The maximum acceleration of a particle moving with simple harmonic motion is ____. (A) ω (B) ω.r (C) ω / 2 π (D) 2 π / ω

The maximum acceleration of a particle moving with simple harmonic motion is ____.
(A) ω
(B) ω.r
(C) ω / 2 π
(D) 2 π / ω
by

1 Answer

Answer :

(B) ω.r
by

Related questions

The maximum acceleration of a particle moving with simple harmonic motion is ____. A. ω B. ω.r C. ω / 2 π D. 2 π / ω

Description : The maximum acceleration of a particle moving with simple harmonic motion is ____. A. ω B. ω.r C. ω / 2 π D. 2 π / ω

Last Answer : B. ω.r

When a body moves with simple harmonic motion, the product of its periodic time and frequency is equal to A. Zero B. One C. π/2 D. 2π

Description : When a body moves with simple harmonic motion, the product of its periodic time and frequency is equal to A. Zero B. One C. π/2 D. 2π

Last Answer : B. One

The vector representing acceleration on a vector diagram for a harmonic motion A) Lags the displacement vector by 90° B) Lags the displacement vector by 180° C) Leads the displacement vector by 90° D) Leads the displacement vector by 180°

Description : The vector representing acceleration on a vector diagram for a harmonic motion A) Lags the displacement vector by 90° B) Lags the displacement vector by 180° C) Leads the displacement vector by 90° D) Leads the displacement vector by 180°

Last Answer : C) Leads the displacement vector by 90°

Body having simple harmonic motion is represented by A) x = A sin ωt B) x = A cos ωt C) x = - A sin ωt D) x = - A cos ωt

Description : Body having simple harmonic motion is represented by A) x = A sin ωt B) x = A cos ωt C) x = - A sin ωt D) x = - A cos ωt

Last Answer : A) x = A sin ωt

The resultant motion of two Simple Harmonic Motions will be A. Simple Harmonic MotionB. Periodic Motion C. Projectile Motion D. Zero

Description : The resultant motion of two Simple Harmonic Motions will be A. Simple Harmonic MotionB. Periodic Motion C. Projectile Motion D. Zero

Last Answer : A. Simple Harmonic Motion

SHM stands for A. Single Harmonic Motion B. Simple Harmonic Motion C. Simple Harmonic Mechanism D. None of the above

Description : SHM stands for A. Single Harmonic Motion B. Simple Harmonic Motion C. Simple Harmonic Mechanism D. None of the above

Last Answer : B. Simple Harmonic Motion

A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The length of pendulum should be doubled c.The mass of the bob should be halved d.The length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled

Description : A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation a.The length of pendulum should be quadrupled b.The ... length of pendulum should be reduced to one fourth e.The mass of the bob should be doubled

Last Answer : a. The length of pendulum should be quadrupled

A particle in simple Harmonic Motion while passing through mean position will have a.Maximum kinetic energy and minimum potential energy b.Average kinetic energy and average potential energy c.Minimum kinetic energy and maximum potential energy d.Maximum kinetic energy and maximum e.Minimum kinetic energy and minimum potential energy

Description : A particle in simple Harmonic Motion while passing through mean position will have a.Maximum kinetic energy and minimum potential energy b.Average kinetic energy and average potential energy c. ... energy d.Maximum kinetic energy and maximum e.Minimum kinetic energy and minimum potential energy

Last Answer : a. Maximum kinetic energy and minimum potential energy

The moving parts of a machine which weigh 1 tonne perform vertical simple harmonic motion with an amplitude of 2.5 cm and a period of 0.5 sec. The base of the machine weighs 3 tonnes and rests on the ground. Maximum reactions on the ground would be a.3.6 tonnes b.2.4 tonnes c.4.0 tonnes d.4.8 tonnes e.4.4 tonnes

Description : The moving parts of a machine which weigh 1 tonne perform vertical simple harmonic motion with an amplitude of 2.5 cm and a period of 0.5 sec. The base of the machine weighs 3 tonnes and rests on the ground. Maximum ... would be a.3.6 tonnes b.2.4 tonnes c.4.0 tonnes d.4.8 tonnes e.4.4 tonnes

Last Answer : e. 4.4 tonnes

The velocity vector in a vector diagram for a harmonic motion A Lags the displacement vector by 180 0 B Lags the displacement vector by 90 0 C Leads the displacement vector by 90 0 D Leads the displacement vector by 180 0

Description : The velocity vector in a vector diagram for a harmonic motion A Lags the displacement vector by 180 0 B Lags the displacement vector by 90 0 C Leads the displacement vector by 90 0 D Leads the displacement vector by 180 0

Last Answer : C Leads the displacement vector by 90 0

The motion of a system executing harmonic motion with one natural frequency is known as _______ A. principal mode of vibration B. natural mode of vibration C. both a. and b. D. none of the above

Description : The motion of a system executing harmonic motion with one natural frequency is known as _______ A. principal mode of vibration B. natural mode of vibration C. both a. and b. D. none of the above

Last Answer : C. both a. and b.

