In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam.
The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student
clears the exam.
A. 22,23,26
B. 21,39,40
C. 29,30,31
D. 0,15,22
by

1 Answer

Answer :

C. 29,30,31
by

Related questions

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence partitions? A. 15, 19 and 25 degrees B. 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Description : f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence ... 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Last Answer : A. 15, 19 and 25 degrees

One of the fields on a form contains a text box which accepts numeric values in the range of 18 to 25. Identify the invalid Equivalance class A. 17 B. 19 C. 24 D. 21

Description : One of the fields on a form contains a text box which accepts numeric values in the range of 18 to 25. Identify the invalid Equivalance class A. 17 B. 19 C. 24 D. 21

Last Answer : A. 17

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

Given the following specification, which of the following values for age are in the SAME equivalence partition? If you are less than 18, you are too young to be insured. Between 18 and 30 inclusive, you will receive a 20% discount. Anyone over 30 is not eligible for a discount. A. 17, 18, 19. B. 29, 30, 31. C. 18, 29, 30. D. 17, 29, 31.

Description : Given the following specification, which of the following values for age are in the SAME equivalence partition? If you are less than 18, you are too young to be insured. Between 18 and 30 inclusive, you will receive a 20% discount. Anyone ... 17, 18, 19. B. 29, 30, 31. C. 18, 29, 30. D. 17, 29, 31.

Last Answer : C. 18, 29, 30.

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

A thermometer measures temperature in whole degrees only. If the temperature falls below 18 degrees, the heating is switched off. It is switched on again when the temperature reaches 21 degrees. What are the best values in degrees to cover all equivalence partitions? A. 15,19 and 25. B. 17,18 and19. C. 18, 20 and22. D. 16, 26 and 32.

Description : A thermometer measures temperature in whole degrees only. If the temperature falls below 18 degrees, the heating is switched off. It is switched on again when the temperature reaches 21 degrees. What are the best values in degrees to ... and 25. B. 17,18 and19. C. 18, 20 and22. D. 16, 26 and 32.

Last Answer : A. 15,19 and 25.

In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8

Description : In an exam the average marks obtained by a candidate is 82 per paper. If he had obtained 32 marks more in science paper & 28more marks in social paper, then his average per paper is increased by 15 marks. Then how many papers when there in examination? A) 10 B) 6 C) 4 D) 8 

Last Answer : C)  let the number of paper be x total mark earned him = 82x then,, 82x+32+28= 97x 15x=60 x= 4 =number of subjects

Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5

Description : Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5 

Last Answer : Answer: B) Maximum total marks = 5 120 = 600 Marks scored by Saravanan = 90/100*600=540 Let the marks scored by him in the 5 subjects be 18x,14x,15x,21x and 22x respectively. 18x + 14x + 15x + 21x + ... A' grade i.e. 0.85 120 = 102 Therefore, he has got an A' grade in 3 subjects.

In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

Description : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

Last Answer : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25 ... the probability that he gets more than 18 marks?

One of the fields on a form contains a text box which accepts alpha numeric values. Identify the Valid Equivalence class A. BOOK B. Book C. Boo01k D. book

Description : One of the fields on a form contains a text box which accepts alpha numeric values. Identify the Valid Equivalence class A. BOOK B. Book C. Boo01k D. book

Last Answer : C. Boo01k

Which of the following is true about White and Black Box Testing Technique:- a) Equivalance partitioning, Decision Table and Control flow are White box Testing Techniques. b) Equivalence partitioning , Boundary Value Analysis , Data Flow are Black Box Testing Techniques. c) Equivalence partitioning , State Transition , Use Case Testing are black box Testing Techniques. d) Equivalence Partioning , State Transition , Use Case Testing and Decision Table are White Box Testing Techniques.

Description : Which of the following is true about White and Black Box Testing Technique:- a) Equivalance partitioning, Decision Table and Control flow are White box Testing Techniques. b) Equivalence partitioning ... , State Transition , Use Case Testing and Decision Table are White Box Testing Techniques.

Last Answer : c) Equivalence partitioning , State Transition , Use Case Testing are black box Testing Techniques.

A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Description :  A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Last Answer : Answer: B  Let x be the maximum marks,  Then (50% of x)+60 = (75% of x)-40  x/2 +60 = 3x/4 -20  60+20 = 3x/4 – x/ 2 X=320  Hence maximum marks = 320  Minimum pass marks = 320/2 + 60 = 220

the mode of the data 21, 26, 22, 29, 23, 29, 26, 29, 22, 23 is?

