Find the area of a triangle formed by A = 3i - 4j + 2k and B = i + j - 2k as adjacent sides measure in metre.

Find the area of a triangle formed by A = 3i - 4j + 2k and B = i + j - 2k as adjacent sides measure in metre.
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Find the area of a triangle formed by A = 3i - 4j + 2k and B = i + j - 2k as adjacent sides measure in metre.
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The cross product of the vectors 3i + 4j – 5k and –i + j – 2k is, a) 3i – 11j + 7k b) -3i + 11j + 7k c) -3i – 11j – 7k d) -3i + 11j – 7k

Description : The cross product of the vectors 3i + 4j – 5k and –i + j – 2k is, a) 3i – 11j + 7k b) -3i + 11j + 7k c) -3i – 11j – 7k d) -3i + 11j – 7k

Last Answer : Answer: b Explanation: Cross product of two vectors is, A X B = (a2*b3 – b2*a3)i – (a1*b3 – b1*a3)j + (a1*b2 – b1*a2)k. Using the formula, the answer can be calculated.

Find unit vector parallel to the resultant of the vectors A = i + 4j - 2k and B = 3i - 5j + k.

Description : Find unit vector parallel to the resultant of the vectors A = i + 4j - 2k and B = 3i - 5j + k.

Last Answer : Find unit vector parallel to the resultant of the vectors \(\overset\rightarrow{A}\) = i + 4j - 2k and \(\overset\rightarrow{B}\) = 3i - 5j + k.

If vectors v1 = 3i + 4j + k and v2 = i - j - k, determine the magnitude of v1 + v2.

Description : If vectors v1 = 3i + 4j + k and v2 = i - j - k, determine the magnitude of v1 + v2.

Last Answer : If vectors v1 = 3i + 4j + k and v2 = i - j - k, determine the magnitude of v1 + v2.

If A = i + 2j + 3k and B = 3i - 2j + k, then the area of parallelogram formed from these vectors as the adjacent sides will be

Description : If A = i + 2j + 3k and B = 3i - 2j + k, then the area of parallelogram formed from these vectors as the adjacent sides will be

Last Answer : If A = i + 2j + 3k and B = 3i - 2j + k, then the area of parallelogram formed from these ... units (C) 6√3 square units (D) 8√3 square units

Find the scalar product of the two vectors v1 = i + 2j + 3k and v2 = 3i + 4j - 5k.

Description : Find the scalar product of the two vectors v1 = i + 2j + 3k and v2 = 3i + 4j - 5k.

Last Answer : Find the scalar product of the two vectors v1 = i + 2j + 3k and v2 = 3i + 4j - 5k.

Find a unit vector in the direction of the vector 3i + 4j.

Description : Find a unit vector in the direction of the vector 3i + 4j.

Last Answer : Find a unit vector in the direction of the vector 3i + 4j.

For Q 45, Tangent vector for line L2 a.i+4j-k b.2i+4j+k c.i-4j-2k d.i+4j+2k

Description : For Q 45, Tangent vector for line L2 a.i+4j-k b.2i+4j+k c.i-4j-2k d.i+4j+2k

Last Answer : d.i+4j+2k

Show that vectors a = 2i + 3j + 6k, b = 3i - 6j + 2k and c = 6i + 2j - 3k are mutually perpendicular.

Description : Show that vectors a = 2i + 3j + 6k, b = 3i - 6j + 2k and c = 6i + 2j - 3k are mutually perpendicular.

Last Answer : Show that vectors a = 2i + 3j + 6k, b = 3i - 6j + 2k and c = 6i + 2j - 3k are mutually perpendicular.

Find the tangent vector of line having end points P1(3,5,8) and P2 (6,4,3) a.3i+j-5k b.3i-j-5k c.3i-j+5k d.-3i-j-5k

Description : Find the tangent vector of line having end points P1(3,5,8) and P2 (6,4,3) a.3i+j-5k b.3i-j-5k c.3i-j+5k d.-3i-j-5k

Last Answer : b.3i-j-5k

What is the volume of a parallelepiped whose sides are given by the vectors a 3i plus wj plus k b -i plus 3j and c 2i plus 2j plus 5k?

