In a distribution the frequency of a class is replaced with a proportion or percent?

In a distribution the frequency of a class is replaced with a proportion or percent?
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Which one of the two you do does not matter.
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In a distribution the frequency of a class is replaced with a proportion or percent?

Description : In a distribution the frequency of a class is replaced with a proportion or percent?

Last Answer : Which one of the two you do does not matter.

How many litres of a 36 litre mixture containing milk and water in the ratio of 4 : 6 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion? a) 3 b) 2 c) 4 d) 7 e) 6

Description : How many litres of a 36 litre mixture containing milk and water in the ratio of 4 : 6 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion? a) 3 b) 2 c) 4 d) 7 e) 6 

Last Answer :  E  The mixture contains 40% milk and 60% water in it.  That is 14.4 litres of milk and 21.6 litres of water.  Now we are replacing the mixture with pure milk so that the amount of milk and water in the ... containing 60% water,  we need to remove ={3.6}/{0.6} litres of the mixture  = 6 litres

How can you use a proportion to solve a percent question?

Description : How can you use a proportion to solve a percent question?

Last Answer : A percent is simply a proportion out of 100.

What should be the proportion of forest cover for India to maintain her ecological balance? (1) 11.1 percent (2) 22.2 percent (3) 33.3 percent (4) 44.4 percent

Description : What should be the proportion of forest cover for India to maintain her ecological balance? (1) 11.1 percent (2) 22.2 percent (3) 33.3 percent (4) 44.4 percent

Last Answer : (3) 33.3 percent Explanation: The minimum area of forests to maintain a good ecological balance has been regarded to be 33%. India lags on this front. The Green India campaign has been ... the Prime Minister for the afforestation of 6 million hectares. The current area under forests is 23%.

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Description : The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Last Answer : Since the class marks are equally spaced. ∴ Class size = 114 - 104 = 10 If a is a class mark and h is size of class interval, then lower limit and upper limit of the class interval area a - h / 2 and a + h / ... are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.

Following is the frequency distribution of total marks obtained by the students of different section of class-IX. -Maths 9th

Description : Following is the frequency distribution of total marks obtained by the students of different section of class-IX. -Maths 9th

Last Answer : Since class intervals of the given frequency distribution are not of equal width. We would make modifications in the lengths of the rectangles in the histogram, so that the areas of rectangles are proportional ... lengths as given in the last column .The histogram of the data is given below.

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Description : The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Last Answer : Since the class marks are equally spaced. ∴ Class size = 114 - 104 = 10 If a is a class mark and h is size of class interval, then lower limit and upper limit of the class interval area a - h / 2 and a + h / ... are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.

Following is the frequency distribution of total marks obtained by the students of different section of class-IX. -Maths 9th

Description : Following is the frequency distribution of total marks obtained by the students of different section of class-IX. -Maths 9th

Last Answer : Since class intervals of the given frequency distribution are not of equal width. We would make modifications in the lengths of the rectangles in the histogram, so that the areas of rectangles are proportional ... lengths as given in the last column .The histogram of the data is given below.

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Description : In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Last Answer : NEED ANSWER

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : NEED ANSWER

If m is the mid-point and l is the upper class limit of a class in a continuous frequency distribution, then lower class limit of the class is -Maths 9th

Description : If m is the mid-point and l is the upper class limit of a class in a continuous frequency distribution, then lower class limit of the class is -Maths 9th

Last Answer : NEED ANSWER

The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Description : The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Description : In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is -Maths 9th

Last Answer : (b) Let x and y be the upper and lower class limit in a frequency distribution. Now, mid value of a class (x + y )/2=10 [given] ⇒ x + y = 20 (i) Also, given that, width of class x- y = 6 (ii) On ... putting x = 13 in Eq. (i), we get 13+y = 20 ⇒ y = 7 Hence, the lower limit of the class is 7.

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : (c) Let x and y be the upper and lower class limit of frequency distribution. Given, width of the class = 5 ⇒ x-y= 5 (i) Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get ... 20-25, 25-30 and 30-35. Thus, the highest class is 30-35, Hence, the upper limit of this class is 35.

