If p is the length of the perpendicular drawn from the origin to the line -Maths 9th

If p is the length of the perpendicular drawn from the origin to the line -Maths 9th
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Let the x-intercept = a. Then y-intercept = –1 – a The equation of the required line is \(rac{x}{a}\) + \(rac{y}{-1-a}\) = 1Given, it passes through (4, 3), so,\(rac{4}{a}\) + \(rac{3}{-1-a}\) = 1⇒ – 4 – 4a + 3a = – a – a2 ⇒ a2 – 4 = 0 ⇒ (a + 2) (a – 2) = 0 ⇒ a = –2, or 2.When a = 2, required line is \(rac{x}{2}\) - \(rac{y}{3}\) = 1When a = –2, required line is \(rac{x}{-2}\) + \(rac{y}{3}\) = 1
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