9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598

9654 ÷ 21 +7638 ÷ 44 = ?

a) 633

b) 600

c) 643

d) 621

e) 598
by

1 Answer

Answer :

9654 ÷ 21 + 7338 ÷ 44 = ?

= 459.714 + 173.59

= 633.304

= 633 (approx)

Answer: a)
by

Related questions

4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these

Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these 

Last Answer : Answer: a)

4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Description : 4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Last Answer : Multiply by 8. Answer: c)

729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541

Description : 729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541

Last Answer : Difference of Difference 9. Answer: a)

259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these

Description : 259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these

Last Answer : Difference of odd numbers 3, 5, 7, 9, 11. Answer: b)

3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

Description : 3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

Last Answer : Answer: a) 

1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Description : 1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Last Answer : ? = 7897 × 4 × 3 / 8 × 5 × 7 = 338.31 = 338 (approx.) Answer: e)

2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)

3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555

Description : 3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555

Last Answer : 3√7469 × √668 = ? = 19.5 × 25.9 = 505.05 = 505 (approx) Answer: c)

(4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885

Description : (4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885

Last Answer : (4.36)^2 × 66.5 - 371 = ? = 19.0096 × 66.5 - 371 = ? = 1264.1384 - 371 = 893.1384 = 893 (approx.) Answer: b)

196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Description : 196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Last Answer : Answer-5 (862) Explanation- add square of prime no. in each step 4,9,25,49,121,so on

5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Description : 5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Last Answer : Answer- 2 (3910) Explanationadd 5^1,5^2,5^3,5^4,5^5 and so on in each step.

16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016

5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these

Description : 5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these

Last Answer : Answer-3(509) Explanation5 x2 +3 =13 13×2 +3=29 29×2+3=61 and so on..

5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975

Description : 5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975

Last Answer : Answer- 5(51975) Explanation- multiply by consecutive odd numbers 5×1=5 5×3=15 15×5=75 75×9=4725 4725×11=51975

363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523

Description : 363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523

Last Answer : Answer- 5 (2523) Explanation- +432 in every step

24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240

Description : 24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240

Last Answer : Answer- 1 (17280) Explanation- 24 x 2=48 48×3=144 144×4=576 576×5=2880

4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60

Description : 4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60

Last Answer : Answer-2 (160) Explanation- 4725 / 4.5=1050 1050/3.5=300 300/2.5=120 120/1.5=80 80/0.5=160

3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556

Description : 3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556

Last Answer : Answer-3 (254545) Explanation25=(3×10)-5 255=(25×10)+5 2545=(255×10)-5 25455=(2545×10)+5 ?=(2545×10)-5 = 254545

3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624

Description : 3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624

Last Answer : Answer- 3 (3754) Explanation- x4+2

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

Calculate the static deflection in μm of transverse vibrations if the frequency is 200Hz. A. 6.21 B. 0.621 C. 62.1 D. 0.006

Description : Calculate the static deflection in μm of transverse vibrations if the frequency is 200Hz. A. 6.21 B. 0.621 C. 62.1 D. 0.006

Last Answer : A. 6.21

22.222 + 2220.2 + 202.20 + 0.0202 – 2.0022 = ? a) 2244.24 b) 2442.64 c) 2424.44 d) 2444.64 e) 2224.84

Description : 22.222 + 2220.2 + 202.20 + 0.0202 – 2.0022 = ? a) 2244.24 b) 2442.64 c) 2424.44 d) 2444.64 e) 2224.84

Last Answer : b) 2442.64

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Description : 60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Last Answer : b) 44 kg

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

Saina spent Rs. 44,668/- on her air tickets, Rs.56,732 on buying gifts to the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount ? a) Rs. 1,25,800/- b) Rs. 1,30,000/- c) Rs. 1,10,500/- d) Rs. 1,68,300/- e) Rs. 1,50,000/-

Description : Saina spent Rs. 44,668/- on her air tickets, Rs.56,732 on buying gifts to the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount ? a) Rs. 1,25,800/- b) Rs. 1,30,000/- c) Rs. 1,10,500/- d) Rs. 1,68,300/- e) Rs. 1,50,000/- 

