The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19 , 29 and 34 respectively is (a) 1994 (b) 1494 (c) 1394 (d) 1496

The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19 , 29 and 34 respectively is (a) 1994 (b) 1494 (c) 1394 (d) 1496
by

1 Answer

Answer :

1394

Hint: Note that 20 -4 = 6; 25 -19 = 6;35-29= 6;40- 34 = 6

Required number = L.C.M. of ( 20, 25, 35 and 40)-6
by

Related questions

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

The largest numbers which divides 30, 78 and 102 to leave the same remainder in each case is (a)24 (b) 20 (c) 8 (d) 16

Description : The largest numbers which divides 30, 78 and 102 to leave the same remainder in each case is (a)24 (b) 20 (c) 8 (d) 16

Last Answer : 24

The L.C.M of two numbers is 14 times their H.C.F . The sum of the L.C.M. and the H.C.F . is 600. If one number is 280 , then the other number is (a) 40 (b) 60 (c) 80 (d) 100

Description : The L.C.M of two numbers is 14 times their H.C.F . The sum of the L.C.M. and the H.C.F . is 600. If one number is 280 , then the other number is (a) 40 (b) 60 (c) 80 (d) 100

Last Answer : 80

Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?

Description : Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?

Last Answer : Ans 1. L.C.M of 2, 4, 6, 8, 10 and 12 is 120. so, the bells will toll together after 120 seconds i.e. 2 minutes . In 30 minutes the bells toll together 30/2 + 1 times i.e. times.

Find the least number of five digits which is exactly divisible by 12, 15 and 18. (a) 1080 (b) 10080 (c) 10025 (d) 11080

Description : Find the least number of five digits which is exactly divisible by 12, 15 and 18. (a) 1080 (b) 10080 (c) 10025 (d) 11080

Last Answer : 10080 Hint : The least number of 5 digits is 10000. L.C.M. of 12, 15 and 18 is 180 . On dividing 10000 is 100. => 10000 + 180- 100 = 10080 is divisible by 180.

The sum of two numbers is 528 and their H.C.F is 33. What is the number of pairs of such numbers ? (a) 4 (b) 12 (c) 8 (d) 6

Description : The sum of two numbers is 528 and their H.C.F is 33. What is the number of pairs of such numbers ? (a) 4 (b) 12 (c) 8 (d) 6

Last Answer : Ans 5. 4 Hint : Let the number be 33x and 33y where x and y are co-prime.

Three measuring rods are 64 cm,80 cm and 96 cm in length . What is the least length of cloth that can can be measured exact number of times using any one of these rods? (a) 9.60 m (b) 8 m (c) 9.60 cm (d) 96 m

Description : Three measuring rods are 64 cm,80 cm and 96 cm in length . What is the least length of cloth that can can be measured exact number of times using any one of these rods? (a) 9.60 m (b) 8 m (c) 9.60 cm (d) 96 m

Last Answer : Ans 4. 9.60 m

A gardener had a number of shrubs to plant in rows . At first he tried to plant 8, then 12 and then 16 in a row but he always had 3 shrubs left with him . On trying 7 shrubs he was left with none.Find the total number of shrubs.

Description : A gardener had a number of shrubs to plant in rows . At first he tried to plant 8, then 12 and then 16 in a row but he always had 3 shrubs left with him . On trying 7 shrubs he was left with none.Find the total number of shrubs.

Last Answer : Ans 3. L.C.M of 8,12,16 = 48 Now, 48 x 1 + 3 = 51 - not divisible by 7 48 x 2 + 3 = 99 - not divisible by 7 48 x 3 + 3 = 147 - not divisible by 7 Required number = 147

The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of these numbers is 275, then find the other number.

Description : The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of these numbers is 275, then find the other number.

Last Answer : Ans 2. Product of two number s = product of their H.C.F. and L.C.M. required number = 11 X 7700/275 = 308

When a number is divided by 36, it leaves a remainder of 19. What will be the remainder when the same number is divided by 12? a) 17 b) 7 c) 34 d) 19

Description : When a number is divided by 36, it leaves a remainder of 19. What will be the remainder when the same number is divided by 12? a) 17 b) 7 c) 34 d) 19

Last Answer : b) 7

Find the greatest unit of time with which 5 hours 15 minutes and 8 hours 24 minutes can both be represented as integers. (a) 70 min. (b) 63 min. (c) 48 min. (d) 42 min.

