Is 17/20 0.68 or 0.85?

Is 17/20 0.68 or 0.85?
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Nevermind I figured out it is 0.85
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According to Whitney's theory, depth of stress block for a balanced section of a concrete beam is limited to (A) 0.43 d (B) 0.537 d (C) 0.68 d (D) 0.85 d Where d is effective depth of beam

Description : According to Whitney's theory, depth of stress block for a balanced section of a concrete beam is limited to (A) 0.43 d (B) 0.537 d (C) 0.68 d (D) 0.85 d Where d is effective depth of beam

Last Answer : Answer: Option B

According to ISI recommendations, the maximum depth of stress block for balanced section of a beam of effective depth d is (A) 0.43 d (B) 0.55 d (C) 0.68 d (D) 0.85 d

Description : According to ISI recommendations, the maximum depth of stress block for balanced section of a beam of effective depth d is (A) 0.43 d (B) 0.55 d (C) 0.68 d (D) 0.85 d

Last Answer : Answer: Option A

In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98

Description : In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98 

Last Answer : Answer: A  Let the total number of eggs in the basket be x  20 % of the eggs are rotten, and eggs in good condition are 68  Therefore, according to the question,  80% of x = 68  80/100 × x = 68  x = (68 × 100)/80  x = 6800 / 80  x = 85  Therefore, total number of eggs in the basket is 85.

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Description : A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

What is the actual length in feet of a one-quarter wavelength of a coax with a velocity factor of 0.68 to 30 MHz? A. 19.26 B. 5.6 C. 17.82 D. 16.97

Description : What is the actual length in feet of a one-quarter wavelength of a coax with a velocity factor of 0.68 to 30 MHz? A. 19.26 B. 5.6 C. 17.82 D. 16.97

Last Answer : B. 5.6

A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm2 , the area of steel required, is (A) 14 cm(B) 15 cm2(C) 16 cm2(D) 17 cm

Description : A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm2 ... area of steel required, is (A) 14 cm (B) 15 cm2 (C) 16 cm2 (D) 17 cm

Last Answer : Answer: Option C

If 68 is divided into two parts such that one part is one-third of the other, then the smallest part is 17.

Description : If 68 is divided into two parts such that one part is one-third of the other, then the smallest part is 17.

Last Answer : If 68 is divided into two parts such that one part is one-third of the other, then the smallest part is 17.

How many times can 17 go into 68 without going over?

Description : How many times can 17 go into 68 without going over?

Last Answer : four17 + 17 = 3434 + 34 = 68

How many times can 17 go into 68 without going over?

Description : How many times can 17 go into 68 without going over?

Last Answer : four17 + 17 = 3434 + 34 = 68

In 2003, a total of 68 male candidates did qualify. What is the respective ratio between males and females who had qualified in 2003? A. 11:25 B. 19:25 C. 17:25 D. 25:13

Description : In 2003, a total of 68 male candidates did qualify. What is the respective ratio between males and females who had qualified in 2003? A. 11:25 B. 19:25 C. 17:25 D. 25:13

Last Answer : C. 17:25

8, 17, 38, 85, 186, ? a) 318 b) 354 c) 397 d) 408 e) 427

Description : 8, 17, 38, 85, 186, ? a) 318 b) 354 c) 397 d) 408 e) 427

Last Answer : Answer: c)

In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Last Answer : d) 85

A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings? A.30 B.37 C.40 D.45 E.None of these

Description : A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings? A.30 B.37 C.40 D.45 E.None of these

Last Answer : Answer – B (37) Explanation – Let the average after 16th innings be a, then total score after 17th innings => 16a+85 = 17 (a+3) a = 85-51 = 34 Average after 17 innings = a + 3 = 34 + 3 = 37

What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Description : What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2

Last Answer : c. 78.94 mts/sec2

The serum estradiol level in women during 1–10 days of menstrual cycle is (A) 0–10 pg/ml (B) 12–20 pg/ml (C) 24–68 pg/ml (D) 80–100 pg/ml

Description : The serum estradiol level in women during 1–10 days of menstrual cycle is (A) 0–10 pg/ml (B) 12–20 pg/ml (C) 24–68 pg/ml (D) 80–100 pg/ml

Last Answer : Answer : C

The drainage area of a town is 12 hectares. Its 40% area is hard pavement ( K = 0.85), the 40% area is unpaved streets (K = 0.20) and the remaining is wooded areas (K = 0.15). Assuming the time of concentration for the areas as 30 minutes and using the formula Ps = 900/(t + 60) the maximum run off is A. 0.10 cumec B. 0.12 cumec C. 0.15 cumec D. 0.20 cumec