Description : the mode of the data 21, 26, 22, 29, 23, 29, 26, 29, 22, 23 is?

Last Answer : the mode of the data 21, 26, 22, 29, 23, 29, 26, 29, 22, 23 is?

In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam? A) 10 B) 12 C) 14 D) 20

Description : In a post graduate examination the marks obtained by a student is 75 per paper. If he had obtained 33 marks more in Evs paper & 27 more marks in science paper, then his average per paper is increased by 3 marks. Then how many papers were there in exam? A) 10 B) 12 C) 14 D) 20

Last Answer : Answer: D)  Let the number of paper be A. Then total marks earned him = 75A from questions, 75A + 33+ 27= 78A 3A = 60=> A=20 = number of subjects

On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Description : On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Description : A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

Students of two university appeared for a common test of maximum 60 marks. The average of their marks for university 1 & university 2 are 39 & 42 respectively. If the no of students of university 1 is twice the no of students of university 2. Then what is the average marks of all students of both the university? A) 40 B) 42 C) 26 D) 36

Description : Students of two university appeared for a common test of maximum 60 marks. The average of their marks for university 1 & university 2 are 39 & 42 respectively. If the no of students of university 1 is twice the no ... the average marks of all students of both the university? A) 40 B) 42 C) 26 D) 36

Last Answer : Answer: A) Let number of students of university2 be N and the no of students of university 1 be 2N the average of university1 and university 2 is 39 and 42 total marks of university 1 students and university 2 ... 78N and N*42 =42N average of both university,  =(78N+42N) /(N+2N) = 40 marks

The mean monthly temperature and rainfall of a station are given below: Month Temperature ºC Rainfall mm January 24 2 February 25 1 March 27 0 April 29 3 May 30 16 June 29 520 July 28 709 August 27 419 September 27 297 October 28 88 November 28 21 December 26 2 Yearly 27 2078 The above said data relate to which of following cities? [CDS 2004] (a) Ahmedabad (b) Bangalore (c) Mumbai (d) Vadodara

Description : The mean monthly temperature and rainfall of a station are given below: Month Temperature ºC Rainfall mm January 24 2 February 25 1 March 27 0 April 29 3 May 30 16 June 29 520 July 28 709 August 27 419 ... to which of following cities? [CDS 2004] (a) Ahmedabad (b) Bangalore (c) Mumbai (d) Vadodara

Last Answer : Ans: (c)

The number of amino acids in single chain polypeptide glucagons is (A) 21 (B) 29 (C) 31 (D) 39

Description : The number of amino acids in single chain polypeptide glucagons is (A) 21 (B) 29 (C) 31 (D) 39

Last Answer : Answer : B

Sufficient energy required to produce 3 ATP from 3 ADP and 3 pi is (A) –21,900 cal (B) 29,900 cal (C) 31,900 cal (D) 39,900 cal

Description : Sufficient energy required to produce 3 ATP from 3 ADP and 3 pi is (A) –21,900 cal (B) 29,900 cal (C) 31,900 cal (D) 39,900 cal

Last Answer : A

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

Bhuj earthquake occurred in (a) 23 January, 2001 (b) 26 January, 2001 (c) 31 January, 2001 (d) 29 January, 2001

Description : Bhuj earthquake occurred in (a) 23 January, 2001 (b) 26 January, 2001 (c) 31 January, 2001 (d) 29 January, 2001

Last Answer : (b) 26 January, 2001

In which range of body mass index (BMI) are patients considered to have increased risk for problems associated with poor nutritional status? a) Below 24 Additionally, higher mortality rates in hospitalized patients and community-dwelling elderly are associated with individuals who have low BMI. b) 25-29 Those who have a BMI of 25 to 29 are considered overweight. c) 30 to 39 Those who have BMI of 30-39 are considered obese. d) Over 40 Those who have BMI over 40 are considered extremely obese.

Description : In which range of body mass index (BMI) are patients considered to have increased risk for problems associated with poor nutritional status? a) Below 24 Additionally, higher mortality rates in hospitalized ... considered obese. d) Over 40 Those who have BMI over 40 are considered extremely obese.

Last Answer : a) Below 24 Additionally, higher mortality rates in hospitalized patients and community-dwelling elderly are associated with individuals who have low BMI.