Description : Find the greatest unit of time with which 5 hours 15 minutes and 8 hours 24 minutes can both be represented as integers. (a) 70 min. (b) 63 min. (c) 48 min. (d) 42 min.

Last Answer : 63 min. 

Insulin is a dimmer. The number of amino acids in the A and B chain respectively is (A) 19 and 28 (B) 21 and 30 (C) 25 and 35 (D) 29 and 38

Description : Insulin is a dimmer. The number of amino acids in the A and B chain respectively is (A) 19 and 28 (B) 21 and 30 (C) 25 and 35 (D) 29 and 38

Last Answer : Answer : B

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Description : A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

Insert the missing number: 16/32, 15 /33, 17/31, 14/34, ? (A) 19/35 (B) 19/30 (C) 18/35 (D) 18/30

Description : Insert the missing number: 16/32, 15 /33, 17/31, 14/34, ? (A) 19/35 (B) 19/30 (C) 18/35 (D) 18/30

Last Answer : Answer: D 16/32 then 15/33 means -1/+1, 17/31 means +2/-2, 14/34 means -3/+3 next +4/-4 i.e 18/30

The normal serum CO2 content is (A) 18–20 meq/L (B) 24–29 meq/L (C) 30–34 meq/L (D) 35–38 meq/L

Description : The normal serum CO2 content is (A) 18–20 meq/L (B) 24–29 meq/L (C) 30–34 meq/L (D) 35–38 meq/L

Last Answer : Answer : B

The optimum temperature for sugarcane is (a) 21-27 °C (b) 14-29 °C (c) 25-30 °C (d) 28-34 °C

Description : The optimum temperature for sugarcane is (a) 21-27 °C (b) 14-29 °C (c) 25-30 °C (d) 28-34 °C

Last Answer : (b) 14-29 °C

What is the smallest number that can be divided by 6 and 7 which leaves a remainder of 4?

Description : What is the smallest number that can be divided by 6 and 7 which leaves a remainder of 4?

Last Answer : The number will 46. (42+4)The number will be 4 greater than their LCM (least commonmultiple) which is 42.Since the two numbers are relatively prime (have no common primefactors) the LCM is 6 x 7.

Minimum clear cover (in mm) to the main steel bars in slab, beam, column and footing respectively, are (a) 10, 15, 20 and 25 (b) 15, 25, 40 and 75 (c ) 20, 25, 30 and 40 (d) 20, 35, 40 and 75

Description : Minimum clear cover (in mm) to the main steel bars in slab, beam, column and footing respectively, are (a) 10, 15, 20 and 25 (b) 15, 25, 40 and 75 (c ) 20, 25, 30 and 40 (d) 20, 35, 40 and 75

Last Answer : (b) 15, 25, 40 and 75

The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Description : The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Last Answer : p(x) is divided by x+ 2 =

The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Description : The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Last Answer : p(x) is divided by x+ 2 =

On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Description : On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

If ax^3 + bx^2 + x – 6 has (x + 2) as a factor and leaves a remainder 4, when divided by (x – 2), the value of a and b respectively are : -Maths 9th

Description : If ax^3 + bx^2 + x – 6 has (x + 2) as a factor and leaves a remainder 4, when divided by (x – 2), the value of a and b respectively are : -Maths 9th

Last Answer : Let p(x) = ax³ + bx² + x - 6 A/C to question, (x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0 So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0 ⇒ ... --(2) solve equations (1) and (2), 4a = 0 ⇒a = 0 and b = 2 Then, equation will be 2x² + x - 6

A bakery bakes 15 batches of 29 cupcakes each week. How many individual cupcakes do they make each week What is the remainder when 57 is divided by 6?

Description : A bakery bakes 15 batches of 29 cupcakes each week. How many individual cupcakes do they make each week What is the remainder when 57 is divided by 6?

Last Answer : 350

What is 64 divided by 29 with a. remainder?

Description : What is 64 divided by 29 with a. remainder?

Last Answer : The quotient is 2 with a remainder of 6

What is the remainder of 34 divided by 6?

Description : What is the remainder of 34 divided by 6?

