In which cross would you obtain a 9:3:3:1 ratio for F2 Progeny. What is the test cross ratio of the same cross.

In which cross would you obtain a 9:3:3:1 ratio for F2 Progeny. What is the test cross ratio of the same cross. 
by

1 Answer

Answer :

Ans: Dihybrid cross. Test cross ratio is 1:1:1:1
by

Related questions

A blue colour flower plant denoted by BB is cross bred with that of white colour flower plant denoted by bb. (a) State the colour of flower you would expect in their F1 generation plants. (b) What must be the percentage of white flower plants in F2 generation if flowers of F1 plants are self-pollinated? (c) State the expected ratio of the genotypes BB and Bb in the F2 progeny. -Biology

Description : A blue colour flower plant denoted by BB is cross bred with that of white colour flower plant denoted by bb. (a) State the colour of flower you would expect in their F1 generation plants. (b) What ... -pollinated? (c) State the expected ratio of the genotypes BB and Bb in the F2 progeny. -Biology

Last Answer : This is your Answer.

f we cross pure-bred tall (dominant) pea plant with pure-bred dwarf (recessive) pea plant we will get pea plants of F1 generation. If we now self-cross the pea plant of F2 generation, then we obtain pea plants of F2 generation. (a) What do the plants of F2 generation look like? (b) State the ratio of tall plants to dwarf plants in F2 generation. (c) State the type of plants not found in F2 generation but appeared in F2 generation, mentioning the reason for the same. -Biology

Description : f we cross pure-bred tall (dominant) pea plant with pure-bred dwarf (recessive) pea plant we will get pea plants of F1 generation. If we now self-cross the pea plant of F2 generation, ... plants not found in F2 generation but appeared in F2 generation, mentioning the reason for the same. -Biology

Last Answer : Answer. (a) All plants of F1 generation will be tall plants. (b) 3:1 (c) Dwarf trait is recessive trait which was not expressed in the F1 generation, the recessive trait gets expressed in the F2 generation after self pollination.

A common test to find the genotype of a hybrid is by (a) crossing of one F2 progeny with female parent (b) studying the sexual behaviour of F1 progenies (c) crossing of one F1 progeny with male parent (d) crossing of one F2 progeny with male parent

Description : A common test to find the genotype of a hybrid is by (a) crossing of one F2 progeny with female parent (b) studying the sexual behaviour of F1 progenies (c) crossing of one F1 progeny with male parent (d) crossing of one F2 progeny with male parent

Last Answer : (c) crossing of one F1 progeny with male parent

What phenotypic and genotypic ratios are expected in F2 generation when monohybrid and dihybrid crosses are made?

Description : What phenotypic and genotypic ratios are expected in F2 generation when monohybrid and dihybrid crosses are made?

Last Answer : Ans: Monohybrid cross : Phenotypic ratio is 3:1 and Genotypic ratio 1:2:1. Dihybrid cross : Phenotypic ratio 9:3:3:1. Genotypic ratio is 1:2:2:4:1:2:1:2:1 

In a genetic cross having recessive epistasis, F2 phenotypic ratio would be (a) 9 : 6 : 1 (b) 15 : 1 (c) 9 : 3 : 4 (d) 12 : 3 : 1.

Description : In a genetic cross having recessive epistasis, F2 phenotypic ratio would be (a) 9 : 6 : 1 (b) 15 : 1 (c) 9 : 3 : 4 (d) 12 : 3 : 1.

Last Answer : (c) 9 : 3 : 4

In a cross between AABB × aabb, the ratio of F2 genotypes between AABB, AaBB, Aabb and aabb would be (a) 9 : 3 : 3 : 1 (b) 2 : 1 : 1 : 2 (c) 1 : 2 : 2 : 1 (d) 7 : 5 : 3 : 1.

Description : In a cross between AABB × aabb, the ratio of F2 genotypes between AABB, AaBB, Aabb and aabb would be (a) 9 : 3 : 3 : 1 (b) 2 : 1 : 1 : 2 (c) 1 : 2 : 2 : 1 (d) 7 : 5 : 3 : 1.

