# solve the system of equations 2r + 2s = 50 and 2r – s = 17. -General Knowledge

solve the system of equations 2r + 2s = 50 and 2r – s = 17. -General Knowledge

Subtract eq1 from eq2: (2r – s = 17) - (2r + 2s = 50): -3s = -33 s = -33/-3 s = 11 Solve for r: 2r + 2(11) = 50 2r = 22 = 50 2r = 50 - 22 2r = 28 r = 28/2 r = 14 set: r = 14, s = 112r + 2s = 50 and 2r – s = 17

## Related questions

Description : A network has 10 nodes and 17 branches. The number of independent mesh equations required to solve the network is   (a) 7 (b) 8 (c) 10 (d) 45

Last Answer : Number of mesh equations required = b-n+1 b - number of branches n- number of nodes Given b= 17, n= 10 =17-10+1 =8 8 equations required to sove the given network.

Description : `2S"(fused)" +Cl_(2) rarr A` `A+H_(2)O rarr HCl+B+C` A, B and C in the above equations are:

Last Answer : `2S"(fused)" +Cl_(2) rarr A` `A+H_(2)O rarr HCl+B+C` A, B and C in the above equations are: A. `S_(2)Cl_ ... (2-)` D. `S_(2)Cl_(2),SO_(2),H_(2)SO_(4)`

Description : The safe length L of a valley curve for night travel is (A) 2S - (1.50 + 0.035 S)/N if L < S (B) NS²/(1.50 + 0.035 S) if L > S (C) Neither (a) nor (b) (D) Both (a) and (b

Description : How do I "solve" this system of equations when there is random variability involved?

Last Answer : If X, Y and Z are known, providing the values would probably help get approximate answers.

Description : What are some fast ways to solve a system of 3 linear equations with this special form?

Last Answer : Perhaps an algebraic matrix ?

Description : Solve the system of equations using Numpy -Web-Development

Description : Use the graph to solve the system of linear equations x - y=4 4x + y=1?

Last Answer : x=4+y4x+y=1 = 4(4+y)+y=116+4y+y=116+5y=15y=-15y=-3x=4+y = x=4+(-3)x=1

Description : Solve the system of homogeneous equations using echelon form

Last Answer : Solve the system of homogeneous equations using echelon form 4x+2y+z+3w=0 6x+3y+4z+7w=0 2x+y+w=0

Description : If you're asked to solve a system of equations in which there is no linear equation to start with you can sometimes begin by isolating and substituting a variable that is squared in both equations?

Description : Is there a general way to solve equations involving both a multiple of x and a power of x?

Description : How can I solve the values of the equations?

Last Answer : I solve it by myself！

Description : Can some one tell me how to solve any of these precal equations?

Last Answer : answer:1. Find the value of the side of a square whose diagonal is known as a'. ([a times (square root of 2)]/2) think about the square as 2 triangles, the diagonal is the hypotenuse. a^2+b^ ... what does everything stand for; does s [equal] distance and t [equal] velocity, or does t [equal] time?

Description : Solve the following equations for x and y. log100 |x+y| = 1/2, -Maths 9th

Last Answer : (b) \(\bigg(rac{10}{3},rac{20}{3}\bigg)\). (+ 10, 20) log100 |x+y| = \(rac{1}{2}\) ⇒ |x + y| = 100\(^{rac{1}{2}}\)⇒ |x + y| = 10 as (-10 is inadmissible) ...(i) log10y - log10| x | = log1004⇒ log10 ... x < 0, then x = 10.∴ If x = \(rac{10}{3}\), then y = \(rac{20}{3}\) and if x = 10, y = 20.

