what- point R is on the perpendicular bisector of QS?

what- point R is on the perpendicular bisector of QS?
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5
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Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

what- Fill in the blank with a word that makes the statement true.The perpendicular bisector of a segment from a point to its image is called the ____ of reflection?

Description : what- Fill in the blank with a word that makes the statement true.The perpendicular bisector of a segment from a point to its image is called the ____ of reflection?

Last Answer : line

If a point on the perpendicular bisector of a segment, then it is?

Description : If a point on the perpendicular bisector of a segment, then it is?

Last Answer : Equidistant from the endpoints of the segment.

The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)

Description : The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)

Last Answer : (d) (0,0)

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB

Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Description : Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Last Answer : According to question prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side,

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB

Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Description : Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Last Answer : According to question prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side,

ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th

Description : ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th

Last Answer : Solution :-

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, then prove that arc PXA ≅ arc PYB. -Maths 9th

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, then prove that arc PXA ≅ arc PYB. -Maths 9th

Last Answer : Solution :- Let AB be a chord of a circle having centre at O. Let PQ be the perpendicular bisector of the chord AB intersect it say at M. Perpendicular bisector of the chord passes through the centre of the circle,i. ... = PM (Common) ∴ △APM ≅ △BPM (SAS) PA = PB (CPCT) Hence, arc PXA ≅ arc PYB

If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th

Description : If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th

Last Answer : Given: Two circles, with centres O and O' intersect at two points A and B. A AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect ... 0° Thus, AP = BP and ∠APO = ∠BPO = 9 0° Hence, OO' is the perpendicular bisector of AB.

The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.

Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th

Description : Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th

Last Answer : Steps of Construction (i) Draw a line segment AB = 5.8 cm. (ii) Taking A as centre and radius more than 1/2AB, draw two arcs, one on either side of AB. (iii) Taking B as centre and ... . (iv) Join CD, intersecting AB at point P. Then, line CPD is the required perpendicular bisector of AB.

what- BD is the perpendicular bisector of?

Description : what- BD is the perpendicular bisector of?

Last Answer : The head administrator expressed that she will take the antibody once immunization targets are met Statecraft in the countryExecutive Sheik Hasina on Saturday said she has not yet taken the Covid-19 antibody however ... at the Shapla Hall of the Prime Minister's Office (PMO).Likewise Read - PM: D

is this statement true or false If you fold the paper so that A matches up with B and then creases the paper, the line formed by the crease is the perpendicular bisector of AB.?

Description : is this statement true or false If you fold the paper so that A matches up with B and then creases the paper, the line formed by the crease is the perpendicular bisector of AB.?

Last Answer : 1

is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

Description : is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

Last Answer : 1

Which of these is the definition of a perpendicular bisector?

Description : Which of these is the definition of a perpendicular bisector?

Last Answer : a line or segment that is perpendicular to the given segment and divides it into two congruent segments

What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?

Description : What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?

Last Answer : Endpoints: (-4, -10) and (8, -1)Midpoint: (2, -5.5)Slope: 3/4Perpendicular slope: -4/3Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x-8.5Perpendicular bisector equation in its general form: 4x+3y+8.5 =0

What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?

Description : What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?

Last Answer : A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = ... - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2

What is the difference between a perpendicular line and a perpendicular bisector?

Description : What is the difference between a perpendicular line and a perpendicular bisector?

Last Answer : A perpendicular line is one that is at right angle to another -usually to a horizontal line. A perpendicular bisector is a linewhich is perpendicular to the line segment joining two identifiedpoints and which divides that segment in two.

What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0

What is the perpendicular bisector equation of the line y equals 5x plus 10 spanning the parabola y equals x squared plus 4?

Description : What is the perpendicular bisector equation of the line y equals 5x plus 10 spanning the parabola y equals x squared plus 4?

Last Answer : If: y = 5x +10 and y = x^2 +4Then: x^2 +4 = 5x +10Transposing terms: x^2 -5x -6 = 0Factorizing the above: (x-6)(X+1) = 0 meaning x = 6 or x =-1Therefore by substitution endpoints of the line are ... .5 = -1/5(x-2.25) => 5y= -x+114.75Perpendicular bisector equation in its general form: x+5y-114.75= 0

How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?