Last Answer : (c) 1 : 2 : 2 : 1

Cross between hybrid and recessive parent is: (a) Back cross (b) Test cross (c) Monohybrid cross (d) Dihybrid cross Ans. (b) ................................................-----------------------------------------.................................................. PMT COACHING CLASSES (Zoology+Botany) – PMT, AIIMS, MBBS,lucknow 1. Largest egg of plant kingdom belongs to: (a) Cycas (b) Pinus (c) Psidium (d) Mangfera

Description : Cross between hybrid and recessive parent is: (a) Back cross (b) Test cross (c) Monohybrid cross (d) Dihybrid cross Ans. (b) ................................................----- ... - PMT, AIIMS, MBBS,lucknow 1. Largest egg of plant kingdom belongs to: (a) Cycas (b) Pinus (c) Psidium (d) Mangfera

Last Answer : Ans. ((a))

What is test cross?

Description : What is test cross?

Last Answer : Ans: Cross between a hybrid or unknown genotype with a recessive parent is called as test cross. It helps in determining the individual as heterozygous or homozygous.

What was the ratio of Mendel's F2 generation for the two-factor cross?

Description : What was the ratio of Mendel's F2 generation for the two-factor cross?

Last Answer : 9:3:3:1 was the ratio of Mendel's f2 generation for the twofactor cross.

A test cross is carried out to (a) determine the genotype of a plant at F2 (b) predict whether two traits are linked (c) assess the number of alleles of a gene (d) determine whether two species or varieties will breed successfully.

Description : A test cross is carried out to (a) determine the genotype of a plant at F2 (b) predict whether two traits are linked (c) assess the number of alleles of a gene (d) determine whether two species or varieties will breed successfully.

Last Answer : (a) determine the genotype of a plant at F2

To obtain haploid plants, we culture _________ e. Entire anther f. Nucleus g. Embryo h. Apical bud

Description : To obtain haploid plants, we culture _________ e. Entire anther f. Nucleus g. Embryo h. Apical bud

Last Answer : e. Entire anther

F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1 : 2 : 1. It represents a case of (a) co-dominance (b) dihybrid cross (c) monohybrid cross with complete dominance (d) monohybrid cross with incomplete dominance.

Description : F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1 : 2 : 1. It represents a case of (a) co-dominance (b) dihybrid cross (c) monohybrid cross with complete dominance (d) monohybrid cross with incomplete dominance.

Last Answer : (d) monohybrid cross with incomplete dominance.

F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1 : 2 : 1. It represents a case of (1) Monohybrid cross with incomplete dominance (2) Co-dominance (3) Dihybrid cross (4) Monohybrid cross with complete dominance

Description : F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1 : 2 : 1. It represents a case of (1) Monohybrid cross with incomplete dominance (2) Co-dominance (3) Dihybrid cross (4) Monohybrid cross with complete dominance

Last Answer : (1) Monohybrid cross with incomplete dominance

On selfing a plant of F1-generation with genotype “AABbCC”, the genotypic ratio in F2-generation will be (a) 3 : 1 (b) 1 : 1 (c) 9 : 3 : 3 : 1 (d) 27 : 9 : 9 : 9 : 3 : 3 : 3 : 1.

Description : On selfing a plant of F1-generation with genotype “AABbCC”, the genotypic ratio in F2-generation will be (a) 3 : 1 (b) 1 : 1 (c) 9 : 3 : 3 : 1 (d) 27 : 9 : 9 : 9 : 3 : 3 : 3 : 1.

Last Answer : (a) 3 : 1

Progeny of a single cross fertilized heterozygous individual

Description : Progeny of a single cross fertilized heterozygous individual

Last Answer : Ans. Inbred

A and B genes are linked. What shall be genotype of progeny in a cross between AB/ab and ab/ab? (a) AAbb and aabb (b) AaBb and aabb (c) AABB and aabb (d) None of these

Description : A and B genes are linked. What shall be genotype of progeny in a cross between AB/ab and ab/ab? (a) AAbb and aabb (b) AaBb and aabb (c) AABB and aabb (d) None of these

Last Answer : (b) AaBb and aabb

Repeated crossing of hybrid progeny back to one of its parents is called as — a. Back cross b. Top cross c. Recurrent cross d. Double cross

Description : Repeated crossing of hybrid progeny back to one of its parents is called as — a. Back cross b. Top cross c. Recurrent cross d. Double cross

Last Answer : a. Back cross

Bisexual flowers are present in both Clerodendron and Scrophularia. Still cross pollination takes place. How?

