In solution, glucose exists as _________(a) the open-chain form only (b) the cyclic hemiacetal form only (c) the cyclic acetal form only (d) an equilibrium mixture of the open-chain form and cyclic hemiacetal forms

In solution, glucose exists as _________
(a) the open-chain form only
(b) the cyclic hemiacetal form only
(c) the cyclic acetal form only
(d) an equilibrium mixture of the open-chain form and cyclic hemiacetal forms
by

1 Answer

Answer :

an equilibrium mixture of the open-chain form and cyclic hemiacetal forms
by

Related questions

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