Normal depth in open channel flow is the depth of flow corresponding to (A) Steady flow (B) Unsteady flow (C) Laminar flow (D) Uniform flow

Normal depth in open channel flow is the depth of flow corresponding to
(A) Steady flow
(B) Unsteady flow
(C) Laminar flow
(D) Uniform flow
by

1 Answer

Answer :

Answer: Option D
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Last Answer : (A) Corresponding to uniform flow

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Last Answer : Answer: Option C

According to Chezy's formula, the discharge through an open channel is (where A = Area of flow, C = Chezy's constant, m = Hydraulic mean depth, and i = Uniform slope in bed) (A) A × m × i) (B) C × m × i) (C) AC × m × i) (D) mi × A × C)

Description : According to Chezy's formula, the discharge through an open channel is (where A = Area of flow, C = Chezy's constant, m = Hydraulic mean depth, and i = Uniform slope in bed) (A) A × m × i) (B) C × m × i) (C) AC × m × i) (D) mi × A × C)

Last Answer : Answer: Option C

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Derivation of Thiem's formula Q = 2 (s1 - s2)/2.3 log10 (r2/r1) is based on the assumption (A) The aquifer is homogeneous, isotropic and of infinite depth and area (B) The well is sunk through the full depth of the aquifer (C) The flow lines are radial and horizontal, and the flow is laminar (D) All the above

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The fluid velocity varies as the square of the cylindrical pipe diameter, in case of steady state laminar flow at constant pressure drop, for __________ fluid. (A) Newtonian (B) Dilatant (C) Pseudo-plastic (D) Non-Newtonian

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Last Answer : Answer: Option D

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