Description : The difference between 45% of a number and 37% of the same number is 896. What is 25% of that number ? a) 1200 b) 2800 c) 2569 d) 3467
Last Answer : Answer: B (45 – 37)% of the number = 896 8 % of the number = 896 Number =896 x100 /8 = 89600/8 = 11200 25% of 11200 = 11200 x 25/100 = 280000 / 100 = 2800
Description : An shopkeeper has 15 models of cup and 9 models of saucer. In how many ways can he make a pair of cup and saucer? A) 100 B) 80 C) 110 D) 135
Last Answer : Answer: D) He has 15 patterns of cup and 9 model of saucer A cup can be selected in 15 ways. A saucer can be selected in 9 ways. Hence one cup and one saucer can be selected in 15×9 ways =135 ways
Description : In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98
Last Answer : Answer: A Let the total number of eggs in the basket be x 20 % of the eggs are rotten, and eggs in good condition are 68 Therefore, according to the question, 80% of x = 68 80/100 × x = 68 x = (68 × 100)/80 x = 6800 / 80 x = 85 Therefore, total number of eggs in the basket is 85.
Description : Nandhini scored 996 marks out of 1200 marks and her elder brother kaviyarasan scored 1020 marks out of 1500 marks. Find the scored percentage which is better? a) 68% b) 83% c) 65% d) 85% e) 97%
Last Answer : Answer: A Percentage of marks scored by nandhini = (994/1200 × 100) = (99400/1200) = (994/12) = 83 % Percentage of marks scored by kaviyarasan = (1020/1500 × 100) = (102000/1500) = (1020/15) = 68 % Hence, the percentage marks scored by nandhini is better.
Description : The Shopkeeper increased the price of a product by 75% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 140% of the required amount. What is the net difference in the ... on that product? a) 12.5 b) 26.0 c) 13.5 d) 17.5 e) 19.8
Last Answer : Answer: D Quantity×Rate=Price 1x1=1 1.4x1.75=2.45 Decrease in price = (0.175/1) × 100 = 17.5%
Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989
Last Answer : Answer: C If Gowthaman had scored 26 marks more, he could have scored 25% Therefore, Mike required 424 + 26 = 450 marks Let the maximum marks be x. Then 25 % of x = 450 (25/100) × x = 450 x = (450 × 100)/25 x = 45000/25 x = 1800
Description : In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800
Last Answer : Answer: D Total number of votes = 15000 Given that 40% of Percentage votes were invalid => Valid votes = 60% Total valid votes = 15000* 60/100 1st candidate got 45% of the total valid votes. Hence ... votes that 2nd candidate got = total valid votes x 55/100 =15000*60/100*55/100 =4950
Description : Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800
Last Answer : Answer: A Percentage savings of Supriya = 100 – (35 + 45) = 20% Let her monthly income be x x X 20 /100 = 25750 x = 25750 × 100/20 x = 128750
Description : Brother's weight is 25 % more than that of sister. What percent is brother’s weight less than sister's weight? a) 25% b) 60% c) 45% d) 20% e) 98%
Last Answer : Answer: D Let sister's weight be 100 kg. Then brother's weight = (100 + 25) kg = 125 kg If brother's weight is 125 kg, then sister's weight is 100 kg. If brother's weight is 1 kg, then ... then sister's weight = (100/125 100) kg Therefore, sister's weight is 20 % less than that of brother.
Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41
Last Answer : Answer: A (i) Percentage scored in Mathematics = 120/180 100 = 12000/180 =1200/18 = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100) = (40000/510) = 4000/51 = 78 22/51 %
Description : A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98
Last Answer : Answer: D 60 kg = 36 kg dhal 24 kg rice -------- 15 kg dhal Total = 15 kg dhal 24 kg rice (new) 24/75×100=32%
Description : A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980
Last Answer : Answer: C Original value is percentage = 100 %. Reduce amount in percentage = 10 % Therefore, Percent value in percentage = 100 % - 10 % = 90 %. According to the problem, 90 % of original value ... Therefore, 100 % of original value = 1080/100 90 = 1200. Thus, the original value was 1200.
Description : Sanjay gets 72 % marks in examinations. If these are 864 marks, find the maximum marks. a) 1050 b) 860 c) 1225 d) 1200 e) 1500
Last Answer : Answer: D Let the maximum marks be s Then 72 % of s = 864 72/100 × s = 864 s = (846 × 100)/72 s = 86400/92 s = 1200 Therefore, maximum marks in the examinations are 1200.
