is this statement true or false If you fold the paper so that A matches up with B and then creases the paper, the line formed by the crease is the perpendicular bisector of AB.?

is this statement true or false  If you fold the paper so that A matches up with B and then creases the paper, the line formed by the crease is the perpendicular bisector of AB.?
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is this statement true or false if you fold the paper so P is on the fold and the 2 sides of L mach up, the line formed by crease is parallel to L?

Description : is this statement true or false if you fold the paper so P is on the fold and the 2 sides of L mach up, the line formed by crease is parallel to L?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.

Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th

Description : Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th

Last Answer : Steps of Construction (i) Draw a line segment AB = 5.8 cm. (ii) Taking A as centre and radius more than 1/2AB, draw two arcs, one on either side of AB. (iii) Taking B as centre and ... . (iv) Join CD, intersecting AB at point P. Then, line CPD is the required perpendicular bisector of AB.

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, then prove that arc PXA ≅ arc PYB. -Maths 9th

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, then prove that arc PXA ≅ arc PYB. -Maths 9th

Last Answer : Solution :- Let AB be a chord of a circle having centre at O. Let PQ be the perpendicular bisector of the chord AB intersect it say at M. Perpendicular bisector of the chord passes through the centre of the circle,i. ... = PM (Common) ∴ △APM ≅ △BPM (SAS) PA = PB (CPCT) Hence, arc PXA ≅ arc PYB

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB

If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB

ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th

Description : ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th

Last Answer : Solution :-

what- Fill in the blank with a word that makes the statement true.The perpendicular bisector of a segment from a point to its image is called the ____ of reflection?

Description : what- Fill in the blank with a word that makes the statement true.The perpendicular bisector of a segment from a point to its image is called the ____ of reflection?

Last Answer : line

is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

Description : is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

Last Answer : 1

What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?

Description : What is the perpendicular bisector equation of the line segment whose endpoints are at -4 -10 and 8 -1 on the Cartesian plane?

Last Answer : Endpoints: (-4, -10) and (8, -1)Midpoint: (2, -5.5)Slope: 3/4Perpendicular slope: -4/3Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x-8.5Perpendicular bisector equation in its general form: 4x+3y+8.5 =0

What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?

Description : What is the perpendicular bisector equation of a line segment with endpoints of p q and 7p 3q?

Last Answer : A line with slope m has a perpendicular with slope m' such that:mm' = -1→ m' = -1/mThe line segment with endpoints (p, q) and (7p, 3q) has slope:slope = change in y / change in x→ m = (3q - q)/(7p - p) = ... - 4p)→ y = -3px/q + 12p² + 2q→ qy = 12p²q + 2q² - 3pxAnother Answer: qy =-3px +12p^2 +2q^2

What is the difference between a perpendicular line and a perpendicular bisector?

Description : What is the difference between a perpendicular line and a perpendicular bisector?

Last Answer : A perpendicular line is one that is at right angle to another -usually to a horizontal line. A perpendicular bisector is a linewhich is perpendicular to the line segment joining two identifiedpoints and which divides that segment in two.

What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0

What is the perpendicular bisector equation of the line y equals 5x plus 10 spanning the parabola y equals x squared plus 4?

Description : What is the perpendicular bisector equation of the line y equals 5x plus 10 spanning the parabola y equals x squared plus 4?

Last Answer : If: y = 5x +10 and y = x^2 +4Then: x^2 +4 = 5x +10Transposing terms: x^2 -5x -6 = 0Factorizing the above: (x-6)(X+1) = 0 meaning x = 6 or x =-1Therefore by substitution endpoints of the line are ... .5 = -1/5(x-2.25) => 5y= -x+114.75Perpendicular bisector equation in its general form: x+5y-114.75= 0

What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0

The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)

Description : The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)

Last Answer : (d) (0,0)

If a point on the perpendicular bisector of a segment, then it is?

Description : If a point on the perpendicular bisector of a segment, then it is?

Last Answer : Equidistant from the endpoints of the segment.

A square sheet of paper ABCD is so folded that B falls on the mid-point M of CD. The crease will divide BC in the ratio -Maths 9th

Description : A square sheet of paper ABCD is so folded that B falls on the mid-point M of CD. The crease will divide BC in the ratio -Maths 9th

Last Answer : answer:

Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Description : Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Last Answer : According to question prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side,

Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Description : Prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side, if intersect they will intersect on the circumcircle of the triangle. -Maths 9th

Last Answer : According to question prove that angle bisector of any angle of a triangle and perpendicular bisector of the opposite side,

If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th

Description : If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th

Last Answer : Given: Two circles, with centres O and O' intersect at two points A and B. A AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect ... 0° Thus, AP = BP and ∠APO = ∠BPO = 9 0° Hence, OO' is the perpendicular bisector of AB.

what- BD is the perpendicular bisector of?

