Which line is parallel to y = 2 and goes through the point (3, 4)?

Which line is parallel to y = 2 and goes through the point (3, 4)?
by

1 Answer

Answer :

The line will have the same slope but with a different yintercept
by

Related questions

Write the equation of a line parallel to y-axis and passing through the point (–4, –5). -Maths 9th

Description : Write the equation of a line parallel to y-axis and passing through the point (–4, –5). -Maths 9th

Last Answer : Solution :- x= -4

The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

Description : The line L is given by x/5 + y/b = 1 passes through the point (13, 32). The line K is parallel to L and has the equation -Maths 9th

Last Answer : (a) 45º The equations of the given lines are: A\(x\) + By = A + B ⇒ By = -A\(x\) + (A + B) ⇒ y = \(-rac{A}{B}x\) + \(rac{(A+B)}{B}\) ....(i)and A(\(x\) - y) + B(\(x\) ... (ii) = m2 = \(rac{(A+B)}{B-A}\)Let θ be the angle between both the lines, then∴ tan θ = 1 ⇒ θ = tan-1 (1) = 45°.

is this statement true or falseIf line x is parallel to line y, then point Z is the only point through which y passes.?

Description : is this statement true or falseIf line x is parallel to line y, then point Z is the only point through which y passes.?

Last Answer : Answers is the place to go to get the answers you need and to ask the questions you want

For a parallel connection of light bulbs, which of the following statements is correct? w) The resistance of each light bulb must be the same. x) If one goes out they all go out. y) Each of the light bulbs operates independently.

Description : For a parallel connection of light bulbs, which of the following statements is correct? w) The resistance of each light bulb must be the same. x) If one goes out they all go out. y) Each of the light bulbs operates independently.

Last Answer : ANSWER: Y -- EACH OF THE LIGHT BULBS OPERATES INDEPENDENTLY.

What is the equation of a line that has a slope of 1/2 and goes through the point (8,8) Write your answer in slope-intercept form?

Description : What is the equation of a line that has a slope of 1/2 and goes through the point (8,8) Write your answer in slope-intercept form?

Last Answer : The answer is:y = 1/2x + 4

What is a point-slope equation of the line with slope -13 that goes through point (5 7)?

Description : What is a point-slope equation of the line with slope -13 that goes through point (5 7)?

Last Answer : Slope: -13Point: (5, 7)Equation: y = -13x+72 whereas -13 is the slope and 72 is the yintercept

When a ray passes through a prism ______. A. It goes undeviated B. It remain parallel to a base C. It bends towards the base D. None

Description : When a ray passes through a prism ______. A. It goes undeviated B. It remain parallel to a base C. It bends towards the base D. None

Last Answer : C. It bends towards the base

At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Description : At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th

Last Answer : hope its clear

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

What is the equation of the line passing through (2, –3) and parallel to the y-axis ? -Maths 9th

Description : What is the equation of the line passing through (2, –3) and parallel to the y-axis ? -Maths 9th

Last Answer : (c) x = 2 Slope of y-axis = tan 90º (∵ y-axis ⊥ x-axis) ∴ Equation of line passing through (2, –3) parallel to y-axis is (y + 3) = tan 90º (x – 2) ⇒ (y + 3) = ∞ (x – 2) ⇒ (x – 2) = \(rac{1}{\infty}\) (y + 3) = 0 ⇒ x = 2.

Identify an equation in slope-intercept from for the line parallel to y=4x-9 that passes through (-5,3)?

Description : Identify an equation in slope-intercept from for the line parallel to y=4x-9 that passes through (-5,3)?

Last Answer : food

An incident ray comes in parallel to the principle axis of a concave mirror. Is it reflected: w) back along the incident ray x) at 30 degrees to incident ray y) through the focal point z) through the center of curvature

Description : An incident ray comes in parallel to the principle axis of a concave mirror. Is it reflected: w) back along the incident ray x) at 30 degrees to incident ray y) through the focal point z) through the center of curvature

Last Answer : ANSWER: Y -- THROUGH THE FOCAL POINT 

ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (i) D is the mid-point of AC (ii) MD ⊥ AC (iii) CM = MA = ½ AB -Maths 9th

Description : ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (i) D is the mid-point of AC (ii) MD ⊥ AC (iii) CM = MA = ½ AB -Maths 9th

