A line segment that connects any two points on the circle?

A line segment that connects any two points on the circle?
by

1 Answer

Answer :

It's called a chord.
by

Related questions

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

Which term describes a line segment that connects a vertex of a triangle to a point on the line containing the opposite sideso that the line segment is perpendicular to that line?

Description : Which term describes a line segment that connects a vertex of a triangle to a point on the line containing the opposite sideso that the line segment is perpendicular to that line?

Last Answer : Altitude

What is Trapezoid is the segment that connects the midpoint of the legs of the trapezoid?

Description : What is Trapezoid is the segment that connects the midpoint of the legs of the trapezoid?

Last Answer : It is called the median.

What is Trapezoid is the segment that connects the midpoint of the legs of the trapezoid?

Description : What is Trapezoid is the segment that connects the midpoint of the legs of the trapezoid?

Last Answer : It is called the median.

An isobar is a line which connects all points below the ground surface at which (a) The local ground elevation is same (b) The settlement is same (c) The vertical stress is the same (d) The ground elevation is varying

Description : An isobar is a line which connects all points below the ground surface at which (a) The local ground elevation is same (b) The settlement is same (c) The vertical stress is the same (d) The ground elevation is varying

Last Answer : (c) The vertical stress is the same

Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Why is the following a poor definition for a diameter. A diameter is a line segment with both endpoints on a circle.?

Description : Why is the following a poor definition for a diameter. A diameter is a line segment with both endpoints on a circle.?

Last Answer : Some segments with both endpoints on a circle are not diameters.

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

In Fig. 10.20, two circles intersects at two points A and B.AD and AC are diameters to the circles. Prove that B lies on the line A segment DC. -Maths 9th

Description : In Fig. 10.20, two circles intersects at two points A and B.AD and AC are diameters to the circles. Prove that B lies on the line A segment DC. -Maths 9th

Last Answer : Solution :- Jion AB ∠ABD = 90° (Angle in a semicircle) Similarly, ∠ABC = 90° So, ∠ABD + ∠ABC = 90° + 90° = 180° Therefore,DBC is a line i.e.,B lies on the segment DC.

Points P (5, -3) is one of the two points of trisection of the line segment joining points A(7, -2) and B(1, -5) near to A. find the coordinates of the other point of trisection. -Maths 9th

Description : Points P (5, -3) is one of the two points of trisection of the line segment joining points A(7, -2) and B(1, -5) near to A. find the coordinates of the other point of trisection. -Maths 9th

Last Answer : answer:

Prove that the line segment joining the mid-points of the diagonals of a trapezium is parallel to the parallel sides and equal to half of their difference. -Maths 9th

Description : Prove that the line segment joining the mid-points of the diagonals of a trapezium is parallel to the parallel sides and equal to half of their difference. -Maths 9th

Last Answer : In a parallelogram ABCD, the bisector of ∠ A also bisects BC at X.Prove that AD = 2AB.

Find the point of trisection of the line segment joining the points (1, 2) and (11, 9) ? -Maths 9th

Description : Find the point of trisection of the line segment joining the points (1, 2) and (11, 9) ? -Maths 9th

Last Answer : Let P divide AB in the ratio k : 1. Then, co-ordinates of P are \(\bigg(rac{7k+4}{k+1},rac{7k+4}{k+1}\bigg)\)But P ≡ (-1, -1)∴ \(rac{7k+4}{k+1}\) = -1 ⇒ 7k + 4 = - k - 1 ⇒ 8k = - ... , it means that the division is external. ∴ AB is divided by P externally in the ratio \(rac{5}{8}\) : 1, i.e. 5 : 8.

A straight line passes through the points (a, 0) and (0, b). The length of the line segment contained between the axes is 13 and the product of -Maths 9th

Description : A straight line passes through the points (a, 0) and (0, b). The length of the line segment contained between the axes is 13 and the product of -Maths 9th

Last Answer : (d) \(rac{23}{\sqrt{17}}\)The given lines are:L : \(rac{x}{5}+rac{y}{b}=1\) ....(i)K : \(rac{x}{c}+rac{y}{3}=1.\) ...(ii)Since line L passes through (13, 32),\(rac{13}{ ... between parallel lines ax + by + c1 = 0 and ax + by c2 = 0 is d = \(rac{|c_2-c_1|}{\sqrt{a^2+b^2}}\bigg)\)

Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Description : Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Last Answer : this is the ans hope its clear

How do I find the midpoint of the line segment joining the points (-1,3) and (-9,8)?

Description : How do I find the midpoint of the line segment joining the points (-1,3) and (-9,8)?

