363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523

363,795,1227,1659,2091, ?

1 : 2423

2 : 2613

3 : 2813

4 : 2513

5 : 2523
by

1 Answer

Answer :

Answer- 5 (2523)

Explanation- +432 in every step
by

Related questions

1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Description : 1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Last Answer : ? = 7897 × 4 × 3 / 8 × 5 × 7 = 338.31 = 338 (approx.) Answer: e)

2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)

(4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885

Description : (4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885

Last Answer : (4.36)^2 × 66.5 - 371 = ? = 19.0096 × 66.5 - 371 = ? = 1264.1384 - 371 = 893.1384 = 893 (approx.) Answer: b)

196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Description : 196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Last Answer : Answer-5 (862) Explanation- add square of prime no. in each step 4,9,25,49,121,so on

5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Description : 5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Last Answer : Answer- 2 (3910) Explanationadd 5^1,5^2,5^3,5^4,5^5 and so on in each step.

16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016

5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these

Description : 5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these

Last Answer : Answer-3(509) Explanation5 x2 +3 =13 13×2 +3=29 29×2+3=61 and so on..

5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975

Description : 5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975

Last Answer : Answer- 5(51975) Explanation- multiply by consecutive odd numbers 5×1=5 5×3=15 15×5=75 75×9=4725 4725×11=51975

24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240

Description : 24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240

Last Answer : Answer- 1 (17280) Explanation- 24 x 2=48 48×3=144 144×4=576 576×5=2880

4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60

Description : 4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60

Last Answer : Answer-2 (160) Explanation- 4725 / 4.5=1050 1050/3.5=300 300/2.5=120 120/1.5=80 80/0.5=160

3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556

Description : 3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556

Last Answer : Answer-3 (254545) Explanation25=(3×10)-5 255=(25×10)+5 2545=(255×10)-5 25455=(2545×10)+5 ?=(2545×10)-5 = 254545

3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624

Description : 3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624

Last Answer : Answer- 3 (3754) Explanation- x4+2

4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these

Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these 

Last Answer : Answer: a)

4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Description : 4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Last Answer : Multiply by 8. Answer: c)

729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541

Description : 729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541

Last Answer : Difference of Difference 9. Answer: a)

259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these

Description : 259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these

Last Answer : Difference of odd numbers 3, 5, 7, 9, 11. Answer: b)

3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

Description : 3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

Last Answer : Answer: a) 

9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598

Description : 9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598

Last Answer : 9654 ÷ 21 + 7338 ÷ 44 = ? = 459.714 + 173.59 = 633.304 = 633 (approx) Answer: a)

3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555

Description : 3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555

Last Answer : 3√7469 × √668 = ? = 19.5 × 25.9 = 505.05 = 505 (approx) Answer: c)

3, 0, -4, -17, -74, ? a) -309 b) -302 c) -363 d) -290 e) -377

Description : 3, 0, -4, -17, -74, ? a) -309 b) -302 c) -363 d) -290 e) -377

Last Answer : The pattern is 3×1-3 = 0 ,0×2-4 = -4 ,-4×3-5 = -17,-17×4-6 =-74,-74×5-7=-377 Answer: e)

What is the nearest tenth to 0.795?

Description : What is the nearest tenth to 0.795?

Last Answer : 0.8

The reduced level of a floor is 99.995 m, the staff reading on the floor is 1.505 m. If the inverted staff reading against the roof is 1.795 m, the floor level below the slab, is (A) 3.290 m (B) 3.300 m (C) 3.275 m (D) 2.790 m

Description : The reduced level of a floor is 99.995 m, the staff reading on the floor is 1.505 m. If the inverted staff reading against the roof is 1.795 m, the floor level below the slab, is (A) 3.290 m (B) 3.300 m (C) 3.275 m (D) 2.790 m

Last Answer : (B) 3.300 m

A hollow shaft has an inner diameter of 3.7 cm and an outer diameter of 4.0 cm. A 1 kN-m torque is applied to this shaft. What is the shear stress at the mid-radius of this shaft? (a) 117Mpa (b) 178 Mpa (c) 286 Mpa (d) 363 Mpa

