Description : 3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these
Last Answer : Answer: a)
Description : 1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338
Last Answer : ? = 7897 × 4 × 3 / 8 × 5 × 7 = 338.31 = 338 (approx.) Answer: e)
Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03
Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)
Description : (4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885
Last Answer : (4.36)^2 × 66.5 - 371 = ? = 19.0096 × 66.5 - 371 = ? = 1264.1384 - 371 = 893.1384 = 893 (approx.) Answer: b)
Description : 196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862
Last Answer : Answer-5 (862) Explanation- add square of prime no. in each step 4,9,25,49,121,so on
Description : 5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these
Last Answer : Answer- 2 (3910) Explanationadd 5^1,5^2,5^3,5^4,5^5 and so on in each step.
Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these
Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016
Description : 5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these
Last Answer : Answer-3(509) Explanation5 x2 +3 =13 13×2 +3=29 29×2+3=61 and so on..
Description : 5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975
Last Answer : Answer- 5(51975) Explanation- multiply by consecutive odd numbers 5×1=5 5×3=15 15×5=75 75×9=4725 4725×11=51975
Description : 363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523
Last Answer : Answer- 5 (2523) Explanation- +432 in every step
Description : 24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240
Last Answer : Answer- 1 (17280) Explanation- 24 x 2=48 48×3=144 144×4=576 576×5=2880
Description : 4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60
Last Answer : Answer-2 (160) Explanation- 4725 / 4.5=1050 1050/3.5=300 300/2.5=120 120/1.5=80 80/0.5=160
Description : 3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624
Last Answer : Answer- 3 (3754) Explanation- x4+2
Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these
Description : 4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these
Last Answer : Multiply by 8. Answer: c)
Description : 729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541
Last Answer : Difference of Difference 9. Answer: a)
Description : 259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these
Last Answer : Difference of odd numbers 3, 5, 7, 9, 11. Answer: b)
Description : 9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598
Last Answer : 9654 ÷ 21 + 7338 ÷ 44 = ? = 459.714 + 173.59 = 633.304 = 633 (approx) Answer: a)
Description : 3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555
Last Answer : 3√7469 × √668 = ? = 19.5 × 25.9 = 505.05 = 505 (approx) Answer: c)
Description : A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21
Last Answer : 125% C.P. of sugar per kg = Rs. 4.25 C.P of the sugar per kg = [4.25×100] / 125 = Rs. 3.40. thus, the profit on 1 kg 85 paise by reducing price to 5 paise, to make same profit he must sell, 85/5 = 17kg so required ratio = 1 : 17. Answer: d)
Description : Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5
Last Answer : Numerator = 4 + 72 – 14 = 62 Denominator = 738 – 730 = 8 Required value = 62/8 = 7.75 Answer: b)
Description : Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at ... same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM
Last Answer : Ajay reads at average rate of 30 pages per hour ie. 1 page in every two minutes. Therefore, by 5:20 PM, he would have covered 25 pages By 6:20 PM, Ajay would have read 25+30 pages and Vikram would have ... and he will also finish 100 pages Hence, both of them will be on same page at 7:50 Answer: a)
Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35
Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)
Description : 210, 154, 182, 168, 175,171.5, ? a) 172.75 b) 173.25 c) 172.25 d) 173.75 e) 174.75
Last Answer : Starting from the third term, every term is the average of the previous two terms. Hence the next term is (175 + 171.5)/ 2 = 173.25 Answer: b)
Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km
Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)
Description : In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is? a) 5 kmph b) 6 kmph c) 6.25 kmph d) 7.5 kmph e) None of these
Last Answer : Let Abhay's speed be x km/hr. Then, 30/x-30/2x= 3 6x = 30 x = 5 km/hr. Answer: a)
Description : 5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these