Last Answer : 85

The midpoint of the line segment joining the points B and D is: (a) (10,11) (b) (11,5) (c) (7/2,11/2) (d) (5,11/2)

Description : The midpoint of the line segment joining the points B and D is: (a) (10,11) (b) (11,5) (c) (7/2,11/2) (d) (5,11/2)

Last Answer : (c) (7/2,11/2)

The point which divides the line segment joining the points (7, –6) and (3, 4) in the ratio 1 : 2 lies in the: (a) I quadrant (b) II quadrant (c) III quadrant (d) IV quadrant

Description : The point which divides the line segment joining the points (7, –6) and (3, 4) in the ratio 1 : 2 lies in the: (a) I quadrant (b) II quadrant (c) III quadrant (d) IV quadrant

Last Answer : (d) IV quadrant

The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)

Description : The point which lies on the perpendicular bisector of the line segment joining the points B(3,5) is: (a) (-3,0) (b) (5,0) (c) (5,-5) (d) (0,0)

Last Answer : (d) (0,0)

The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30

Description : The point (-1,2) divides the line segment joining the points A(2,5) and B(x,y) in the ratio 3:4, then the value of x2 + y2 is : (a) 27 (b) 28 (c) 29 (d) 30

Last Answer : (c) 29

The ratio in which P ( , B(2,-5) is : (a) 1:5 (b) 5:1 ) divides the line segment joining the points A ( , (c) 1:4 ) and (d) 4:1

Description : The ratio in which P ( , B(2,-5) is : (a) 1:5 (b) 5:1 ) divides the line segment joining the points A ( , (c) 1:4 ) and (d) 4:1

Last Answer : (a) 1:5

Consider a window bounded by the lines : x = 0; y= 0; x = 5 and y = 3. The line segment joining (–1, 0) and (4, 5), if clipped against this window will connect the points (A) (0, 1) and (2, 3) (B) (0, 1) and (3, 3) (C) (0, 1) and (4, 3) (D) (0, 1) and (3, 2)

Description : Consider a window bounded by the lines : x = 0; y= 0; x = 5 and y = 3. The line segment joining (–1, 0) and (4, 5), if clipped against this window will connect the points (A) (0, 1) and (2, 3) (B) (0, 1) and (3, 3) (C) (0, 1) and (4, 3) (D) (0, 1) and (3, 2)

Last Answer : (A) (0, 1) and (2, 3)

A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th

Description : A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th

Last Answer : Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 ... Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142 HOPE IT HELPS YOU

A river is said to be of uniform section if in its section A) A segment of a circle can be fitted (B) A parabolic section can be fitted (C) A rectangular section can be fitted (D) All the above

Description : A river is said to be of uniform section if in its section A) A segment of a circle can be fitted (B) A parabolic section can be fitted (C) A rectangular section can be fitted (D) All the above

Last Answer : Answer: Option D

In the Perceptual Map each segment has a set of circles where: a. The inner fine cut circles have a radius of 4 units. b. The inner fine cut circles represent the heart of the segment where demand is strong. c. At the center of each inner fine cut circle is the ideal spot where demand is strongest. d. a and b. e. a, b and c.

Description : In the Perceptual Map each segment has a set of circles where: a. The inner fine cut circles have a radius of 4 units. b. The inner fine cut circles represent the heart of the segment where demand is strong. ... cut circle is the ideal spot where demand is strongest. d. a and b. e. a, b and c.

Last Answer : b. The inner fine cut circles represent the heart of the segment where demand is strong.

Every year the Traditional segment circle drifts ____ in performance and _____ in size. a. +1.0, -0.7 b. +0.7, -0.7 c. -0.7, +0.7 d. +0.5, -0.5 e. +0.9, -0.9

Description : Every year the Traditional segment circle drifts ____ in performance and _____ in size. a. +1.0, -0.7 b. +0.7, -0.7 c. -0.7, +0.7 d. +0.5, -0.5 e. +0.9, -0.9

Last Answer : b. +0.7, -0.7

In the Marketing Plan, Research and Development addresses all but the: a. placement of each product inside a market segment circle. b. number of products in each segment. c. age of your products. d. automation of assembly lines. e. reliability of each product.

Description : In the Marketing Plan, Research and Development addresses all but the: a. placement of each product inside a market segment circle. b. number of products in each segment. c. age of your products. d. automation of assembly lines. e. reliability of each product.

Last Answer : d. automation of assembly lines.

On the perceptional map, where is the “sweet/ideal spot” in the High End segment? a. in the center of the circle c. there is no sweet spot in High End b. on the trailing edge of the circle d. on the leading edge of the circle

Description : On the perceptional map, where is the “sweet/ideal spot” in the High End segment? a. in the center of the circle c. there is no sweet spot in High End b. on the trailing edge of the circle d. on the leading edge of the circle

Last Answer : d. on the leading edge of the circle

Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Description : Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Last Answer : Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB. ⇒ OP ... 90° Now, ∠POX + ∠XOQ = 90° + 90° = 180° so, POQ is a straight line . Hence proved

Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Description : Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Last Answer : Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB. ⇒ OP ... 90° Now, ∠POX + ∠XOQ = 90° + 90° = 180° so, POQ is a straight line . Hence proved

is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

Description : is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

Last Answer : 1

What is a market segment? a. Group of customers with differing purchasing concerns b. Area of perceptual map where all points intersect c. Group of customers with similar purchasing concerns d. Geographic area where customers are located e. Common area of buying patterns

Description : What is a market segment? a. Group of customers with differing purchasing concerns b. Area of perceptual map where all points intersect c. Group of customers with similar purchasing concerns d. Geographic area where customers are located e. Common area of buying patterns

Last Answer : c. Group of customers with similar purchasing concerns

The longest railway line in the world connects ______. (1) New York and Seattle (2) Leningrad and Vladivostok (3) Trivandrum and Guwahati (4) Perth and Sydney

Description : The longest railway line in the world connects ______. (1) New York and Seattle (2) Leningrad and Vladivostok (3) Trivandrum and Guwahati (4) Perth and Sydney

Last Answer : (2) Leningrad and Vladivostok Explanation: The Trans-Siberian Railway, a network of railways connecting Moscow with the Russian Far East, is the longest railway line in the world with a ... main route of the Trans-Siberian Railway begins in Moscow and connects Vladivostok via southern Siberia.

