The Francis formula for the discharge over Cipoletti weir is (A) 1.84 LH1/2 (B) 1.84 LH (C) 1.84 LH3/2 (D) 1.84 LH5/

The Francis formula for the discharge over Cipoletti weir is
(A) 1.84 LH1/2
(B) 1.84 LH
(C) 1.84 LH3/2
(D) 1.84 LH5/
by

1 Answer

Answer :

Answer: Option C
by

Related questions

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When the coefficient of discharge (Cd) is 0.623, then the general equation for discharge over a rectangular weir is (A) 1.84(L - 0.1nH)H 3/2 (B) 1.84(L - nH)H 2 (C) 1.84(L - 0.1nH)H 5/2 (D) 1.84(L - nH)H 3

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According to Bazin's formula, the discharge over a rectangular weir is mL2g x H 3/2where m is equal to (A) 0.405 + (0.003/H) (B) 0.003 + (0.405/H) (C) 0.405 + (H/0.003) (D) 0.003 + (H/0.405)

Description : According to Bazin's formula, the discharge over a rectangular weir is mL2g x H 3/2where m is equal to (A) 0.405 + (0.003/H) (B) 0.003 + (0.405/H) (C) 0.405 + (H/0.003) (D) 0.003 + (H/0.405)

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Description : The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of ... 2g [H1 2 - Ha 2 ] (D) (2/3) Cd L. 2g [H1 5/2 - Ha 5/2]

Last Answer : Answer: Option B

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Last Answer : Answer: Option D

The absolute percentage error in the computed discharge over a rectangular weir corresponding to an absolute error of 1.5 % in the measurement of head over the sill of the weir would be : (a) 1.5 (b) 2.25 (c) 2.5 (d) 3.75

Description : The absolute percentage error in the computed discharge over a rectangular weir corresponding to an absolute error of 1.5 % in the measurement of head over the sill of the weir would be : (a) 1.5 (b) 2.25 (c) 2.5 (d) 3.75

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