Last Answer : 7.5 – 5 = 2.5 11.25 – 7.5 = 3.75 => 3.75 – 2.5 = 1.25 11.25 – 7.5 = 3.75 17.5 – 11.25 = 6.25 => 6.25 – 3.75 = 2.5 Answer: a)
Description : A man plays 100 games with cards. He gets Rs.5 if he wins and pays Rs.2 if he loses. If he wins Rs.3 on the whole, in how many games did he win? a) 25 b) 28 c) 29 d) 32 e) None of these
Last Answer : Suppose he wins the first game and loses the second. Then his gain =Rs 5- Rs 2 = Rs 3 out of remaining 98 games, amount won =amount lost =>Games won : Games lost 2 : 5 In last 98 Games, he wins =2/7 × 98 =28 games =>Total games he won =28 + 1 =29 Answer: c)
Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these
Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)
Description : 1595 ÷ 25 × 36.5 a) 2459 b) 2329 c) 2359 d) 2429 e) 2349
Last Answer : Answer: b)
Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40
Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)
Description : The compound interest accrued on an amount of Rs. 25,500 at the end of three years is Rs. 8,440.5.What would be the simple interest accrued on the same amount at the same rate in the same period? a) Rs. 5,450/- b) Rs. 8,750/- c) Rs. 4,350/- d) Rs. 3,650/- e) Rs. 7,650/-
Last Answer : A = P + Interest = 25500 + 8440.5 = 33940.5 A = P + 1 + (R/100)^3 33940.5 = 25500 a + R/100)^3 a + R/100)^3 = 33940.5 / 25500 a + R/100)^3 = 1.331 a + R/100)^3 = ... R = 10% Simple Interest = Principle Rate Time / 100 = 25500 10 3/100 = 7650 Answer: e)
Description : A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these
Last Answer : % profit = Loss/Actual Weight x 100 = 500 – 425/500 × 100 = 75/500 x 100 = 15% Answer: b)
Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these
Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number
Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31
Last Answer : 5 : 30 : 31
Description : The profit made by selling 25 m of a cloth equals the selling price of 5 m of that cloth. find the profit percentage? a)25% b)20% c)16 2/3% d)30%
Last Answer : a)25%
Description : Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is: A.45 B.25 C.30 D.45 E.None of these
Last Answer : Answer – D (45) Explanation – Let the fourth number be a then hen, third number = 5a, second number= 5a/3 and first=10a/3 a+ 5a+ 5a/3 + 10/3 = 24.75 x 4 so,a=9 So, the numbers are 9, 45, 15 and 30
Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26
Last Answer : 2;
Description : What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh
Last Answer : 3) 23.94 lakh
Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25
Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)
Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these
Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62 216:36 Answer: b)
Description : 7% of 77 + 77% of 777 + 777% of 7777 a) 58090.54 b) 60457.25 c) 68709.16 d) 71000.01 e) None of these
Last Answer : 7% of 77 + 77% of 777 + 777% of 7777 = 0.07 × 77 + 0.77 × 777 + 7.77 × 7777 = 61030.97 Answer: e)
Description : 72× 25 + 45× 96 = 163 + ? a) 1912 b) 2024 c) 1844 d) 1908 e) 1960
Last Answer : 1800 + 4320 = 4096 + ? ? = 1800 + 4320 – 4096 = 2024 Answer: b)
Description : 3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35
Last Answer : ? + 75 = 52 + 58 = 110 ? = 110 – 75 = 35 Answer: e)
Description : 15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004
Last Answer : The series is a geometric progression with a common ratio 1.2. Hence the next term is 25.92 × 1.2 = 31.104 Answer: a)
Description : 2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25
Last Answer : The series is (2 + 7) × 1 = 9; (9 + 6) × 2 = 30; (30 + 5) × 3 = 105; (105 + 4) × 4 = 436; (436 + 3) × 5 = 2195; (2195 + 2) × 6 = 13182 Answer: d)
Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above
Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)
Description : 25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36
Last Answer : The series is 3×5+10=25,4×6+10=34,5×7+10=45,6×8+10=58,7×9+10=73,8× 10+10=90,9×11+10=109 Hence missing term=34 Answer: b)
Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598
Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)
Description : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? a) 357.637 b) 458.558 c) 229.357 d) 277.367 e) 498.627
Last Answer : (3333÷30) + (665 ÷ 25) + (3771 ÷ 27) = ? Sol: 111.1 + 26.6 + 139.667 = ? ? = 277.367 Answer: d)