Identify the correct trend given below : ( Atomic no : Ti=22, Cr=24 and Mo=42)

Identify the correct trend given below : ( Atomic no : Ti=22, Cr=24 and Mo=42)
by

1 Answer

Answer :

Identify the correct trend given below : ( Atomic no : Ti=22, Cr=24 and Mo=42) A. `Delta_(0)of [Cr(H_(2)O)_(6)] ... _(6)]^(+3)gt[Ti(H_(2)O)_(6)]^(2+)`
by
selected by

Related questions

Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] Correct combination for `[PtCl_

Description : Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] Correct combination for `[PtCl_

Last Answer : Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78 ... (IV),(iv),P D. (III),(ii),R

Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] Correct combination for `[VCl_(

Description : Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] Correct combination for `[VCl_(

Last Answer : Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78 ... (III),(ii),R D. (IV),(iv),Q

Amongst `[TiE_(6)]^(2-), [CoF_(6)]^(3-), Cu_(2)Cl_(2)` and `[NiCl_(4)]^(2-)` [Atomic no. `Ti = 22, Co = 27, Cu = 29, Ni = 28`] the colourless species

Description : Amongst `[TiE_(6)]^(2-), [CoF_(6)]^(3-), Cu_(2)Cl_(2)` and `[NiCl_(4)]^(2-)` [Atomic no. `Ti = 22, Co = 27, Cu = 29, Ni = 28`] the colourless species

Last Answer : Amongst `[TiE_(6)]^(2-), [CoF_(6)]^(3-), Cu_(2)Cl_(2)` and `[NiCl_(4)]^(2-)` [Atomic no. `Ti = 22, ... (2)Cl_(2)` D. `TiF_(6)^(2-) and Cu_(2)Cl_(2)`

Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] About `(CrCl_(3)(NH_(3))_(3))`

Description : Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] About `(CrCl_(3)(NH_(3))_(3))`

Last Answer : Matching the information given in the three columns of the following table. [Note: Atomic Number of Cr=24,V=23,Pt=78)] ... (IV),(i), R D. (I),(ii),S

Compare the following complexes with respect to their shape, magnetic behaviour and the hybrid orbitals involved : (i) [CoF4]2- (ii) [Cr(H2O)2(C2O4)2]– (iii) [Ni(CO)4] (Atomic number : Co = 27, Cr = 24, Ni = 28) -Chemistry

Description : Compare the following complexes with respect to their shape, magnetic behaviour and the hybrid orbitals involved : (i) [CoF4]2- (ii) [Cr(H2O)2(C2O4)2]– (iii) [Ni(CO)4] (Atomic number : Co = 27, Cr = 24, Ni = 28) -Chemistry

Last Answer : (i) [COF4]2_ : Tetrafluorido cobalt (III) ion Coordination number = 4 Shape = Tetrahedral Hybridisation = sp3 Important Questions for Class 12 Chemistry Chapter 9 Coordination Compounds Class 12 Important Questions 7

Most common stainless steel type 316, which is highly resistant to corrosion contains (A) 16-13% Cr 10-14% Ni and 2-3% Mo (B) 20-22% Cr, and 8-10% Ni (C) 2-4% Cr, 22% NI and 2-4% Mo (D) None of these

Description : Most common stainless steel type 316, which is highly resistant to corrosion contains (A) 16-13% Cr 10-14% Ni and 2-3% Mo (B) 20-22% Cr, and 8-10% Ni (C) 2-4% Cr, 22% NI and 2-4% Mo (D) None of these

Last Answer : (A) 16-13% Cr 10-14% Ni and 2-3% Mo

Mark correct option related to preservation period a) Nominal roll cum attendance & destruction of record register is permanent b) All records of registration and parcel dept except foreign article is 1 year c) All records of registration and parcel dept related fo foreign articles is 1 ½ year d) All records of MO is 1 ½ year, IPO 42 months, Book of MO receipt is 2 years e) All the above

Description : Mark correct option related to preservation period a) Nominal roll cum attendance & destruction of record register is permanent b) All records of registration and parcel dept except foreign article is 1 year c) All records ... 1 ½ year, IPO 42 months, Book of MO receipt is 2 years e) All the above

