Water contained in a beaker can be made to boil by passing steam through it  (a) at atmospheric pressure  (b) at a pressure below the firuosphejric pressure  (c) at a pressure greater than atmospheric pressure  (d) any pressure  (e) not possible.

Water contained in a beaker can be made to boil by passing steam through it  (a) at atmospheric pressure  (b) at a pressure below the firuosphejric pressure  (c) at a pressure greater than atmospheric pressure  (d) any pressure  (e) not possible.
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Answer : c
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A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

For which of the following substances, the gas laws can be used with minimum error  (a) dry steam  (b) wet steam  (c) saturated steam  (d) superheated steam  (e) steam at atmospheric pressure.

Description : For which of the following substances, the gas laws can be used with minimum error  (a) dry steam  (b) wet steam  (c) saturated steam  (d) superheated steam  (e) steam at atmospheric pressure.

Last Answer : Answer : d

What is the temperature when water and vapor are in equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

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Description : What is the temperature when water and vapor are in the equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

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According to Dalton’s law, the total pres sure of the mixture of gases is equal to  (a) greater of the partial pressures of all  (b) average of the partial pressures of all  (c) sum of the partial pressures of all  (d) sum of the partial pressures of all divided by average molecular weight  (e) atmospheric pressure.

Description : According to Dalton's law, the total pres sure of the mixture of gases is equal to  (a) greater of the partial pressures of all  (b) average of the partial pressures of all  (c) sum ... all  (d) sum of the partial pressures of all divided by average molecular weight  (e) atmospheric pressure.

Last Answer : Answer : c

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Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

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Last Answer : Answer: A

Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Description : Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Last Answer : Answer: A

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Last Answer : Answer : b

What mass of nitrogen is contained in a10 ft3 vessel at a pressure of 840atm and 820°R? Make a computation by using ideal gas equation.  a. 194lb  b. 214lb  c. 394 lb  d. 413lb formula: m=pV /RT

Description : What mass of nitrogen is contained in a10 ft3 vessel at a pressure of 840atm and 820°R? Make a computation by using ideal gas equation.  a. 194lb  b. 214lb  c. 394 lb  d. 413lb formula: m=pV /RT

Last Answer : 394 lb

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Last Answer : Saturation Temperature

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Description : Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Last Answer : 96%

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Description : One barometric pressure or 1 atmospheric pressure is equal to  (a) 1 kgf/cnr2  (b) 1.033 kgf/cm2  (c) 0 kgf/cm2  (d) 1.0197 kgf/cm2  (e) 100 kgf/cm2.

Last Answer : Answer : b

The flow energy of 5 ft3 of a fluid passing a boundary to a system is 80,000 ft-lb. Determine the pressure at this point.  a. 222 psi  b. 333 psi  c. 444 psi  d. 111 psi formula: Ef= pV

Description : The flow energy of 5 ft3 of a fluid passing a boundary to a system is 80,000 ft-lb. Determine the pressure at this point.  a. 222 psi  b. 333 psi  c. 444 psi  d. 111 psi formula: Ef= pV

Last Answer : 111 psi

The flow energy of 150 L of a fluid passing a boundary to a system is 110 kJ. Determine the pressure at this point  a. 733.33 kPa  b. 833.33 kPa  c. 933.33 kPa  d. 633.33 kPa

Description : The flow energy of 150 L of a fluid passing a boundary to a system is 110 kJ. Determine the pressure at this point  a. 733.33 kPa  b. 833.33 kPa  c. 933.33 kPa  d. 633.33 kPa

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Description : While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Last Answer : 217.7 kPa

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Description : A vertical column of water will be supported to what height by standard atmospheric pressure. If the Y w = 62.4lb/ft3 po = 14.7 psi.  a. 44.9 ft  b. 33.9 ft  c. 22.9 ft  d. 55.9 ft formula: ho= po/Yw

Last Answer : 33.9 ft

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Description : A vertical column of water will be supported to what height by standard atmospheric pressure.  a. 33.9 ft  b. 45 ft  c. 67 ft  d. 25.46 ft ho= Po/Yo

Last Answer : 33.9 ft

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Description : While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Last Answer : 217.17 kpa

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Description : Water boils when:  A. Its saturated vapor pressure equals to the atmospheric pressure  B. Its vapor pressure equals 76cm of mercury  C. Its temperature reaches 212 degree Celsius  D. Its vapor pressure is 1 gram per sq. cm

Last Answer : Its saturated vapor pressure equals to the atmospheric pressure

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Description : The volume of a gas under standard atmospheric pressure & 76 cmHg is 200m³. What is the volume when pressure is 80 cmHg if the temperature is unchanged?  a) 180 in³  b) 170 in³  c) 160 in³  d) 190 in³ Formula: P2V2 = P1V1

Last Answer : 190 in³

What type of pressure cannot be used for Boyle’s Law?  a. Atmospheric Pressure  b. Gauge Pressure  c. Surface Pressure  d. Isobaric Pressure

Description : What type of pressure cannot be used for Boyle’s Law?  a. Atmospheric Pressure  b. Gauge Pressure  c. Surface Pressure  d. Isobaric Pressure

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Last Answer : standard atmospheric pressure

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The difference between the absolute pressure and the atmospheric pressure is called the _____ pressure.  A. Gage  B. Normal  C. Standard  D. Vacuum