Description : Bisexual flowers are present in both Clerodendron and Scrophularia. Still cross pollination takes place. How?

Last Answer : Ans: In clerodendron the androecium attains maturity earlier than gynoecium and in Scrophulria the gynoecium attains maturity earlier than androecium.  

What cross is useful in determining the genetic purity of gametes? Show with an example.

Description : What cross is useful in determining the genetic purity of gametes? Show with an example.  

Last Answer : Ans: Test cross. If it is done between an individual with Tt genotype and the recessive parent with tt genotype, 50% of the individuals obtained will be tall and the remaining are dwarf. 

Tissue culture is a good technique to a) Cross two varieties b) Rapidly increase the size of a trees by strengthening the stem c) Eliminate virus d) Improve yield of crops

Description : Tissue culture is a good technique to a) Cross two varieties b) Rapidly increase the size of a trees by strengthening the stem c) Eliminate virus d) Improve yield of crops 

Last Answer : c) Eliminate virus 

F2 generation of a monohybrid cross. -Biology

Description : F2 generation of a monohybrid cross. -Biology

Last Answer : answer:

F2 generation of a dihybrid cross. -Biology

Description : F2 generation of a dihybrid cross. -Biology

Last Answer : answer:

One of the parents of a cross has a mutation in its mitochondria. In that cross, that parent is taken as a male. During segregation of F2 progenies that mutation is found in (a) one-third of the progenies (b) none of the progenies (c) all the progenies (d) fifty percent of the progenies.

Description : One of the parents of a cross has a mutation in its mitochondria. In that cross, that parent is taken as a male. During segregation of F2 progenies that mutation is found in (a) one-third of the progenies (b) none of the progenies (c) all the progenies (d) fifty percent of the progenies.

Last Answer : (b) none of the progenies

In Mendel’s experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYY × rryy? (a) Round seeds with yellow cotyledons, and wrinkled seeds with yellow cotyledons (b) Only round seeds with green cotyledons (c) Only wrinkled seeds with yellow cotyledons (d) Only wrinkled seeds with green cotyledons

Description : In Mendel's experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the ... green cotyledons (c) Only wrinkled seeds with yellow cotyledons (d) Only wrinkled seeds with green cotyledons

Last Answer : (d) Only wrinkled seeds with green cotyledons

In the F2 generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are:

Description : 4) In the F2 generation of a Mendelian dihybrid cross the number of phenotypes and genotypes are: (a) Phenotypes-4,genotypes-16 (b) ) Phenotypes-9,genotypes-4 (c) ) Phenotypes-4,genotypes-8 (d) ) Phenotypes-4,genotypes-9

Last Answer : 4.d Phenotypes-4,genotypes-9

5 Consider a cross in which a trait is inherited by incomplete dominance. What percentage of the F2 from the matng of homozygous dominant and homozygous recessive individuals will possess the dominant phenotype?

Description : 5 Consider a cross in which a trait is inherited by incomplete dominance. What percentage of the F2 from the matng of homozygous dominant and homozygous recessive individuals will possess the dominant phenotype? a) 0 per cent b) 25 per cent c) 50 per cent d) 75 per cent

Last Answer : ANS: b 25 per cent

Select the correct Match : (1) Ribozyme - Nucleic acid (2) F2 x Recessive parent - Dihybrid cross (3) TH. Morgan - Transduction (4) G. Mendel - Transformation

Description : Select the correct Match : (1) Ribozyme - Nucleic acid (2) F2 x Recessive parent - Dihybrid cross (3) TH. Morgan - Transduction (4) G. Mendel - Transformation

Last Answer : (1) Ribozyme - Nucleic acid

When white -flowered plant were crossed with pure red - flowered plants, the progeny were - (a) White flowered (b) Red flowered (c) Exhibiting 3:1 ratio of red to whiteflowered plants (d) Exhibiting 1:1 ratio of red to whiteflowered plants

Description : When white -flowered plant were crossed with pure red - flowered plants, the progeny were - (a) White flowered (b) Red flowered (c) Exhibiting 3:1 ratio of red to whiteflowered plants (d) Exhibiting 1:1 ratio of red to whiteflowered plants

Last Answer : Ans:(b)

In hybridisation, Tt × tt gives rise to the progeny of ratio (a) 2 : 1 (b) 1 : 2 : 1 (c) 1 : 1 (d) 1 : 2.

