a volume of `10 dm^(3)` to ` ... . `-1.73 KJ` C. `3.46 KJ` D. Zero

0.01 mole of iodoform `(CHI_(3))` reacts with Ag to produce a gas whose volume at NTP is `2CHI_(3)+6Ag to6Agl(s)+C_(2)H_(2)(g)`

Description : 0.01 mole of iodoform `(CHI_(3))` reacts with Ag to produce a gas whose volume at NTP is `2CHI_(3)+6Ag to6Agl(s)+C_(2)H_(2)(g)`

Last Answer : 0.01 mole of iodoform `(CHI_(3))` reacts with Ag to produce a gas whose volume at NTP is `2CHI_(3)+6Ag ... mL B. 112 mL C. 336 mL D. None of these

One mole of aniline warmed with the mixture of `NaNO_(2)+HCl`. If we assume 100% yield, volume of `N_(2)` gas liberated at S.T.P is

Description : One mole of aniline warmed with the mixture of `NaNO_(2)+HCl`. If we assume 100% yield, volume of `N_(2)` gas liberated at S.T.P is

Last Answer : One mole of aniline warmed with the mixture of `NaNO_(2)+HCl`. If we assume 100% yield, volume of `N_(2)` gas ... 4 L` C. `33.6 L` D. `44.8 L`

What is the volume occupied by one mole of a gas under standard conditions called?

Description : What is the volume occupied by one mole of a gas under standard conditions called?

Last Answer : ANSWER: A MOLAR VOLUME

In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

Description : In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

Last Answer : 1 atm

In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

Description : In thermodynamics the standard pressure is 100.0 kpa . What is this value in units of atmospheres?

Last Answer : 1 atm

Unit for pressure used in weather maps is millibar. 1 millibar is equal to A. 1000 bar B. 100 kPa C. 100 Pa D. 1 atm

Description : Unit for pressure used in weather maps is millibar. 1 millibar is equal to A. 1000 bar B. 100 kPa C. 100 Pa D. 1 atm

Last Answer : 100 Pa