According to Bazin's formula, the discharge over a rectangular weir is mL2g x H
3/2where m is equal
to
(A) 0.405 + (0.003/H)
(B) 0.003 + (0.405/H)
(C) 0.405 + (H/0.003)
(D) 0.003 + (H/0.405)

1 Answer

Answer :

Answer: Option A

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