Description : How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?

Last Answer : What is the answer ?

What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0

In a purely cohesive soil, the critical centre lies at the intersection of (A) Perpendicular bisector of slope and the locus of the centre (B) Perpendicular drawn at 1/3rd slope from toe and the locus of the centre (C) Perpendicular drawn at 2/3rd slope from toe and the locus of the centre (D) Directional angles

Description : In a purely cohesive soil, the critical centre lies at the intersection of (A) Perpendicular bisector of slope and the locus of the centre (B) Perpendicular drawn at 1/3rd slope from toe and the ... C) Perpendicular drawn at 2/3rd slope from toe and the locus of the centre (D) Directional angles

Last Answer : Answer: Option D

An amount of money is to be distributed among P, Q and R in the ratio of 5:4:7 respectively. If the total share of P and R is 3 times the share of Q, what is definitely Q’s share? a) 2000 b) 4000 c) 6000 d) Data inadequate e) None of these

Description : An amount of money is to be distributed among P, Q and R in the ratio of 5:4:7 respectively. If the total share of P and R is 3 times the share of Q, what is definitely Q’s share? a) 2000 b) 4000 c) 6000 d) Data inadequate e) None of these

Last Answer : Answer: D 

P started a business in 1990 by investing Rs.25,000. She invested Rs. 10,000 as additional amount in 1991 and her friend Q joined her with an amount of Rs.35,000. P invested another Rs. 10,000 in 1992 and R joined them with Rs. 35,000. At the end of these 3 years, they earned a profit of Rs. 150,000. Find Q's share? a) Rs.50,000 b) Rs.65,000 c) Rs.75,000 d) Rs.15,000

Description : P started a business in 1990 by investing Rs.25,000. She invested Rs. 10,000 as additional amount in 1991 and her friend Q joined her with an amount of Rs.35,000. P invested another Rs. 10,000 in 1992 and R joined them ... ,000. Find Q's share? a) Rs.50,000 b) Rs.65,000 c) Rs.75,000 d) Rs.15,000

Last Answer : Answer: A) P invested Rs.25,000 for 12 months, Rs.(25000 + 10000) for 12 months, , Rs.(25000 + 10000 + 10000) for 12 months. i.e., P invested Rs.25,000 for 12 months, Rs.35000 for 12 months Rs.45000 for 12 months. Q ... Q's share = Rs.(1,50,000 x 2 /(3+2+1)) = Rs.(1,50,000 x 2/6) = Rs.50,000

Three friends started a Company, let there names are P, Qand R. What profit Q will get, if, 1. R invested Rs. 4000 for nine months, his profit was 3/2 times that of Q's and his investment was four times that of P. 2. P and Q invested for one year in the proportion 1 : 2 respectively. 3. The three together got Rs. 500 as profit at the year end. A) Only 1 and 3 B) Only 1 and 2 C) All 1, 2 and 3 D) None of above

Description : Three friends started a Company, let there names are P, Qand R. What profit Q will get, if, 1. R invested Rs. 4000 for nine months, his profit was 3/2 times that of Q's and his investment was four times that of P. 2. ... year end. A) Only 1 and 3 B) Only 1 and 2 C) All 1, 2 and 3 D) None of above

Last Answer : Answer: C) 1 and 2 will give : R = Rs. (4000 x 9) for 1 year = Rs. 36000 for 1 year. P = Rs. (1/4 * 4000 * 12 ) for 1 year = Rs 12000 for 1 year Q = Rs 24000 for one year R:P:Q = ... Profit = 500 Now from the ratio and total profit we can get Share of R. R share will be = 500 * 2/6 = 166.66

Divide Rs 1728 among P, Q, R in such way that 8 times P's share is 12times Q's share and is 6 times R's share. How much does each get? A) Rs. 576,384,768 B) Rs. 588,392,484 C) Rs. 592, 384, 652 D) None of the above