Description : A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9
Last Answer : Answer: E Price of the wooden a year before = $25200 Price of the wooden after a year = $11200 Decrease in price = $(25200 - 11200) = $14000 Therefore, decrease % = 14000/25200 × 100 % = 55 5/9 %
Description : If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241
Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298
Last Answer : Answer: B The number of students with first division = 56 % of 900 = 56/100 × 900 = 50400/100 = 504 And, the number of students with second division = 27 % of 900 = 27/100 × 900 =24300/100 = 243 Therefore, the number of students who just passed = 900 – (504 + 243) = 900- 747 = 153
Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1
Last Answer : Answer: E Total cost of the items he purchased = Rs.75 Given that out of this Rs.75, 90 Paise is given as tax => Total tax incurred = 90 Paise = Rs.90/100 Let the cost of the tax free items = x Given that tax rate = ... −0.9 −x) = 90 ⇒ (75 − 0.9 − x) = 5 x = 75 − 0.9 - 5 X=69.1
Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298
Last Answer : Answer: D Let the maximum marks be x. Aashika’s marks = 32% of x Aashika secured 1328 marks Therefore, 32% of x = 1328 ⇒ 32/100 × x = 1328 x = (1328 × 100)/32 x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.
Description : A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320? a)50% b)66 2/3% c)62 1/2% d)56 1/4%
Last Answer : d)56 1/4%
Description : The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8
Last Answer : Answer: D Population in a small town last year = 50000 Population in a small town after one year = 63750 Increase in population = 63750 - 50000 = 13750 Therefore, percentage increase in population = ... /50000 100 = 1375000/50000 = 27.5% Thus, the increase in population is 27.5%
Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price = $37.5 - $ 30 = $ 7.5 Therefore, percentage increase in price = Increase in price/ ... = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %
Description : A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2
Last Answer : Answer: D 90 kg = 81 kg sugar 9 kg rava Adding = 30 kg sugar Total = 111kg sugar 9kg rava (new) 111/120 × 100 = 92.5 =92 1 /2
Description : What causes the differences in the percentage of the work force in different countries?
Last Answer : I blame demography.
Description : Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?
Last Answer : Just divide it.
Description : How to Reduce Your Body Fat Percentage ?
Last Answer : How to Reduce Your Body Fat Percentage Losing weight doesn't only mean bringing down the numbers on your bathroom scale. Most of the time, people lose more muscles than fat because of misguided weight loss ... body you want. Lose weight safely. Don't fall into the pit of fast weight loss programs.
Description : In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93
Last Answer : Answer: D Total number of votes polled = (2272+15272+23256) =40800 Required percentage = 23256/40800 ×100 = 2325600/40800 = 57
Description : In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989
Last Answer : Answer: B Total marks in the test = (560 + 160) × 100 /25 = 720 ×100/25 = 72000/25 = 2880 Passing marks for girls =2880 × 60/100 = 1728 Required marks = 1728 – 216 = 1512
Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7
Description : The total power of an AM transmitter having a carrier power of 50 W and the percentage of modulation at 80% is A) 50 W B) 66 W C) 68 W D) 70 W
Last Answer : The total power of an AM transmitter having a carrier power of 50 W and the percentage of modulation at 80% is 66 W
Description : Two transformers A and B having equal outputs and voltage ratios but unequal percentage impedances of 4 and 2 are operating in parallel. The transformer A will be overloaded by
Last Answer : Two transformers A and B having equal outputs and voltage ratios but unequal percentage impedances of 4 and 2 are operating in parallel. The transformer A will be overloaded by 33%
Description : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be ______. (A) 20% (B) 40% (C) 50% (D) 30%
Last Answer : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be 20%.
Description : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Last Answer : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Description : What is the percentage of stray losses in DC machine?
Last Answer : Percentage of stray losses in DC machine is about 1 % .
Description : A vendor bought 30 dozen bananas at Rs.16 per dozen. He sold 10 dozens at Rs.20 per dozen and 16 dozens at Rs.25 per dozen. The remaining 4 dozens were rotten and he threw away. Find his profit percentage. a)20% b)25% c)30% d)33 1/3%
Last Answer : b)25%
Description : In a birthday party, every person shakes hand with every other person. If there was a total of 66 handshakes in the party, how many persons were present in the party? A) 9 B) 8 C) 7 D) 12
Last Answer : Answer: D) Assume that in a party every person shakes hand with every other person Number of hand shake = 66 Total number of hand shake is given by nC2 Let n = the total number of persons ... cannot take negative value of n So, n = 12 Therefore number of persons in the party = 12
Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5
Last Answer : Answer: D Let the number be m. Decrease = 24 % of m = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594 19m = 594 × 25 19m = 14850 m = 14850/19 m =781.5
Description : After selling a fan at 6% gain and a fridge at 9% gain, a shopkeeper gains Rs 5100. But if he sells the fan at 9% gain and the fridge at 6% loss, he gains Rs 1800 on the whole transaction. Find the original price of the fan.