The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Description : The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these

Last Answer : Answer – B (100) Explanation – Let the number of passed candidates be a Then total marks =>120 x 35 = 39 a + (120 – a) x 15 4200 = 39 a + 1800 – 15 a a = 100

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

A wholesaler sells printer cartridges. The minimum order quantity is 5. There is a 20% discount for orders of 100 or more printer cartridges. You have been asked to prepare test cases using various values for the number of printer cartridges ordered. Which of the following groups contain three test inputs that would be generated using Boundary Value Analysis? A. 5, 6, 20 B. 4, 5, 80C. 4, 5, 99 D. 1, 20, 100

Description : A wholesaler sells printer cartridges. The minimum order quantity is 5. There is a 20% discount for orders of 100 or more printer cartridges. You have been asked to prepare test cases using various values for the number of printer cartridges ... A. 5, 6, 20 B. 4, 5, 80C. 4, 5, 99 D. 1, 20, 100

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

A leaf spring consists of 3 extra full length leaves and 14 graduated length leaves. The maximum force that can act on the spring is 70kN and the distance between eyes of the spring is 1.2m. Width and thickness of the leaves are 100mm and 12mm respectively. If modulus of elasticity is 207000N/mm², calculate the initial nip. (a) 26.8mm (b) 24.9mm (c) 22.5mm (d)23.1mm

Description : A leaf spring consists of 3 extra full length leaves and 14 graduated length leaves. The maximum force that can act on the spring is 70kN and the distance between eyes of the spring is 1.2m. Width and thickness of the ... /mm², calculate the initial nip. (a) 26.8mm (b) 24.9mm (c) 22.5mm (d)23.1mm

Last Answer : b) 24.9mm

The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these

Description : The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these 

Last Answer :  Answer: A 3:2 = 30:20 30% boys = (30/100) × 30= 9 70% girls = (70/100) × 20 = 14 (9+14) : (50-23) = 23 : 27

The ratio of the ages of Bala and Babu is 13: 11. The total of their ages is 3.6decades. The proportion of their ages after 0.95decades will be [1 Decade = 10 years] a) 24:23 b) 12:11 c) 27:24 d) 29:26

Description : The ratio of the ages of Bala and Babu is 13: 11. The total of their ages is 3.6decades. The proportion of their ages after 0.95decades will be [1 Decade = 10 years] a) 24:23 b) 12:11 c) 27:24 d) 29:26

Last Answer : D Let, Bala’s age = 13A and babu’s age = 11A Then 13A + 11A = 36 A = 1.5 Bala’s age = 19.5years and Babu’s age = 16.5 years Proportion of their ages after 9.5 is = (19.5+9.5) : (16.5 + 9.5) = 29 : 26

The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Description : The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Last Answer : (b) 37.29 kN

In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

From a cask of milk containing 45 litres, 9 litres are drawn out and the cask is filled up with water.If the same process is repeated a second, then a third time, what will be the number of litres of milk left in the cask? a) 31.2 b) 20.9 c) 23.04 d) 12.39 e) 15.36

Description :  From a cask of milk containing 45 litres, 9 litres are drawn out and the cask is filled up with water.If the same process is repeated a second, then a third time, what will be the number of litres of milk left in the cask? a) 31.2 b) 20.9 c) 23.04 d) 12.39 e) 15.36

Last Answer : C where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is the number of processes. Initial quantity:45 Withdrawn quantity=9 number of times repeated=3 ... ] Quantity of milk left after the 3rd operation =45*(45-9)/45)^3 = 23.04 litres.

The average age of A and B is 20 years. If C were to replace A, the average would be 19 and id C were to replace B,the average would be 21 . The ages of A, B and C are (in years) (a) 22, 17,16 (b) 22, 18, 20 (c) 30, 18, 15 (d) 23, 17 ,15

Description : The average age of A and B is 20 years. If C were to replace A, the average would be 19 and id C were to replace B,the average would be 21 . The ages of A, B and C are (in years) (a) 22, 17,16 (b) 22, 18, 20 (c) 30, 18, 15 (d) 23, 17 ,15

Last Answer : 22, 18, 20 Hint : A + B = 2 x 20 C + B = 2 x 19 A + C = 2 x 21

Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39

Description : Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39

Last Answer : 1;  Total number of students

Your Western Electric 3A test set meter reading is -23 dBm at at test point level of -8 dB. This is ______ dBrnc0. A. 75 B. 29 C. 30 D. 31

Description : Your Western Electric 3A test set meter reading is -23 dBm at at test point level of -8 dB. This is ______ dBrnc0. A. 75 B. 29 C. 30 D. 31

Last Answer : A. 75

In a system designed to work out the tax to be paid: An employee has £4000 of salary tax free. The next £1500 is taxed at 10%. The next £28000 after that is taxed at 22%. Any further amount is taxed at 40%. To the nearest whole pound, which of these is a valid Boundary Value Analysis test case? A. £28000. B. £33501. C. £32001. D. £1500

Description : In a system designed to work out the tax to be paid: An employee has £4000 of salary tax free. The next £1500 is taxed at 10%. The next £28000 after that is taxed at 22%. Any further amount is taxed ... of these is a valid Boundary Value Analysis test case? A. £28000. B. £33501. C. £32001. D. £1500

Last Answer : B. £33501.

