The mean of the observation 7, 8, 9, 11 and 15 is 10.

The mean of the observation 7, 8, 9, 11 and 15 is 10.
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The mean of the observation 7, 8, 9, 11 and 15 is 10.
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I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 XII=12 XIII=13 XIV=14 XV=15...... Of course, I + XI = X is wrong. You are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Description : I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 ... are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Last Answer : Most people would get to one move at the least, but the real answer is zero moves. If you rotate the whole question around 180 degrees, it will display this: X = IX + I

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 days and 8 kg to 10 kg (C) 105 days to 120 days and 18 kg to 21 kg (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg

What is the output of the following? i = 5 while True: if i%0O9 == 0: break print(i) i += 1 a) 5 6 7 8 b) 5 6 7 8 9 c) 5 6 7 8 9 10 11 12 13 14 15 …. d) error

Description : What is the output of the following? i = 5 while True: if i%0O9 == 0: break print(i) i += 1 a) 5 6 7 8 b) 5 6 7 8 9 c) 5 6 7 8 9 10 11 12 13 14 15 …. d) error

Last Answer : d) error

The average of 12 numbers is 7.9. The average of 5 of them is 6.8, while the average of other five is 7.7. what is the average of the remaining 2 numbers? A) 10.25 B) 11.15 C) 12.65 D) 13.25

Description : The average of 12 numbers is 7.9. The average of 5 of them is 6.8, while the average of other five is 7.7. what is the average of the remaining 2 numbers? A) 10.25 B) 11.15 C) 12.65 D) 13.25

Last Answer : B) Sum of the remaining 2 numbers = [(12 * 7.9) – (586.8) – (5*7.7)]  = 94.8 – 34 – 38.5  = 22.3  Required average = 22.3 / 2  = 11.15

Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Description : Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Last Answer : Answer: C

On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Description : On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Description : The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Last Answer : D) Calculated mean of 8 articles = 15 Incorrect sum of these 8 articles = (15*8) = 120. Correct sum of these 8 articles = (incorrect sum) - (sum of incorrect articles) + (sum of actual articles) = [120 ... (30)] = 130 Therefore, correct mean = 130/8 = 16.25 Hence, the correct mean is 16.25.

A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Description : A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Last Answer : d) Rs. 15 ,

Gross assets are Rs.1,01,000, fictitious assets Rs.350 are included in the gross assets. External liabilities are Rs.7,500. 6% prefer share capital is Rs.45,000. Equity capital is 4,500 equity shares of Rs.10 each fully paid. Average expected profit is Rs.8,500. Transfer to reserves is 10%. Pref. dividend is payable. NRR is 9%. The Net Asset Value Per share is A Rs.11 B Rs.10.70 C Rs.15 D Rs.20s

Description : Gross assets are Rs.1,01,000, fictitious assets Rs.350 are included in the gross assets. External liabilities are Rs.7,500. 6% prefer share capital is Rs.45,000. Equity capital is 4,500 equity shares of Rs.10 each fully ... . The Net Asset Value Per share is A Rs.11 B Rs.10.70 C Rs.15 D Rs.20

Last Answer : Rs.10.70

Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by Image (A) {(11,0.8), (13,1), (15,1)} (B) {(11,0.3), (12,0.5), (13,1), (14,1), (15,1), (16,0.5), (17,0.2)} (C) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,1), (16,0.5), (17,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Description : Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by (A) {(11,0.8), (13,1), (15,1)} ( ... ,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Last Answer : (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Find the mode of the data 7, 8, 9, 9, 10, 7, 11, 10, 7, 6.

Description : Find the mode of the data 7, 8, 9, 9, 10, 7, 11, 10, 7, 6.

Last Answer : Find the mode of the data 7, 8, 9, 9, 10, 7, 11, 10, 7, 6.

