Description : If the numerator of a fraction is increased by 300% and the denominator of the fraction is increased by 150%, the resultant fraction is 3/5. What is the original fraction? a) 7/5 b) 3/7 c) 7/15 d) 1/6 e) None of these
Last Answer : x + 300% of x / y +150% of y = 3/5 400x/250y = 3/5 x/y = 3 × 250 /5 × 400 x/y = 3/8 Answer: e)
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these
Last Answer : Let the numerator & denominator of a fraction be n & d. According to questions, = n × 5 / d × 8 = 5/9 = n/d = 8 × 5 / 5 × 9 = n/d = 8/9 Answer: c)
Description : When 7 is added to the numerator and denominator of the fraction, then the new ratio of numerator and denominator becomes 13:19, what is the original ratio ? A) 11:13 B) 7:9 C) 4:7 D) Can’t be determined E) None of these
Last Answer : Answer: D X+7/y+7 = 13/19 x and y are different variable, so original fraction cannot be determined
Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98
Last Answer : Answer: E Original cost = $140 Decrease in it = 30% of $140 = 30/100 × 140 = 4200/100 = $42 Therefore, decrease cost = $140 - $42 = $98
Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price = $37.5 - $ 30 = $ 7.5 Therefore, percentage increase in price = Increase in price/ ... = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %
Description : A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3
Last Answer : Answer: A Total number of fruits shopkeeper bought = 1800 + 1200 = 1000 Number of rotten blackberry = 45% of 1800 = 45/100 1800 = 81000/100 = 810 Number of rotten blueberry = 24% of 1200 ... Therefore Percentage of fruits in good condition = (1902/3000 100) = (190200/3000) = 63.4%
Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298
Last Answer : Answer: B The number of students with first division = 56 % of 900 = 56/100 × 900 = 50400/100 = 504 And, the number of students with second division = 27 % of 900 = 27/100 × 900 =24300/100 = 243 Therefore, the number of students who just passed = 900 – (504 + 243) = 900- 747 = 153
Description : Sanjay gets 72 % marks in examinations. If these are 864 marks, find the maximum marks. a) 1050 b) 860 c) 1225 d) 1200 e) 1500
Last Answer : Answer: D Let the maximum marks be s Then 72 % of s = 864 72/100 × s = 864 s = (846 × 100)/72 s = 86400/92 s = 1200 Therefore, maximum marks in the examinations are 1200.
Description : Can anyone explain to me what's lacsap's fraction? Also how to find the general term use to find the numerator and denominator?
Last Answer : answer:This looks suspiciously like Pascal's Triangle, which is a way of generating and organizing the binomial coefficients. Or see Wolfram Mathworld. Pascal's triangle has wide appeal for its rich ... as well. Dynamite stuff from a 17C French genius! So what's with the backward spelling?
Description : Is there a fraction with a smaller numerator and denominator that is equivalent to 412?
Last Answer : If you mean 4/12 then it is equivalent to 1/3
Description : What is a fraction in which the greatest common factor of the numerator and the denominator is 1 is written in what?
Last Answer : simplest form
Description : What term describes a fraction that has numerator that is equal to or greater than the denominator?
Last Answer : It is classed as an improper fraction
Description : Why Can you multiply the numerator and denominator of a fraction by the same number to write an equivalent fraction?
Last Answer : Because a fraction is represented by the ratio of the twonumbers and multiplying both by the same number does not changetheir ratio.
Description : What is a fraction when the numerator is grater than its denominator?
Last Answer : It then is an improper or 'top heavy' fraction as for example7/4
Description : If either the numerator or the denominator of a fraction is prime number then the fraction must be in its simplest form.true or faulse?
Last Answer : 1
Description : Determine the relationship between the pair of words NUMERATOR : DENOMINATOR and then select the pair of words from the following which have a similar relationship: (A) fraction : decimal (B) divisor : quotient (C) top : bottom (D) dividend : divisor
Last Answer : (C) top : bottom
Description : Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs ... the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67
Last Answer : Answer – B (Rs 10.875) Explanation – Total C.P = Rs. (120 x 110) =Rs. 13200. Total S.P = Rs.[(30 x 110 + 30 x 12) + (75 x 110 + 75 x 14) + (15 x 110 – 15 x 7) =Rs..14505 Average profit = Rs. (14505 – 13200) /120 = Rs. 1305/120= 10.875
Description : A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980
Last Answer : Answer: C Original value is percentage = 100 %. Reduce amount in percentage = 10 % Therefore, Percent value in percentage = 100 % - 10 % = 90 %. According to the problem, 90 % of original value ... Therefore, 100 % of original value = 1080/100 90 = 1200. Thus, the original value was 1200.
