6 men and 10 women can finish making pots in 8 days, while the 4 men and 6 women can finish it in 12 days. Find the time taken by the one man alone from that of one woman alone to finish the work. -Maths 9th
Given: 6 men and 10 women can finish making pots in 8 days 4 men and 6 women can finish it in 12 days To find: Time taken by the one man alone from that of one woman alone to finish the work Solution:Let the work done by 1 man in 1 day = 1/xLet the work done by 1 woman in 1 day = 1/y According to the question: 6 men and 10 women can finish making pots in 8 days So,6/x + 10/y = 1/8 -------------(I) 4 men and 6 women can finish it in 12 days. So,4/x + 6/y = 1/12 --------(II) Take 1/x = M and 1/y = W On solving the equation (I) and (II) we get:M=1/48 , W= 0 So, x = 48Then time taken by the one man alone from that of one woman alone to finish the work is 48 days