Last Answer : Solution: (i) In ΔACB, M is the midpoint of AB and MD || BC , D is the midpoint of AC (Converse of mid point theorem) (ii) ∠ACB = ∠ADM (Corresponding angles) also, ∠ACB = 90° , ∠ADM = 90° and MD ⊥ AC (iii ... SAS congruency] AM = CM [CPCT] also, AM = ½ AB (M is midpoint of AB) Hence, CM = MA = ½ AB

4. ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30). Show that F is the mid-point of BC. -Maths 9th

Description : 4. ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30). Show that F is the mid-point of BC. -Maths 9th

Last Answer : . Solution: Given that, ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. To prove, F is the mid-point of BC. Proof, BD intersected EF at G. In ΔBAD, E is the ... point of BD and also GF || AB || DC. Thus, F is the mid point of BC (Converse of mid point theorem)

ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th

Description : ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th

Last Answer : Given: A △ABC , right - angled at C. A line through the mid - point M of hypotenuse AB parallel to BC intersects AC at D. To Prove: (i) D is the mid - point of AC (ii) MD | AC (iii) CM = MA = 1 / 2 ... congruence axiom] ⇒ AM = CM Also, M is the mid - point of AB [given] ⇒ CM = MA = 1 / 2 = AB.

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th

Description : ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th

Last Answer : Given: A △ABC , right - angled at C. A line through the mid - point M of hypotenuse AB parallel to BC intersects AC at D. To Prove: (i) D is the mid - point of AC (ii) MD | AC (iii) CM = MA = 1 / 2 ... congruence axiom] ⇒ AM = CM Also, M is the mid - point of AB [given] ⇒ CM = MA = 1 / 2 = AB.

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

Write the equation of a line parallel to x-axis and passing through the point (–3, –4). -Maths 9th

Description : Write the equation of a line parallel to x-axis and passing through the point (–3, –4). -Maths 9th

Last Answer : Solution :- y = -4

ABC is a triangle right-angled at C. A line through the mid-point of hypotenuse AB and parallel to BC intersects AC at D. Show that -Maths 9th

Description : ABC is a triangle right-angled at C. A line through the mid-point of hypotenuse AB and parallel to BC intersects AC at D. Show that -Maths 9th

Last Answer : Solution :-

In Fig. 8.53,ABCD is a parallelogram and E is the mid - point of AD. A line through D, drawn parallel to EB, meets AB produced at F and BC at L.Prove that (i) AF = 2DC (ii) DF = 2DL -Maths 9th

Description : In Fig. 8.53,ABCD is a parallelogram and E is the mid - point of AD. A line through D, drawn parallel to EB, meets AB produced at F and BC at L.Prove that (i) AF = 2DC (ii) DF = 2DL -Maths 9th

Last Answer : Given, E is mid point of AD Also EB∥DF ⇒ B is mid point of AF [mid--point theorem] so, AF=2AB (1) Since, ABCD is a parallelogram, CD=AB ⇒AF=2CD AD∥BC⇒LB∥AD In ΔFDA ⇒LB∥AD ⇒LDLF​=ABFB​=1 from (1) ⇒LF=LD so, DF=2DL

is this statement true of false if point P is not on line L, the rhombus method can be used to construct a line M that is parallel to line L through P.?

Description : is this statement true of false if point P is not on line L, the rhombus method can be used to construct a line M that is parallel to line L through P.?

Last Answer : 1

What is the first step in the construction of a line parallel to AB through point P?

Description : What is the first step in the construction of a line parallel to AB through point P?

Last Answer : Need answer

How do you write an equation that is parallel to a given line and passes through the given point?

Description : How do you write an equation that is parallel to a given line and passes through the given point?

Last Answer : Parallel straight line equations have the same slope but withdifferent y intercepts

To construct a parallel to a line through a point not on the line using folding you can perform the construction twice?

Description : To construct a parallel to a line through a point not on the line using folding you can perform the construction twice?

