7 persons enter an elevator on the ground floor of a 11 storey hotel. Any one of them can leave the elevator at any of the 10 floors. -Maths 9th

7 persons enter an elevator on the ground floor of a 11 storey hotel. Any one of them can leave the elevator at any of the 10 floors. -Maths 9th
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There are 10 persons who are to be seated around a circular table. Find the probability that two particular persons will always sit together. -Maths 9th

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A woman is sitting in her hotel room when there is a knock at the door. She opened the door to see a man whom she had never seen before. He said 'oh I'm sorry, I have made a mistake, I thought this was my room.' He then went down the corridor and in the elevator. The woman went back into her room and phoned security. What made the woman so suspicious of the man? -Riddles

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The floor of a rectangular hall has a perimeter 250 m. If the cost of painting the four walls at the rate of Rs.10 per m2 is Rs.15000, find the height of the hall. -Maths 9th

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Find the five rational no. Between5/7 and9/11 -Maths 9th

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Find the five rational no. Between5/7 and9/11 -Maths 9th

Description : Find the five rational no. Between5/7 and9/11 -Maths 9th

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A bag contains 5 green and 11 blue balls and the second one contains 3 green and 7 blue balls. Two balls are drawn from one of the bags. -Maths 9th

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A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

Description : A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

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A floral design on a floor is made up of 16 tiles which are triangular, ... -Maths 9th

Description : A floral design on a floor is made up of 16 tiles which are triangular, ... -Maths 9th

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A wall of length 10 m is to be built across an open ground. -Maths 9th

Description : A wall of length 10 m is to be built across an open ground. -Maths 9th

Last Answer : Length of the wall = 10 m = 1000 cm Thickness of the wall = 42 cm Height of the wall = 5 m = 500 cm ∴ Volume of the wall = 1000 × 500 × 42 cm3 Volume of each brick = 42 × 12 × 10 cm3 No. of bricks = Volume of the wall / Volume of each brick = 1000 × 500 × 42 / 42 × 12 × 10 = 4166.67 = 4167

A wall of length 10 m is to be built across an open ground. -Maths 9th

Description : A wall of length 10 m is to be built across an open ground. -Maths 9th

Last Answer : Length of the wall = 10 m = 1000 cm Thickness of the wall = 42 cm Height of the wall = 5 m = 500 cm ∴ Volume of the wall = 1000 × 500 × 42 cm3 Volume of each brick = 42 × 12 × 10 cm3 No. of bricks = Volume of the wall / Volume of each brick = 1000 × 500 × 42 / 42 × 12 × 10 = 4166.67 = 4167

If the storey height is equal to length of RCC wall, the percentage increase in strength is (A) 0 (B) 10 (C) 20 (D) 30

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Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Description : Find the range of the given data : 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 -Maths 9th

Last Answer : Here, the minimum and maximum values of given data are 6 and 32 respectively. Range = 32 – 6 = 26

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Last Answer : In conclusion, the range of data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, and 20 is 26.

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Description : The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11 and 20 is -Maths 9th

Last Answer : (d) In a given data, maximum value = 32 and minimum value = 6 We know, range of the data = maximum value – minimum value = 32 – 6 = 26 Hence, the range of the given data is 26.

In Fig. 10.11, find the value of x and y. -Maths 9th

Description : In Fig. 10.11, find the value of x and y. -Maths 9th

Last Answer : Solution :- y = 2∠ ACB ⇒ y = 2 65° ⇒ y = 130° OA = ... Or 2x = 50° Or x = 25°

Let A = {(2, 5, 11)}, B = {3, 6, 10} and R be a relation from A to B defined by R = {(a, b) : a and b are co-prime}. Then R is -Maths 9th

Description : Let A = {(2, 5, 11)}, B = {3, 6, 10} and R be a relation from A to B defined by R = {(a, b) : a and b are co-prime}. Then R is -Maths 9th

Last Answer : (c) {(2, 3), (5, 3), (5, 6), (11, 3), (11, 6), (11, 10)}

While removing the second primary molar of a 9 years-old child, the apical ¼ of the root fractures and stays in the socket, A. You will just leave it and observe it B. You take surgically by a lingual flap C. You try to take out by using a root apex elevator D. You use a fine-end forceps to take it out

Description : While removing the second primary molar of a 9 years-old child, the apical ¼ of the root fractures and stays in the socket, A. You will just leave it and observe it B. You take surgically by a lingual ... try to take out by using a root apex elevator D. You use a fine-end forceps to take it out

Last Answer : A. You will just leave it and observe it

P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another Rs 18 lakh few years. At the end of 10 years profit Of R is equal to sum of profit of P and Q. Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years