If the chance that a vessel arrives safely at a port is 9/10 , then what is the chance that out of 5 vessels expected at least 4 will arrive safely ? -Maths 9th

1 Answer

Answer :

(a) \(rac{(14 imes9^4)}{10^5}\)P(At least 4 vessels arrive safely) = P(exactly four vessels arrive safely) + P(All five vessels arrive safely)= 5C4 =\(\big(rac{9}{10}\big)^4\) x \(\big(rac{1}{10}\big)\) + \(\big(rac{9}{10}\big)^5\)= \(rac{5}{10}\) x \(\big(rac{9}{10}\big)^4\) + \(\big(rac{9}{10}\big)^5\) = \(\big(rac{9}{10}\big)^4\) \(\bigg(rac{5}{10}+rac{9}{10}\bigg)\) = \(rac{14 imes9^4}{10^5}.\)

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