Test cases need to be written for A. Valid and unexpected conditions B. Valid and expected conditions C. Both A and B D. None of the above

Description : Test cases need to be written for A. Valid and unexpected conditions B. Valid and expected conditions C. Both A and B D. None of the above

Last Answer : C. Both A and B

In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Description : In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Last Answer : Answer: A Difference = 672-126 = 546 According to the question, 70% of total aggregate = 546 Total aggregate marks = 546 × 100 /70  = 54600/70  = 780

An input field takes the year of birth between 1900 and 2004 The boundary values for testing this field are A. 0,1900,2004,2005 B. 1900, 2004 C. 1899,1900,2004,2005 D. 1899, 1900, 1901,2003,2004,2005

Description : An input field takes the year of birth between 1900 and 2004 The boundary values for testing this field are A. 0,1900,2004,2005 B. 1900, 2004 C. 1899,1900,2004,2005 D. 1899, 1900, 1901,2003,2004,2005

Last Answer : C. 1899,1900,2004,2005

vIf the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Description : If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Last Answer : 2) 39 : 28: 20

The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20

Description : The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20 

Last Answer : A) According to the question 40*21=23*8+26*10+18*14+8×X 840=184+260+252+8x 8x=144  X=144/8=18 runs

The BOA shall submit to the PRC the ratings obtained by each candidate within how many calendar days after the examination? a. 5 days b. 10 days c. 15 days d. 30 days

Description : The BOA shall submit to the PRC the ratings obtained by each candidate within how many calendar days after the examination? a. 5 days b. 10 days c. 15 days d. 30 days

Last Answer : 10 days

On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29

In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200

Description : In an competitive examination, the average was found to be 72 marks. After detecting the errors the marks of 94 candidates had to be charged from 90 to 66 each, and the average is reduced to 64 marks. Find the total number of candidates who took the exam. A) 282 B) 382 C) 828 D) 200 

Last Answer :  A)  let the number of candidates be A total marks of candidates = 72A after detecting error the change of marks for one candidate = 90 - 66 = 24 marks change of marks for 94 candidates = 94*24 = ... after detecting error of N candidates = 64A then, 72A- 2256= 64A , 8A=2256 A=282

Which of these numbers prime 20 or 21 or 22 or 23 or 24?

Description : Which of these numbers prime 20 or 21 or 22 or 23 or 24?

Last Answer : You can work this out, Prime numbers can only be divided bythemselves or 1. Therefore as 20 can be divided by 2 it it notprime. The same is true for 22 and 24. Thus the prime must beeither 21 or 23.See if either of these numbers can be divided by 7, if it canthen the prime must be the other number.

How can you make 24 using the numbers 21 22 23 and 20?

Description : How can you make 24 using the numbers 21 22 23 and 20?

Last Answer : (23-21) x 22-20

The banks will be licensed as payments banks under ______ of the Banking Regulation Act, 1949. A. Section 21 B. Section 22 C. Section 23 D. Section 24 E. None of the Above

Description : The banks will be licensed as payments banks under ______ of the Banking Regulation Act, 1949. A. Section 21 B. Section 22 C. Section 23 D. Section 24 E. None of the Above

Last Answer : B. Section 22 Explanation: The payment banks will be licensed as payments banks under Section 22 of the Banking Regulation Act, 1949 and will be registered as public limited company under the Companies Act, 2013.

The small finance banks will be licensed under ______ of the Banking Regulation Act, 1949. A. Section 21 B. Section 22 C. Section 23 D. Section 24 E. None of the Above

Description : The small finance banks will be licensed under ______ of the Banking Regulation Act, 1949. A. Section 21 B. Section 22 C. Section 23 D. Section 24 E. None of the Above

Last Answer : B. Section 22 Explanation: The small finance banks will be licensed under Section 22 of the Banking Regulation Act, 1949.