Description : A hollow shaft has an inner diameter of 3.7 cm and an outer diameter of 4.0 cm. A 1 kN-m torque is applied to this shaft. What is the shear stress at the mid-radius of this shaft? (a) 117Mpa (b) 178 Mpa (c) 286 Mpa (d) 363 Mpa

Last Answer : (c) 286 Mpa

Suppose that we have numbers between 1 and 1000 in a binary search tree and want to search for the number 364. Which of the following sequences could not be the sequence of nodes examined? (A) 925, 221, 912, 245, 899, 259, 363, 364 (B) 3, 400, 388, 220, 267, 383, 382, 279, 364 (C) 926, 203, 912, 241, 913, 246, 364 (D) 3, 253, 402, 399, 331, 345, 398, 364

Description : Suppose that we have numbers between 1 and 1000 in a binary search tree and want to search for the number 364. Which of the following sequences could not be the sequence of nodes examined? (A) 925, 221, 912, 245, 899, ... 926, 203, 912, 241, 913, 246, 364 (D) 3, 253, 402, 399, 331, 345, 398, 364 

Last Answer : (C) 926, 203, 912, 241, 913, 246, 364

Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855

Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855

Last Answer : Answer: E  Increase = 90 % of 450  = 90/100 × 450  = 40500/100  = 405 Therefore, increase value = 450 + 405 = 855

187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Description : A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Last Answer : 125% C.P. of sugar per kg = Rs. 4.25 C.P of the sugar per kg = [4.25×100] / 125 = Rs. 3.40. thus, the profit on 1 kg 85 paise by reducing price to 5 paise, to make same profit he must sell, 85/5 = 17kg so required ratio = 1 : 17. Answer: d)

3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Description : 3 1/7 + 4 2/5 - ? = -2 3/5 a) a) 10 1/7 b) b) 7 1/10 c) c) 8 8/7 d) d) 9 8/7 e) None of these

Last Answer : 3 1/7 + 4 2/5 - ? = -2 3/5 22/7 + 22/5 + 13/5 = 355/35 = 71/7 = 10 1/7 Answer: a)

Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Description : Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5

Last Answer : Numerator = 4 + 72 – 14 = 62 Denominator = 738 – 730 = 8 Required value = 62/8 = 7.75 Answer: b)

Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Description : Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Last Answer : (0.625×0.0729×28.9) / (0.0081×0.025×1.7) = (625/25) × (729/81) × (289/17) = 25×9× 17 = 3825. Answer: d)

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at what time will they be reading the same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Description : Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at ... same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Last Answer : Ajay reads at average rate of 30 pages per hour ie. 1 page in every two minutes. Therefore, by 5:20 PM, he would have covered 25 pages By 6:20 PM, Ajay would have read 25+30 pages and Vikram would have ... and he will also finish 100 pages Hence, both of them will be on same page at 7:50 Answer: a)

A committee of 5 members is to be formed from 8 men and 5 women. How many committees can be formed if at least 2 women and 1 man have to present in the committee? a) 800 b) 840 c) 880 d) 920 e) 996

Description : A committee of 5 members is to be formed from 8 men and 5 women. How many committees can be formed if at least 2 women and 1 man have to present in the committee? a) 800 b) 840 c) 880 d) 920 e) 996

Last Answer : The various possible cases are: i. 2 women and 3 men = 5C2 × 8C3 = 10 × 56 = 560 ii. 3 women and 2 men = 5C3 × 8C2 = 10 × 28 = 280 iii. 4 women and 1 men = 5C4 × 8C1 = 5 × 8 = 40 Total = 560 + 280 + 40 = 880 Answer: c)

What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Description : What is the size of the longest pencil that can fit in a box with dimensions 12 cm× 10 cm× 8cm? a) 15 b) 15.5 c) 17 d) 17.5 e) 18

Last Answer : Answer: d)

The average monthly expenditure of a family was Rs. 2200 during the first 3 months; Rs. 2250 during the next 4 months and Rs. 3120 during the last 5 months of a year. If the total savings during the year were Rs. 1260, then the average monthly income was: a) Rs. 2605 b) Rs. 2680 c) Rs. 2705 d) Rs. 2745 e) Rs. 2595