Last Answer : perpendicular line segment (apex)

Dew point of an air-water vapor mixture (A) Decreases with decrease in pressure (B) At constant humidity & total pressure is fixed (C) Corresponding to any point on the humidity chart is obtained by projecting a line through this point parallel to the temperature axis and to the saturation curve (D) All 'a', 'b' & 'c'

Description : Dew point of an air-water vapor mixture (A) Decreases with decrease in pressure (B) At constant humidity & total pressure is fixed (C) Corresponding to any point on the humidity chart is obtained by projecting a ... to the temperature axis and to the saturation curve (D) All 'a', 'b' & 'c'

Last Answer : (D) All 'a', 'b' & 'c'

As one goes across a period in the periodic table, the ionization energy generally increases for one of the following reasons. Is it because of the increasing w) atomic radius x) melting point y) nuclear charge z) density

Description : As one goes across a period in the periodic table, the ionization energy generally increases for one of the following reasons. Is it because of the increasing w) atomic radius x) melting point y) nuclear charge z) density

Last Answer : ANSWER: Y -- NUCLEAR CHARGE

A curve that goes through all the tangency points of an x and y isoquants in a Edgeworth Box is called (a) Indifference curve (b) Trade indifference curve (c) Offer curve (d) Contract curve

Description : A curve that goes through all the tangency points of an x and y isoquants in a Edgeworth Box is called (a) Indifference curve (b) Trade indifference curve (c) Offer curve (d) Contract curve

Last Answer : Offer curve

What is the slope of the line that goes through (-34) and (2-6)?

Description : What is the slope of the line that goes through (-34) and (2-6)?

Last Answer : If you mean points of (-3, 4) and (2, -6) then the slope is-2

What Graph a line that goes through the points -3-2 and 47?

Description : What Graph a line that goes through the points -3-2 and 47?

Last Answer : We don't have your graph so can't answer your question.

In figure LM is a line parallel to the Y-axis at a distance of 3 units. -Maths 9th

Description : In figure LM is a line parallel to the Y-axis at a distance of 3 units. -Maths 9th

Last Answer : Given, LM is a line parallel to the Y-axis and its perpendicular distance from Y-axis is 3 units. (i) Coordinate of point P = (3, 2) [since, its perpendicular distance from X-axis is 2] Coordinate of ... 3, abscissa of point M = 3 Difference between the abscissa of the points L and M = 3 -3 = 0

In figure LM is a line parallel to the Y-axis at a distance of 3 units. -Maths 9th

Description : In figure LM is a line parallel to the Y-axis at a distance of 3 units. -Maths 9th

Last Answer : Given, LM is a line parallel to the Y-axis and its perpendicular distance from Y-axis is 3 units. (i) Coordinate of point P = (3, 2) [since, its perpendicular distance from X-axis is 2] Coordinate of ... 3, abscissa of point M = 3 Difference between the abscissa of the points L and M = 3 -3 = 0

In fig.4.7, LM is a line parallel to the y - axis at a distance of 2 units. -Maths 9th

Description : In fig.4.7, LM is a line parallel to the y - axis at a distance of 2 units. -Maths 9th

Last Answer : Given , LM is a line parallel to the Y-axis and its perpendicular distance from Y-axis is 3 units. (i) Coordinates of point P=(3,2) [since,its perpendicular distance from X-axis is 2] Coordinate of point ... L=3 , abscissa of point M=3 ∴∴ Difference between the abscissa of the points L and M =3-3=0

The equation of a line parallel to the y- axis is of the form ................. -Maths 9th

Description : The equation of a line parallel to the y- axis is of the form ................. -Maths 9th

Last Answer : answer:

What is the equation of the line having the y-intercept –1 and parallel to the line y = 5x – 7 ? -Maths 9th

Description : What is the equation of the line having the y-intercept –1 and parallel to the line y = 5x – 7 ? -Maths 9th

Last Answer : Slope of AB = \(rac{2-4}{1-0}\) = -2, Slope of BC = \(rac{3-2}{3-1}\) = \(rac{1}{2}\)Slope of AC = \(rac{3-4}{3-0}\) = \(-rac{1}{3}\)Slope of AB × Slope of BC = -2 x \(rac{1}{2}\) = -1∴ AB ⊥ BC, i.e, ∠B = 90º ⇒ ΔABC is a right angled.