The longest railway line in the world connects _______ (1) New York and Seattle (2) Leningrad and Vladivostok (3) Trivandrum and Guwahati (4) Perth and Sydney

Description : The longest railway line in the world connects _______ (1) New York and Seattle (2) Leningrad and Vladivostok (3) Trivandrum and Guwahati (4) Perth and Sydney

Last Answer : Leningrad and Vladivostok

A circle is passing through two end points A[6,4] and B[10,10]. Find center point ofcircle a.7,8 b.8,8 c.8,7 d.7,7

Description : A circle is passing through two end points A[6,4] and B[10,10]. Find center point ofcircle a.7,8 b.8,8 c.8,7 d.7,7

Last Answer : c.8,7

A semi-circle of diameter 14 cm has three chords of equal length connecting the two end points of the diameter so as -Maths 9th

Description : A semi-circle of diameter 14 cm has three chords of equal length connecting the two end points of the diameter so as -Maths 9th

Last Answer : (c)\(\bigg(rac{147 imes\sqrt3}{4}\bigg)\) cm2Take the trapezoid ABCD in the semi-circle with centre O such that AD = DC = CB. Now, complete the circle and draw an identical trapezoid in the other semicircle also. Then, ADCBEF ... {1}{2}\)x \(rac{3\sqrt3}{2}\) x 49 = \(rac{147 imes\sqrt3}{4}\) cm2.

A parabola is drawn through two given points `A(1,0)` and `B(-1,0)` such that its directrix always touches the circle `x² + y^2 = 4.` Then, The locus

Description : A parabola is drawn through two given points `A(1,0)` and `B(-1,0)` such that its directrix always touches the circle `x² + y^2 = 4.` Then, The locus

Last Answer : A parabola is drawn through two given points `A(1,0)` and `B(-1,0)` such that its directrix always touches the circle ... `(x^(2))/(5)+(y^(2))/(4)=1`

If three equal chords meet at three distinct points on the circle, then the angle between any two chords is `____________`.

Description : If three equal chords meet at three distinct points on the circle, then the angle between any two chords is `____________`.

Last Answer : If three equal chords meet at three distinct points on the circle, then the angle between any two chords is `____________`.

A wire has resistance `12 Omega`. It is bent in the form of a circle. The effective resistance between two points across a diameter is.

Description : A wire has resistance `12 Omega`. It is bent in the form of a circle. The effective resistance between two points across a diameter is.

Last Answer : A wire has resistance `12 Omega`. It is bent in the form of a circle. The effective resistance between two ... ` B. `6Omega` C. `3Omega` D. `24Omega`

One of the Lehmann's rules of plane tabling, is (A) Location of the instrument station is always distant from each of the three rays from the known points in proportion to their distances (B) When looking in the direction of each of the given points, the instrument station will be on the right side of one and left side of the other ray (C) When the instrument station is outside the circumscribing circle its location is always on the opposite side of the ray to the most distant point as the inter-section of the other two rays (D) None of these

Description : One of the Lehmann's rules of plane tabling, is  (A) Location of the instrument station is always distant from each of the three rays from the  known points in proportion to their distances  ( ... to the most distant point as the inter-section of the other two rays  (D) None of these 

Last Answer : (A) Location of the instrument station is always distant from each of the three rays from the  known points in proportion to their distances 

Smallest circle that intersects N number of points on the coordinate plane?

Description : Smallest circle that intersects N number of points on the coordinate plane?

Last Answer : I don’t see how the upper bound is radius of 20. How does that circle have “20 intersection points?”

How do you work out the centre of a circle when you only know 4 points on it's circumference?

Description : How do you work out the centre of a circle when you only know 4 points on it's circumference?

Last Answer : You only need 3 points to find the center. Here is a hint. The perpendicular bisector of any chord of a circle goes through the center. If you need more help, I will provide it.

A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Description : A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Last Answer : a.9.24,9.24

In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Description : In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

Last Answer : Join OE. In ΔOME and ΔONE, OM =ON [equal chords are equidistant from the centre] ∠OME = ∠ONE = 90° OE =OE [common sides] ∠OME ≅ ∠ONE [by SAS congruency] ⇒ ME = NE [by CPCT] In quadrilateral OMEN, ... =ON , ME = NE and ∠OME = ∠ONE = ∠MEN = ∠MON = 90° Hence, OMEN is a square. Hence proved.