I. 2a^2 − 11a + 12 = 0 II. 35b^2 − 18b − 8 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

I. 2a^2 − 11a + 12 = 0

II. 35b^2 − 18b − 8 = 0

1 : if a > b

2 : if a < b

3 : if a ≥ b

4 : if a ≤ b

5 : if a = b or the relation between a and b cannot be established.
by

1 Answer

Answer :

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1 : if a > b

by

Related questions

I. 28a^2 + 25a − 8 = 0 II. 5b^2 − 13b − 6 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 28a^2 + 25a − 8 = 0 II. 5b^2 − 13b − 6 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 5 : if a = b or the relation between a and b cannot be established.  

I. 12a^2 − a − 6 = 0 II. 8b^2 − 26b + 15 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 12a^2 − a − 6 = 0 II. 8b^2 − 26b + 15 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 4 : if a ≤ b

I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 20a^2 + 51a + 28 = 0 II. 15b^2 − 61b + 56 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 2 : if a < b

I. 32a^2 + 52a + 15 = 0 II. 8b^2 + 38b + 35 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Description : I. 32a^2 + 52a + 15 = 0 II. 8b^2 + 38b + 35 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.

Last Answer : 3 : if a ≥ b

I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 4 : if x < y

I. 63x^2 – 275x + 300 = 0 II. 18y^2 – 85y + 100 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 63x^2 – 275x + 300 = 0 II. 18y^2 – 85y + 100 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 2 : if x ≤ y

I. 20x^2 – 119x + 176 = 0 II. 18y^2 – 123y + 209 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 20x^2 – 119x + 176 = 0 II. 18y^2 – 123y + 209 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 5 : if x = y or relationship cannot be  established

I. 3x^2 – 47x + 184 = 0 II. 3y^2 – 38y + 119 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 3x^2 – 47x + 184 = 0 II. 3y^2 – 38y + 119 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 3 : if x > y

I. 6x^2 – 71x + 195 = 0 II. 12y^2 – 97y + 195 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 6x^2 – 71x + 195 = 0 II. 12y^2 – 97y + 195 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 1 : if x ≥ y

What is the radius of the circle/ I.Ratio of its area to circumference is >7. II.Diameter of the circle is ≤ 32. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question.

Description : What is the radius of the circle/ I.Ratio of its area to circumference is >7. II.Diameter of the circle is ≤ 32. If the question can be answered with the help of statement I alone, If ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question.

Last Answer : Let the radius of the circle be r units From statement 1: [πr^2]/ [ 2 πr ] > 7 or r > 14 From statement II: 2r≤32 R ≤ 16 Hence, r can be 15 or 16 units Hence, Answer : d

√(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Description : √(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Last Answer : Answer: d)

(1024 − 263 − 233) ÷ (986 − 764 − 156) = ? a) 9 b) 6 c) 7 d) 8 e) None of these

Description : (1024 − 263 − 233) ÷ (986 − 764 − 156) = ? a) 9 b) 6 c) 7 d) 8 e) None of these

Last Answer : Answer: d) 

Naphthenic acid is represented by (A) CnH2n+2O2 (B) CnH2n-2O2 (C) CnH2n+2O2 (n ≥ 6) (D) CnH2n+6O2 (n ≤ 6)

Description : Naphthenic acid is represented by (A) CnH2n+2O2 (B) CnH2n-2O2 (C) CnH2n+2O2 (n ≥ 6) (D) CnH2n+6O2 (n ≤ 6)

Last Answer : (B) CnH2n-2O2

. Which of the following relationships between co-efficient of friction (μ) between rock & roll and a (half of the angle of nip) of the particle to be crushed is correct? (A) μ > tan α (B) μ ≥ tan α (C) μ > tan 2α (D) μ ≤ tan α

Description : . Which of the following relationships between co-efficient of friction (μ) between rock & roll and a (half of the angle of nip) of the particle to be crushed is correct? (A) μ > tan α (B) μ ≥ tan α (C) μ > tan 2α (D) μ ≤ tan α

Last Answer : (B) μ ≥ tan α

The grammar with production rules S → aSb |SS|λ generates language L given by: (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (B) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≤ nb(v) where v is any prefix of w} (C) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (D) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≤ nb(v) where v is any prefix of w}