All active prostaglandins have atleast one double bond between positions: (A) 7 and 8 (B) 9 and 10 (C) 11 and 12 (D) 13 and 14 FATS AND FATTY ACID METABOLISM 95

Description : All active prostaglandins have atleast one double bond between positions: (A) 7 and 8 (B) 9 and 10 (C) 11 and 12 (D) 13 and 14 FATS AND FATTY ACID METABOLISM 95

Last Answer : Answer : A

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years  1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)

ormal size of brick used in India is a) 22 x 11.2 x 7 cm* b) 25 x 16 x 8 cm c) 19 x 12 x 9 cm d) 20 x 10 x 5 cm

Description : ormal size of brick used in India is a) 22 x 11.2 x 7 cm* b) 25 x 16 x 8 cm c) 19 x 12 x 9 cm d) 20 x 10 x 5 cm

Last Answer : a) 22 x 11.2 x 7 cm*

The term total milk solids describes the remaining ____ percent of milk. a. 10–11 c. 5–7 b. 12–13 d. 8–9

Description : The term total milk solids describes the remaining ____ percent of milk. a. 10–11 c. 5–7 b. 12–13 d. 8–9

Last Answer : b. 12–13

The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Description : The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Last Answer : A Let M age and N age be 8x years and 9x years. Then 9x - 8x = 6 <=> x = 6 So required ratio will be (8x+6): (9x+6) 54:60 9:10

Faucet A and B can fill a tank in 15 and 9 hrs respectively. Faucet C can empty it in 45 h. The tank is half full. All the three faucets are in operation simultaneously. After how much time the tank will be full ? A) 1(7/15)hrs B) 2(1/11)hrs C) 3(3/14)hrs D) 3(3/11)hrs

Description : Faucet A and B can fill a tank in 15 and 9 hrs respectively. Faucet C can empty it in 45 h. The tank is half full. All the three faucets are in operation simultaneously. After how much time the tank will be full ? A) 1(7/15)hrs B) 2(1/11)hrs C) 3(3/14)hrs D) 3(3/11)hrs

Last Answer : C In 1 hr = 1/15+1/9 – 1/45 =>3+5-1/45 = 7/45 ½ tank filled by 3 Faucets = 45/7*1/2 => 45/14 =>3(3/14)

In an artesian aquifer, the draw downs in two observation wells at distances 100 m, and 200 m were found same after one hour and x hours respectively. The value of x, is (A) 2 hours (B) 4 hours (C) 9 hours (D) 16 hours

Description : In an artesian aquifer, the draw downs in two observation wells at distances 100 m, and 200 m  were found same after one hour and x hours respectively. The value of x, is  (A) 2 hours  (B) 4 hours  (C) 9 hours  (D) 16 hours 

Last Answer : (B) 4 hours

yr-old baby presented with his parents with pallor his HB is 9, he has microcytic hypochromic anemia, no other complain .. what u'll do for him ?? iron therapy and close observation daily multivitamins with iron _______________________________

Description : yr-old baby presented with his parents with pallor his HB is 9, he has microcytic hypochromic anemia, no other complain .. what u'll do for him ?? iron therapy and close observation daily multivitamins with iron _______________________________

Last Answer : iron therapy and close observation daily multivitamins with iron ___________________________________

The normal range of plasma calcium is (A) 3-5 mg/dl (B) 5-10 mg/dl (C) 9-11 mg/dl (D) 11-15 mg/dl

Description : The normal range of plasma calcium is (A) 3-5 mg/dl (B) 5-10 mg/dl (C) 9-11 mg/dl (D) 11-15 mg/dl

Last Answer : Answer : C

Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours

Description : Two pipes fills a tank in 12 hours and 15 hours respectively while a third pipe empties the tank in 18 hours. !f all three pipes operate simultaneously, in what time will the tank be full? a) 10 hours b) 10 10/17 hours c) 11 hours d) 9 hours e) 12 1/17 hours

Last Answer : b) 10 10/17 hours

P, Q, R invested in the ratio of 15:16:17. After the end of the business teram they receives the profit in the ratio 9:10:11. Find the ratio of time in which they invested in the business. A) 934:1699:1578 B)1224:1275:1320 C)1578:1668:8096. D) None

Description : P, Q, R invested in the ratio of 15:16:17. After the end of the business teram they receives the profit in the ratio 9:10:11. Find the ratio of time in which they invested in the business. A) 934:1699:1578 B)1224:1275:1320 C)1578:1668:8096. D) None

Last Answer : Answer: B)  P, Q, R invest the amount in the ratio 15:16:17  T1, T2, T3 are time for investment profit gained =investment × time  Profit ratio= 9: 10: 11=15 × T1 :16 × T2 : 17 × T3  T1:T2:T3 =1224:1275:1320

The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

A conventional vehicle costs 10 to 15 percent per mile in fuel to operate. How much does an electric vehicle cost per mile? • 2 to 4 cents • 5 to 6 cents • 7 to 8 cents • 9 to 10 cents

