Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?
Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0
Description : What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?
Last Answer : Endpoints: (-4, -10) and (8, -1)Midpoint: (2, -5.5)Slope: 3/4Perpendicular slope: -4/3Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x-8.5Perpendicular bisector equation in its general form: 4x+3y+8.5 =0
Description : What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?
Last Answer : A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = ... - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2
Description : is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?
Last Answer : 1
Description : What is the perpendicular bisector equation of the line y equals 5x plus 10 spanning the parabola y equals x squared plus 4?
Last Answer : If: y = 5x +10 and y = x^2 +4Then: x^2 +4 = 5x +10Transposing terms: x^2 -5x -6 = 0Factorizing the above: (x-6)(X+1) = 0 meaning x = 6 or x =-1Therefore by substitution endpoints of the line are ... .5 = -1/5(x-2.25) => 5y= -x+114.75Perpendicular bisector equation in its general form: x+5y-114.75= 0
Description : The loop transfer of a system is G(s) H(s) = 5/(s+1) (2s+1)(3s+1) which has the phase crossover frequency fc = 0.16 Hz. The gain margin (dB) of the system is (a) 6 (b) 4 (c) 2 (d) 0
Last Answer : The loop transfer of a system is G(s) H(s) = 5/(s+1) (2s+1)(3s+1) which has the phase crossover frequency fc = 0.16 Hz. The gain margin (dB) of the system is 6
Description : Combine plus signs and five 2's to get 28. Combine plus signs and eight 8's to get 1,000. -Riddles
Last Answer : 22+2+2+2=28; 888+88+8+8+8=1,000
Description : Which of the following corresponds to the configuration `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)` ?
Last Answer : Which of the following corresponds to the configuration `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)` ? A. He B. Na C. Mg D. Ar
Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th
Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.
Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th
Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.
Description : Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th
Last Answer : Steps of Construction (i) Draw a line segment AB = 5.8 cm. (ii) Taking A as centre and radius more than 1/2AB, draw two arcs, one on either side of AB. (iii) Taking B as centre and ... . (iv) Join CD, intersecting AB at point P. Then, line CPD is the required perpendicular bisector of AB.
Description : is this statement true or false If you fold the paper so that A matches up with B and then creases the paper, the line formed by the crease is the perpendicular bisector of AB.?
Description : What is the difference between a perpendicular line and a perpendicular bisector?
Last Answer : A perpendicular line is one that is at right angle to another -usually to a horizontal line. A perpendicular bisector is a linewhich is perpendicular to the line segment joining two identifiedpoints and which divides that segment in two.
Description : The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)
Last Answer : (d) (0,0)
Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th
Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB
Description : Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th
Last Answer : According to question prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side,
Description : ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th
Last Answer : Solution :-
Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, then prove that arc PXA ≅ arc PYB. -Maths 9th
Last Answer : Solution :- Let AB be a chord of a circle having centre at O. Let PQ be the perpendicular bisector of the chord AB intersect it say at M. Perpendicular bisector of the chord passes through the centre of the circle,i. ... = PM (Common) ∴ △APM ≅ △BPM (SAS) PA = PB (CPCT) Hence, arc PXA ≅ arc PYB
Description : If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th
Last Answer : Given: Two circles, with centres O and O' intersect at two points A and B. A AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect ... 0° Thus, AP = BP and ∠APO = ∠BPO = 9 0° Hence, OO' is the perpendicular bisector of AB.
Description : what- BD is the perpendicular bisector of?
Last Answer : The head administrator expressed that she will take the antibody once immunization targets are met Statecraft in the countryExecutive Sheik Hasina on Saturday said she has not yet taken the Covid-19 antibody however ... at the Shapla Hall of the Prime Minister's Office (PMO).Likewise Read - PM: D
Description : what- point R is on the perpendicular bisector of QS?
Last Answer : 5
Description : what- Fill in the blank with a word that makes the statement true.The perpendicular bisector of a segment from a point to its image is called the ____ of reflection?
Last Answer : line
Description : Which of these is the definition of a perpendicular bisector?
Last Answer : a line or segment that is perpendicular to the given segment and divides it into two congruent segments
Description : How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?
Last Answer : What is the answer ?
Description : If a point on the perpendicular bisector of a segment, then it is?
Last Answer : Equidistant from the endpoints of the segment.
Description : In a purely cohesive soil, the critical centre lies at the intersection of (A) Perpendicular bisector of slope and the locus of the centre (B) Perpendicular drawn at 1/3rd slope from toe and the ... C) Perpendicular drawn at 2/3rd slope from toe and the locus of the centre (D) Directional angles
Last Answer : Answer: Option D
Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th
Last Answer : NEED ANSWER
Last Answer : This answer was deleted by our moderators...