Last Answer : e) All the above

The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Description : The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Last Answer : a) Rs.22.57

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

Which of the following complexes will mostly likely abosorb visible light ? (At nos. Sc=21,Ti=22,V=23,Zn=30)

Description : Which of the following complexes will mostly likely abosorb visible light ? (At nos. Sc=21,Ti=22,V=23,Zn=30)

Last Answer : Which of the following complexes will mostly likely abosorb visible light ? (At nos. Sc=21,Ti=22,V=23,Zn=30) A. `[Sc ... )` D. `[Zn(NH_(3))_(6)]^(2+)`

If total income of company B in 2008 was Rs.140 crore, what was the total expenditure of that company in the same year? (approx) a) Rs.100.66 cr. b) Rs.110.33 cr. c) Rs.98.22 cr. d) Rs.94.90 cr. e) Rs.96.55 cr.

Description : If total income of company B in 2008 was Rs.140 crore, what was the total expenditure of that company in the same year? (approx) a) Rs.100.66 cr. b) Rs.110.33 cr. c) Rs.98.22 cr. d) Rs.94.90 cr. e) Rs.96.55 cr.

Last Answer : e) Rs.96.55 cr.

The rules related to MO in IPO act explained in section a) 43 to 48 b) 38 to 42 c) 49 to 53 c ) None of these

Description : The rules related to MO in IPO act explained in section a) 43 to 48 b) 38 to 42 c) 49 to 53 c ) None of these

Last Answer : a) 43 to 48

1The elements of the second period of the Periodic Table are given below: Li Be B C N O F (a) Give reason to explain why atomic radii decrease from Li to F. (b) Identify the most (i) metallic and (ii)non-metallic element. -Science

Description : 1The elements of the second period of the Periodic Table are given below: Li Be B C N O F (a) Give reason to explain why atomic radii decrease from Li to F. (b) Identify the most (i) metallic and (ii)non-metallic element. -Science

Last Answer : a) It is because nuclear charge increases due to increase in atomic number, therefore, force of attraction between nucleus and valence electrons increases, i.e. effective nuclear charge increases, hence ... element is ‘F’ because it can gain electrons easily due to smallest atomic size.

The pair having the same magnetic moment is [at. No. `Cr = 24, Mn = 25, Fe = 26 " and " Co = 27]`

Description : The pair having the same magnetic moment is [at. No. `Cr = 24, Mn = 25, Fe = 26 " and " Co = 27]`

Last Answer : The pair having the same magnetic moment is [at. No. `Cr = 24, Mn = 25, Fe = 26 " and " Co = 27]` A. `[Cr( ... (H_(2)O)_(6)]^(2+) and [CoCl_(4)]^(2-)`

In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Description : In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Last Answer : C. 29,30,31

What is the atomic number of Ti ?

Description : What is the atomic number of Ti ?

Last Answer : The atomic number of Ti is 22

Use the information and data given below to answer the questions • Stronger intermolecular forces result in higher boiling point • Strength of London forces increases with the number of electrons in the molecule • Boiling point of HF ,HCl, HBr and HI are 293K,189K,206K and 238K respectively (a) Which type of intermolecular forces are present in the molecules HCl, HBr and HI? (b) Looking at the trend of boiling points of HCl, HBr and HI, explain, out of dipole interaction and London interaction, which one predominant here? (c) Why is the boiling point of HF highest while that of HCl lowest?

Description : Use the information and data given below to answer the questions Stronger intermolecular forces result in higher boiling point Strength of London forces increases with the number of electrons in the molecule ... here? (c) Why is the boiling point of HF highest while that of HCl lowest?

Last Answer : Ans :( a) In the molecules HCl, HBr and HI, dipole-dipole interaction and London forces are present. (b) Dipole moment of HCl > HBr > HI but boiling point of HCl < HBr

What is the atomic number of Cr ?

Description : What is the atomic number of Cr ?