Description : What is the volume of a parallelepiped whose sides are given by the vectors a 3i plus wj plus k b -i plus 3j and c 2i plus 2j plus 5k?

Last Answer : What is the answer ?

In an isosceles triangle, the measure of each of equal sides is 10 cm and the angle between them is 45º. The area of the triangle is: -Maths 9th

Description : In an isosceles triangle, the measure of each of equal sides is 10 cm and the angle between them is 45º. The area of the triangle is: -Maths 9th

Last Answer : (c) 25√2 cm2.ΔABC is an isosceles triangle with AB = AC = 10 cm. ∠A = 45° ∴ Area of ΔABC= \(rac{1}{2}\) x 10 x 10 x sin 45°[Using Δ = \(rac{1}{2}\) bc sin A]= \(rac{50}{\sqrt2}\) = \(rac{50}{\sqrt2}\) x \(rac{\sqrt2}{\sqrt2}\) = 25√2 cm2.

Prove that the figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a parallelogram. -Maths 9th

Description : Prove that the figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a parallelogram. -Maths 9th

Last Answer : Solution :-

What is an angle formed by one side of a triangle and the extension of an adjacent side?

Description : What is an angle formed by one side of a triangle and the extension of an adjacent side?

Last Answer : Exterior and interior angles at the vertex of a triangle add upto 180 degrees

P = i + 2k and Q = 2i + j -2k are two vectors, find the unit vector parallel to P x Q.

Description : P = i + 2k and Q = 2i + j -2k are two vectors, find the unit vector parallel to P x Q.

Last Answer : P = i + 2k and Q = 2i + j -2k are two vectors, find the unit vector parallel to P x ... find the vector perpendicular to P and Q of magnitude 6 units.

Find the angle between the vectors A = i + 2j - k and  B = -i + j - 2k.

Description : Find the angle between the vectors A = i + 2j - k and  B = -i + j - 2k.

Last Answer : Find the angle between the vectors A = i + 2j - k and B = -i + j - 2k.

Given E = 40xyi + 20x 2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3). a) 105 b) 106 c) 107 d) 108

Description : Given E = 40xyi + 20x 2 j + 2k. Calculate the potential between two points (1,-1,0) and (2,1,3). a) 105 b) 106 c) 107 d) 108

Last Answer : b) 106

Given B= (10/r)i+( rcos θ) j+k in spherical coordinates. Find Cartesian points at (- 3,4,0) a) -2i + j b) 2i + k c) i + 2j d) –i – 2k

Description : Given B= (10/r)i+( rcos θ) j+k in spherical coordinates. Find Cartesian points at (- 3,4,0) a) -2i + j b) 2i + k c) i + 2j d) –i – 2k

Last Answer : a) -2i + j

A rhombus has sides of length 1 and area 1/2 Find the angle between the two adjacent sides of the rhombus -Maths 9th

Description : A rhombus has sides of length 1 and area 1/2 Find the angle between the two adjacent sides of the rhombus -Maths 9th

Last Answer : answer:

The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle. -Maths 9th

Description : The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle. -Maths 9th

Last Answer : area of rectangle is l×b 16×8 =128cm sq .area of rectangle is 128cm sq

What is the area of a quadrilateral in which angle 109 degrees is between sides 0.38cm and 0.69cm when adjacent angle 123 degrees is between sides 0.38cm and 0.42cm?

Description : What is the area of a quadrilateral in which angle 109 degrees is between sides 0.38cm and 0.69cm when adjacent angle 123 degrees is between sides 0.38cm and 0.42cm?

Last Answer : Here's how I solve it using the Sine and Cosine rules, and area of a triangle based on sine of angle between two given lengths:Let the quadrilateral be ABCD with ADC = 109°, DCB = 128°, ... the area of the 4 sided quadrilateral works out as 0.305 square cm rounded to three decimal places.