If m is the mid-point and l is the upper class limit of a class in a continuous frequency distribution, then lower class limit of the class is -Maths 9th

Description : If m is the mid-point and l is the upper class limit of a class in a continuous frequency distribution, then lower class limit of the class is -Maths 9th

Last Answer : (b) Let x and y be the lower and upper class limit of a continuous frequency distribution. Now, mid-point of a class = (x + y)/2 = m [given] ⇒ x + y = 2 m =x + l = 2m [∴ y = l = upper class limit (given)] ⇒ x = 2 m-l Hence, the lower class limit of the class is 2m – l.

The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Description : The class marks of a frequency distribution are given as follows 15, 20, 25, …. The class corresponding to the class mark 20 is -Maths 9th

Last Answer : (b) Since, the difference between mid value is 5. So, the corresponding class to the class mark 20 must have difference 5. Therefore, option (c) and (d) are wrong. Since, the mid value is 20 which can get only, if we take option (b)

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

If the class marks in frequency distribution are -Maths 9th

Description : If the class marks in frequency distribution are -Maths 9th

Last Answer : The class size of the distribution is = 40.5 - 33.5 = 7 The required class of the class mark 33.5 is [33.5 - 7/2] - [33.5 + 7/2], i.e., 30 - 37.

Did you know 40 percent of human jobs could be replaced by AI in the future? -Do You Know?

Description : Did you know 40 percent of human jobs could be replaced by AI in the future? -Do You Know?

Last Answer : Kai-Fu Lee, a venture capitalist who used to develop artificial intelligence for both Microsoft and Google, told CBS' 60 Minutes that AI will displace 40 percent of the world's workers within 15 years. ... ] is going to change the world more than anything in the history of mankind, Lee told CBS.

54] In operating a 400hz transformer at 50Hz A. Only voltage is reduced in the same proportion as the frequency B. Only KVA rating is reduced in the same proportion as the frequency C. Both voltage and KVA rating are reduced in the same proportion as frequency d. None of the above

Description : 4] In operating a 400hz transformer at 50Hz A. Only voltage is reduced in the same proportion as the frequency B. Only KVA rating is reduced in the same proportion as the frequency C. Both voltage and KVA rating are reduced in the same proportion as frequency D. None of the above

Last Answer : B. Only KVA rating is reduced in the same proportion as the frequency

For an antenna to be frequency-independent, it should expand or contract in proportion to the

Description : For an antenna to be frequency-independent, it should expand or contract in proportion to the  (a) gain (b) directivity (c) wavelength (d) impedance

Last Answer : For an antenna to be frequency-independent, it should expand or contract in proportion to the impedance

Which of the following techniques yields a simple random sample? a. Choosing volunteers from an introductory psychology class to participate b. Listing the individuals by ethnic group and choosing a proportion from within each ethnic group at random. c. Numbering all the elements of a sampling frame and then using a random number table to pick cases from the table. d. Randomly selecting schools, and then sampling everyone within the school.

Description : Which of the following techniques yields a simple random sample? a. Choosing volunteers from an introductory psychology class to participate b. Listing the individuals by ethnic group and choosing a ... from the table. d. Randomly selecting schools, and then sampling everyone within the school.

Last Answer : c. Numbering all the elements of a sampling frame and then using a random number table to pick cases from the table

One of the reasons why FDM is being replaced by TDM is A. noise is amplified with voice when an FDM system is used B. it is difficult to place channels side by side C. there is more time than frequency D. Most available frequencies has been used

Description : One of the reasons why FDM is being replaced by TDM is A. noise is amplified with voice when an FDM system is used B. it is difficult to place channels side by side C. there is more time than frequency D. Most available frequencies has been used