Description : Divide Rs 1728 among P, Q, R in such way that 8 times P's share is 12times Q's share and is 6 times R's share. How much does each get? A) Rs. 576,384,768 B) Rs. 588,392,484 C) Rs. 592, 384, 652 D) None of the above

Last Answer : Answer: A)  Given, 8P=12Q=6R  4P=6Q=3R=>4P=6Q=>6/4Q=>P=3/2Q  6Q=3R R=6Q/3=2Q  Then, P+Q+R=1728  3/2Q+Q+2Q=1728  3Q+2Q+4Q=3456  9Q=3456  Q=384  P=3/2Q =3/2*384=576,R=2Q=768  A:B:C=576:384:768

P, Q & R are three partners start a business. Thrice P’s capital is equal to four times Q’s capital and Q’s capital is 6 times R’s capital. Out of a total profit Rs.35860 at the end of the year, Q’s share is A) Rs.12334 B) Rs.14344 C) Rs. 21500 D) Rs.17600

Description : P, Q & R are three partners start a business. Thrice P’s capital is equal to four times Q’s capital and Q’s capital is 6 times R’s capital. Out of a total profit Rs.35860 at the end of the year, Q’s share is A) Rs.12334 B) Rs.14344 C) Rs. 21500 D) Rs.17600

Last Answer : Answer: B) Let R = c Q = 6c P = 24c/3 = 8c P : Q : R= 8c:6c:c = 8: 6: 1 So Q’s capital = Rs. 35860 * 6/15 = Rs.14344

PQRS is a parallelogram whose area is 180 cm2 and A is any point on the diagonal QS. The area of △ASR = 90 cm2. Find this statement is true or false. -Maths 9th

Description : PQRS is a parallelogram whose area is 180 cm2 and A is any point on the diagonal QS. The area of △ASR = 90 cm2. Find this statement is true or false. -Maths 9th

Last Answer : Solution :- As diagonal of the parallelogram divides it into two triangles of equal area. Since, area (△SRQ ) = 1/2 area(PQRS) area (△SRQ ) = 1/2 x 180 ... = 90 cm2 (Given) This is not possible unless area (△SRQ ) = area (△ASR ) So, the given statement is false.

Prove that the length of the tangents drawn from an external point to a circle are equal, hence show that the centre lies on the bisector of the angle between the two tangents? -SST 10th

Description : Prove that the length of the tangents drawn from an external point to a circle are equal, hence show that the centre lies on the bisector of the angle between the two tangents? -SST 10th

Last Answer : Given: PT and TQ are two tangent drawn from an external point T to the circle C (O, r). To prove: 1. PT = TQ 2. ∠OTP = ∠OTQ Construction: Join OT. Proof: We know that, a tangent to ... point to a circle are equal. ∠OTP = ∠OTQ, ∴ Centre lies on the bisector of the angle between the two tangents.

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : This answer was deleted by our moderators...

A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a point P on the right bisector of bending ang

Description : A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a point P on the right bisector of bending ang

Last Answer : A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a ... (3pid))` D. `(sqrt(3mu_(0)I))/(2pid)`

If line KL is a bisector of FH at point J which statements is true?

Description : If line KL is a bisector of FH at point J which statements is true?

Last Answer : With the limited information provided by the question, the onlystatement which must be true is FJ = JH.

What is the concurrent point of the angle bisector?

Description : What is the concurrent point of the angle bisector?

Last Answer : It is the vertex of the angle.