The sides of a triangle are in the ratio of 3 : 4 : 5 and its perimeter is 510 m. What is the measure of its greatest side? -Maths 9th

Description : The sides of a triangle are in the ratio of 3 : 4 : 5 and its perimeter is 510 m. What is the measure of its greatest side? -Maths 9th

Last Answer : Let the sides of triangle be 3x,4x,5x Perimeter =3x + 4x + 5x=144 cm 12x=144 ∴x=12 Then sides of triangle are 3x=3 12=36 cm, 4x=4 12=48 cm, 5x=5 12=60 cm. Now, Semi perimeter, s=2 Sum of sides of ... , Area of triangle =s (s−a)(s−b)(s−c) = 72(72−36)(72−48)(72−60) = 72 36 24 12 = 864 cm2

Construct a triangle whose sides are 3.6 cm , 3.0 cm and 4. 8 cm. Bisect the smallest angle and .measure each part. -Maths 9th

Description : Construct a triangle whose sides are 3.6 cm , 3.0 cm and 4. 8 cm. Bisect the smallest angle and .measure each part. -Maths 9th

Last Answer : To construct a triangle ABC in which AB = 3.6 cm, AC = 3.0 cm and BC = 4. 8 cm, use the following steps. Draw a line segment BC of length 4.8 cm. From B, point A is at a distance of 3.6 cm. ... at P. Joining BP, we obtain angle bisector of ∠B. Flere, ∠ABC=39° Thus, ∠ABD = ∠DBC = ½ x 139° = 19.5°

Construct a triangle whose sides are 3.6 cm , 3.0 cm and 4. 8 cm. Bisect the smallest angle and .measure each part. -Maths 9th

Description : Construct a triangle whose sides are 3.6 cm , 3.0 cm and 4. 8 cm. Bisect the smallest angle and .measure each part. -Maths 9th

Last Answer : To construct a triangle ABC in which AB = 3.6 cm, AC = 3.0 cm and BC = 4. 8 cm, use the following steps. 1.Draw a line segment BC of length 4.8 cm. 2.From B, point A is at a distance of 3.6 ... 3.Joining BP, we obtain angle bisector of ∠B. 4.Flere, ∠ABC=39° Thus, ∠ABD = ∠DBC = 1/2 x 139° = 19.5°

what- Two sides of a triangle measure 8 cm and 15 cm.What is the least possible length of the third side if the length is a whole number?

Description : what- Two sides of a triangle measure 8 cm and 15 cm.What is the least possible length of the third side if the length is a whole number?

Last Answer : 8cm

what- Two sides of a triangle measure 7 ft and 12 ft.What is the greatest possible length of the third side if the length is a whole number?

Description : what- Two sides of a triangle measure 7 ft and 12 ft.What is the greatest possible length of the third side if the length is a whole number?

Last Answer : 18 ft

In what way does knowing the measure of the three sides of a triangle tell you more than just knowing the measures of the three angles?

Description : In what way does knowing the measure of the three sides of a triangle tell you more than just knowing the measures of the three angles?

Last Answer : Ion kn

In what way does knowing the measure of the three sides of a triangle tell you more than just knowing the measures of the three angles?

Description : In what way does knowing the measure of the three sides of a triangle tell you more than just knowing the measures of the three angles?

Last Answer : Ion kn

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Description : If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Description : If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.

30. Radical centre of circles drawn on the sides as a diameter of triangle formed by the lines the `3x-4y+6=0`, `x-y+2=0` and `4x+3y-17=0` is

Description : 30. Radical centre of circles drawn on the sides as a diameter of triangle formed by the lines the `3x-4y+6=0`, `x-y+2=0` and `4x+3y-17=0` is

Last Answer : 30. Radical centre of circles drawn on the sides as a diameter of triangle formed by the lines the `3x-4y+6=0`, `x-y+ ... . (-2,3) C. (-2,-3) D. (2,3)

A rhombus shaped sheet with perimeter 40 and digonals are 12 cm is painted on bith sides at the rate of rs 5 per metre square. Find the cost of painting -Maths 9th

Description : A rhombus shaped sheet with perimeter 40 and digonals are 12 cm is painted on bith sides at the rate of rs 5 per metre square. Find the cost of painting -Maths 9th