Description : Solve these following equations: (i) 3x + 3 = 15 (ii) 2y + 7 =19 -Maths 9th

Description : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1)` `(iii) (log_(10)(100x))^(2)+(log_(10)(10

Last Answer : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1 ... 1)` `(v)5^(2x)=3^(2x)+2.5^(x)+2.3^(x)`

Description : Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`

Last Answer : Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`

Description : Solve the following equations (where `[*]` denotes greatest integer function and `{*}` represent fractional part function and sgn represents signum fu

Last Answer : Solve the following equations (where `[*]` denotes greatest integer function and `{*}` represent fractional part function ... 2[x]=3x`, `0 le x le 2`

Description : Solve the following equations (where `[*]` dentoes greatest integer function and `{*}` represent fractional part function) `(i) 2[x]+3[x]=4x-1` `(ii)

Last Answer : Solve the following equations (where `[*]` dentoes greatest integer function and `{*}` represent fractional part function) ... }` `(iii) [x]+2{-x}=3x`

Description : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

Last Answer : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

Description : How do you solve equations and inequalities examples?

Last Answer : First, you must learn to solve equations, since inequalitieshave some additional complications.Solving equations may requiremany different methods; but the main method for simple equations isto do the same manipulation on ... you can divide bothsides by 2, with the result:x = 5That's the solution.

Description : The number of independent equations to solve a network is equal to?

Last Answer : The number of independent equations to solve a network is equal to the number of chords.

Description : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

Last Answer : If `(2p+5q)/(2r+5s) = (4p-3q)/(4r-3s)`, then find the relation between p, q, r and s.

Description : The loop transfer of a system is G(s) H(s) = 5/(s+1) (2s+1)(3s+1) which has the phase crossover frequency fc = 0.16 Hz. The gain margin (dB) of the system is  (a) 6 (b) 4 (c) 2 (d) 0

Last Answer : The loop transfer of a system is G(s) H(s) = 5/(s+1) (2s+1)(3s+1) which has the phase crossover frequency fc = 0.16 Hz. The gain margin (dB) of the system is 6

Description : If x + y + z = 2s, then what is (s – x)^3 + (s – y)^3 + 3(s – x) (s – y)z equal to : -Maths 9th

Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0

Description : What is the perpendicular bisector equation of a line with endpoints of s 2s and 3s 8s?

Last Answer : Endpoints: (s, 2s) and (3s, 8s)Midpoint: (2s, 5s)Slope of line: 3/1Slope of perpendicular line: -1/3Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y =-x+17sPerpendicular bisector equation in its general form: x+3y-17s =0

Description : Pick out the wrong statement. (A) The equivalent stiffness of two springs (of equal stiffness 'S') in series is S/2 while in parallel is 2S (B) For a helical spring, deflection is ... is less than the buckling load (D) Modulus of resilience is proportional to (stress at elastic limit)2

Description : If N is deviation angle the length L of a parabolic vertical curve for overtaking sight distance S, is (A) NS²/9.6 if L > S (B) NS²/9.6 if L < S (C) 2S - 9.6/N if L < S (D) Both (A) and (C)

Description : If N is deviation angle, the length L, of a parabolic vertical curve for safe stopping distance S, is (A) NS²/4.4 if L > S (B) 2S - 4.4/N if L < S (C) 2S - 4.4/N if L > S (D) Both (a) and (b)

Description : When a piggy bank has 160 total coins valuing 10.50. Think about a system of equations that can be used to represent the number of nickels and dimes and then think through?

Last Answer : If n is the number of nickels and d the number of dimes, thenthe equations are:n + d = 160 (total number of coins)5n + 10d = 1050 (total value).And I have thought through to the answer.

Description : How do I use Ohm's law to show that power can be expressed by the equation P=I^2R?

Last Answer : Are you allowed to also use the relationship that P=IV? Because given that equation, it is then just a matter of simple replacement. V=IR (Ohm’s law), so replace the V in the first equation with IR to get P=I^2R.

Description : Centroid of the are of circle shown in adjacement figure is a.r sin (?/2)/2 ?, 0 b.r sin (?)/?, 0 c.2 r sin (?/2)/?, 0 d.107 dynes e.2r sin (?)/?, 0

Last Answer : c. 2 r sin (?/2)/?, 0

Description : If the radius of a sphere is 2r, then its volume will be -Maths 9th

Last Answer : As, r=2r Volume of sphere = 4​/3π(2r)^3 =32/3​πr^3

Description : If the radius of a sphere is 2r, then its volume will be -Maths 9th

Last Answer : (d) Given, radius of a sphere = 2r Volume of a sphere =4/3 π(Radius)3 = 4/3 π(2r)3 = 4/3 π 8r3 = (32 πr3)/3 cu units Hence the volume of a sphere is (32 πr3)/3 cu units.