A straight line is parallel to the lines 3x – y – 3 = 0 and 3x – y + 5 = 0 and lies between them. -Maths 9th

Description : A straight line is parallel to the lines 3x – y – 3 = 0 and 3x – y + 5 = 0 and lies between them. -Maths 9th

Last Answer : (c) 3x - 4y + 15 = 0 Let (m > 0) be the gradient (slope) of the required line. Then, Equation of any line through (-5, 0) having slope = m is y - 0 = m(x - (-5)) or mx - y + 5m = 0 ...(i) Its ... (rac{3}{4}\) (∵ m is +ve)∴ Required equation: y = \(rac{3}{4}\) (x + 5)⇒ 3x - 4y + 15 = 0.

Which line is parallel to y = -3x?

Description : Which line is parallel to y = -3x?

Last Answer : 12x +4y = -2

Find the equation of tangent of the curve `y^(2) = 4x+5` which is parallel to the line ` 2x-y=5`.

Description : Find the equation of tangent of the curve `y^(2) = 4x+5` which is parallel to the line ` 2x-y=5`.

Last Answer : Find the equation of tangent of the curve `y^(2) = 4x+5` which is parallel to the line ` 2x-y=5`.

What equation represents a line that is parallel to the line y-4x plus 5?

Description : What equation represents a line that is parallel to the line y-4x plus 5?

Last Answer : Need answer

What is the slope of a line parallel to the line whose equation is 2x+y=62x+y=6. Fully reduce your answer.?

Description : What is the slope of a line parallel to the line whose equation is 2x+y=62x+y=6. Fully reduce your answer.?

Last Answer : 44811

A perfectly elastic supply curve will be (a) Parallel to Y axis or a vertical line ; (b) Parallel to X axis; (c) U shaped ; (d) Downward sloping

Description : A perfectly elastic supply curve will be (a) Parallel to Y axis or a vertical line ; (b) Parallel to X axis; (c) U shaped ; (d) Downward sloping

Last Answer : the aggregate demand curve

A perfect inelastic supply curve will be (a) Parallel to Y axis or a vertical line ; (b) Parallel to X axis ; (c) U shaped; (d) Downward sloping

Description : A perfect inelastic supply curve will be (a) Parallel to Y axis or a vertical line ; (b) Parallel to X axis ; (c) U shaped; (d) Downward sloping

Last Answer : (a) Parallel to Y axis or a vertical line ;

Long run supply curve of a decreasing cost industry is (a) Downward sloping curve ; (b) Upward sloping curve; (c) Straight line parallel to X axis ; (d) Straight line parallel to y axis

Description : Long run supply curve of a decreasing cost industry is (a) Downward sloping curve ; (b) Upward sloping curve; (c) Straight line parallel to X axis ; (d) Straight line parallel to y axis

Last Answer : (a) Downward sloping curve ;

Find the co-ordinates of that point on the curve `x^(2)/a^(2)+y^(2)/b^(2) = 1` at which the tangent drawn is parallel to Y-axis.

Description : Find the co-ordinates of that point on the curve `x^(2)/a^(2)+y^(2)/b^(2) = 1` at which the tangent drawn is parallel to Y-axis.

Last Answer : Find the co-ordinates of that point on the curve `x^(2)/a^(2)+y^(2)/b^(2) = 1` at which the tangent drawn is parallel to Y-axis.

Find the co-ordinates of that point on the curve `x^(3)+y^(3)= a^(3)` at which the tangent drawn is parallel to X-axis.

Description : Find the co-ordinates of that point on the curve `x^(3)+y^(3)= a^(3)` at which the tangent drawn is parallel to X-axis.

Last Answer : Find the co-ordinates of that point on the curve `x^(3)+y^(3)= a^(3)` at which the tangent drawn is parallel to X-axis.

For a point charge to feel a net force in a homogeneous magnetic field, which one of the following statements is true? The charge must: w) move parallel to the magnetic lines of flux x) have a component of its motion perpendicular to the lines of flux y) be stationary z) be a positive charge

Description : For a point charge to feel a net force in a homogeneous magnetic field, which one of the following statements is true? The charge must: w) move parallel to the magnetic lines of flux x) have a component of its motion perpendicular to the lines of flux y) be stationary z) be a positive charge

Last Answer : ANSWER: X -- HAVE A COMPONENT OF ITS MOTION PERPENDICULAR TO THE LINES OF FLUX