Description : The grammar with production rules S → aSb |SS|λ generates language L given by: (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} (B) L = {w∈{a, b}* | na(w) = nb(w) and na(v ... (D) L = {w∈{a, b}* | na(w) ≠ nb(w) and na(v) ≤ nb(v) where v is any prefix of w}

Last Answer : (A) L = {w∈{a, b}* | na(w) = nb(w) and na(v) ≥ nb(v) where v is any prefix of w} 

A set of processors P1, P2, ......, Pk can execute in parallel if Bernstein's conditions are satisfied on a pair wise basis; that is P1 || P2 || P3 || ..... || Pk if and only if: (A) Pi || Pj for all i ≠ j (B) Pi || Pj for all i = j+1 (C) Pi || Pj for all i ≤ j (D) Pi || Pj for all i ≥ j

Description : A set of processors P1, P2, ......, Pk can execute in parallel if Bernstein's conditions are satisfied on a pair wise basis; that is  P1 || P2 || P3 || ..... || Pk if and only if: (A) Pi || Pj for all i ≠ j (B) Pi || Pj for all i = j+1 (C) Pi || Pj for all i ≤ j (D) Pi || Pj for all i ≥ j

Last Answer : (A) Pi || Pj for all i ≠ j Explanation: Bernstein's Condition: 1. If process Pi writes to a memory cell Mi, then no process Pj can read the cell Mi. 2. If process Pi read from a memory ... Mi. 3. If process Pi writes to a memory cell Mi, then no process Pj can write to the cell Mi.

If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Description : If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Last Answer : Let the rate of interest p.c.p.a. be x. 2496 =15000 * x /100 x = 16.64 16.64 is the rate of interest compounded for two year & for one year = 8% 8% C.I. table for two year. I year = 8% II year = 8.64 Total =16.64% Answer: a)

Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 units of labour. There is a no other constraint on production. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : from statement I : Let the price of product Q be P' Then the price of product R is 4P From Statement II: Cost of product Q =2 Cost of product R=5 Therefore, Profit percentage of product ... )=80P-100 Hence, product R is more profitable. Both statements are required to answer the question Answer :c

A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger in age gets 6 chocolates. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : From both statement I and II: Let the number of chocolates received by child older than 5 years be x and that of for child than 5 years or younger be y Therefore, 5x + 6 y = 43 Since x and y has to ... for the above equation will be x=5 and y=3 Hence, 5 children are older than 5 years Answer : c

Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 units of labour. There is a no other constraint on production. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : Is it more profitable for Company M to produce Q? I. Product R sells at a price four times that of Q II. One unit of Q requires 2 units of labour, while one unit of R requires 5 ... both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : from statement I : Let the price of product Q be P' Then the price of product R is 4P From Statement II: Cost of product Q =2 Cost of product R=5 Therefore, Profit percentage of product ... )=80P-100 Hence, product R is more profitable. Both statements are required to answer the question Answer :c

X says to Y,”I am 3 times as old as you were 3 years ago”.How old is X? I. Y ‘s age 17 years from now is same as X’s present age. II. X’s age nine years from now is 3 times Y’s present age. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : X says to Y, I am 3 times as old as you were 3 years ago .How old is X? I. Y s age 17 years from now is same as X's present age. II. X's age nine years from now is ... with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : Let the current ages of X and Y be a and b respectively From the question: A=3(a-b) From statement I: A=b + 17 B = a-17 Therefore, a = 3(a-17-3) a=3a-60 2a=60 A=30 Hence, X ... a+9)/3 Substituting this in first equation, A=a+9-9 Hence, no result Therefore, statement I alone is sufficient Answer :a

An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these

Description : If the numerator of a fraction is increased by 25% and the denominator is doubled, the fraction thus obtained is 5/9. What is the original fraction? a) 3/4 b) 7/8 c) 8/9 d) Cannot be determined e) None of these

Last Answer : Let the numerator & denominator of a fraction be n & d. According to questions, = n × 5 / d × 8 = 5/9 = n/d = 8 × 5 / 5 × 9 = n/d = 8/9 Answer: c)

