Let angular value of one graduation of a tube of length be the radius of
its internal curved surface, then
(A) = x/206265 R
(B) = R/206265 x
(C) = 206265/x. R
(D) = x. R/206265
its internal curved surface, then
(A) = x/206265 R
(B) = R/206265 x
(C) = 206265/x. R
(D) = x. R/206265