Last Answer : A. noise is amplified with voice when an FDM system is used

The principles of antihypertensive drug usage enunciated in JNC VI and WHO-ISH guidelines include the following except: A. Therapy for grade I and II hypertension should be initiated with a single drug B. Dose of thiazide diuretic should be 12.5-25 mg hydrochlorothiazide or equivalent per day C. All subjects with BP higher than 140/90 mmHg should be put on antihypertensive medication immediately D. If the drug chosen initially fails to lower BP, it should be replaced by a drug/combination from another class

Description : The principles of antihypertensive drug usage enunciated in JNC VI and WHO-ISH guidelines include the following except: A. Therapy for grade I and II hypertension should be initiated with a single drug ... initially fails to lower BP, it should be replaced by a drug/combination from another class

Last Answer : C. All subjects with BP higher than 140/90 mmHg should be put on antihypertensive medication immediately

What is the percent distribution of first letters in the last names in the US?

Description : What is the percent distribution of first letters in the last names in the US?

Last Answer : A 3.75%B 8.96%C 6.38%D 5.65%E 2.03%F 3.63%G 5.34%H 5.59%I 0.76%J 1.36%K 5.70%L 5.24%M 8.28%N 2.13%O 1.63%P 5.27%Q 0.26%R 4.80%S 10.93%T 3.88%U 0.47%V 2.55%W 3.46%X 0.02%Y 0.65%Z 1.29%per the US 2000 Census table of all valid last names appearingthe 100 or more times (covering 90% of responses).

All elements of the marketing mix are influenced by physical distribution functions. For this reason, it is important for marketers to remember that A)physical distribution decisions must be made prior to any other marketing strategy consideration. B)physical distribution costs often rise as customer service requirements decrease. C)over 75 percent of all marketing costs are associated with physical distribution expenditures. D)no single distribution system is ideal for all situations and target markets.

Description : All elements of the marketing mix are influenced by physical distribution functions. For this reason, it is important for marketers to remember that A)physical distribution decisions must be made ... expenditures. D)no single distribution system is ideal for all situations and target markets.

Last Answer : D)no single distribution system is ideal for all situations and target markets.

When asked about the quality of Electrico's distribution system, Mark Johnson proclaims that 95 percent of all orders are filled within two working days. This statement represents the firm's A)mission statement. B)response factor. C)shipping objective. D)customer commitment. E)service standard.

Description : When asked about the quality of Electrico's distribution system, Mark Johnson proclaims that 95 percent of all orders are filled within two working days. This statement represents the firm's A)mission statement. B)response factor. C)shipping objective. D)customer commitment. E)service standard.

Last Answer : E)service standard.

In a power or distribution transformer about 10 percent end turns are heavily insulated?

Last Answer : In a power or distribution transformer about 10 percent end turns are heavily insulated to withstand the high voltage drop due to line surge produced by the shunting capacitance of the end turns.

To draw a histogram to represent the following frequency distribution : -Maths 9th

Description : To draw a histogram to represent the following frequency distribution : -Maths 9th

Last Answer : Adjusted frequency of a class = Minimum class size of frequency distribution × Frequency of given class / Class size of given class ∴ Adjusted frequency for the class 25 - 45 = 5 × 8 / 20 = 2

In figure, there is a histogram depicting daily wages of workers in d factory. Construct the frequency distribution table. -Maths 9th

Description : In figure, there is a histogram depicting daily wages of workers in d factory. Construct the frequency distribution table. -Maths 9th

Last Answer : Frequency distribution table

Draw a histogram and frequency polygon for the following distribution : -Maths 9th

Description : Draw a histogram and frequency polygon for the following distribution : -Maths 9th

Last Answer : We represent class limits along x-axis and number of students along y-axis on a suitable Scale.

