Description : Can you find the axis of symmetry of the graph of y = arctan(x) + arctan(6 - x)
Last Answer : answer:We can start by finding the vertex. So when does dy/dx=0? dy/dx = 1/(1+x^2) - 1/(1+(6-x)^2) = 0. Note that when x=3, this equation is true. So, the line of ... This graph is parabolic, and therefore has only one vertex. 2) This graph is symmetric. This could also be proved using derivatives.