Last Answer : Saving = 22% Spent = a00 - 22) = 78% Spending money = 44668 + 56732 = 101400 78%- 101400 100% = 101400 100/78 = 130000 Answer: b)

The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher? A.50 B.44 C.45 D.42 E.None of these

Description : The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher? A.50 B.44 C.45 D.42 E.None of these

Last Answer : Answer – C (45) Explanation – Total ages of 30 boys = 14 x 30 = 420 years Total age when class teacher is included = 15 x 31 = 465 years Age of class teacher = 465 – 420 = 45 years

23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Description : 23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750

Last Answer : 24× 62.5× 12 = ? × 30 24× 750 = ? × 30 ? = (24× 750) / 30 = 600 Answer: b)

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these

Description : It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these

Last Answer : Let the speed of the train be x km/hr and that of the car be y km/hr. Then, 120/x+480/y= 8 1/x+4/y=1/15 ....(i) And, 200/x+400/y=25/3 1/x+2/y=1/24 ....(ii) Solving (i) and (ii), we get: x = 60 and y = 80. Ratio of speeds = 60 : 80 = 3 : 4. Answer: c)

280 600 ? 2504 5036 a) 1364 b) 1236 c) 1362 d) 1361 e) None of these

Description : 280 600 ? 2504 5036 a) 1364 b) 1236 c) 1362 d) 1361 e) None of these

Last Answer : 118 – 35 = 83 280 – 118 = 162 =>162 – 83 = 79 280 – 118 = 162 600 – 280 = 320 =>320 – 162 = 158 Answer: b)

A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? A.310 m B.350 m C.600 m D.490 m E.None of these

Description : A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform? A.310 m B.350 m C.600 m D.490 m E.None of these

Last Answer : Answer - B (350 m) Explanation - when it cross a pole actually it is crossing itself so, S = 300/18 let length of platform be p relative speed = total lengths/time speed of ... pole,man and other is of considerable length like platform ,bridge. when train crosses pole,man it crosses itself

2/3 part of the sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 35, what is the sum? (a) Rs.500 (b) Rs.600 (c) Rs.700 (d) Rs.850 (e) Rs.950

Description : 2/3 part of the sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 35, what is the sum? (a) Rs.500 (b) Rs.600 (c) Rs.700 (d) Rs.850 (e) Rs.950

Last Answer : (c) Rs.700

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92

Description : If 6 years are subtracted from the present age of Anuj and the remainder is divided by 18, then the present age of his grandson Gopal is obtained.If Gopal is 2 years younger to Mohan whose age is 5 years, then what is the age of Anuj? A.44 B.60 C.80 D.92

Last Answer : Answer : B (60) Explanation - Let Anuj's age be X Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 - 2 = 3) If Arun had born 6 years before, his age would had been X - 6. As per the ... as that of Gokul's age. i.e. (X - 6) /18= 3 X-6 =3 x 18 x = 60

Arjun scored 230 runs which included 10 boundaries and 15 sixes. What percentage of his total score did he make by running between the wickets? a) 44.12% b) 45.35% c) 43.47% d) 42%

Description : Arjun scored 230 runs which included 10 boundaries and 15 sixes. What percentage of his total score did he make by running between the wickets? a) 44.12% b) 45.35% c) 43.47% d) 42%

Last Answer : c) 43.47%

Akbar and Birbal started a business with investments of Rs.30000 and Rs.40000 respectively. At the end of the one year, they gave 10% of the total profit of Rs.7000 to charity. Find the difference in the profit of shares of both out of the remaining profit (in Rs.) a)600 b)900 c)500 d)8001

Description : Akbar and Birbal started a business with investments of Rs.30000 and Rs.40000 respectively. At the end of the one year, they gave 10% of the total profit of Rs.7000 to charity. Find the difference in the profit of shares of both out of the remaining profit (in Rs.) a)600 b)900 c)500 d)8001

Last Answer : b)900

Ravi marked his Walkman at 60% above his cost price. If he had decreased his discount from 20% to 10%. he would have earned Rs.80 more. Find his cost price. a)640 b)600 c)500 d)800