To draw a histogram to represent the following frequency distribution : -Maths 9th

Description : To draw a histogram to represent the following frequency distribution : -Maths 9th

Last Answer : Adjusted frequency of a class = Minimum class size of frequency distribution × Frequency of given class / Class size of given class ∴ Adjusted frequency for the class 25 - 45 = 5 × 8 / 20 = 2

In figure, there is a histogram depicting daily wages of workers in d factory. Construct the frequency distribution table. -Maths 9th

Description : In figure, there is a histogram depicting daily wages of workers in d factory. Construct the frequency distribution table. -Maths 9th

Last Answer : Frequency distribution table

Draw a histogram and frequency polygon for the following distribution : -Maths 9th

Description : Draw a histogram and frequency polygon for the following distribution : -Maths 9th

Last Answer : We represent class limits along x-axis and number of students along y-axis on a suitable Scale.

To draw a histogram to represent the following frequency distribution. -Maths 9th

Description : To draw a histogram to represent the following frequency distribution. -Maths 9th

Last Answer : NEED ANSWER

For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are, respectively -Maths 9th

Description : For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are, respectively -Maths 9th

Last Answer : NEED ANSWER

The frequency distribution has been represented graphically as follows. -Maths 9th

Description : The frequency distribution has been represented graphically as follows. -Maths 9th

Last Answer : NEED ANSWER

To draw a histogram to represent the following frequency distribution. -Maths 9th

Description : To draw a histogram to represent the following frequency distribution. -Maths 9th

Last Answer : Frequency distribution.

For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are, respectively -Maths 9th

Description : For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abscissae are, respectively -Maths 9th

Last Answer : (c) Class marks i.e., the mid-point of the classes are abscissa of the points, which we plot for frequency polygon.

The frequency distribution has been represented graphically as follows. -Maths 9th

Description : The frequency distribution has been represented graphically as follows. -Maths 9th

Last Answer : No, here the widths of the rectangles are varying, so we need to make certain modifications in the length of the rectangles so that the areas are proportional to the frequencies. We proceed as ... Now, we get the following modified table So, the correct histogram with varying width is given below

In a frequency distribution, -Maths 9th

Description : In a frequency distribution, -Maths 9th

Last Answer : Lower limit of the class = 10 - 1/2 x 6 = 10 - 3 = 7

The frequency distribution: -Maths 9th

Description : The frequency distribution: -Maths 9th

Last Answer : No, as the classes are of varying widths, not of uniform widths.

Convert the given frequency distribution into a continuous -Maths 9th

Description : Convert the given frequency distribution into a continuous -Maths 9th

Last Answer : Consider the classes 150 - 153 and 154 - 157. The lower limit of 154 - 157 = 154 The upper limit of 150 - 153 = 153 The difference = 154 - 153 = 1 Half the difference = 1/2 = 0.5 So, the ... Continuous classes formed are: 153.5 is included in the class interval 153.5 - 157.5 and 157.5 - 161.5.

Prepare a continuous grouped frequency distribution from the following data: -Maths 9th

Description : Prepare a continuous grouped frequency distribution from the following data: -Maths 9th

Last Answer : If m is mid-point of a class and h is the class size, lower and upper limits of the class intervals are m - h/2 and m + h/2 respectively. Class size (h) = 15 - 5 = 10 So, the class interval formed ... 2) - (5 + 10/2) i.e., 0 - 10 Continuing in the same manner, the continuous classes formed are:

Draw a frequency polygon for the following distribution: -Maths 9th

Description : Draw a frequency polygon for the following distribution: -Maths 9th

Last Answer : Solution :-

Is A frequency of distribution is a way to describe numerical data categorically?

Description : Is A frequency of distribution is a way to describe numerical data categorically?

Last Answer : Need answer

What graph describe the frequency distribution of categorical variable?

Description : What graph describe the frequency distribution of categorical variable?

Last Answer : what is chi-square test of 2X2 table,what we choose for yatescorrection formula

When do we use types of frequency distribution?

Description : When do we use types of frequency distribution?

Last Answer : What is the answer ?

A switchboard, for a AC electrical distribution system, will be provided with which of the following components? A. Frequency meter. B. Ammeter C. Voltmeter D. All of the above

Description : A switchboard, for a AC electrical distribution system, will be provided with which of the following components? A. Frequency meter. B. Ammeter C. Voltmeter D. All of the above

Last Answer : Answer: D