Description : In hybridisation, Tt × tt gives rise to the progeny of ratio (a) 2 : 1 (b) 1 : 2 : 1 (c) 1 : 1 (d) 1 : 2.

Last Answer : (c) 1 : 1

Which of the following statement is correct? (1) The causal organism for foolish seedling disease is the source of gibberellin (2) Abscisic acid is a growth promoter (3) The ratio of auxin : cytokinin control cell differentiation (4) Bolting of cabbage can be induced by treatment with IAA

Description : Which of the following statement is correct? (1) The causal organism for foolish seedling disease is the source of gibberellin (2) Abscisic acid is a growth promoter (3) The ratio of auxin : cytokinin control cell differentiation (4) Bolting of cabbage can be induced by treatment with IAA

Last Answer : Ans. ((d))

Development of shoot and root is determined by: (a) Cytokinin and auxin ratio (b) Enzymes (c) Temperature (d) Plant nutrients

Description : Development of shoot and root is determined by: (a) Cytokinin and auxin ratio (b) Enzymes (c) Temperature (d) Plant nutrients

Last Answer : Ans. ((a))

If a dwarf pea plant was treated with gibberellic acid, it became as tall, as tall pea plants. If these pea plants are crossed with pure tall pea plants, what will be the phenotypic ratio in F1 generation? (a) All dwarf plants (b) 50% tall and 50% dwarf plants (c) 75% tall and 25% dwarf plants (d) 100% tall plants

Description : If a dwarf pea plant was treated with gibberellic acid, it became as tall, as tall pea plants. If these pea plants are crossed with pure tall pea plants, what will be the phenotypic ratio in F1 generation? ... (b) 50% tall and 50% dwarf plants (c) 75% tall and 25% dwarf plants (d) 100% tall plants

Last Answer : Ans. ((d))

The ovule in which embryo sac become horse shoe shaped in: (a) Amphitropous (b) Camphylotropous (c) Orthotropous (d) Anatropous Ans. (a) ......................................................---------------------------......................................................................... BOTANY PRACTICE TEST SAMPLE QUESTIONS 1. Caruncle develops-from: (a) Outer integument (b) Ctyledon (c) Funiculus (d) Inner integuments

Description : The ovule in which embryo sac become horse shoe shaped in: (a) Amphitropous (b) Camphylotropous (c) Orthotropous (d) Anatropous Ans. (a) .................................. ... TEST SAMPLE QUESTIONS 1. Caruncle develops-from: (a) Outer integument (b) Ctyledon (c) Funiculus (d) Inner integuments

Last Answer : Ans. ((a))

In Antirrhinum (Snapdragon), a red flower was crossed with a white flower and in F1 generation all pink flowers were obtained. When pink flowers were selfed, the F2 generation showed white, red and pink flowers. Choose the incorrect statements from the following. (a) Law of segregation does not apply in this experiment. (b) This experiment does not follow the Principle of Dominance. (c) Pink colour in F1 is due to incomplete dominance. (d) Ratio of F2 is 1 4 2 4 1 4 ( ) red p : ( ink w ) : ( ) hite .

Description : In Antirrhinum (Snapdragon), a red flower was crossed with a white flower and in F1 generation all pink flowers were obtained. When pink flowers were selfed, the F2 generation showed white, red and pink flowers. Choose the incorrect ... F2 is 1 4 2 4 1 4 ( ) red p : ( ink w ) : ( ) hite .

Last Answer : (a) Law of segregation does not apply in this experiment.

An individual cannot pass on to its progeny the experiences of its lifetime.” Justify the statement with the help of an example and also give reason for the same. -Biology

Description : An individual cannot pass on to its progeny the experiences of its lifetime.” Justify the statement with the help of an example and also give reason for the same. -Biology

Last Answer : Experience achieved during the lifetime of an individual does not make any change in the gene of the individual. For example, if a person reads a book on birds, the knowledge he earns ... knowledge will not get automatically transmitted to his next generation. Such a trait is called acquired trait.

