(ii) \( \left( A ^{-1}\right)^{-1}= A \).22. Verify : \( A(\operatorname{adj} \cdot A)=(\operatorname{adj} \cdot A) A=|A| I \) when(i) \( A=\left[\begin{array}{rrr}1 & -2 & 2 \\ 2 & 3 & 5 \\ -2 & 0 & 1\end{array}\right] \)

(ii) \( \left( A ^{-1}\right)^{-1}= A \).22. Verify : \( A(\operatorname{adj} \cdot A)=(\operatorname{adj} \cdot A) A=|A| I \) when(i) \( A=\left[\begin{array}{rrr}1 & -2 & 2 \\ 2 & 3 & 5 \\ -2 & 0 & 1\end{array}\right] \)
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(ii) \( \left( A ^{-1}\right)^{-1}= A \). 22. Verify : \( A(\operatorname{adj} \cdot A)=(\operatorname{ ... 3 & 5 \\ -2 & 0 & 1\end{array}\right] \)
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Last Answer : answer:

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