According to Bazin's formula, the discharge over a rectangular weir is mL2g x H
3/2where m is equal
to
(A) 0.405 + (0.003/H)
(B) 0.003 + (0.405/H)
(C) 0.405 + (H/0.003)
(D) 0.003 + (H/0.405)
3/2where m is equal
to
(A) 0.405 + (0.003/H)
(B) 0.003 + (0.405/H)
(C) 0.405 + (H/0.003)
(D) 0.003 + (H/0.405)