The pollination between two different flowers present on same plant is called as

Description : The pollination between two different flowers present on same plant is called as

Last Answer : The pollination between two different flowers present on same plant is called as – Geitonogamy

For successful grafting, stock and scion shall be a) Of different species b) Of same species c) Of similar groups d) Of different classA

Description : For successful grafting, stock and scion shall be a) Of different species b) Of same species c) Of similar groups d) Of different classA

Last Answer : b) Of same species

Two vessels A and B contain sugar and rava in the ratio 4 : 3 and 2 : 3 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing sugar and rava in the ratio 1 : 2? a) 2:9 b) 3:2 c) 7:9 d) 2:7 e) 7:4

Description : Two vessels A and B contain sugar and rava in the ratio 4 : 3 and 2 : 3 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing sugar and rava in the ratio 1 : 2? a) 2:9 b) 3:2 c) 7:9 d) 2:7 e) 7:4

Last Answer : E Let Cost Price(CP) of 1 kg sugar be Rs.1 Quantity of sugar in 1kg mixture from vessel A=4/7 Cost Price(CP) of 1kg mixture from vessel A = Rs. =4/7 Quantity of sugar in 1 kg mixture from vessel ... from vessel C=1/2 Cost Price(CP) of 1 kg mixture from vessel C(Mean Price) = Rs.=1/2

Consider two pipes of same length and diameter through which water is passed at the same velocity. The friction factor for rough pipe is f1 and that for smooth pipe is f2 . Pick out the correct statement(A) f1 = f2 (B) f1 < f2 (C) f1 > f2 (D) Data not sufficient to relate f1 & f2

Description : Consider two pipes of same length and diameter through which water is passed at the same velocity. The friction factor for rough pipe is f1 and that for smooth pipe is f2 . Pick out the correct statement. (A) f1 = f2 (B) f1 < f2 (C) f1 > f2 (D) Data not sufficient to relate f1 & f2

Last Answer : (C) f1 > f2

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Description : Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Last Answer : Answer – B (11 : 9) Explanation – In the same time, they cover 110 km and 90 km respectively.Ratio of their speeds = 110 : 90 = 11 : 9 

Give two reasons for the appearance of variations among the progeny formed by sexual reproduction. -Biology

Description : Give two reasons for the appearance of variations among the progeny formed by sexual reproduction. -Biology

Last Answer : Now, the two major reasons for appearance of variation among the progeny formed from sexual reproduction are; crossing over in which the DNA gets exchanged between the homologous chromosomes during the meiosis that causes variation in the offspring.

A Mendelian experiment consisted of breeding pea plants bearing violet flowers with pea plants bearing white flowers. What will be the result in F1 progeny ? -Science

Description : A Mendelian experiment consisted of breeding pea plants bearing violet flowers with pea plants bearing white flowers. What will be the result in F1 progeny ? -Science

Last Answer : Violet flowers

Through which are the characters are transferred from parents to progeny? -Do You Know?

Description : Through which are the characters are transferred from parents to progeny? -Do You Know?

Last Answer : answer:

Progeny of foundation or registered seed

Description : Progeny of foundation or registered seed

Last Answer : Ans. Certified seed

Progeny of breeder seed

Description : Progeny of breeder seed

Last Answer : Ans. Foundation seed

Progeny selection is also known as

Description : Progeny selection is also known as

Last Answer : Ans. Ear to row method of selection

A progeny of single homozygous, self pollinated crops

Description : A progeny of single homozygous, self pollinated crops

Last Answer : Ans. Pure line

Repeated crossing of hybrid progeny back to one of its parents

Description : Repeated crossing of hybrid progeny back to one of its parents

Last Answer : Ans. Back Cross

Progeny of a single plant, obtained by asexual reproduction

Description : Progeny of a single plant, obtained by asexual reproduction

Last Answer : Ans. Clone

All the progeny obtained from a single plant by vegetative pro pa-gallon are called - (1) Clones (2) Pure line (3) Indred line (4) Pedigree line

Description : All the progeny obtained from a single plant by vegetative pro pa-gallon are called - (1) Clones (2) Pure line (3) Indred line (4) Pedigree line

Last Answer : (1) Clones Explanation: A clone is obtained by vegetative propagation of a single plant and it propagates vegetatively in successive generation. It offers excitation for exploiting desirable ... their original characteristics after many years of vegetative propagation i.e. they are stable.