Last Answer : The atomic number of Cr is 24

The deficiencies of micronutrients, not only affect growth of plants but also vital functions such as photosynthetic and mitochondrial electron flow. Among the list given below, which group of three elements shall affect most, both photosynthetic and mitochondrial electron transport?(a) Co, Ni, Mo (b) Ca, K, Na (c) Mn, Co, Ca (d) Cu, Mn, Fe

Description : The deficiencies of micronutrients, not only affect growth of plants but also vital functions such as photosynthetic and mitochondrial electron flow. Among the list given below, which group of three elements shall affect most, both ... , Mo (b) Ca, K, Na (c) Mn, Co, Ca (d) Cu, Mn, Fe

Last Answer : d) Cu, Mn, Fe

Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : [Co(NH3)6]+3, [Cr(NH3)6]3+, Ni(CO)4 (At. nos. : Co = 27, Cr = 24, Ni = 28) -Chemistry

Description : Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : [Co(NH3)6]+3, [Cr(NH3)6]3+, Ni(CO)4 (At. nos. : Co = 27, Cr = 24, Ni = 28) -Chemistry

Last Answer : (i) [Co(NH3)6]+3 → Octahedral shape, d2sp3 hybridisation, diamagnetic Formation of [Co(NH2)6]+3 → oxidation state of Co is +3.

Magnetic moments of `V(Z = 23), Cr(Z = 24), Mn (Z = 25)` are x,y,z. HencE:

Description : Magnetic moments of `V(Z = 23), Cr(Z = 24), Mn (Z = 25)` are x,y,z. HencE:

Last Answer : Magnetic moments of `V(Z = 23), Cr(Z = 24), Mn (Z = 25)` are x,y,z. HencE: A. `x=y=z` B. `xltyltz` C. `xltzlty` D. `zltyltx`

What is the highest oxidation state shown by Cr. (24) , Mn(25) ?

Description : What is the highest oxidation state shown by Cr. (24) , Mn(25) ?

Last Answer : Ans: Cr. Shows (+6) and Mn Shows (+7) Oxidation state .  

Explain the trend of the following in group 13 elements : A. atomic radii  B. ionization enthalpy  C. electron affinity

Description : Explain the trend of the following in group 13 elements : A. atomic radii  B. ionization enthalpy  C. electron affinity

Last Answer : Explain the trend of the following in group 13 elements : A. atomic radii B. ionization enthalpy C. electron affinity

Proceeding across a period in the Periodic Table, what atomic size trend is observed?

Description : Proceeding across a period in the Periodic Table, what atomic size trend is observed?

Last Answer : ANSWER: ATOMIC SIZE DECREASES

What is the atomic number of Mo ?

Description : What is the atomic number of Mo ?

Last Answer : The atomic number of Mo is 42

Which one is the correct relation between energy efficiency ratio (EER) and coefficient of performance (COP)?  A. EER = 2.34 COP  B. EER = 3.24 COP  C. EER = 3.42 COP  D. EER = 4.23 COP

Description : Which one is the correct relation between energy efficiency ratio (EER) and coefficient of performance (COP)?  A. EER = 2.34 COP  B. EER = 3.24 COP  C. EER = 3.42 COP  D. EER = 4.23 COP

Last Answer : EER = 3.42 COP

The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Description : The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Last Answer : (b) 37.29 kN

At which latitude, heat gain through insolation approximately equals heat loss through terrestrial radiation? (a) 22 1 2 ° North and South (b) 40° North and South (c) 42 1 2 ° North and South (d) 66° North and South

Description : At which latitude, heat gain through insolation approximately equals heat loss through terrestrial radiation? (a) 22 1 2 ° North and South (b) 40° North and South (c) 42 1 2 ° North and South (d) 66° North and South

Last Answer : (b) 40° North and South

Maximum permissible concentration (i.e. TLV) of DDT in public water supply system is __________ micro gram (μ g)/litre. (A) 22 (B) 42 (C) 332 (D) 1050

Description : Maximum permissible concentration (i.e. TLV) of DDT in public water supply system is __________ micro gram (μ g)/litre. (A) 22 (B) 42 (C) 332 (D) 1050

Last Answer : (B) 42

If the natural moisture content, the liquid limit and plastic limit of a soil sample are stated as 30.5%, 42.5% and 22.5% respectively, the ratio of liquidity index and plastic index, is (A) (B) ½ (C) 2 (D) 2½

