To set out a parallel from a given inaccessible point to a given line AB, the following observations
are made:
Distance AB and angle PAM = a and angle PBA = b are measured where M is a point on the
line BA produced. The perpendicular to the desired parallel line from A and B are:
(A) AB/(cot b - cot a)
(B) AB/(cos b - cos a)
(C) AB/(cot a - cot b)
(D) AB/(cot a - cos b)

1 Answer

Answer :

(A) AB/(cot b - cot a)

Related questions

Description : To orient a plane table at a point roughly south of the mid-point of two inaccessible conical hill stations and in the plains, a point is selected in line with AB and table is oriented at by bringing ab ... , is (A) Unique and correct (B) Incorrect (C) Manifold and correct (D) Not reliable

Last Answer : (C) Manifold and correct

Description : The co-ordinate of a point measured perpendicular to the parallel, is called (A) Total latitude (B) Meridian distance (C) Total departure (D) Consecutive co-ordinate

Last Answer : (A) Total latitude

Description : A dumpy level was set up at mid-point between pegs A and B, 80 m apart and the staff readings were 1.32 and 1.56. When the level was set up at a point 10 m from A on BA produced, the staff readings obtained at A ... this set up at S should be (A) 1.435 (B) 1.345 (C) 1.425 (D) None of these

Last Answer : (B) 1.345

Description : If angle A is acute and cos A = 8/17 then cot A is : (a) 8/15 (b) 17/8 (c) 15/8 (d) 17/15

Last Answer : (a) 8/15

Description : For determining the support reactions at A and B of a three hinged arch, points B and Care joined  and produced to intersect the load line at D and a line parallel to the load line through A at D'.  Distances AD, DD ... reactions at A and B is  (A) 30°  (B) 45°  (C) 60°  (D) 90

Last Answer : (D) 90

Description : The bearing of line AB is 152° 30' and angle ABC measured clockwise is 124° 28'. The bearing of BC is (A) 27° 52' (B) 96° 58' (C) 148° 08' (D) 186° 58'

Last Answer : (B) 96° 58'

Description : Orientation of a plane table by solving two point problems is only adopted when (A) Saving of time is a main factor (B) Better accuracy is a main factor (C) Given points are inaccessible (D) None of these

Last Answer : (C) Given points are inaccessible

Description : The distances AC and BC are measured from two fixed points A and B whose distance AB is known. The point C is plotted by intersection. This method is generally adopted in (A) Chain surveying (B) Traverse method of surveys (C) Triangulation (D) None of these

Last Answer : (A) Chain surveying

Description : The area of a plane triangle ABC, having its base AC and perpendicular height , is  (A) ½ bh (B) ½ ba sin C (C) ½ bc sin A (D) All the above

Last Answer : (D) All the above

Description : What is the value of sin A cos A tan A + cos A sin A cot A ? -Maths 9th

Last Answer : answer:

Description : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Last Answer : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Description : `int(1)/(cos x . cot x ) dx`

Last Answer : `int(1)/(cos x . cot x ) dx`

Description : If `2cosec theta - cos theta cot theta >= k AA theta in (0,pi),` then value of `k` is

Last Answer : If `2cosec theta - cos theta cot theta >= k AA theta in (0,pi),` then value of `k` is

Description : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),(cosec^(-1)x,tan^(-1)x,cot^(-1)x):}]` and `B =

Last Answer : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),( ... )=-A(x)` D. `A(x) + A(-x) = - piI_(3)`

Description : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) cos phi -1, tan(2pi-theta) > 0 and -1 <

Last Answer : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) ... (3pi)/(2)` D. `(3pi)/(2) lt phi lt 2pi`

Description : The live load to be considered for an inaccessible roof, is (A) Nil (B) 75 kg/m2 (C) 150 kg/cm2 (D) 200 kg/m

Last Answer : Answer: Option B

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

Description : In Fig. 8.53,ABCD is a parallelogram and E is the mid - point of AD. A line through D, drawn parallel to EB, meets AB produced at F and BC at L.Prove that (i) AF = 2DC (ii) DF = 2DL -Maths 9th