Last Answer : Let ABCD be a rhombus, then AB=BC=CD=DA=x Perimeter of rhombus =40cm ⇒4x=40cm⇒x=10cm ∴AB=BC=CD=DA=10cm In △ABC,S=2a+b+c​=210+10+12​=16cm ar△ABC=16(16−10)(16−10)(16−12)​=16×6×6×4​=48cm2ar.ABCD=2×48=96cm2 Cost of painting the sheet =Rs(5×96×2)=Rs960 [Both sides]

A rhombus shaped sheet with perimeter 40 and digonals are 12 cm is painted on bith sides at the rate of rs 5 per metre square. Find the cost of painting -Maths 9th

Description : A rhombus shaped sheet with perimeter 40 and digonals are 12 cm is painted on bith sides at the rate of rs 5 per metre square. Find the cost of painting -Maths 9th

Last Answer : Let ABCD be a rhombus, then AB=BC=CD=DA=x Perimeter of rhombus =40cm ⇒4x=40cm⇒x=10cm ∴AB=BC=CD=DA=10cm In △ABC,S=2a+b+c​=210+10+12​=16cm ar△ABC=16(16−10)(16−10)(16−12)​=16×6×6×4​=48cm2ar.ABCD=2×48=96cm2 Cost of painting the sheet =Rs(5×96×2)=Rs960 [Both sides]

A wall have length 24m and breadth 16m. What will be total cost of painting it from both sides if rate of painting is Rs 8 per square metre? 1) Rs 5696 2) Rs 5856 3) Rs 6032 4) Rs 6144 5) Rs 6272

Description : A wall have length 24m and breadth 16m. What will be total cost of painting it from both sides if rate of painting is Rs 8 per square metre? 1) Rs 5696 2) Rs 5856 3) Rs 6032 4) Rs 6144 5) Rs 6272

Last Answer : 4) Rs 6144

Find the projection of A on B. Given A = 10j + 3k and B = 4j + 5k. a) 6 b) 6.25 c) 6.5 d) 6.75

Description : Find the projection of A on B. Given A = 10j + 3k and B = 4j + 5k. a) 6 b) 6.25 c) 6.5 d) 6.75

Last Answer : b) 6.25

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Description : The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Last Answer : Here, length of rectangle ABCD = 8 cm and breadth of rectangle ABCD = 6.cm Let E, F, G and H are the mid-points of the sides of rectangle ABCD, then EFGH is a rhombus.

The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Description : The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm, is -Maths 9th

Last Answer : Here, length of rectangle ABCD = 8 cm and breadth of rectangle ABCD = 6.cm Let E, F, G and H are the mid-points of the sides of rectangle ABCD, then EFGH is a rhombus.

Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Description : Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Last Answer : We know that, each angle of a rectangle is right angle (i.e., 90°) and its opposite sides are equal and parallel. To construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm, use the ... AD and CD. Thus, ABCD is the required rectangle with adjacent sides of length 5 cm and 3.5 cm.

Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Description : Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Last Answer : To construct a triangle ABC in which AB = 3.6 cm, AC = 3.0 cm and BC = 4. 8 cm, use the following steps. 1.Draw a line segment BC of length 4.8 cm. 2.From B, point A is at a distance of 3.6 ... 3.Joining BP, we obtain angle bisector of ∠B. 4.Flere, ∠ABC=39° Thus, ∠ABD = ∠DBC = 1/2 x 139° = 19.5°

If two adjacent sides of a kite are 5cm and 7cm, find its perimeter. -Maths 9th

Description : If two adjacent sides of a kite are 5cm and 7cm, find its perimeter. -Maths 9th

Last Answer : Solution :-

The lengths of two adjacent sides of a parallelogram are 17 cm and 12 cm. -Maths 9th

Description : The lengths of two adjacent sides of a parallelogram are 17 cm and 12 cm. -Maths 9th