Description : Ravi marked his Walkman at 60% above his cost price. If he had decreased his discount from 20% to 10%. he would have earned Rs.80 more. Find his cost price. a)640 b)600 c)500 d)800

Last Answer : c)500

A merchant claims to sell goods at his cost price. But by using false weights, he give only 600 gm of goods for every 1 kg that he buys.What is his profit percentage? a)40% b)100% c)60% d)66 2/3%

Description : A merchant claims to sell goods at his cost price. But by using false weights, he give only 600 gm of goods for every 1 kg that he buys.What is his profit percentage? a)40% b)100% c)60% d)66 2/3%

Last Answer : d)66 2/3%

Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Description : Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Last Answer : c)600 

If a book is sold at 20% more than its usual price, an extra profit of Rs.120 would be made on it. find its usual selling price. a)Rs.500 b)Rs.600 c)Rs.750 d)Rs.800

Description : If a book is sold at 20% more than its usual price, an extra profit of Rs.120 would be made on it. find its usual selling price. a)Rs.500 b)Rs.600 c)Rs.750 d)Rs.800

Last Answer : b)Rs.600

The sale price of an article including the sale tax is Rs. 616. The rate of sale tax is 10% . If the shopkeeper has made a profit of 12%, the cost price of the article is [The Pearson Guide book] A. Rs 500 B. Rs 515 C. Rs 550 D. Rs 600

Description : The sale price of an article including the sale tax is Rs. 616. The rate of sale tax is 10% . If the shopkeeper has made a profit of 12%, the cost price of the article is [The Pearson Guide book] A. Rs 500 B. Rs 515 C. Rs 550 D. Rs 600

Last Answer : Answer – A. Rs 500 Explanation – 110% of S.P. = 616 = S.P. = Rs.(616 x 100/110) = Rs.560. C.P. = Rs (100/112 x 560) = Rs 500

A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then Rs. 64 more would have been obtained. What is the sum? (a) Rs.600 (b) Rs.700 (c) Rs.800 (d) Rs.900

Description : A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then Rs. 64 more would have been obtained. What is the sum? (a) Rs.600 (b) Rs.700 (c) Rs.800 (d) Rs.900

Last Answer : (c) Rs.800

A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Description : A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21

Last Answer : 125% C.P. of sugar per kg = Rs. 4.25 C.P of the sugar per kg = [4.25×100] / 125 = Rs. 3.40. thus, the profit on 1 kg 85 paise by reducing price to 5 paise, to make same profit he must sell, 85/5 = 17kg so required ratio = 1 : 17. Answer: d)

Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)

21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Description : 21, 23, 29, 53, 173, _____ a) 210 b) 893 c) 720 d) 253 e) 293

Last Answer : Difference between each successive tam is factorial of number starting from 2, like 23-21 = 2, then 29-23 = 6 means 3!, then 53-29 = 24 means 4!, then next difference is 173-53 = 120 means 5!, so next difference would be 6! i.e. 720 so term will be 173+720 = 893. Answer: b)

The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Description : The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Last Answer : Let the length of the park be x metres. Width = x × 10 / 21 = 10x / 21 Area = x × 10x / 21 = 3360 or, x^2 = 3360 × 21 / 10 = 7056 or, x = 84 Hence, length = x = 84m and width = 84 × 10 / 21 = 40 metres Difference = 84 – 40 = 44 metres Answer: b)

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)

15 17 21 29 45 77 ? a) 109 b) 125 c) 141 d) 173 e) None of these

Description : 15 17 21 29 45 77 ? a) 109 b) 125 c) 141 d) 173 e) None of these

Last Answer : 15 + 2 = 17 17 + 4 = 21 21 + 8 = 29 29 + 16 = 45 45 + 32 = 77 77 + 64 = 141 Answer: c)

15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Description : 15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Last Answer : The series is a geometric progression with a common ratio 1.2. Hence the next term is 25.92 × 1.2 = 31.104 Answer: a)

If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

Last Answer : If the distance be x km, then x/40-x/50=6/60 x/4-x/5=1 x=20 km. Required time = (20/40) hour – 11 minutes = (1/2×60-11) minutes = 19 minutes Answer: c)