Last Answer : Given, E is mid point of AD Also EB∥DF ⇒ B is mid point of AF [mid--point theorem] so, AF=2AB (1) Since, ABCD is a parallelogram, CD=AB ⇒AF=2CD AD∥BC⇒LB∥AD In ΔFDA ⇒LB∥AD ⇒LDLF​=ABFB​=1 from (1) ⇒LF=LD so, DF=2DL

Description : There are two stations A and B. Which of the following statements is correct? (A) The fore bearing of AB is AB (B) The back bearing of AB is BA (C) The fore and back bearings of AB differ by 180° (D) All the above

Last Answer : (D) All the above

Description : For location of soundings a range and one angle from the shore involves the following operations. Which one is correct? (A) A range line is established (B) The first and the last soundings ... angular observations (C) The intermediate soundings are fixed by the time intervals (D) All the above

Last Answer : (D) All the above

Description : To orient a plane table at a point with two inaccessible points, the method generally adopted, is (A) Intersection (B) Resection (C) Radiation (D) Two point problem

Last Answer : (D) Two point problem

Description : Which of the following methods of plane table surveying is used to locate the position of an inaccessible point? (A) Radiation (B) Intersection (C) Traversing (D) Resection

Last Answer : (B) Intersection

Description : Given L1 = L(a*baa*) and L2 = L(ab*) The regular expression corresponding to language L3 = L1/L2 (right quotient) is given by (A) a*b (B) a*baa* (C) a*ba* (D) None of the above

Last Answer : (C) a*ba* 

Description : If S, L and R are the arc length, long chord and radius of the sliding circle then the perpendicular distance of the line of the resultant cohesive force, is given by (A) a = S.R/L (B) a = L.S/R (C) a = L.R/S (D) None of these

Last Answer : (A) a = S.R/L

Description : In Fraunhofer diffraction pattern for single slit, a central maximum is obtained when angle of diffraction q is equal to zero. What it actually indicates? A. All the diffracted rays are parallel and focused ... are diffracted by the slit in all the directions D. The rays are reflected by the slit

Last Answer : A. All the diffracted rays are parallel and focused by slit at a single point on screen

Description : The torque expression of a current carrying conductor is a) T = BIA cos θ b) T = BA cos θ c) T = BIA sin θ d) T = BA sin θ

Last Answer : c) T = BIA sin θ

Description : ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (i) D is the mid-point of AC (ii) MD ⊥ AC (iii) CM = MA = ½ AB -Maths 9th

Last Answer : Solution: (i) In ΔACB, M is the midpoint of AB and MD || BC , D is the midpoint of AC (Converse of mid point theorem) (ii) ∠ACB = ∠ADM (Corresponding angles) also, ∠ACB = 90° , ∠ADM = 90° and MD ⊥ AC (iii ... SAS congruency] AM = CM [CPCT] also, AM = ½ AB (M is midpoint of AB) Hence, CM = MA = ½ AB

Description : ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th

Last Answer : Given: A △ABC , right - angled at C. A line through the mid - point M of hypotenuse AB parallel to BC intersects AC at D. To Prove: (i) D is the mid - point of AC (ii) MD | AC (iii) CM = MA = 1 / 2 ... congruence axiom] ⇒ AM = CM Also, M is the mid - point of AB [given] ⇒ CM = MA = 1 / 2 = AB.

Description : ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th

Last Answer : Given: A △ABC , right - angled at C. A line through the mid - point M of hypotenuse AB parallel to BC intersects AC at D. To Prove: (i) D is the mid - point of AC (ii) MD | AC (iii) CM = MA = 1 / 2 ... congruence axiom] ⇒ AM = CM Also, M is the mid - point of AB [given] ⇒ CM = MA = 1 / 2 = AB.