Description : On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40
Last Answer : Answer: E 60% of 500 = 300 80% of 250 = 200 No. of correct answers in remaining 250 questions = 300 – 200 = 100 Percentage = 100 x 100/ 250 = 40%
Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4
Last Answer : Answer: D Let the marks secured by them be x and (x + 18) Then sum of their marks = x + (x + 18) = 2x + 18 Given that (x + 18) was 72% of the sum of their marks =>(x+18) = 72/100(2x+18) => ... 11x = 126 x = 11.45 Then (x + 18) = 11.45 + 18 = 29.45 Hence their marks are 11.45 and 29.45
Description : A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2
Last Answer : Answer: D 90 kg = 81 kg sugar 9 kg rava Adding = 30 kg sugar Total = 111kg sugar 9kg rava (new) 111/120 × 100 = 92.5 =92 1 /2
Description : A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98
Last Answer : Answer: D 60 kg = 36 kg dhal 24 kg rice -------- 15 kg dhal Total = 15 kg dhal 24 kg rice (new) 24/75×100=32%
Description : What percent of a day in 12 hours? a) 25 b) 60 c) 45 d) 20 e) 50
Last Answer : Answer: E Total hours in a day = 24 Required percent = 12/24 ×100 = 50%
Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7
Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41
Last Answer : Answer: A (i) Percentage scored in Mathematics = 120/180 100 = 12000/180 =1200/18 = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100) = (40000/510) = 4000/51 = 78 22/51 %
Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98
Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.
Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180
Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45 x = (45 × 100)/25 x = (4500)/25 x = 180 Therefore, the total number of matches played is 180.
Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313
Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000 = (104/100) × (106/100) × (110/100) × 200000 = 1.04×1.06×1.1×200000 = 2,42,528
Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855
Last Answer : Answer: E Increase = 90 % of 450 = 90/100 × 450 = 40500/100 = 405 Therefore, increase value = 450 + 405 = 855
Description : The Shopkeeper increased the price of a product by 75% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 140% of the required amount. What is the net difference in the ... on that product? a) 12.5 b) 26.0 c) 13.5 d) 17.5 e) 19.8
Last Answer : Answer: D Quantity×Rate=Price 1x1=1 1.4x1.75=2.45 Decrease in price = (0.175/1) × 100 = 17.5%
Description : Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18
Last Answer : Answer: A Let a family's monthly consumption of chenna dhal be x kg. To keep the expenditure fixed, their consumption for this month should be 70x/80 = 7x/8. Reduction in consumption = x/8 = 12.5% of x
Description : A man sold a cycle at a loss of 15%. Had he sold it for Rs.241.87 more he would have gained 24%. For what value should he sell it in order to earn a profit of 30%? a) Rs. 782 b) Rs. 792 c) Rs. 796 d) Rs. 800 e) Rs. 806
Last Answer : Let the cost price be Rs. X :. Selling price = 85X/100 If profit is 24% then selling price = 124X/100 Now, (124X/100) – (85X/100) = 241.8 Or. X= (24180/39) = Rs.620 For 30% gain SP = (130/100)×620 = Rs. 806 Answer is: e)
Description : When the numerator and denominator have 1 as a common factor?
Last Answer : The fraction is in its simplest form.
