Description : The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of these numbers is 275, then find the other number.
Last Answer : Ans 2. Product of two number s = product of their H.C.F. and L.C.M. required number = 11 X 7700/275 = 308
Description : The sum of two numbers is 528 and their H.C.F is 33. What is the number of pairs of such numbers ? (a) 4 (b) 12 (c) 8 (d) 6
Last Answer : Ans 5. 4 Hint : Let the number be 33x and 33y where x and y are co-prime.
Description : Three measuring rods are 64 cm,80 cm and 96 cm in length . What is the least length of cloth that can can be measured exact number of times using any one of these rods? (a) 9.60 m (b) 8 m (c) 9.60 cm (d) 96 m
Last Answer : Ans 4. 9.60 m
Description : The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19 , 29 and 34 respectively is (a) 1994 (b) 1494 (c) 1394 (d) 1496
Last Answer : 1394 Hint: Note that 20 -4 = 6; 25 -19 = 6;35-29= 6;40- 34 = 6 Required number = L.C.M. of ( 20, 25, 35 and 40)-6
Description : The largest numbers which divides 30, 78 and 102 to leave the same remainder in each case is (a)24 (b) 20 (c) 8 (d) 16
Last Answer : 24
Description : A gardener had a number of shrubs to plant in rows . At first he tried to plant 8, then 12 and then 16 in a row but he always had 3 shrubs left with him . On trying 7 shrubs he was left with none.Find the total number of shrubs.
Last Answer : Ans 3. L.C.M of 8,12,16 = 48 Now, 48 x 1 + 3 = 51 - not divisible by 7 48 x 2 + 3 = 99 - not divisible by 7 48 x 3 + 3 = 147 - not divisible by 7 Required number = 147
Description : Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?
Last Answer : Ans 1. L.C.M of 2, 4, 6, 8, 10 and 12 is 120. so, the bells will toll together after 120 seconds i.e. 2 minutes . In 30 minutes the bells toll together 30/2 + 1 times i.e. times.
Description : Find the least number of five digits which is exactly divisible by 12, 15 and 18. (a) 1080 (b) 10080 (c) 10025 (d) 11080
Last Answer : 10080 Hint : The least number of 5 digits is 10000. L.C.M. of 12, 15 and 18 is 180 . On dividing 10000 is 100. => 10000 + 180- 100 = 10080 is divisible by 180.
Description : Find the greatest unit of time with which 5 hours 15 minutes and 8 hours 24 minutes can both be represented as integers. (a) 70 min. (b) 63 min. (c) 48 min. (d) 42 min.
Last Answer : 63 min.
Description : The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: A.30 B.22 C.40 D.60 E.None of these
Last Answer : Answer – C (40) Explanation – Let the numbers be 2x and 3x. Then, their L.C.M. = 6x. So, 6x = 48 or x = 8. The numbers are 16 and 24. Hence, required sum = (16 + 24) = 40.
Description : The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: A.269 B.275 C.308 D.310 E.None of these
Last Answer : Answer – C (308) Explanation – Other number =[11 x 7700]/275 = 308
Description : A student was once given a simple task to accomplish. He was given 6 numbers: 1, 10, 20, 30, 40, and 80, and was told to sum them together to be equal to 100. At last, he was able to accomplish this task. How did he do it? -Riddles
Last Answer : He read 10 and 80 backwards to give him 01 and 08 respectively. So, 1 + 01 + 20 + 30 + 40 + 08 = 100.
Description : Amount of phenylacetic acid excreted in the urine in phenylketonuria is (A) 100–200 mg/dL (B) 200–280 mg/dL (C) 290–550 mg/dL (D) 600–750 mg/dL
Last Answer : Answer : C
Description : Standard quantity of material per unit 5KG. Standard Price Rs 5 per KG. actual number of units 400 units. Actual quantity 2,200KG and price of material Rs 4.80 per kg. Calculate material price. a) 100(F) b) 500(A) c) 440(F) d) 600(F)
Last Answer : The standard quantity of material per unit is 5KG, so the standard quantity for 400 units would be: Standard quantity = 5KG/unit x 400 units = 2000KG The standard price per KG is Rs 5, so the ... material cost was lower than the standard material cost. Option (c) is the correct answer: 440(F).