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Description : In a trapezium ABCD, AB is parallel to CD, BD is perpendicular to AD. AC is perpendicular to BC. If AD = BC = 15 cm and AB = 25 cm, -Maths 9th

Last Answer : answer:

Description : While measuring the distance between two points along upgrade with the help of a 20 m chain, the forward end of the chain is shifted forward through a distance (A) 20 (sin - 1) (B) 20 (cos - 1) (C) 20 (sec - 1) (D) 20 (cosec - 1)

Last Answer : (C) 20 (sec - 1)

Description : Pick up the incorrect statement from the following: (A) The bottom and top ends of slump mould are parallel to each other (B) The axis of the mould is perpendicular to the end faces (C) The ... clean and free from set cement (D) The mould is in the form of a frustum of hexagonal pyramid

Last Answer : Answer: Option D

Description : Desired tension in an open belt drive system can be maintained (without changing center to center distance between two pulley)by using A)ldler pulley. B)slide rail C) Tilting angle. D)none of the above

Last Answer : A)ldler pulley

Description : Reduced bearing of a line is an angle between (A) North line and given line measured clockwise (B) North line and given line measured anticlockwise (C) East or west and the given line (D) Given line and the part of the meridian whether N end or S end, lying adjacent to it

Last Answer : (D) Given line and the part of the meridian whether N end or S end, lying adjacent to it

Description : ABCD is a trapezium in which AB || CD and AD = BC (see Fig. 8.23). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint : Extend AB and draw a line through C parallel to DA intersecting AB produced at E.] -Maths 9th

Last Answer : ] Solution: To Construct: Draw a line through C parallel to DA intersecting AB produced at E. (i) CE = AD (Opposite sides of a parallelogram) AD = BC (Given) , BC = CE ⇒∠CBE = ∠CEB also, ∠A+∠CBE = ... BC (Given) , ΔABC ≅ ΔBAD [SAS congruency] (iv) Diagonal AC = diagonal BD by CPCT as ΔABC ≅ ΔBA.

Description : In PCM, it converts the PAM sampled to parallel PCM codes

Last Answer : Analog-to-Digital converter

Description : Find the distance of a heavenly object from the earth if the parallactic angle as measured from two places at a distance of `6.284xx10^(6)m` apart is

Last Answer : Find the distance of a heavenly object from the earth if the parallactic angle as measured from two places at a ... .284xx10^(6)m` apart is `2^(@)`.

Description : If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured ... ) Kx (1 - x/l) + bw (C) Kx (1 + x/l) + bw (D) All the above

Last Answer : Answer: Option B

Description : Location of soundings by two angles from the shore requires establishing (A) One range line parallel to shore (B) One range line perpendicular to shore (C) Two range lines mutually perpendicular (D) No range line

Last Answer : (D) No range line

Description : Littoral drift (A) Is the raised line of sand, parallel to the sea coast (B) Is the slow movement of surface water at sea caused by the wind (C) Is a current parallel to the shore, caused due to tangential component of the wind (D) Is a current perpendicular to the shore line caused due to wind

Last Answer : (C) Is a current parallel to the shore, caused due to tangential component of the wind

Description : You have to observe an included angle with better accuracy than what is achievable by a vernier,  you will prefer the method of  (A) Repetition  (B) Reiteration  (C) Double observations  (D) Exactness

Last Answer : (A) Repetition 

Description : If a 30 m chain diverges through a perpendicular distance d from its correct alignment, the error in length, is (A) (d²/60) m (B) (d²/30) m (C) (d²/40) m (D) (d/30) m

Last Answer : (A) (d²/60) m

Description : The plotting of inaccessible points in a plane-table survey can be done by the method of (a) Interpolation (b) Radiation (c) Intersection (d) Traversing

Last Answer : (c) Intersection

Description : To remove an alternator operating in parallel with another unit from the main electrical bus, you must FIRST _________. A. adjust the power factor on both units B. set the desired voltage on ... C. open the circuit breaker on the outgoing alternator D. remove the load from the outgoing alternator

Last Answer : Answer: D

Description : ABCD is a trapezium in which AB || DC and AD = BC. If P, Q, R and S be respectively the mid-points of BA, BD, CD and CA, then PQRS is a -Maths 9th

Last Answer : Here is your First of all we will draw a quadrilateral ABCD with AD = BC and join AC, BD, P,Q,R,S are the mid points of AB, AC, CD and BD respectively. In the triangle ABC, P and Q are mid points of AB and AC respectively. All sides are equal so PQRS is a Rhombus.