The volume of water which must be added to `0.4 dm^(3)` of 0.25 N oxalic acid in order to make it exactly decinormal is :

The volume of water which must be added to `0.4 dm^(3)` of 0.25 N oxalic acid in order to make it exactly decinormal is :
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The volume of water which must be added to `0.4 dm^(3)` of 0.25 N oxalic acid in order to make it exactly decinormal ... `0.6 dm^(3)` D. `0.8 dm^(3)`
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