Description : The average monthly expenditure of a family was Rs. 2200 during the first 3 months; Rs. 2250 during the next 4 months and Rs. 3120 during the last 5 months of a year. If the total savings during the year were Rs. 1260 ... income was: a) Rs. 2605 b) Rs. 2680 c) Rs. 2705 d) Rs. 2745 e) Rs. 2595

Last Answer : Total expenditure for first 3 months = 2200 3 = Rs 6600 Total expenditure for next 4 months = 2250 4 = Rs9000 Total expenditure for last 5 months = 3120 5 = Rs 15600 Total expenditure = 6600 + ... + savings = 31200 + 1260 = Rs 324060 Average monthly income = 32460/12 = Rs 2705 Answer: c)

Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Description : Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Last Answer : Let the sum be S, time be ‘n’ years for 6%. n+2 years for 5% 2400 = S + S ×n × 6/100 2400 = S + S × (n+2) × 5/100 So, 6n = 5(n+2) or n = 10 years. 2400 = S + S × 10 × 6/100 = 1.6S S = 2400/1.6 = 1500 Answer: a)

The monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio 9 : 7. If each person saves Rs. 500 per month, then what are their monthly incomes? a) Rs 8000 and Rs 10000 b) Rs 3750 and Rs 3000 c) Rs 5000 and Rs 4000 d) Rs 4500 and Rs 4000 e) None of the above

Description : The monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio 9 : 7. If each person saves Rs. 500 per month, then what are their monthly incomes? a) Rs 8000 and Rs ... Rs 3750 and Rs 3000 c) Rs 5000 and Rs 4000 d) Rs 4500 and Rs 4000 e) None of the above

Last Answer : Let the incomes of two persons be 5x and 4x let the expenditures of them be 9y and 7y Each person saves Rs. 500 Therefore, 5x - 9y = 500 4x - 7y = 500 Solving the above equations, 20x - 36y = 2000 20x - ... = 500 + 9(500) = 5000 X = 1000 Hence, their salaries are Rs. 5000 and Rs. 4000 Answer: c)

A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Description : A man can row 15 km/hr in still water. It takes him twice as long to row upstream as to row downstream. Find the rate of stream? a) 5 km/hr b) 10 km/hr c) 7.5 km/hr d) 6 km/hr e) 8 km/hr

Last Answer : Let the man’s upstream speed be x km/hour and downstream speed will be 2x km/hour Speed in still water = 1/2 (2x + x) = 3x/2 km/hour 3x/2 = 15 X = 10 Hence, his downstream speed = 20km/hour Rate of stream = 1/2 (20-10) = 5km/hour Answer: a)

5 ? 4 7.5 17 45 a) 3.5 b) 3 c) 2.5 d) 2 e) None of these

Description : 5 ? 4 7.5 17 45 a) 3.5 b) 3 c) 2.5 d) 2 e) None of these

Last Answer : The series is ×0.5 + 0.5, ×1 + 1, ×1.5 + 1.5, ... Answer: b)

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Description : 2 3 5 8 14 23 41 69 a) 5 b) 8 c) 14 d) 41 e) 69

Last Answer : The series is an alternate series, having S 1 = 2 5 14 41; ×3 – 1 in each term S 2 = 3 8 23 69; ×3 – 1 in each term Answer: e)

3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5

Description : 3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5

Last Answer : The series is ×2.5, ×2 alternately Answer: a)

5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Last Answer : The series is +5, +7, +9, +11, .... Answer: c)

[(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)

The incomes of A of B are in the ratio 3:2 and their expenditure are in the ratio 5:3 if each saves rupees 2000, what is their income? a) 32000 b) 20000 c) 1190 d) 8000 e) None of these

Description : The incomes of A of B are in the ratio 3:2 and their expenditure are in the ratio 5:3 if each saves rupees 2000, what is their income? a) 32000 b) 20000 c) 1190 d) 8000 e) None of these

Last Answer : Let the income be 3x and 2x. It is given that the saving of each is Rs. 2000. Then, their expenditures are 3x - 2000 and 2x - 2000 Again, (3x - 2000)/(2x - 2000) = 5/3 => 3(3x - 2000) = 5(2x - ... -x = -4000 => x = 4000 Therefore, their salaries are 3 x 4000 = 12000 and 2 x 4000 = 8000 Answer: d)

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)