Description : The drainage area of a town is 12 hectares. Its 40% area is hard pavement ( K = 0.85), the 40% area is unpaved streets (K = 0.20) and the remaining is wooded areas (K = 0.15). Assuming the time of concentration ... 60) the maximum run off is A. 0.10 cumec B. 0.12 cumec C. 0.15 cumec D. 0.20 cumec

Last Answer : ANS: C

What is the approximate voltage per cell produced by the nickel-iron (Edison) battery? A. 0.85 volts B. 1.35 volts C. 2.20 volts D. 6.05 volts

Description : What is the approximate voltage per cell produced by the nickel-iron (Edison) battery? A. 0.85 volts B. 1.35 volts C. 2.20 volts D. 6.05 volts

Last Answer : Answer: B

What is the refractive index of an ionospheric layer with 100x105 free electrons per m3 ? Assume frequency to be at 20 MHz. A. 0.99 B. 0.15 C. 0.78 D. 0.85

Description : What is the refractive index of an ionospheric layer with 100x105 free electrons per m3 ? Assume frequency to be at 20 MHz. A. 0.99 B. 0.15 C. 0.78 D. 0.85

Last Answer : A. 0.99

What is the bond length of a carbon-carbon double bond? (a) 1.20 Å (b) 1.34 Å (c) 1.54 Å (d) 1.68 Å

Description : What is the bond length of a carbon-carbon double bond? (a) 1.20 Å (b) 1.34 Å (c) 1.54 Å (d) 1.68 Å

Last Answer : 1.34 Å

A rise in temperature of 20 Kelvin degrees is equal to a rise of: w) 20 degrees Celsius x) 36 degrees Celsius y) 68 degrees Celsius z) 293 degrees Celsius

Description : A rise in temperature of 20 Kelvin degrees is equal to a rise of: w) 20 degrees Celsius x) 36 degrees Celsius y) 68 degrees Celsius z) 293 degrees Celsius

Last Answer : ANSWER: W -- 20 DEGREES CELSIUS

A train crosses a platform and a scooter standing on the platform in 20 seconds, 12seconds respectively.What is the length of the platform if the speed of the train is 25 km/hr? A) 55.8 m B) 75m C) 124m D) 68.5m

Description : A train crosses a platform and a scooter standing on the platform in 20 seconds, 12seconds respectively.What is the length of the platform if the speed of the train is 25 km/hr? A) 55.8 m B) 75m C) 124m D) 68.5m 

Last Answer : Answer: A Explanation: Given that, The speed of the train = 25km/hr = 25x 5/18 m/sec = 125/18 m/sec The train crosses a scooter in 12 seconds. Then, Length of the train = 125/18*12= 83.33 Now, ... 18(X +83.3)= 2500 18X=1000.6 X=55.58 m Hence the platform is 55.58 m long.

What is the force on an object that goes from 35 ms to 85 ms in 20 second and has a mass of 148 kg?

Description : What is the force on an object that goes from 35 ms to 85 ms in 20 second and has a mass of 148 kg?

Last Answer : Feel Free to Answer

What Barclay's bank has sort code 20-85-59?

Description : What Barclay's bank has sort code 20-85-59?

Last Answer : Need answer

The normal values for creatinine clearance varies from (A) 20–40 ml/min (B) 40–60 ml/min (C) 70–85 ml/min (D) 95–105 ml/min

Description : The normal values for creatinine clearance varies from (A) 20–40 ml/min (B) 40–60 ml/min (C) 70–85 ml/min (D) 95–105 ml/min

Last Answer : Answer : D

Cellulose content in bamboo fibre is about __________ percent. (A) 10 (B) 20 (C) 50 (D) 85

Description : Cellulose content in bamboo fibre is about __________ percent. (A) 10 (B) 20 (C) 50 (D) 85

Last Answer : (C) 50

P2O5 content in triple superphosphate is about __________ percent. (A) 42-50 (B) 15-20 (C) 85-90 (D) 70-75

Description : P2O5 content in triple superphosphate is about __________ percent. (A) 42-50 (B) 15-20 (C) 85-90 (D) 70-75

Last Answer : (A) 42-50

P2O5 content in superphosphate is about __________ percent. (A) 30-35 (B) 15-20 (C) 65-70 (D) 85-90

Description : P2O5 content in superphosphate is about __________ percent. (A) 30-35 (B) 15-20 (C) 65-70 (D) 85-90

Last Answer : (B) 15-20

Average human body contains about __________ percent water by weight. (A) 20 (B) 40 (C) 70 (D) 85

Description : Average human body contains about __________ percent water by weight. (A) 20 (B) 40 (C) 70 (D) 85

