In a reversible chemical reaction having two reactants in equilibrium, if the concentration of the reactants are doubled, then the equilibrium constant will (A) Remain the same (B) Be halved (C) Also be doubled (D) Become one fourth

In a reversible chemical reaction having two reactants in equilibrium,
if the concentration of the reactants are doubled, then the equilibrium
constant will
(A) Remain the same
(B) Be halved
(C) Also be doubled
(D) Become one fourth
by

1 Answer

Answer :

(A) Remain the same
by

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Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3