A and B established a firm together. A’s investment was thrice that of B’s. A also kept the investment for twice as much time as B. If B got a profit of 4000, what was the total profit? A.30,000 B.28,000 C.40,000 D.45,000

Description : A and B established a firm together. A’s investment was thrice that of B’s. A also kept the investment for twice as much time as B. If B got a profit of 4000, what was the total profit? A.30,000 B.28,000 C.40,000 D.45,000

Last Answer : Answer- B(28,000) Explanation:- let B’s investment= X then A’s investment= 3X lets tim for B = t then,A’s time= 2t A:B 3X x 3t : X x t 6:1 B’s share= 1/7 x total = 4000 total=28,000

The IEEE 802.11a, uses _________. A) FHSS B) DSSS C) OFDM D) either (a)or (b)

Description : The IEEE 802.11a, uses _________. A) FHSS B) DSSS C) OFDM D) either (a)or (b)

Last Answer : OFDM

Which of the following is developing CCK-OFDM? a) IEEE 802.11a b) IEEE 802.11b c) IEEE 802.15.4 d) IEEE 802.11g

Description : Which of the following is developing CCK-OFDM? a) IEEE 802.11a b) IEEE 802.11b c) IEEE 802.15.4 d) IEEE 802.11g

Last Answer : d) IEEE 802.11g

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Description : The average age of 30 students in a class is 12 years. The average age of a group of 5 of the students is 10 years and that of another group of 5 of them is 14 years. The average of the remaining students is : a) 8 years b) 10 years c) 12 years d) 14 years e) 15 years

Last Answer : Let it be x . Then : 5×10+5×14+20×x=30×12 20x=360-120 or 20x=240 or x = 12 Answer: c)

A and B enter into a partnership. A contributes Rs. 16,000 and B Rs. 12,000. At the end of 6 months C joins them with a capital of Rs. 20,000. In what ratio should they divide their annual profit? a) 8:6:5 b) 4 :3 :5 c) 5:6:8 d) 5:3:4 e) 5:7:8

Description : A and B enter into a partnership. A contributes Rs. 16,000 and B Rs. 12,000. At the end of 6 months C joins them with a capital of Rs. 20,000. In what ratio should they divide their annual profit? a) 8:6:5 b) 4 :3 :5 c) 5:6:8 d) 5:3:4 e) 5:7:8

Last Answer : a) 8:6:5

A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Description : A reduction of 20% in the price of sugar enables a person to get 7.8 kg more sugar for Rs.3.90. The original price of sugar per kg is a) Rs. 10 b) Rs.11.50 c) Rs. 12.5 d) Rs. 15 , e) Rs. 10.5

Last Answer : d) Rs. 15 ,

Pipe A can fill a water tank in 8 hours, Pipe B can fill the same tank in 12 hours and Pipe C can empty the tank in 24 hours. If all three pipes are opened together, in how many hours will the tank be completely filled or empty? a) 4.8 hours b) 5 hours c) 5.4 hours d) 6 hours e) 7.2 hours

Description : Pipe A can fill a water tank in 8 hours, Pipe B can fill the same tank in 12 hours and Pipe C can empty the tank in 24 hours. If all three pipes are opened together, in how many hours will the tank be completely filled or empty? a) 4.8 hours b) 5 hours c) 5.4 hours d) 6 hours e) 7.2 hours

Last Answer : If all the three pipes are opened together, in one hour they will fill 1/8 + 1/12 – 1/24 = (3+2-1)/24 = 1/6 part of tank. So, to fill it completely it will take 6 hours. Answer is: d)

A this usual rowing rate, Mohit can travel 12 miles downstream in a certain river in 6 hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24 miles round trip, the downstream 12 miles would then take only one hour less than the upstream 12 miles. What is the speed of the current in miles per hour? A.2.5m/hr B.4 m/hr C.8/3 m/hr D. 5/3m/hr

Description : A this usual rowing rate, Mohit can travel 12 miles downstream in a certain river in 6 hours less than it takes him to travel the same distance upstream. But if he could double his usual rowing rate for his 24 miles round trip, ... current in miles per hour? A.2.5m/hr B.4 m/hr C.8/3 m/hr D. 5/3m/hr