Description : If the natural moisture content, the liquid limit and plastic limit of a soil sample are stated as 30.5%, 42.5% and 22.5% respectively, the ratio of liquidity index and plastic index, is (A) (B) ½ (C) 2 (D) 2½

Last Answer : Answer: Option C

Four equal sized maximum circular plates are cut off from a square sheet of area 784 cm2. What is the circumference of each plate? a) 22 cm b) 44 cm c) 42 cm d) 40cm

Description : Four equal sized maximum circular plates are cut off from a square sheet of area 784 cm2. What is the circumference of each plate? a) 22 cm b) 44 cm c) 42 cm d) 40cm

Last Answer : b) 44 cm

Which one of the following is decimal value of a signed binary number 1101010, if it is in 2's complement form? (A) -42 (B) - 22 (C) -21 (D) -106

Description : Which one of the following is decimal value of a signed binary number 1101010, if it is in 2's complement form? (A) -42 (B) - 22 (C) -21 (D) -106

Last Answer : (B) - 22

How many numbers greater than 400 can be formed with digits 3,4,8,9 with no digits being repeated? a) 24 b) 18 c) 42 d) 45

Description : How many numbers greater than 400 can be formed with digits 3,4,8,9 with no digits being repeated? a) 24 b) 18 c) 42 d) 45

Last Answer : c) 42

10) i) \( A=\{a, b, c\} \) and \( B=\{x, 4\} \). Write \( A \times B \)ii) Graph of the function \( f: R \rightarrow R \) is given below.a) Write the value of \( f(x) \)b) Write the range of \( f(x) \)c) Identify The function and choose the correct answer.

Description : 10) i) \( A=\{a, b, c\} \) and \( B=\{x, 4\} \). Write \( A \times B \)ii) Graph of the function \( f: R \rightarrow R \) is given below.a) Write the value of \( f(x) \)b) Write the range of \( f(x) \)c) Identify The function and choose the correct answer.

Last Answer : 10) i) \( A=\{a, b, c\} \) and \( B=\{x, 4\} \). Write \( A \times B \) ii) ... of \( f(x) \) c) Identify The function and choose the correct answer.

The figure given below show the structure of plasma membrane, with its parts labelled from A to E, Identify the correct :-

Description : The figure given below show the structure of plasma membrane, with its parts labelled from A to E, Identify the correct :-

Last Answer : The figure given below show the structure of plasma membrane, with its parts labelled from A ... . `Dto` Its polar tail contain saturated hydrocarbon

Identify from the following states of India through which the Tropic of Cancer passes and arrange them from east to west: 1. Gujarat 2. West Bengal 3. Uttar Pradesh 4. Jharkhand 5. Madhya Pradesh 6. Bihar 7. Chhattisgarh Select the correct answer using the code given below: [NDA 2011] (a) 2-5-7-4-1 (b) 2-4-7-5-1 (c) 3-2-6-7-5 (d) 3-7-4-6-2

Description : Identify from the following states of India through which the Tropic of Cancer passes and arrange them from east to west: 1. Gujarat 2. West Bengal 3. Uttar Pradesh 4. Jharkhand 5. Madhya Pradesh 6. Bihar 7. Chhattisgarh Select the correct answer ... -4-1 (b) 2-4-7-5-1 (c) 3-2-6-7-5 (d) 3-7-4-6-2

Last Answer : Ans: (b)

Identify the components labelled A, B, C and D in the diagram below from the list (i) to (viii) given along withComponents : (i) Cristae of mitochondria (ii) Inner membrane of mitochondria (iii) Cytoplasm (iv) Smooth endoplasmic reticulum (v) Rough endoplasmic reticulum (vi) Mitochondrial matrix (vii) Cell vacuole (viii) Nucleus The correct components are: A B C D (a) (v) (iv) (viii) (iii) (b) (i) (iv) (viii) (vi) (c) (vi) (v) (iv) (vii) (d) (v) (i) (iii) (ii)

Description : Identify the components labelled A, B, C and D in the diagram below from the list (i) to (viii) given along with Components : (i) Cristae of mitochondria (ii) Inner membrane of mitochondria (iii) Cytoplasm (iv) Smooth endoplasmic ... viii) (vi) (c) (vi) (v) (iv) (vii) (d) (v) (i) (iii) (ii)