Last Answer : For △BCD: Let a = 17 cm, b = 12 cm, c = 25 cm So its semi-perimeter, s = (a + b + c)/2 = (17 + 12 + 25)/2 = 27 cm ∴ Area of △BCD = root under(√(s -a)(s - b)(s - c)) = ... △BCD = 2 x 90 = 180 cm2 Also, area of parallelogram ABCD = DC x AE ∴ 180 = 12 x AE ⇒ AE = 180/12 = 15 cm

A cyclic parallelogram having unequal adjacent sides is necessarily a: -Maths 9th

Description : A cyclic parallelogram having unequal adjacent sides is necessarily a: -Maths 9th

Last Answer : answer:

The adjacent sides of a parallelogram are 2a and a. If the angle between them is 60°, then one of the diagonals of the parallelogram is -Maths 9th

Description : The adjacent sides of a parallelogram are 2a and a. If the angle between them is 60°, then one of the diagonals of the parallelogram is -Maths 9th

Last Answer : answer:

The diagonal of the parallelogram made by two vectors as adjacent sides is not passing through common point of two vectors. What does it represent?

Description : The diagonal of the parallelogram made by two vectors as adjacent sides is not passing through common point of two vectors. What does it represent?

Last Answer : The diagonal of the parallelogram made by two vectors as adjacent sides is not passing through common point of two vectors. What does it represent?

An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Description : An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Last Answer : B. 28.8 x 10-2k

An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of the operation is 2.0kmph then the area covered (ha), in 8 hr day is given by: a) 1.85/1000k b) 28.8 * 10-2k c) k/6.456 d) 1.762k

Description : An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of the operation is 2.0kmph then the area covered (ha), in 8 hr day is given by: a) 1.85/1000k b) 28.8 * 10-2k c) k/6.456 d) 1.762k

Last Answer : b) 28.8 * 10-2k

If ten students are asked to measure the length of a piece of cloth upto a mm, using a metre scale,

Description : If ten students are asked to measure the length of a piece of cloth upto a mm, using a metre scale,

Last Answer : If ten students are asked to measure the length of a piece of cloth upto a mm, using a ... you think their answers will be identical? Give reasons.

A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, -Maths 9th

Description : A triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm and 30 cm, -Maths 9th

Last Answer : For the given triangle, we have a = 28 cm, b = 30 cm, c = 26 cm Area of the given parallelogram = Area of the given triangle ∴ Area of the parallelogram = 336 cm2 ⇒ base x height = 336 ⇒ ... be the height of the parallelogram. ⇒ h = 33628 = 12 Thus, the required height of the parallelogram = 12 cm

Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm. Find its area. -Maths 9th

Description : Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm. Find its area. -Maths 9th

Last Answer : Let the sides of the triangle be a = 12x cm, b = 17x cm, c = 25x cm Perimeter of the triangle = 540 cm Now, 12x + 17x + 25x = 540 ⇒ 54x = 54 ⇒ x = 10 ∴ a = (12 x10)cm = 120cm, b = (17 x 10) cm = 170 cm and c = (25 x 10)cm = 250 cm Now, semi-perimeter, s = 5402cm = 270 cm

Find the area of a triangle whose sides are 4.5 cm and 10 cm and perimeter 10.5 cm. -Maths 9th

Description : Find the area of a triangle whose sides are 4.5 cm and 10 cm and perimeter 10.5 cm. -Maths 9th

Last Answer : Step-by-step explanation: ◾As we have given the two sides of triangle, let the three sides of triangle are (a) , (b), (c) . ◾And perimeter of given triangle is 10.5 cm ◾were, let us assume the sides are, ... . ◾So, the area of a triangle whose sides are 4.5 cm and 10 cm and perimeter 10.5 [Area ]=

Find the area of a triangle whose sides are 12 cm, 6 cm and 15 cm. -Maths 9th

Description : Find the area of a triangle whose sides are 12 cm, 6 cm and 15 cm. -Maths 9th

Last Answer : Using the formulas A=s(s﹣a)(s﹣b)(s﹣c) s=a+b+c 2Solving forA A=1 4﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1 4·﹣124+2·(12·6)2+2·(12·15)2﹣64+2·(6·15)2﹣154≈34.19704cm²