Description : A transfer function has a second order denominator and constant gain in the numerator
Last Answer : A transfer function has a second order denominator and constant gain in the numerator the system has two zeros at infinity
Description : Dhivya, Dinesh and Deepi enter into a partnership and their shares are in the ratio 1/3 :1/4 :1/5. After 2 months, dhivya withdraws half of her capital and after 10 months, a profit of Rs. 462 is divided among them, what is Deepi’s share? A) 123.56 B) 165.45 C) 143.3 D) 146.43
Last Answer : Answer: C) Ratio of initial investments = 1/3 : 1/4 : 1/5 = 20 :15 :12 Let their initial investments be 20x, 15x and 12x respectively Dhivya: Dinesh :Deepi = (20x *2 +10x *10) : (15x *12) : (12x*12) =140x : ... 70:90:72 = 35 : 45 :36 Deepi s share = Rs.462 * 36/116 = Rs(16632/116) =Rs.143.3
Description : In each of the following questions select the related letters/word/number from the given alternatives. 1. CFIL: ORUX::GDJM: ? (a) HJLN (b) NQST (c) PSVY (d) RTVX 2. BEHK: YVSP::DGJM : ? (a) JGDA (b) ... Chisel (d) Statue 9. MKQO: LNPR:: ?XVTZ (a) YSUW (b) SVWY (c) VTWY (d) WYTS
Last Answer : 1. (c) 2. (c) 3. (c) 4. (c) 5. (d) 6. (b) 7. (d) 8. (d) 9. (a)
Description : Find the magnetization of the field which has a magnetic moment 16 units in a volume of 1.2 units. a) 16.67 b) 13.33 c) 15.56 d) 18.87
Last Answer : b) 13.33
Description : The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300
Last Answer : Answer: A A/B = 15/16 and B/C = 17*18 So A : B : C = 15*17 : 16*17 : 16*18 = 255 : 272 : 288 So C’s salary = [288/(255+272+288)] * 1,87,450= Rs 66,240
Description : Redgram worth Rs. 112 per kg and Rs.123 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 142 per kg, the price of the third variety per kg will be a) 153 b) 175.50 c) 43.9 d) 227.9 e) 166.5
Last Answer : E Since first second varieties are mixed in equal proportions so their average price = Rs.(112 + 123/2) = Rs. 117.5 So, the mixture is formed by mixing two varieties, one at Rs. 117.50 per kg and the ... ratio 2 : 2, i.e., 1 : 1. We have to find x. By the rule of allgation
Description : What causes the differences in the percentage of the work force in different countries?
Last Answer : I blame demography.
Description : What is it that can be more than 100%?
Last Answer : I have heard of alcohol being more than 100%. Red necks trust in Trump?
Description : Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?
Last Answer : Just divide it.
Description : How to Reduce Your Body Fat Percentage ?
Last Answer : How to Reduce Your Body Fat Percentage Losing weight doesn't only mean bringing down the numbers on your bathroom scale. Most of the time, people lose more muscles than fat because of misguided weight loss ... body you want. Lose weight safely. Don't fall into the pit of fast weight loss programs.
Description : In a birthday party, every person shakes hand with every other person. If there was a total of 66 handshakes in the party, how many persons were present in the party? A) 9 B) 8 C) 7 D) 12
Last Answer : Answer: D) Assume that in a party every person shakes hand with every other person Number of hand shake = 66 Total number of hand shake is given by nC2 Let n = the total number of persons ... cannot take negative value of n So, n = 12 Therefore number of persons in the party = 12
Description : An shopkeeper has 15 models of cup and 9 models of saucer. In how many ways can he make a pair of cup and saucer? A) 100 B) 80 C) 110 D) 135
Last Answer : Answer: D) He has 15 patterns of cup and 9 model of saucer A cup can be selected in 15 ways. A saucer can be selected in 9 ways. Hence one cup and one saucer can be selected in 15×9 ways =135 ways
Description : A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450
Last Answer : Answer: A) Number of ways to choose 10 questions from part A = 12C10 Number of ways to choose 8 questions from part B = 12C8 Total number of ways= 12C10 × 12C8 = 12C2 × 12C4 [∵ nCr = nC(n-r)] ={12×11}/{2×1}X{12×11×10×9} / {4×3×2×1} =66×495 =32670
Description : Pramoth has 12 friends and he wants to invite 7 of them to a party. How many times will 4 particular friends never attend the party? A) 8 B) 7 C) 12 D) 15
Last Answer : Answer: A) Remove the 4 particular friends and invite 7 friends from the remaining 8 (12-4) friends . this can be done in 8C7 ways. Therefore , required number of ways = = 8C7 = 8C1 = 8
Description : The population of a town is 16200. It decreases annually at the rate of 40% p.a. What was its population 3 years ago? a) 75000 b) 65000 c) 84900 d) 93600
Last Answer : Answer: A (Ago = 100 numerator) Ago 3 years = 16200×(100/60×100/60×100/60) = 75000
Description : The population of a town is 15000. It increases annually at the rate of 20% p.a. What will be its population after 3 years? a) 65439 b) 25920 c) 37193 d) 41093
Last Answer : Answer: B Formula : ( After =100 denominator ) (Ago = 100 numerator) After 3 years = 15000×(1+20/100)^3 = 15000 ×(120/100)^3 = 15000 ×(1.2)^3 = 15000 ×(1.728) = 25920