The center of gravity of a triangle lies at the point of (A) Concurrence of the medians (B) Intersection of its altitudes (C) Intersection of bisector of angles (D) Intersection of diagonals

Description : The center of gravity of a triangle lies at the point of (A) Concurrence of the medians (B) Intersection of its altitudes (C) Intersection of bisector of angles (D) Intersection of diagonals

Last Answer : (A) Concurrence of the medians

The perpendicular offset from the tan-get to the central point of the circular curve, is (A) (B) (C) R (1 - (D) R (1 -

Description : The perpendicular offset from the tan-get to the central point of the circular curve, is (A) (B) (C) R (1 - (D) R (1 -

Last Answer : Answer: Option C

For an infinite sheet of positive charge, the electric field lines: w) run parallel to the sheet of charge x) are perpendicular to the sheet of charge and point in toward the sheet y) are perpendicular to the sheet of charge and point away from the sheet z) fall off as one over r squared

Description : For an infinite sheet of positive charge, the electric field lines: w) run parallel to the sheet of charge x) are perpendicular to the sheet of charge and point in toward the sheet y) are perpendicular to the sheet of charge and point away from the sheet z) fall off as one over r squared

Last Answer : ANSWER: Y -- ARE PERPENDICULAR TO THE SHEET OF CHARGE AND POINT AWAY  

Have you ever advised your friends not spend their time on Qs they have no answer for? See detail.

Description : Have you ever advised your friends not spend their time on Qs they have no answer for? See detail.

Last Answer : No, never. It isn’t my place to tell people what to do. They are intelligent, sentient people and are perfectly capable of making their own judgments on what to ask. It would be rude and presumptuous of me to instruct someone on what they should or shouldn’t do on a website.

Alright, 2 Qs: a list of all books by BrianWeiss ; What are some other similar riliable authors of this same topic?

Description : Alright, 2 Qs: a list of all books by BrianWeiss ; What are some other similar riliable authors of this same topic?

Last Answer : Sounds like homework! Use Google and do your own legwork.

What theme of QS is this?

Description : What theme of QS is this?

Last Answer : It does appear to be Bezel with some tweaks to it. I don't know how to adjust the appearance of QS, but I'm sure that more experienced users of the program do. I don't really mind ... cause simplicity really is the name of the game. The less appearance, the better- Quicksilver is just so seamless!

Anything like QS for PC?

Description : Anything like QS for PC?

Last Answer : These look pretty promising. I’ve used Launchy, and like it, but it doesn’t have as many features as QS.

What should I know before buying a Wii and Xbox 360? Additional Qs inside.

Description : What should I know before buying a Wii and Xbox 360? Additional Qs inside.

Last Answer : I LOVE my Wii. I just got Wii Carnival Games and it is fun, fun, fun!!! I tend to like triva games. Smarty Pants is good, and I like the Big Brain Academy. The Price is Right is fun too. Especially, if you ever wanted to go on the show.

Essay due tomorrow! Is it ok? Q's..Please help. Tense, wording etc...

Description : Essay due tomorrow! Is it ok? Q's..Please help. Tense, wording etc...

Last Answer : I think I can fix the punctuation; I haven’t gone over it yet. If u seen any major issues please point them out?

"suzy-Qs" or "ho-hos"?

Description : "suzy-Qs" or "ho-hos"?

Last Answer : Ho-ho’s w/out a doubt. In college, I can remember buying a box….and the cashier noticing it was open at check-out. She was mortified and starting to call for someone to exchange it for me/....until (chagrined) I told her I had a bit of a snack, while shopping. Ooops.

Two q's regarding the Alyogyne huegelii: why do the leaves turn yellow and why doesn't it flowera/

Description : Two q's regarding the Alyogyne huegelii: why do the leaves turn yellow and why doesn't it flowera/

Last Answer : Need Answer

In the figure shown here, QS = SR, QU = SU, PW = WS and ST || RV. What is the value of -Maths 9th

Description : In the figure shown here, QS = SR, QU = SU, PW = WS and ST || RV. What is the value of -Maths 9th

Last Answer : answer:

If PQRS is trapezium such that PQ > RS and L, M are the mid-points of the diagonals PR and QS respectively then what is LM equal to? -Maths 9th

Description : If PQRS is trapezium such that PQ > RS and L, M are the mid-points of the diagonals PR and QS respectively then what is LM equal to? -Maths 9th

Last Answer : if pqrs is a trapezium so pq and RS are parallel is you draw a diagonal you will divide the trapezium into two parts such that two equal triangle so