Description : what- BD is the perpendicular bisector of?

Last Answer : The head administrator expressed that she will take the antibody once immunization targets are met Statecraft in the countryExecutive Sheik Hasina on Saturday said she has not yet taken the Covid-19 antibody however ... at the Shapla Hall of the Prime Minister's Office (PMO).Likewise Read - PM: D

what- point R is on the perpendicular bisector of QS?

Description : what- point R is on the perpendicular bisector of QS?

Last Answer : 5

Which of these is the definition of a perpendicular bisector?

Description : Which of these is the definition of a perpendicular bisector?

Last Answer : a line or segment that is perpendicular to the given segment and divides it into two congruent segments

How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?

Description : How would the construction be different if you changed the compass setting in the next step of the perpendicular bisector construction?

Last Answer : What is the answer ?

In a purely cohesive soil, the critical centre lies at the intersection of (A) Perpendicular bisector of slope and the locus of the centre (B) Perpendicular drawn at 1/3rd slope from toe and the locus of the centre (C) Perpendicular drawn at 2/3rd slope from toe and the locus of the centre (D) Directional angles

Description : In a purely cohesive soil, the critical centre lies at the intersection of (A) Perpendicular bisector of slope and the locus of the centre (B) Perpendicular drawn at 1/3rd slope from toe and the ... C) Perpendicular drawn at 2/3rd slope from toe and the locus of the centre (D) Directional angles

Last Answer : Answer: Option D

EF is the transversal to two parallel lines AB and CD. GM and HL are the bisector of the corresponding angles EGB and EHD.Prove that GL parallel to HL. -Maths 9th

Description : EF is the transversal to two parallel lines AB and CD. GM and HL are the bisector of the corresponding angles EGB and EHD.Prove that GL parallel to HL. -Maths 9th

Last Answer : AB || CD and a transversal EF intersects them ∴ ∠EGB = ∠GHD ( Corresponding Angles) ⇒ 2 ∠EGM = 2 ∠GHL ∵ GM and HL are the bisectors of ∠EGB and ∠EHD respectively. ⇒ ∠EGM = ∠GHL But these angles form a pair of equal corresponding angles for lines GM and HL and transversal EF. ∴ GM || HL.

EF is the transversal to two parallel lines AB and CD. GM and HL are the bisector of the corresponding angles EGB and EHD.Prove that GL parallel to HL. -Maths 9th

Description : EF is the transversal to two parallel lines AB and CD. GM and HL are the bisector of the corresponding angles EGB and EHD.Prove that GL parallel to HL. -Maths 9th

Last Answer : AB || CD and a transversal EF intersects them ∴ ∠EGB = ∠GHD ( Corresponding Angles) ⇒ 2 ∠EGM = 2 ∠GHL ∵ GM and HL are the bisectors of ∠EGB and ∠EHD respectively. ⇒ ∠EGM = ∠GHL But these angles form a pair of equal corresponding angles for lines GM and HL and transversal EF. ∴ GM || HL.

True or False The intersection of the segment and its bisector is the segment's midpoint.?

Description : True or False The intersection of the segment and its bisector is the segment's midpoint.?

Last Answer : TRUE

True or False The intersection of the segment and its bisector is the segment's midpoint.?

Description : True or False The intersection of the segment and its bisector is the segment's midpoint.?

Last Answer : TRUE

Tunneling _____________ to the fold axis is not at all desirable. (A) Perpendicular (B) Parallel (C) None of these

Description : Tunneling _____________ to the fold axis is not at all desirable. (A) Perpendicular (B) Parallel (C) None of these

Last Answer : (A) Perpendicular 

I have a small layer of fat above an abdominal scar. Can this be liposuctioned with ultrasound, then injected into facial creases?

Description : I have a small layer of fat above an abdominal scar. Can this be liposuctioned with ultrasound, then injected into facial creases?

Last Answer : There are soundproofing foams, panels,and composite for walls. These materials can be installed on the outside and inside of walls.You can soundproof an area yourself or get professional help. You can ... Directory and they should be able to give you more options as far as businesses are concerned.

Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Description : Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Last Answer : The lines are perpendicular to a common line AB. Hence, the angle between these lines will be 90+90=180∘ Since, the angle between them is 180∘, the lines are parallel to each other.

Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Description : Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Last Answer : To draw a line perpendicular to AB through A and B, respectively. Use the following steps of construction. 1.Draw a line segment AB = 4 cm. 2.Taking 4 as centre and radius more than ½ AB (i.e ... [since, it sum of interior angle on same side of transversal is 180°, then the two lines are parallel]

In Fig. 7.19, AD and BC are equal perpendicular to a line segment AB. Show that CD bisects AB. -Maths 9th

Description : In Fig. 7.19, AD and BC are equal perpendicular to a line segment AB. Show that CD bisects AB. -Maths 9th

Last Answer : Solution :-

To set out a parallel from a given inaccessible point to a given line AB, the following observations are made: Distance AB and angle PAM = a and angle PBA = b are measured where M is a point on the line BA produced. The perpendicular to the desired parallel line from A and B are: (A) AB/(cot b - cot a) (B) AB/(cos b - cos a) (C) AB/(cot a - cot b) (D) AB/(cot a - cos b)

Description : To set out a parallel from a given inaccessible point to a given line AB, the following observations are made: Distance AB and angle PAM = a and angle PBA = b are measured where M is a point on the line BA produced. The ... cos b - cos a) (C) AB/(cot a - cot b) (D) AB/(cot a - cos b)

Last Answer : (A) AB/(cot b - cot a)

is this statement true or falseIf two lines are perpendicular to the same line, then they are parallel to each other.?

Description : is this statement true or falseIf two lines are perpendicular to the same line, then they are parallel to each other.?

Last Answer : 1

If line KL is a bisector of FH at point J which statements is true?

Description : If line KL is a bisector of FH at point J which statements is true?

Last Answer : With the limited information provided by the question, the onlystatement which must be true is FJ = JH.

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Description : In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Last Answer : (a) We know that, the perpendicular from the centre of a circle to a chord bisects the chord. AC = CB = 1/2 AB = 1/2 x 8 = 4 cm given OA = 5 cm AO2 = AC2 + OC2 (5)2 = (4)2 + OC2 25 = 16 + OC2 ... length is always positive] OA = OD [same radius of a circle] OD = 5 cm CD = OD - OC = 5 - 3 = 2 cm

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Last Answer : According to question prove that P, Q, R and D are concyclic.

In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Description : In figure, if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB, then CD is equal to -Maths 9th

Last Answer : (a) We know that, the perpendicular from the centre of a circle to a chord bisects the chord. AC = CB = 1/2 AB = 1/2 x 8 = 4 cm given OA = 5 cm AO2 = AC2 + OC2 (5)2 = (4)2 + OC2 25 = 16 + OC2 ... length is always positive] OA = OD [same radius of a circle] OD = 5 cm CD = OD - OC = 5 - 3 = 2 cm

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Last Answer : According to question prove that P, Q, R and D are concyclic.

In a parallelogram ABCD, AE is perpendicular to DC and CF is perpendicular to AD. If AB = 10 cm, AE = 6 cm and CF = 8 cm, then find AD. -Maths 9th

Description : In a parallelogram ABCD, AE is perpendicular to DC and CF is perpendicular to AD. If AB = 10 cm, AE = 6 cm and CF = 8 cm, then find AD. -Maths 9th

Last Answer : Given, Parallelogram ABCD pAE = 8cm AB = 16cm CF = 10cm In a parallelogram, we know that opposite sides are equal. Therefore, CD = AB = 16cm To find the value of AD, the base is multiplied with height. Area of parallelogram = b x h 16 x 8 = AD x 10 128 = 10AD AD = 12.8cm

If crease-recovery angle of a finished fabric is 300 and above then it is called?

Description : If crease-recovery angle of a finished fabric is 300 and above then it is called?

Last Answer : Durable crease

What is the easiest way to get wrinkles and deep creases out of new curtains?

Description : What is the easiest way to get wrinkles and deep creases out of new curtains?

Last Answer : Spray them with water should work and then just let them hang. You could steam them if you have a steamer, that would even work better, just be careful not to hold the steam handle too close because of the ... my first suggestion first if it was me. It's the simplest, and if it works you're done.

Can you help me figure out how to fix my hat creases?

Description : Can you help me figure out how to fix my hat creases?

Last Answer : I would immerse it in water to soften, they usually have that stiff stuff behind the logo and then shape it while it is wet and let it dry on something round, maybe a small kettle to make sure the ... to hurt them, I have one that has probably been washed 50 times or so and is still going strong.

Any ideas how to get the creases out of a new curtain (without ironing it)?

Description : Any ideas how to get the creases out of a new curtain (without ironing it)?

Last Answer : My first thought was to hang them and then steam them.