What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?

1 Answer

Answer :

Endpoints: (-4, -10) and (8, -1)Midpoint: (2, -5.5)Slope: 3/4Perpendicular slope: -4/3Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x-8.5Perpendicular bisector equation in its general form: 4x+3y+8.5 =0

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