x mmol of `KMnO_(4)` react completely with y mmol of `MnSO_(4)` in presence of fluoride ions to give `MnF_(4)` quantitatively. Then :

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x mmol of `KMnO_(4)` react completely with y mmol of `MnSO_(4)` in presence of fluoride ions to give `MnF_(4)` ... =y B. 4x=y C. `xgty` D. `x lt y`

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