Last Answer : 5.6667

Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these

Description : Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? A.27 7/9 m B.28 m C.29 m D.30 2/7 m E.None of these 

Last Answer : Answer – A (27 7/9 m) Explanation – When SAME direction- MINUS Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec. Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his 20 coins and Marat loses 30 coins. Now, the ratio of gold coins with them is 41:34:46, respectively. How many coins did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these

Description : Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his ... did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these 

Last Answer : Answer: A 41x+40+34x+20+46x+30=4325 =>121x=4325-90 =>x=35 Required answer, number of coins received by parat =34x+20=34×35+20=1210

The average marks scored by two Class A1 and A2 students are 120 and 130 respectively. If 8 students are moved from Class A2 to Class A1 and the average marks of the two Class get interchanged. Find the total number of students in two Class put together, if the average marks scored by the 8 students who moved is 150 A) 25 B) 30 C) 35 D) 40

Description : The average marks scored by two Class A1 and A2 students are 120 and 130 respectively. If 8 students are moved from Class A2 to Class A1 and the average marks of the two Class get interchanged. Find the total number ... average marks scored by the 8 students who moved is 150 A) 25 B) 30 C) 35 D) 40

Last Answer :  D)  let the number of students in Class A1 be x and class A2 be y. Total marks scored by the students will be 120x and 130y, the average gets interchanged after moving student from y Thus we get, 130y- ... (x+8) 120x+1200=130x+1040 10x=160 X=16 Thus the total number of students =24+16=40

What number is greater than 10 and has the property that when divided either by 5 or by 7 the remainder is 1 what is the smallest odd counting number that has this property?

Description : What number is greater than 10 and has the property that when divided either by 5 or by 7 the remainder is 1 what is the smallest odd counting number that has this property?

Last Answer : 71

What is the smallest positive number that will give a remainder of 3 when it is divided by 4 5 or 10?

Description : What is the smallest positive number that will give a remainder of 3 when it is divided by 4 5 or 10?

Last Answer : Try 23

What is the smallest positive number that will give a remainder of 3 when it is divided by 4 5 or 10?

Description : What is the smallest positive number that will give a remainder of 3 when it is divided by 4 5 or 10?

Last Answer : Try 23

Each branch of amylopectin is at an interval of glucose units: (A) 14–20 (B) 24–30 (C) 34–40 (D) 44–50

Description : Each branch of amylopectin is at an interval of glucose units: (A) 14–20 (B) 24–30 (C) 34–40 (D) 44–50

Last Answer : B

Lakshadweep is a group of how many islands? [Teachers' Exam 1994] (a) 22 (b) 25 (c) 32 (d) 35

Description : Lakshadweep is a group of how many islands? [Teachers' Exam 1994] (a) 22 (b) 25 (c) 32 (d) 35

Last Answer : Ans: (b)

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these

Description : The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these

Last Answer : Answer – D (548) Explanation – Required number = (L.C.M. of 12, 15, 20, 54) + 8 = 540 + 8 = 548.

If the polynomial x^19 + x^17 + x^13 + x^11 + x^7 + x^5 + x^3 is divided by (x^2 + 1), then the remainder is : -Maths 9th

Description : If the polynomial x^19 + x^17 + x^13 + x^11 + x^7 + x^5 + x^3 is divided by (x^2 + 1), then the remainder is : -Maths 9th

Last Answer : answer:

Mark the correct option relating to age limit a) For WLI & EA policies the insurant should not be less than 19 year an not more than 55 year on the date of next birthday b) For CWLA the upper age limit is 50 year c) The max age limit for 15 and 20 year AEA is 45 and 40 respectively d) Under Ugal suraksha policy age at entry of both the spouses should not be less than 21 year and not more than 45 year. e) All the above

Description : Mark the correct option relating to age limit a) For WLI & EA policies the insurant should not be less than 19 year an not more than 55 year on the date of next birthday b) For CWLA the upper age ... of both the spouses should not be less than 21 year and not more than 45 year. e) All the above

Last Answer : e) All the above

Which article of the constitution prohibits the employment of children bellow 14 years of age in any factory ,mine or other hazardous job- a) Art-14 b) Art-19 c) Art-24 d) Art-29

Description : Which article of the constitution prohibits the employment of children bellow 14 years of age in any factory ,mine or other hazardous job- a) Art-14 b) Art-19 c) Art-24 d) Art-29