Last Answer : (a) (v) (iv) (viii) (iii)

Identify the crop on the basis of the following characteristics - 1. It is a kharif crop. 2. Aus, Aman and Boro are its three different growing periods in an agricultural yea 3. About one-fourth of the total cropped area of India is under its cultivation.Select the correct answer using the code given below -a. Wheatb. Ricec. Cottond. Pulses

Description : Identify the crop on the basis of the following characteristics - 1. It is a kharif crop. 2. Aus, Aman and Boro are its three different growing periods in an agricultural yea 3. About one-fourth of the ... . Select the correct answer using the code given below - a. Wheat b. Rice c. Cotton d. Pulses

Last Answer : b. Rice

The main objectives of student evaluation of teachers are: (a) To gather information about student weaknesses. (b) To make teachers take teaching seriously. (c) To help teachers adopt innovative methods of teaching. (d) To identify the areas of further improvement in teacher traits. Identify the correct answer from the codes given below: (A) (a) and (b) only (B) (b), (c) and (d) only (C) (a), (b) and (c) only (D) (a) only

Description : The main objectives of student evaluation of teachers are: (a) To gather information about student weaknesses. (b) To make teachers take teaching seriously. (c) To help teachers adopt innovative methods of teaching. (d) To identify the ... (c) and (d) only (C) (a), (b) and (c) only (D) (a) only

Last Answer : Answer: B 

45.4 L of nitrogen reacted with 22.7 L of oxygen and 45.4 L of nitrogen oxide was formed. The reaction is given below: 2N2(g) + O2(g) →2N2O(g) Which law is being obeyed in this experiment? Write the statement of this law.

Description : 45.4 L of nitrogen reacted with 22.7 L of oxygen and 45.4 L of nitrogen oxide was formed. The reaction is given below: 2N2(g) + O2(g) →2N2O(g) Which law is being obeyed in this experiment? Write the statement of this law.

Last Answer : Ans. Gay lussac’s law of gaseous volume is being obeyed. According to gay lussac’s law of gaseous volumes, gases combine or are produced in a chemical reaction in a simple ration by volume, provided that all gases are the same temperature and pressure.

Mark the correct option a) The final withdrawal in saving account made through SB 7 only b) In joint B saving accounts at the ti c) Saving account of deceased depositor can not be transferred from one post office to another post officed) All the above

Description : Mark the correct option a) The final withdrawal in saving account made through SB 7 only b) In joint B saving accounts at the ti c) Saving account of deceased depositor can not be transferred from one post office to another post office d) All the above

Last Answer : d) All the above

In sub offices where there are no treasurer cash for payment of MOs will be given to the Postmen by the a) Sub Postmaster b) Joint custodian c) The MO clerk d) The head Postman

Description : In sub offices where there are no treasurer cash for payment of MOs will be given to the Postmen by the a) Sub Postmaster b) Joint custodian c) The MO clerk d) The head Postman

Last Answer : c) The MO clerk

There is a barrel with no lid and some **** in it. 'This barrel of **** is more than half full,' said Curly. 'No it's not,' says Mo. 'It's less than half full.' Without any measuring implements and without removing any **** from the barrel, how can they easily determine who is correct? -Riddles

Description : There is a barrel with no lid and some wine in it. 'This barrel of wine is more than half full,' said Curly. 'No it's not,' says Mo. 'It's less than half full.' Without any measuring implements and without removing any wine from the barrel, how can they easily determine who is correct? -Riddles

Last Answer : Tilt the barrel until the wine barely touches the lip of the barrel. If the bottom of the barrel is visible then it is less than half full. If the barrel bottom is still completely covered by the wine, then it is more than half full.

A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Description : A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Last Answer : a.9.24,9.24

The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec

Description : The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec

Last Answer : a. 12 rad/sec

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science

Description : An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science

Last Answer : Given r =42.250 km , T= 24 hour Linear velocity in circular motion is given by v=2πrT=2×3.14×42.25024=11.05km/hrv=2πrT=2×3.14×42.25024=11.05km/hr