Description : To pump water from a water reservoir 3 m deep and maximum water level at 135 m, a pump is installed to lift water up to R.L. 175 m at a constant rate of 36,00,000 litres per hour. If the length of the ... the water horse power of the pump is (A) 400 (B) 450 (C) 500 (D) 600
Last Answer : (D) 600
Description : A 15-year-old girl was seen by her family physician because of increasing lethargy. She had a recent history of the "flu". Biochemistry tests show that she has renal impairement. ... will likely develop a restrictive lung disease 5) She will probably improve with additional corticosteroid therapy
Last Answer : Answers-2 The findings point to focal segmental glomerulosclerosis (FSGS), which leads to chronic renal failure in half of cases. The lack of resolution with corticosteroid therapy and the progression to chronic renal failure is what sets FSGS apart from minimal change disease.
Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180
Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)
Description : Osmotic pressure of plasma is (A) 80–100 milliosmole/litre (B) 180–200 milliosmole/litre (C) 280–300 milliosmole/litre (D) 380–400 milliosmole/litre
Description : The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: A.124 B.100 C.111 D.175 E.None of these
Last Answer : Answer – C (111) Explanation – Let the numbers be 37a and 37b. Then, 37a x 37b = 4107 ab = 3. Now, co-primes with product 3 are (1, 3). So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Description : Calculate the Polar moment of inertia in m 4 of a single motor system from the following data: C = 8 GN/m 2 , L=9m, I = 600 Kg-m 2 , f=10 Hz a) 0.00027b) 0.00032 c) 0.00045 d) 0.00078
Last Answer : a) 0.00027
Description : If the degree of saturation of a partially saturated soil is 60%, then air content of the soil is (A) 40 % (B) 60 % (C) 80 % (D) 100 %
Last Answer : (A) 40 %
Description : Which of the following statements regarding cash flow patterns (for time periods 0, 1, 2, 3, and 4) is correct? A. The sequence of -Rs.100, Rs.50, Rs.40, Rs.60, and Rs.50 is a non-conventional cash ... -Rs.50, Rs.50, Rs.70, Rs.60, and -Rs.150 potentially has at most two internal rates of return.
Last Answer : B. The sequence of -Rs.100, Rs.600, -Rs.1,100, Rs.600, and Rs.20 potentially has a maximum of two internal rates of return.
Description : A hollow shaft of 1 m length is designed to transmit a power of 30 kW at 700 rpm. The maximum permissible angle of twist in the shaft is 1o. The inner diameter of the shaft is 0.7 times the outer diameter. The modulus of ... shaft is _______. (a) 43 to 45 (b) 50to 60 (c) 70 to 80 (d) 85 to 100
Last Answer : (a) 43 to 45
Description : 90% of the caprolactam is converted to nylon-6 on its condensation polymerisation in the reactor maintained at a temperature of __________ °C. (A) -5 (B) 10-30 (C) 250-280 (D) 500-600
Last Answer : (C) 250-280
Description : Abel apparatus is used for those oils, whose flash points are _______°F. (A) < 120 (B) > 120 (C) > 280 (D) 300-600
Last Answer : (A) < 120
Description : 90% of the caprolactam is converted to nylon-6 on its condensation polymerisation in the reactor maintained at __________ °C. (A) < 0 (B) 10-30 (C) 250-280 (D) 500-600
Last Answer : (B) 10-30
Description : Typical human voice is centered around ________Hz. (A) 200-400 (B) 280-3000 (C) 400-600 (D) 1400-1800
Last Answer : (B) 280-3000
Description : 280 600 ? 2504 5036 a) 1364 b) 1236 c) 1362 d) 1361 e) None of these
Last Answer : 118 – 35 = 83 280 – 118 = 162 =>162 – 83 = 79 280 – 118 = 162 600 – 280 = 320 =>320 – 162 = 158 Answer: b)
Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Last Answer : B. 80 L
Description : 2 If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Description : A gun fires shell with a muzzle velocity of 600 m/sec. The angle of inclination of the gun so that the shell hits a target at a distance of 32 km at level 100 m higher than the gun would be approximately? a.60? b.45? c.30? d.15? e.Either of (A) and (C)
Last Answer : e. Either of (A) and (C)
Description : A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s.How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above
Last Answer : Radius = 70m, So circumference = 2 (22/7) 70 =440m Relative speed = 10 +20 = 30m/s They will meet everytime at the starting point when the distance covered by both put together is a multiple of 440 ... =1800/44 =40.9 So they will meet 40 times (we need to ignore the decimal part). Answer : b
Description : A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s. How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above
Description : Calculate the power output in horsepower of an 80-kg man that climbs a flight of stairs 3.8 m high in 4.0 s. a) 744.8 hp b) 0.998 hp c) 746 hp d) 1.998 hp Formula: Power = Fd/t = mgh/t F = W = mg d = h
Last Answer : 0.998 hp
Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17
Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.