Last Answer : Answer-C Basic Formula: Speed of the stream = ½ (a-b) km/hr Explanation: Let the speed in still water be x m/hr Speed of stream be y m/hr Then, speed upstream = x-y m/hr and Speed downstream = x+y m/hr 12/x-y - ... 1] 3y^2 = 8 y so, y = 8/3 speed of the current = 8/3 m/hr = 2 (2/3) m/hr

The average age of two persons is 46 years. 16 years back the ratio between their ages were 1 : 2, then what is the difference between present ages of these two persons? 1) 16 years 2) 20 years 3) 24 years 4) 12 years 5) 8 years

Description : The average age of two persons is 46 years. 16 years back the ratio between their ages were 1 : 2, then what is the difference between present ages of these two persons? 1) 16 years 2) 20 years 3) 24 years 4) 12 years 5) 8 years

Last Answer : 2) 20 years

Is X divisible by 12? a. X leaves a remainder 2 when divided by 8 b. X is divisible by 3. c. X is divisible by 6. a) If the data in statement a is sufficient to answer the question, while the data in statement b and c are not required to answer the question. b) If the data in statement b is sufficient to answer the question, while the data in statement a and c are not required to answer the question c) If the data in statement a and b are sufficient to answer the question, while the data in statement c is not required to answer the question. d) If the data in statement a, b and c together are necessary to answer the question. e) If the data in statement a, b and c together are not sufficient to answer the question.

Description : Is X divisible by 12? a. X leaves a remainder 2 when divided by 8 b. X is divisible by 3. c. X is divisible by 6. a) If the data in statement a is sufficient to answer the question, while ... the question. e) If the data in statement a, b and c together are not sufficient to answer the question.

Last Answer : From (a), we notice that the number is of the form 8n+2, which means it also leaves a remainder 2 on being divided by 4. So, its not divisible by 12. From (b) and (c) together, the number can be any multiple of 6, from which we cant conclusively say if number is divisible by 12. Answer: a)

A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has the son covered at the point when the father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

Description : A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has ... father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

Last Answer : Time taken is same for both father and son Let x be the distance son travelled before being overtaken by his father Time taken by son = x/5 km/hour Time taken by father = (1000 + x) / 7.5 km/hr Since, time taken is same x/5 = (1000 + x) / 7.5 or x = 2000m Answer: b)

15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Description : 15 30 ? 40 8 48 a) 10 b) 20 c) 18 d) 12 e) None of these

Last Answer : The series is ×2, ÷3, ×4, ÷5, ... Answer: a)

A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Description : A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Last Answer : Let quantities of milk and water in the mixture be 3x and 2x. Then if 4 litres of water is added to the mixture the ratio of milk and water become 1:1. It can be written as (3x): (2x + 4) = 1 ... Therefore, the milk in the mixture is 4x3 = 12 litres and quantity of water = 4x2 = 8 liters Answer: a)

8/15 of 3/17 of 12/13 of 15470 = ? a) 1242 b) 1344 c) 1464 d) 1504 e) 1624

Description : 8/15 of 3/17 of 12/13 of 15470 = ? a) 1242 b) 1344 c) 1464 d) 1504 e) 1624

Last Answer : b) 1344

The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these

Description : The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these

Last Answer : Answer – D (548) Explanation – Required number = (L.C.M. of 12, 15, 20, 54) + 8 = 540 + 8 = 548.

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of theseSix bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16

In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Description : In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Last Answer : C)1:2

Sanki purchased 20 dozen notebook at Rs. 48 per dozen. He sold 8 dozen at 10% profit and remaining 12 dozen with 20% profit. What is his profit percentage in the transaction? A. 8% B. 15% C. 16% D. 19%

Description : Sanki purchased 20 dozen notebook at Rs. 48 per dozen. He sold 8 dozen at 10% profit and remaining 12 dozen with 20% profit. What is his profit percentage in the transaction? A. 8% B. 15% C. 16% D. 19% 

