Which of these is the solution to the system of equations?

Which of these is the solution to the system of equations?
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( 3,10)
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If the system of equations `x-k y-z=0, k x-y-z=0,x+y-z=0` has a nonzero solution, then the possible value of `k` are `-1,2` b. `1,2` c. `0,1` d. `-1,1

Description : If the system of equations `x-k y-z=0, k x-y-z=0,x+y-z=0` has a nonzero solution, then the possible value of `k` are `-1,2` b. `1,2` c. `0,1` d. `-1,1

Last Answer : If the system of equations `x-k y-z=0, k x-y-z=0,x+y-z=0` has a nonzero solution, then the possible value of `k` ... 1,2` B. `1,2` C. `0,1` D. `-1,1`

The system of equations `alphax+y+z=alpha-1, x+alphay+z=alpha-1, x+y+alphaz=alpha-1` has no solution if alpha is (A) 1 (B) not -2 (C) either -2 or 1 (

Description : The system of equations `alphax+y+z=alpha-1, x+alphay+z=alpha-1, x+y+alphaz=alpha-1` has no solution if alpha is (A) 1 (B) not -2 (C) either -2 or 1 (

Last Answer : The system of equations `alphax+y+z=alpha-1, x+alphay+z=alpha-1, x+y+alphaz=alpha-1` has no solution if alpha is ... 2 B. 1 C. `-2` D. Either - 2 or 1

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Assertion (A) : The value of k for which the system of linear equations kx+2y+1=0 and 6x+4y-5=0 has a unique solution is 3. Reason (R):The system of linear equations a1x + b1y + c1= 0 and a2x + b2y + c2 = 0 has a unique solution if (a) Both A and R are correct; R is the correct explanation of A. (b) Both A and R are correct; R is not the correct explanation of A. (c) A is correct; R is incorrect. (d) R is correct; A is incorrect.

Description : Assertion (A) : The value of k for which the system of linear equations kx+2y+1=0 and 6x+4y-5=0 has a unique solution is 3. Reason (R):The system of linear equations a1x + b1y + c1= 0 and a2x + ... not the correct explanation of A. (c) A is correct; R is incorrect. (d) R is correct; A is incorrect.

Last Answer : (d) R is correct; A is incorrect.

The solution of the following system of linear equations in two variables is: 55x + 67y = 311; 67x + 55y = 299 (a) (2, 3) (b) (3, 2) (c) (-2,3) (d) (3, -2)

Description : The solution of the following system of linear equations in two variables is: 55x + 67y = 311; 67x + 55y = 299 (a) (2, 3) (b) (3, 2) (c) (-2,3) (d) (3, -2)

Last Answer : (b) (3, 2)

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Check whetherx =2 and y = 1 is a solution of the following equations or not. -Maths 9th

Description : Check whetherx =2 and y = 1 is a solution of the following equations or not. -Maths 9th

Last Answer : Given, x = 2 and y = 1 (i) Given, linear equation is 2x + 5y = 9. On putting x = 2 and y= 1 in LHS, we get LHS = 2x + 5y =2(2) + 5(1) = 4 + 5 = 9 = RHS So, x = 2 and y=1 is a solution of given ... + 3 (1) = 5 + 3 = 8 ≠ 14 ⇒ LHS ≠ RHS So, x = 2 and y = 1 is not a solution of given equation.

In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

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Last Answer : (i) If we substitute x = 4, we get L.H.S = x + 4 = 4 + 4 = 8 and R.H.S = 2x = 2 x 4 = 8 ∴ L.H.S = R.H.S. Hence, 4 is a solution of x + 4 = 2x. (ii) If we substitute y = 3, we get L.H.S = y - 7 = 3 - ... S = 2u + 7 = 2(5) + 7 = 10 + 7 = 17 ∴ L.H.S = R.H.S. Hence , 5 is a solution of 3u + 2 = 2u + 7

In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

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Last Answer : (i) f we substitute x = √2, we get L.H.S. = 2x - 3 = 2(√2) - 3 = 2√2 - 3 and R.H.S = x / 2 - 2 = √2 / 2 - 2 ∴ L.H.S. ≠ R.H.S . Hence, √2 is not a solution of 2x - 3 = x / 2 - 2 (ii) If we substitute ... = 7 ∴ L.H.S. ≠ R.H.S . Hence , -1 is not a solution of 24 - 3 (u - 2) = u + 8

Check whetherx =2 and y = 1 is a solution of the following equations or not. -Maths 9th

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Last Answer : Given, x = 2 and y = 1 (i) Given, linear equation is 2x + 5y = 9. On putting x = 2 and y= 1 in LHS, we get LHS = 2x + 5y =2(2) + 5(1) = 4 + 5 = 9 = RHS So, x = 2 and y=1 is a solution of given ... + 3 (1) = 5 + 3 = 8 ≠ 14 ⇒ LHS ≠ RHS So, x = 2 and y = 1 is not a solution of given equation.

In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

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Last Answer : (i) If we substitute x = 4, we get L.H.S = x + 4 = 4 + 4 = 8 and R.H.S = 2x = 2 x 4 = 8 ∴ L.H.S = R.H.S. Hence, 4 is a solution of x + 4 = 2x. (ii) If we substitute y = 3, we get L.H.S = y - 7 = 3 - ... S = 2u + 7 = 2(5) + 7 = 10 + 7 = 17 ∴ L.H.S = R.H.S. Hence , 5 is a solution of 3u + 2 = 2u + 7

In the following equations , verify whether the given value of the variable is a solution of the equation : -Maths 9th

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Last Answer : (i) f we substitute x = √2, we get L.H.S. = 2x - 3 = 2(√2) - 3 = 2√2 - 3 and R.H.S = x / 2 - 2 = √2 / 2 - 2 ∴ L.H.S. ≠ R.H.S . Hence, √2 is not a solution of 2x - 3 = x / 2 - 2 (ii) If we substitute ... = 7 ∴ L.H.S. ≠ R.H.S . Hence , -1 is not a solution of 24 - 3 (u - 2) = u + 8

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How many real solutions (intersections) will there be in this system of two equations 5x(2) plus y 2x(2) plus y?

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If = = in the system of equations a 1 x + b 1 y + c 1 = 0 and a 2 x + b 2 y + c 2 = 0 Statement 1 : This is the condition for inconsistent equations Statement 2 : There exists infinitely many solutions Statement 3 : The equations satisfying the condition are parallel Which of the above statements are true ? e) S1 only f) S1 and S2 g) S1 and S3 h) S2 only Answer: (d) S2 o

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