The velocity vector in a vector diagram for a harmonic motion A Lags the displacement vector by 180 0 B Lags the displacement vector by 90 0 C Leads the displacement vector by 90 0 D Leads the displacement vector by 180 0

Description : The velocity vector in a vector diagram for a harmonic motion A Lags the displacement vector by 180 0 B Lags the displacement vector by 90 0 C Leads the displacement vector by 90 0 D Leads the displacement vector by 180 0

Last Answer : C Leads the displacement vector by 90 0

The motion of a system executing harmonic motion with one natural frequency is known as _______ A) principal mode of vibration B) natural mode of vibration C) both a. and b. D)none of the above

Description : The motion of a system executing harmonic motion with one natural frequency is known as _______ A) principal mode of vibration B) natural mode of vibration C) both a. and b. D)none of the above

Last Answer : C) both a. and b.

If frequency of excitation of a forced vibration system with negligible damping is very close to natural frequency of the system, then the system will A) Execute harmonic motion of large amplitude B) Beat with a very high peak amplitude C) Perform aperiodic motion D) None of the above

Description : If frequency of excitation of a forced vibration system with negligible damping is very close to natural frequency of the system, then the system will A) Execute harmonic motion of large amplitude B) Beat with a very high peak amplitude C) Perform aperiodic motion D) None of the above

Last Answer : A) Execute harmonic motion of large amplitude

If the amplitude of harmonic motion is large, its frequency A) Will always be high B) Will always be less C) Can have any value D) Will be zero

Description : If the amplitude of harmonic motion is large, its frequency A) Will always be high B) Will always be less C) Can have any value D) Will be zero

Last Answer : C) Can have any value

If harmonic motion of same frequency and same phase are superimposed in two perpendicular directions ( x and y) then, the resultant motion will be, A) circle B) An ellipse C) An square D) An rectangle

Description : If harmonic motion of same frequency and same phase are superimposed in two perpendicular directions ( x and y) then, the resultant motion will be, A) circle B) An ellipse C) An square D) An rectangle

Last Answer : C) An square

The velocity vector in a vector diagram for a harmonic motion A) Lags the displacement vector by 180° B) Leads the displacement vector by 90° C) Lags the displacement vector by 90° D) Leads the displacement vector by 180°

Description : The velocity vector in a vector diagram for a harmonic motion A) Lags the displacement vector by 180° B) Leads the displacement vector by 90° C) Lags the displacement vector by 90° D) Leads the displacement vector by 180°

Last Answer : B) Leads the displacement vector by 90°

Harmonic motion is A) Necessarily a periodic motion B) An aperiodic motion C) A motion described in a circle D) A random motion

Description : Harmonic motion is A) Necessarily a periodic motion B) An aperiodic motion C) A motion described in a circle D) A random motion

Last Answer : A) Necessarily a periodic motion

The velocity vector in a vector diagram for a harmonic motion C (A) Lags the displacement vector by 180 0 (B) Lags the displacement vector by 90 0 (C) Leads the displacement vector by 90 0 (D) Leads the displacement vector by 180 0

Description : The velocity vector in a vector diagram for a harmonic motion C (A) Lags the displacement vector by 180 0 (B) Lags the displacement vector by 90 0 (C) Leads the displacement vector by 90 0 (D) Leads the displacement vector by 180 0

Last Answer : (C) Leads the displacement vector by 90 0

A particle is moving in a uniform circular motion with constant speed v along a circle of radius r. The acceleration-of the particle is – (1) zero (2) V/r (3) V/r² (4) V²/r

Description : A particle is moving in a uniform circular motion with constant speed v along a circle of radius r. The acceleration-of the particle is – (1) zero (2) V/r (3) V/r² (4) V²/r

Last Answer : (4) V²/r Explanation: When a particle is moving in a uniform circular motion with constant speed and radius. the acceleration of the particle is given by v2/r. The particle will exhibit centripetal acceleration.