Description : The sum of two numbers is 14. The larger number minus three times the lesser number is -2. What is the lesser number?
Last Answer : 16
Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60
Last Answer : 45
Description : The normal value of over flow rates for plain primary sedimentation tanks, ranges between A. 25,000 to 35,000 litres/sqm/day B. 40,000 to 50,000 litres/sqm/day C. 50,000 to 60,000 litres/sqm/day D. 80,000 to 100,000 litres/sqm/day
Last Answer : ANS: B
Description : The normal values of over flow rates for sedimentation tanks using coagulant, ranges between A. 25,000 to 35,000 litres/sqm/day B. 40,000 to 50,000 litres/sqm/day C. 50,000 to 60,000 litres/sqm/day D. 80,000 to 100,000 litres/sqm/day
Last Answer : ANS: C
Description : A four pole turbogenerator is used in conjunction with a 160 pole propulsion motor. If the generator is turning at 3,200 RPM, what is the current speed of the propeller? A. 40 RPM B. 60 RPM C. 80 RPM D. 100 RPM
Last Answer : Answer: C
Description : What is the area in floriculture (in 000 hectare) in India ? (A) 40 – 50 (B) 60 – 80 (C) 100 – 120 (D) None of these
Last Answer : (C) 100 – 120
Description : An intense rain is falling at a uniform rate of 7.5 cm/hour for a period of 60 minutes on a basin whose area is 500 hectares. If the average infiltration capacity during the entire rain period is assumed to be 1.5 ... of the basin, is (A) 40 cumecs (B) 60 cumecs (C) 80 cumecs (D) 100 cumecs
Last Answer : Answer: Option C
Description : Which of the following represents hardest grade of bitumen? (A) 30/40 (B) 60/70 (C) 80/100 (D) 100/120
Last Answer : Answer: Option A
Description : The usual spans with R.C.C. poles are (a) 40—50 meters (b) 60—100 meters (c) 80—100 meters (d) 300—500 meters
Last Answer : (c) 80—100 meters
Description : Transmission voltage of ll kV is normally used for distances upto (a) 20—25 km (b) 40—50 km (c) 60—70 km (d) 80—100 km
Last Answer : (a) 20—25 km
Description : What is the area in floriculture (in 1000 hectare) in India a) 40 - 50 b) 60 - 80 c) 100 - 120 d) None of these
Last Answer : c) 100 - 120
Description : The first electronic general purpose digital computer built by Eckert and Mauchly called ENIAC did not work on the stored program concept. How many numbers could it store in its internal memory? A) 100 B) 20 C) 40 D) 80
Last Answer : Answer : B
Description : How many numbers could ENIAC store in its internal memory A) 100 B) 20 C) 80 D) 40
Description : The first electronic general purpose digital computer built by Mauchly and Eckert called ENIA did not work on the stored program principle. How many numbers could it store in its internal memory? a. 100 b. 20 c. 40 d. 80
Last Answer : 20