Description : A conventional vehicle costs 10 to 15 percent per mile in fuel to operate. How much does an electric vehicle cost per mile? • 2 to 4 cents • 5 to 6 cents • 7 to 8 cents • 9 to 10 cents

Last Answer : • 2 to 4 cents

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, woman and one boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Description : 8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, ... boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Last Answer : A Efficiency of 8 men and 8 boys = 10% Efficiency of 9 women and 7boys = 10% Efficiency of 7 men and 6 women = 10% So, Efficiency of 15 men, 15women and 15boys = 30% So, efficiency of 1 man ... efficiency Efficiency of 1 man, 1 woman and 1 boy = 4% Required number of days = 100/4=25 days

Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days

Description : Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days 

Last Answer : B Nandhu's 1 day work = 1/10 Naren's 1 day work = 1/15 Abishek's 1 day work =1/30 Nandhu's 2 day's work =(1/10*2) =1/5 (nandhu + naren+abishek)'s 1 day work = 1/10+1/15+1/30 =3+2+1/30 =6/30 ... +1/5 = 2/5 Now 2/5 work is done in 3 days Whole work will be done in 3 *5/2 = 15/2 = 7.5 days

Evaluate: `lim_(x rarr oo) (11|x|+7)/(8|x|-9)`.

Description : Evaluate: `lim_(x rarr oo) (11|x|+7)/(8|x|-9)`.

Last Answer : Evaluate: `lim_(x rarr oo) (11|x|+7)/(8|x|-9)`.

Number of identical terms in the sequence `2, 5, 8, 11, ...` up to 100 terms and 3, 5, 7, 9, 11, ... Up to 100 terms is

Description : Number of identical terms in the sequence `2, 5, 8, 11, ...` up to 100 terms and 3, 5, 7, 9, 11, ... Up to 100 terms is

Last Answer : Number of identical terms in the sequence `2, 5, 8, 11, ...` up to 100 terms and 3, 5, 7, 9, 11, ... Up to 100 terms is A. 33 B. 17 C. 50 D. 147

Samara was playing a game. She wrote down this number sentence to find the total number of points for 11 games in a row. 5 7 9 3 1 3 9 8 5 2 3 What's the sum of her scores?

Description : Samara was playing a game. She wrote down this number sentence to find the total number of points for 11 games in a row. 5 7 9 3 1 3 9 8 5 2 3 What's the sum of her scores?

Last Answer : 55

Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Description : Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Last Answer : C Time taken by Siva = 8 h Time taken by Anirudh = 7 h For your convenience take the product of times taken by both as a distance. Then the distance = 56km Since, Siva covers half of the distance in 2 ... by them = 28/15 = 1 hr 52 min Thus , they will cross each other at 6 : 52am.

Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Description : Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Last Answer : Answer: E Brass in A = 3/5 * 50 = 30 kg, Brass in B = 4/7 * 70 = 40 kg Total brass = 30+40 = 70 kg So copper in mixture is (50+70) – 70 = 50 kg So copper to brass = 50 : 70=5:7

From separate solution of four sodium salt NaW, Nax, NaY and NaZ had pH 7.0 , 9.0 , 10 . 0 and 11.0 respectively , when each solution was 0.1 M , the

Description : From separate solution of four sodium salt NaW, Nax, NaY and NaZ had pH 7.0 , 9.0 , 10 . 0 and 11.0 respectively , when each solution was 0.1 M , the

Last Answer : From separate solution of four sodium salt NaW, Nax, NaY and NaZ had pH 7.0 , 9.0 , 10 . 0 and 11.0 ... acid is :- A. HW B. HX C. HY D. HZ

After operative removal of the parathyroid glands resulting into hypoparathyroidism the concentration of the serum calcium may drop below (A) 11 mg (B) 10 mg (C) 9 mg (D) 7 mg

Description : After operative removal of the parathyroid glands resulting into hypoparathyroidism the concentration of the serum calcium may drop below (A) 11 mg (B) 10 mg (C) 9 mg (D) 7 mg

Last Answer : Answer : D

How many digits are there in Mobile Money Identifier(MMID)? A. 7 digits B. 9 digits C. 10 digits D. 11 digits E. None of the Above

Description : How many digits are there in Mobile Money Identifier(MMID)? A. 7 digits B. 9 digits C. 10 digits D. 11 digits E. None of the Above

Last Answer : A. 7 digits Explanation: Mobile Money Identifier is a 7 digit number, issued by banks. MMID is one of the input which when clubbed with mobile number facilitates fund transfer. Combination of ... and helps in identifying the beneficiary details. Different MMID s can be linked to same Mobile Number.