Last Answer : let the price of fan be X and fridge be Y 6x/100+9y/100 = 5100 6x+9y=510000------(1) then 9x/100-6y/100=1800 9x-6y=180000-------(2) Calculate both, the we will get x=Rs40000
Description : A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450
Last Answer : Answer: A) Number of ways to choose 10 questions from part A = 12C10 Number of ways to choose 8 questions from part B = 12C8 Total number of ways= 12C10 × 12C8 = 12C2 × 12C4 [∵ nCr = nC(n-r)] ={12×11}/{2×1}X{12×11×10×9} / {4×3×2×1} =66×495 =32670
Description : Pramoth has 12 friends and he wants to invite 7 of them to a party. How many times will 4 particular friends never attend the party? A) 8 B) 7 C) 12 D) 15
Last Answer : Answer: A) Remove the 4 particular friends and invite 7 friends from the remaining 8 (12-4) friends . this can be done in 8C7 ways. Therefore , required number of ways = = 8C7 = 8C1 = 8
Description : mouli had $ 3600 left after spending 40 % of the money he took for shopping. How much money did he take along with him? a) 2500 b) 6000 c) 4500 d) 3000 e) 9800
Last Answer : Answer: B Let the money he took for shopping be x. Money he spent = 40 % of x = 40/100 x = 4/10 x Money left with him = x - 4/10 x = (10x - 4x)/10 = 6x/10 But money left with ... 6x/10 = 3600 x = 3600 10/6 x = 36000/6 x = 6000 Therefore, the money he took for shopping is 6000.
Description : There are 312, 260 and 156 students in class X, XI and XII respectively. Buses are to be hired to take these students to a picnic. Find the maximum number of students who can sit in a bus if each bus takes equal number of students (a) 52 (b) 56 (c) 48 (d) 63
Last Answer : (a) 52
Description : Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60
Last Answer : Answer: C Observer 36/62, 39/63, 43/61, 48/64, ? series Upper part is increase by 3, 4, 5, 6 i.e 36+3= 39, 39+4 = 43, 43+5 = 48, 48 + 6 = 54.
Description : In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814
Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320 = 75/100 *5320 = 399000/100 = 3990
Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800
Last Answer : Answer: D Total number of invalid votes = 55 % of 280000 = 55/100 280000 = 15400000/100 = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000 = 40/100 126000 = 5040000/100 = 50400
Description : The value of a machine depreciates at the rate of 20% every year. It was purchased 6 years ago. If its present value is Rs. 17,496, its purchase price was : a) 25023.4 b) 67040.0 c) 34171.8 d) 27337.5
Last Answer : Answer: C Purchase price = 17,496 / (1 -20/ 100)³ = 17,496 × 10/8 × 10/8 ×10/8 = 17496 × 1.25 × 1.25 ×1.25 = 17496 ×1.953 = 34171.8
Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4
Last Answer : Answer: D Let the marks secured by them be x and (x + 18) Then sum of their marks = x + (x + 18) = 2x + 18 Given that (x + 18) was 72% of the sum of their marks =>(x+18) = 72/100(2x+18) => ... 11x = 126 x = 11.45 Then (x + 18) = 11.45 + 18 = 29.45 Hence their marks are 11.45 and 29.45
Description : Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18
Last Answer : Answer: A Let a family's monthly consumption of chenna dhal be x kg. To keep the expenditure fixed, their consumption for this month should be 70x/80 = 7x/8. Reduction in consumption = x/8 = 12.5% of x
Description : An alloy contains 36 % of bronze. What quantity of alloy is required to get 340 g of bronze? a) 1500 b) 944.4 c) 950 d) 1000 e) 980.5
Last Answer : Answer: B Let the quantity of alloy required = x g Then 36 % of x =340 g ⇒ 36/100 × x = 340 g x = (340 × 100)/36 g x = 34000/36 g x = 944.4 g
Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5
Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130 = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X