Description : Without finding the cubes, factorise: (2r-3s)3 +(3s -5t)3+ (5t-2r)3. -Maths 9th

Description : The radius of sphere is 2r, then find its volume. -Maths 9th

Last Answer : Volume of the sphere = 4/3.π.(2r)3 = 32/3πr3

Description : In the circuit diagram,heat produces in R, 2R and `1.5 R` are in the ratio of

Last Answer : In the circuit diagram,heat produces in R, 2R and `1.5 R` are in the ratio of A. `4:2:3` B. `8:4:27` C. `2:4:3` D. `27:8:4`

Description : If r is the radius of a circle and d is its diameter is an equivalent formula for the circumference C 2r?

Description : If r is the radius of a circle and d is its diameter is an equivalent formula for the circumference C 2r?

Description : When the following expression is written in simplest form what is the coefficient of the variable term -1.5r plus 6r and ndash 12.2r?

Last Answer : When the following expression is written in simplest form what is the coefficient of the variable term -1.5r plus 6r and ndash 12.2r?

Description : Weight of a person at a height of 2R from the centre of the earth, where R is the radius of the earth- (1) remains same (2) becomes half (3) becomes twice (4) becomes one-fourth

Last Answer : (4) becomes one-fourth Explanation: The gravitational force is proportional to 1/R2, where R is the distance from the centre of the Earth. So at a height of 2R from the centre of the earth, the corresponding weight would be one-fourth of the original weight.

Description : If a wire of resistance R is melted and recast to half of its length, then the new resistance of the wire will be - (1) R/4 (2) R/2 (3) R (4) 2R

Description : A centrifugal filtration unit operating at a rotational speed of w has inner surface of the liquid (density ρL) located at a radial distance R from the axis of rotation. The thickness of the liquid film is δ and no cake is formed. The ... . ρL (C) ½w 2 . δρL (2R + δ) (D) ½w 2 . R . ρL(R + 2δ)

Last Answer : (C) ½w 2 . δρL (2R + δ)

Description : Velocity of escape is equal to A. r √(2g); where r: radius of Earth or any other planet for that matter, g: gravitational field strength B. g √(2r); where r: radius of ... (2gr); where r: radius of Earth or any other planet for that matter, g: gravitational field strength

Last Answer : √(2gr); where r: radius of Earth or any other planet for that matter, g: gravitational field strength

Description : Heat produced when a steady state current, I passes through an electrical conductor having resistance, 'R' is (A) IR (B) I 2R (C) IR 2 (D) I 2R

Last Answer : (B) I 2R

Last Answer : Advantage: • Easier to build • Number of bits can be expanded by adding more sections. Disadvantage: • More power dissipation makes heating, which in turns develops non-linearties in DAC.

Description : The radius of Gyration (k) for Rim Type Flywheel having radius ‘r’ is given by 1. k = 2r 2. k = r/2 3. k = r 4. k = r/3

Last Answer : 3. k = r

Description : . In case of turbulent flow of fluid through a circular pipe, the (A) Mean flow velocity is about 0.5 times the maximum velocity (B) Velocity profile becomes flatter and flatter with ... , shear stresses, random orientation of fluid particles and slope of velocity profile at the wall are more

Last Answer : (D) Skin friction drag, shear stresses, random orientation of fluid particles and slope of velocity profile at the wall are more

Description : The following gas phase reactions are carried out isothermally in a CSTR. A → 2R ; r1 = k1pA ; k1 = 20mole/(sec.m3 bar) A → 3S ; r2 = k2 pA ; k2 = 40mole/(sec.m3 .bar) What is the maximum possible value of FR(mole/sec.)? (A) 1/3 (B) 1/2 (C) 2/3 (D) 2