Last Answer : (C) 70

Cellulose percentage in bamboo fibre is about (A) 10 (B) 20 (C) 50 (D) 85

Description : Cellulose percentage in bamboo fibre is about (A) 10 (B) 20 (C) 50 (D) 85

Last Answer : (C) 50

285. Sucrose content in the raw juice extracted from sugar cane is about __________ percent(A) 1 - 2 (B) 15 - 20 (C) 50 - 60 (D) 80 - 85

Description : . Sucrose content in the raw juice extracted from sugar cane is about __________ percent (B) 15 - 20 (A) 1 - 2285 (C) 50 - 60 (D) 80 - 85

Last Answer : (B) 15 - 20

Iron content in Indian iron ore is about __________ percent. (A) 80-85 (B) 60-65 (C) 40-45 (D) 20-25

Description : Iron content in Indian iron ore is about __________ percent. (A) 80-85 (B) 60-65 (C) 40-45 (D) 20-25

Last Answer : (B) 60-65

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

The batting average for 20 innings of a cricketer is 25 runs. His highest score exceeds his lowest score by 86 runs. If these two innings are excluded, the average of the remaining 18 innings is 22runs. Find out the highest score of the player. A) 85 B) 90 C) 95 D) 100

Description : The batting average for 20 innings of a cricketer is 25 runs. His highest score exceeds his lowest score by 86 runs. If these two innings are excluded, the average of the remaining 18 innings is 22runs. Find out the highest score of the player. A) 85 B) 90 C) 95 D) 100

Last Answer : C) Total runs scored by the player in 20 innings = 20*25 Total runs scored by the player in 18 innings after excluding two innings = 18 22 Sum of the scores of the excluded innings = 20 25 - 18 22 = 104 Given that ... Now x + 86 + x = 104 => 2x = 18 then x = 9 Highest score = 9+ 86 = 95

Using the following thermochemical data. `C(S)+O_(2)(g)rarr CO_(2)(g), Delta H=94.0` Kcal `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l), Delta H=-68.0` Kcal `C

Description : Using the following thermochemical data. `C(S)+O_(2)(g)rarr CO_(2)(g), Delta H=94.0` Kcal `H_(2)(g)+1//2O_(2)(g)rarr H_(2)O(l), Delta H=-68.0` Kcal `C

Last Answer : Using the following thermochemical data. `C(S)+O_(2)(g)rarr CO_(2)(g), Delta H=94.0` Kcal `H_(2)(g)+1// ... .0` Kcal C. `-114.0` Kcal D. `+114.0` Kcal

The heat of combustion of `CH_(4(g)), C_((g))` and `H_(2(g))` at `25^(@)C` are `-212.4` K cal, -94.0 K cal and -68.4 K cal respectively, the heat of f

Description : The heat of combustion of `CH_(4(g)), C_((g))` and `H_(2(g))` at `25^(@)C` are `-212.4` K cal, -94.0 K cal and -68.4 K cal respectively, the heat of f

Last Answer : The heat of combustion of `CH_(4(g)), C_((g))` and `H_(2(g))` at `25^(@)C` are `-212.4` K cal, -94.0 ... .4` K cal C. `-375.2` K cal D. `+212.8` K cal

How do you write 0.68 in words?

Description : How do you write 0.68 in words?

Last Answer : sixty-eight hundredths

Is 0.75 equivalent as 68?

Description : Is 0.75 equivalent as 68?

Last Answer : If you mean 6/8 then it is equivalent to 0.75

The serum estradiol level in men is (A) 0–5 pg/ml (B) 5–10 pg/ml (C) 24–68 pg/ml (D) 40–60 pg/ml

Description : The serum estradiol level in men is (A) 0–5 pg/ml (B) 5–10 pg/ml (C) 24–68 pg/ml (D) 40–60 pg/ml

Last Answer : Answer : C

The width of a rectangular sewer is twice its depth while discharging 1.5 m/sec. The width of the sewer is A. 0.68 m B. 0.88 m C. 1.36 m D. 1.76 m

Description : The width of a rectangular sewer is twice its depth while discharging 1.5 m/sec. The width of the sewer is A. 0.68 m B. 0.88 m C. 1.36 m D. 1.76 m

Last Answer : ANS: C

What is the velocity factor of coaxial cable with a characteristic impedance of 50Ω and capacitance of 30pF/ft and inductance of 75 nH/ft? A. 0.58 B.0.68 C. 0.98 D. 0.81

Description : What is the velocity factor of coaxial cable with a characteristic impedance of 50Ω and capacitance of 30pF/ft and inductance of 75 nH/ft? A. 0.58 B.0.68 C. 0.98 D. 0.81