Last Answer : c) Art-24

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

In Joule's experiment, an insulated container contains 20 kg of waterinitially at 25°C. It is stirred by an agitator, which is made to turn by aslowly falling body weighing 40 kg through a height of 4 m. The process isrepeated 500 times. The acceleration due to gravity is 9.8 ms-2. Neglectingthe heat capacity of agitator, the temperature of water (in °C) is(A) 40.5(B) 34.4(C) 26.8(D) 25

Description : In Joule's experiment, an insulated container contains 20 kg of waterinitially at 25°C. It is stirred by an agitator, which is made to turn by a slowly falling body weighing 40 kg through a height of 4 m. The process is repeated ... temperature of water (in °C) is (A) 40.5 (B) 34.4 (C) 26.8 (D) 25

Last Answer : (B) 34.4

A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32

Description : A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively: (1) 14 and 15 (2) 14 and 29 (3) 15 and 14 (4) 16 and 32

Last Answer : (3) 15 and 14

If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

Description : If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, ... , the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

Last Answer : Answer: Option C

When (x^3 – 2x^2 + px – q) is divided by (x^2 – 2x – 3), the remainder is (x – 6), What are the values of p and q respectively ? -Maths 9th

Description : When (x^3 – 2x^2 + px – q) is divided by (x^2 – 2x – 3), the remainder is (x – 6), What are the values of p and q respectively ? -Maths 9th

Last Answer : answer:

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

The average weather(rainfall) for the first 6 days out of 8 days recorded to be 9 cm. The rainfall on last 2 days was in the ratio 2:3. the average of 8 days was 14.2 cm. What was the rainfall on the last day? A) 7.8 B) 34.4 C) 35.76 D) 8.9

Description : The average weather(rainfall) for the first 6 days out of 8 days recorded to be 9 cm. The rainfall on last 2 days was in the ratio 2:3. the average of 8 days was 14.2 cm. What was the rainfall on the last day? A) 7.8 B) 34.4 C) 35.76 D) 8.9

Last Answer : C) according to question (6×9+3x+2x)/8=14.2 54+5x=113.6 X=11.92 Last day rainfall=3×11.92=35.76cm

By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Description : By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Last Answer : Selling price = Rs. 40 Loss = 20% Therefore, cost price = 40×100 /(100 - 20) = Rs. 50 Therefore, cost price of each lemon = Rs. 50/45 Now, selling price = Rs. 24 Profit = 20% Cost price = 24×100/120 = Rs. 20 Number of lemons for Rs. 20 = 20/(50/45) = 900/50 = 18 Answer: d)

The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20

Description : The Cricketer average score in 40 over is 21, if the man scores 23runs in 8over, 26 runs in 10 over and 18runs in 14 over. What is the average score in remaining over? A) 18 B) 19 C) 16 D) 20 

Last Answer : A) According to the question 40*21=23*8+26*10+18*14+8×X 840=184+260+252+8x 8x=144  X=144/8=18 runs

The stresses developed in concrete and steel in reinforced concrete beam 25 cm width and 70 cm effective depth, are 62.5 kg/cm2 and 250 kg/cm2 respectively. If m = 15, the depth of its neutral axis is (A) 20 cm (B) 25 cm (C) 30 cm (D) 35 cm

Description : The stresses developed in concrete and steel in reinforced concrete beam 25 cm width and 70 cm effective depth, are 62.5 kg/cm2 and 250 kg/cm2 respectively. If m = 15, the depth of its neutral axis is (A) 20 cm (B) 25 cm (C) 30 cm (D) 35 cm

Last Answer : Answer: Option C

`IP_(1),IP_(2),IP_(3),IP_(4) and IP_(5)` for an element is 7.1,14.3,34.5,46.8 and 162.2 eV respectively then element is :-

Description : `IP_(1),IP_(2),IP_(3),IP_(4) and IP_(5)` for an element is 7.1,14.3,34.5,46.8 and 162.2 eV respectively then element is :-

Last Answer : `IP_(1),IP_(2),IP_(3),IP_(4) and IP_(5)` for an element is 7.1,14.3,34.5,46.8 and 162.2 eV respectively then element is :- A. Na B. Si C. F D. Ca

What is the remainder of 494 divided by 14?

Description : What is the remainder of 494 divided by 14?

Last Answer : 35.2857