Description : Find parametric equation for Y-coordinates of Hermite cubic spline curve having endpoints P0[4,4]; P1[8,5] a.2u3-3u2+2u+4 b.3u3-2u2-2u-4 c.2u3-3u2-2u-4 d.2u3+3u2+2u+4
Last Answer : a.2u3-3u2+2u+4
Description : Find parametric equation for X-coordinates of hermite cubic spline curve having endpoints P0[4,4]; P1[8,5] a.-5u3+8u2+u+1 b.5u3+8u2+u+1 c.8u3-5u2-u+1 d.8u3+5u2+u+1
Last Answer : a.-5u3+8u2+u+1
Description : What’s s the midpoint of the line segment with endpoints (-5.5, -6.1) and (-0.5, 9.1)?
Last Answer : M = (-5.5+-0.5, -6.1+9.1) = -6.0, 3.0
Description : If the characteristics equation of a closed loop system is s2+2s+2=0, then the system is (A) Over damped (B) Critically damped (C) Under damped (D) Undamped
Last Answer : C. Solving the above character equation gives complex roots -1+i and -1-i. If we plot that roots on real and imaginary axis plane(s-plane), it will be completely on left side of s-plane. So, the oscillations of the above conjugate roots are underdamped and are absolutely stable.
Description : Why is the following a poor definition for a diameter. A diameter is a line segment with both endpoints on a circle.?
Last Answer : Some segments with both endpoints on a circle are not diameters.
Description : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.
Last Answer : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.
Description : Is there such a font for price tags, where every thing is in '8's and can be shaded off to appear as another number?
Last Answer : That font type is usually referred to as LED or Digital.
Description : How many 8's go into 49?
Last Answer : 6 times with a remainder of 1 or 6.125 times
Description : Using only addition, how do you add eight 8s and get the number 1,000?
Last Answer : A: 888 + 88 + 8 + 8 + 8 = 1000.
Description : The transfer function of a process is 1/(16s 2 + 8s + 4). If a step change isintroduced into the system, then the response will be (A) Under damped (B) Critically damped (C) Over damped (D) None of these
Last Answer : (A) Under damped
Description : Which of the following rRNAs acts as structural RNA as well as ribozyme in bacteria? (a) 5S rRNA (b) 18S rRNA (c) 23S rRNA (d) 5.8S rRNA
Last Answer : (a) 5S rRNA
Last Answer : (c) 23S rRNA
Description : Why do you extract lower 8’s by directing the extraction lingually:** A. Because of the roots direction B. Thinner bone C. Lingual deviation
Last Answer : B. Thinner bone
Description : How many 8’s are there in the following sequence which are preceded by 5 but not immediately followed by 3? 5 8 3 7 5 8 6 3 8 5 4 5 8 4 7 6 5 5 8 3 5 8 7 5 8 2 8 5 (A) 4 (B) 5 (C) 7 (D) 3
Last Answer : Answer: A
Description : Find the equation of the straight line passing through the point (4, 5) and perpendicular to 3x – 2y + 5 = 0. -Maths 9th
Last Answer : There are two ways to prove it. 1st way: Area of triangle formed by the given points = 0 if they are collinear.∴ \(rac{1}{2}\) [\(x\)(2 - (y + 1) ) + 1((y + 1) - 1) + 0(1 - 2)] = 0⇒ \(rac{1}{2}\) [2\(x\) - \(x\)y - \( ... y - \(x\)y - 1 + \(x\) ⇒ x + y = \(x\)y ⇒ \(rac{1}{x}\) + \(rac{1}{y}\) = 1.
Description : What is an equation of the line that is perpendicular to y plus 1-3(x-5) and passes through the point (4-6)?
Last Answer : Need answer
Description : What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?
Last Answer : If you mean point (-1, 4) and equation of 4x-3y = -9 then y =4/3x+3Slope of equation: 4/3Perpendicular slope: -3/4Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
Description : If line KL is a bisector of FH at point J which statements is true?
Last Answer : With the limited information provided by the question, the onlystatement which must be true is FJ = JH.
Description : A point Q on a segment with endpoints A (2,-1) and C (4,2) partitions the segment in a 4:1 ratio. Find Q. You must show all work to receive credit?
Last Answer : yor mom is fat
Description : AB has endpoint A(-8,6) and B(6,0). Find the endpoints of its image after the similarity transformation. Translation: (x,y) -> (x,y - 6) Dilation: (x,y) -> (1/2 x, 1/2 y)?
Last Answer : A(-4,0) B(3,-3)