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Last Answer : Gage

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Description : What is considered as the actual pressure at a given position and is measured relative to absolute vacuum?  A. Gage pressure  B. Absolute pressure  C. Atmospheric pressure  D. Vacuum pressure

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Which of the following is NOT a value of the standard atmospheric pressure?  A. 1 bar  B. 1 atm  C. 1 kgf/cm^2  D. 14.223 psi

Description : Which of the following is NOT a value of the standard atmospheric pressure?  A. 1 bar  B. 1 atm  C. 1 kgf/cm^2  D. 14.223 psi

Last Answer : 14.223 psi

Which of the following is correct?  A. Absolute pressure = Gauge pressure + Atmospheric pressure  B. Gauge pressure = Absolute pressure + Atmospheric pressure  C. Atmospheric pressure = Absolute pressure + Gauge pressure  D. Absolute pressure = Gauge pressure – Atmospheric pressure

Description : Which of the following is correct?  A. Absolute pressure = Gauge pressure + Atmospheric pressure  B. Gauge pressure = Absolute pressure + Atmospheric pressure  C. Atmospheric pressure = Absolute pressure + Gauge pressure  D. Absolute pressure = Gauge pressure – Atmospheric pressure

Last Answer : Answer: A

At steam point, the temperature of water and its vapor at standard pressure are:  a. Extremes or maximum  b. unity  c. in equilibrium  d. undefined

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Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Description : Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Last Answer : 97.6%,2713 kJ/kg

A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Description : A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Last Answer : 265.4°C, 430.7kJ/kg, 71.4kJ/kg, 1.0327kJ/(kg)(K),502.1 kJ/kg

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

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Last Answer : 3300 lbf-ft/lbm

Compressed air coming out from a punctured football  (a) becomes hotter  (b) becomes cooler1  (c) remains at the same temperature  (d) may become hotter or cooler depend-ing upon the humidity of the surround¬ing air  (e) attains atmospheric temperature.

Description : Compressed air coming out from a punctured football  (a) becomes hotter  (b) becomes cooler1  (c) remains at the same temperature  (d) may become hotter or cooler depend-ing upon the humidity of the surround¬ing air  (e) attains atmospheric temperature.

Last Answer : (b) becomes cooler1

Boyle’s law i.e. pV = constant is applicable to gases under  (a) all ranges of pressures  (b) only small range of pressures  (c) high range of pressures  (d) steady change of pressures  (e) atmospheric conditions.

Description : Boyle’s law i.e. pV = constant is applicable to gases under  (a) all ranges of pressures  (b) only small range of pressures  (c) high range of pressures  (d) steady change of pressures  (e) atmospheric conditions.

Last Answer : Answer : b

The ratio of specific heat at constant pressure (Cp) and specific heat at constant volume (cv) is  A. equal to one  B. less than one  C. greater than one  D. none of these

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Last Answer : Answer: C

What is defined as the direct conversion of a substance from the solid to the vapor state or vice versa without passing the liquid state?  A. Condensation  B. Vaporization  C. Sublimation  D. Cryogenation

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Last Answer : Sublimation

For which of the following substances, the internal energy and enthalpy are the functions of temperature only  (a) any gas  (b) saturated steam  (c) water  (d) perfect gas  (e) superheated steam.

Description : For which of the following substances, the internal energy and enthalpy are the functions of temperature only  (a) any gas  (b) saturated steam  (c) water  (d) perfect gas  (e) superheated steam.

Last Answer : Answer : d

Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits.  (a) 02, N2, steam, C02  (b) Oz, N2, water vapour  (c) S02, NH3, C02, moisture  (d) 02, N2, H2, air  (e) steam vapours, H2, C02.

Description : Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits.  (a) 02, N2, steam, C02  (b) Oz, N2, water vapour  (c) S02, NH3, C02, moisture  (d) 02, N2, H2, air  (e) steam vapours, H2, C02.

Last Answer : Answer : d

The efficiency of Carnot cycle is maximum for  (a) gas engine  (b) well lubricated engine  (c) petrol engine  (d) steam engine  (e) reversible engine.

Description : The efficiency of Carnot cycle is maximum for  (a) gas engine  (b) well lubricated engine  (c) petrol engine  (d) steam engine  (e) reversible engine.

Last Answer : Answer : e

During throttling process  (a) heat exchange does not take place  (b) no work is done by expanding steam  (c) there is no change of internal energy of steam  (d) all of the above  (e) entropy decreases.

Description : During throttling process  (a) heat exchange does not take place  (b) no work is done by expanding steam  (c) there is no change of internal energy of steam  (d) all of the above  (e) entropy decreases.

Last Answer : Answer : d

Superheated vapour behaves  (a) exactly as gas  (b) as steam  (c) as ordinary vapour  (d) approximately as a gas  (e) as average of gas and vapour.

Description : Superheated vapour behaves  (a) exactly as gas  (b) as steam  (c) as ordinary vapour  (d) approximately as a gas  (e) as average of gas and vapour.

Last Answer : Answer : d

The greater the pressure difference in throttling, the lesser is the irreversibility.  A. Yes  B. No

Description : The greater the pressure difference in throttling, the lesser is the irreversibility.  A. Yes  B. No

Last Answer : Answer: B