Last Answer : B.0.68

A sand mixture was screened through a standard 10-mesh screen. The mass fraction of the oversize material in feed, overflow and underflow were found to be 0.38, 0.79 and 0.22 respectively. The screen effectiveness based on the oversize is (A) 0.50 (B) 0.58 (C) 0.68 (D) 0.62

Description : A sand mixture was screened through a standard 10-mesh screen. The mass fraction of the oversize material in feed, overflow and underflow were found to be 0.38, 0.79 and 0.22 respectively. The screen effectiveness based on the oversize is (A) 0.50 (B) 0.58 (C) 0.68 (D) 0.62

Last Answer : (A) 0.50

The thermal radiative flux from a surface of emissivity = 0.4 is 22.68 kW/m2 . The approximate surface temperature (K) is (Stefan-Boltzmann constant = 5.67 × 10 -8 W/m2 .K4 )(A) 1000(B) 727(C) 800(D) 1200

Description : The thermal radiative flux from a surface of emissivity = 0.4 is 22.68 kW/m2 . The approximate surface temperature (K) is (Stefan-Boltzmann constant = 5.67 × 10 -8 W/m2 .K4 ) (A) 1000 (B) 727 (C) 800 (D) 1200

Last Answer : (A) 1000

Find the reflection coefficient of the wave with SWR of 3.5. a) 0.55 b) 0.23 c) 0.48 d) 0.68

Description : Find the reflection coefficient of the wave with SWR of 3.5. a) 0.55 b) 0.23 c) 0.48 d) 0.68

Last Answer : a) 0.55

If voids ratio is 0.67, water content is 0.188 and specific gravity is 2.68, the degree of saturation of the soil, is (A) 25 % (B) 40 % (C) 60 % (D) 75 %

Description : If voids ratio is 0.67, water content is 0.188 and specific gravity is 2.68, the degree of saturation of the soil, is (A) 25 % (B) 40 % (C) 60 % (D) 75 %

Last Answer : Answer: Option D

Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Description : Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Last Answer : -364 BTU/lbm

A computer program selects an integer in the set {k : 1 ≤ k ≤ 10,00,000} at random and prints out the result. This process is repeated 1 million times. What is the probability that the value k = 1 appears in the printout atleast once ? (A) 0.5 (B) 0.704 (C) 0.632121 (D) 0.68

Description : A computer program selects an integer in the set {k : 1 ≤ k ≤ 10,00,000} at random and prints out the result. This process is repeated 1 million times. What is the probability that the value k = 1 appears in the printout atleast once ? (A) 0.5 (B) 0.704 (C) 0.632121 (D) 0.68

Last Answer : (C) 0.632121

A three-phase synchronous motor has a terminal voltage of 460 V and a terminal current of 120 A at a power factor of 0.95 lagging, synchronous reactance of 1.68 ohm and the field current is 47 A. The field to armature mutual inductance of the synchronous motor is _____________.

Description : A three-phase synchronous motor has a terminal voltage of 460 V and a terminal current of 120 A at a power factor of 0.95 lagging, synchronous reactance of 1.68 ohm and the field current is 47 A. The field to armature mutual ... _____________.      (a). 20mH   (b). 16mH   (c). 24mH   (d). 22mH

Last Answer : 22

An overhead transmission line has a span of 260 m. The weight of the conductor is 0.68 kg/m. The maximum

Description : An overhead transmission line has a span of 260 m. The weight of the conductor is 0.68 kg/m. The maximum allowable tension in the line is 1550 kg. Maximum sag of the line should be (a) 5.8 m (b) 4.6 m (c) 2.7 m (d) 3.7 m 

Last Answer : Maximum sag = (l^2)/8c So c = T/W c = 1550/0.68 c= 2279.4 Now Maximum sag = (260^2)/8(2279.4) = 3.7 (d)

If a circuit has resistances of 5, 10, and 20 ohms connected in parallel, what is the combined resistance of the circuit? A. 1.5 ohms B. 2.9 ohms C. 17.5 ohms D. 35.0 ohms

Description : If a circuit has resistances of 5, 10, and 20 ohms connected in parallel, what is the combined resistance of the circuit? A. 1.5 ohms B. 2.9 ohms C. 17.5 ohms D. 35.0 ohms

Last Answer : Answer: B

What force is necessary to hold a weight of 100 kg suspended on a rope wrapped 3 times around a post ( a.0.35 b.0.8 c.1.46 d.2.85 e.107 dynes

Description : What force is necessary to hold a weight of 100 kg suspended on a rope wrapped 3 times around a post ( a.0.35 b.0.8 c.1.46 d.2.85 e.107 dynes

Last Answer : a. 0.35