Molecular weight of polymers are in the range of (A) 10 to 10 3 (B) 10 2 -10 7 (C) 10 7 -10 9 (D) 10 9 -10 11

Description : Molecular weight of polymers are in the range of (A) 10 to 10 3 (B) 10 2 -10 7 (C) 10 7 -10 9 (D) 10 9 -10 11

Last Answer : (B) 10 2 -10

Momentum of electron having mass 9.1 × 10-31 kg and velocity 2.0 × 107 is A. 1.91 × 10-23 B. 2.34 × 10-23 C. 3.11 × 10-19 D. 7.88 × 10-34

Description : Momentum of electron having mass 9.1 × 10-31 kg and velocity 2.0 × 107 is A. 1.91 × 10-23 B. 2.34 × 10-23 C. 3.11 × 10-19 D. 7.88 × 10-34

Last Answer : 1.91 × 10-23

Force per meter on two wires carrying a current of 1 A placed 1 m apart is equal to A. 6.7 × 10-11 N B. 9.0 × 109 N C. 2.0 × 10-7 N D. 3.0 × 10-4 N

Description : Force per meter on two wires carrying a current of 1 A placed 1 m apart is equal to A. 6.7 × 10-11 N B. 9.0 × 109 N C. 2.0 × 10-7 N D. 3.0 × 10-4 N

Last Answer :  2.0 × 10-7 N

Molecular weights of polymers are in the range of (A) 10 2 - 10(B) 10 5 - 10 9 (C) 10 2 - 10 7 (D) 10 9 - 10 11

Description : Molecular weights of polymers are in the range of (A) 10 2 - 10 (B) 10 5 - 10 9 (C) 10 2 - 10 7 (D) 10 9 - 10 11

Last Answer : (C) 10 2 - 10 7

According to Indian Standards Institute, the actual size of modular bricks is (A) 23 cm × 11.5 cm × 7.5 cm (B) 25 cm × 13 cm × 7.5 cm (C) 19 cm × 9 cm × 9 cm (D) 20 cm × 10 cm × 10 cm

Description : According to Indian Standards Institute, the actual size of modular bricks is (A) 23 cm × 11.5 cm × 7.5 cm (B) 25 cm × 13 cm × 7.5 cm (C) 19 cm × 9 cm × 9 cm (D) 20 cm × 10 cm × 10 cm

Last Answer : (C) 19 cm × 9 cm × 9 cm

In 2003, if the number of female qualified candidates was 70, what was the respective ratio of number of female qualified candidates and number of male qualified candidates same year? A. 5:9 B. 7:11 C. 10:11 D. 10:13 E. 5:7

Description : In 2003, if the number of female qualified candidates was 70, what was the respective ratio of number of female qualified candidates and number of male qualified candidates same year? A. 5:9 B. 7:11 C. 10:11 D. 10:13 E. 5:7

Last Answer : E. 5:7

How many cups of water do humans require per day? a. 1 to 3 c. 5 to 9 b. 10 to 12 d. 7 to 11

Description : How many cups of water do humans require per day? a. 1 to 3 c. 5 to 9 b. 10 to 12 d. 7 to 11

Last Answer : d. 7 to 11

Suppose that the virtual Address space has eight pages and physical memory with four page frames. If LRU page replacement algorithm is used, .............. number of page faults occur with the reference string. 0 2 1 3 5 4 6 3 7 4 7 3 3 5 5 3 1 1 1 7 2 3 4 1 (A) 11 (B) 12 (C) 10 (D) 9

Description : Suppose that the virtual Address space has eight pages and physical memory with four page frames. If LRU page replacement algorithm is used, .............. number of page faults occur with the reference string. 0 2 1 3 5 4 6 3 7 4 7 3 3 5 5 3 1 1 1 7 2 3 4 1 (A) 11 (B) 12 (C) 10 (D) 9

Last Answer : (A) 11

Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by ‘A’ is Rs 40,000, out of a total annual profit of Rs 33,000, C’s share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Description : Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by A' is Rs 40,000, out of a total annual ... share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Last Answer : Answer: A Sum invested by A , B and C is 5 * 12:7 * 12:6 * 6 + 3 * 6 or 60 : 84 : 54 or 10 : 14 : 9 :: Share of C = ( 9 / 33 ) * 33000 = Rs. 9000