Last Answer : Answer – C (16%) Explanation – C.P of 20 dozen = Rs.(48 x 20) = Rs.960 C.P of 8 dozen = Rs. (48 x8) = Rs. 384. C.P of 12 dozen =Rs. (960 – 384) = Rs. 576 Total S.P = Rs. (110/100 x 384 +120/100 x 576) = Rs.1113.60 ∴ Profit % = (153.60/960 x 100)% =16%

Hemant sold 10 sarees for a total profit of Rs. 460 and 12 sarees for a total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per sarees? A. Rs 7.10 B. Rs 7.60 C. Rs 7.99 D. Rs 8

Description : Hemant sold 10 sarees for a total profit of Rs. 460 and 12 sarees for a total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per sarees? A. Rs 7.10 B. Rs 7.60 C. Rs 7.99 D. Rs 8

Last Answer : Answer – B (Rs 7.60) Explanation – Total profit required = Rs.(42 x 18) = Rs.756 Profit on 22 sarees = Rs. (460 + 144) = Rs. 604 Profit on 20 sarees = Rs. (756 – 604) = Rs. 152 Average profit on these sarees = Rs.(152/20) = Rs. 7.60

The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books? A.Rs 10 and Rs 16 B.Rs 12 and Rs 24 C.Rs 24 and Rs 18 D.Rs 28 and Rs 12 E.None of these

Description : The average price of 10 books is Rs. 12 while the average price of 8 of these books is Rs. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of ... and Rs 16 B.Rs 12 and Rs 24 C.Rs 24 and Rs 18 D.Rs 28 and Rs 12 E.None of these

Last Answer : Answer - A (Rs 10 and Rs 16) Explanation - Total price of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26 Let the price of one book be Rs.x Then, the price of other book = Rs. (x ... /5)x= (8/5)x so, x +(8/5)x=26 , x=10 The prices of the two books are Rs. 10 and Rs. 16

For any two real number a b and , we defined aRb if and only if sin^2a + cos^2b = 1. The relation R is -Maths 9th

Description : For any two real number a b and , we defined aRb if and only if sin^2a + cos^2b = 1. The relation R is -Maths 9th

Last Answer : (d) an equivalence relationGiven, a R b ⇒ sin2a + cos2b = 1 Reflexive: a R a ⇒ sin2 a + cos2 a = 1 ∀ a ∈ R (True) Symmetric: a R b ⇒ sin2 a + cos2 b = 1 ⇒ 1 - cos2 a + 1 - sin2 b = 1 ⇒ sin2 b + ... + cos2 b + sin2 b + cos2 c = 2 ⇒ sin2 a + cos2 c = 1 ⇒ a R c (True)∴ R is an equivalence relation.

Rubesh generally takes 80 minutes to reach home from office. Due to rain, he travelled at 2/3rd of his usual speed for the 1st half of the distance. At what speed should rubesh travel the remaining distance to reach home on time? a) 1.5 times the original speed b) 2 times the original speed c) 2.5 times the original speed d) 3 times the original speed e) Cannot reach on time

Description : Rubesh generally takes 80 minutes to reach home from office. Due to rain, he travelled at 2/3rd of his usual speed for the 1st half of the distance. At what speed should rubesh travel the remaining distance ... c) 2.5 times the original speed d) 3 times the original speed e) Cannot reach on time

Last Answer : Under the normal speed, 40 minutes for half the distance Due to rain, time taken will be 40 / (2/3) = 40 × (3/2) = 60 minutes So, in 20 minutes he has to cover the distance he usually covers in 40 minutes. So, he has to travel at twice the original speed. Answer: b)

The price of two dozens of oranges is Rs.120/-more than the price of one kg. of mango. The price of one dozen of apple is Rs.80/- more than the price of one kg of mango. Which of the following represents the ratios of the price of one orange and one apple respectively? a) 4 : 5 b) 3 : 2 c) 7 : 9 d) Cannot be determined

Description : The price of two dozens of oranges is Rs.120/-more than the price of one kg. of mango. The price of one dozen of apple is Rs.80/- more than the price of one kg of mango. Which of the following represents the ... apple respectively? a) 4 : 5 b) 3 : 2 c) 7 : 9 d) Cannot be determined e) None of these

Last Answer : Because no. of mangoes is unknown. So ratio cannot be calculated. Answer: d)