In case of simple harmonic motion, displacement is proportional to the (A) Velocity (B) Acceleration (C) Both (A) & (B) (D) Neither (A) nor (B)

Description : In case of simple harmonic motion, displacement is proportional to the (A) Velocity (B) Acceleration (C) Both (A) & (B) (D) Neither (A) nor (B)

Last Answer : B) Acceleration

A body which is attached to a spring undergoes simple harmonic motion. The magnitude of the body's acceleration is: w) constant x) proportional to its displacement from its equilibrium position y) zero z) always increasing.

Description : A body which is attached to a spring undergoes simple harmonic motion. The magnitude of the body's acceleration is: w) constant x) proportional to its displacement from its equilibrium position y) zero z) always increasing.

Last Answer : ANSWER: X -- PROPORTIONAL TO ITS DISPLACEMENT FROM ITS EQUILIBRIUM POSITION 

In simple harmonic motion, the acceleration is: w) constant x) proportional to the distance from the central position y) greatest when the velocity is greatest z) none of the above

Description : In simple harmonic motion, the acceleration is: w) constant x) proportional to the distance from the central position y) greatest when the velocity is greatest z) none of the above

Last Answer : ANSWER: X -- PROPORTIONAL TO THE DISTANCE FROM THE CENTRAL POSITION

Which of the following statements dealing with simple harmonic motion of a mass-spring system is TRUE? w) The acceleration is largest when the oscillating mass is instantaneously at rest. x) The larger the spring force constant the larger the period. y) The period of the motion depends linearly on the amplitude of the motion. z) The acceleration is larger when the oscillating mass has its greatest velocity.

Description : Which of the following statements dealing with simple harmonic motion of a mass-spring system is TRUE? w) The acceleration is largest when the oscillating mass is instantaneously at rest. x) The ... of the motion. z) The acceleration is larger when the oscillating mass has its greatest velocity.

Last Answer : ANSWER: W -- THE ACCELERATION IS LARGEST WHEN THE OSCILLATING MASS IS INSTANTANEOUSLY AT REST 

A body in Simple Harmonic Motion will attain maximum velocity when it passes through a.Point of 0.75 amplitude b.Extreme point of the oscillation of L.H.S. c.Point of half amplitude d.Extreme point of the oscillation at R.H.S. e.Mean position

Description : A body in Simple Harmonic Motion will attain maximum velocity when it passes through a.Point of 0.75 amplitude b.Extreme point of the oscillation of L.H.S. c.Point of half amplitude d.Extreme point of the oscillation at R.H.S. e.Mean position

Last Answer : e. Mean position

The period of oscillation of a particle undergoing simple harmonic motion is: w) independent of the amplitude of the motion x) directly proportional to the frequency of oscillation y) independent of the frequency of oscillation z) none of the above

Description : The period of oscillation of a particle undergoing simple harmonic motion is: w) independent of the amplitude of the motion x) directly proportional to the frequency of oscillation y) independent of the frequency of oscillation z) none of the above

Last Answer : ANSWER: W -- INDEPENDENT OF THE AMPLITUDE OF THE MOTION 

The unbalanced force caused by an eccentric mass m rotating at an angular speed v and located at a distance r from the axis of rotation is 2 a. mr ω 2 b. mgω 2 c. mr ω 2

Description : The unbalanced force caused by an eccentric mass m rotating at an angular speed v and located at a distance r from the axis of rotation is 2 a. mr ω 2 b. mgω 2 c. mr ω 2

Last Answer : c. mr ω 2

A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Description : A weight of 50 N is suspended from a spring of stiffness 4000N/m and subjected to a harmonic force of magnitude 60N and frequency 60 Hz. what will be the static displacement of the spring due to maximum applied force A. 0.015m B. 0.15 m C. 15 m D. 150m

Last Answer : B. 0.15 m

The periodic time of a body moving in Simple Harmonic Motion is a.Directly proportional to its angular velocity b.Directly proportional to the weight of the body c.Inversely proportional to the square of angular velocity d.Directly proportional to the momentum of swinging body e.Inversely proportional to the angular velocity

Description : The periodic time of a body moving in Simple Harmonic Motion is a.Directly proportional to its angular velocity b.Directly proportional to the weight of the body c.Inversely proportional to ... d.Directly proportional to the momentum of swinging body e.Inversely proportional to the angular velocity

Last Answer : e. Inversely proportional to the angular velocity

SHM is the motion in which acceleration of the body is proportional to its displacement and directed towards the mean position. A. True B. False C. Neither True Nor False D. None

Description : SHM is the motion in which acceleration of the body is proportional to its displacement and directed towards the mean position. A. True B. False C. Neither True Nor False D. None

Last Answer : A. True

The motion of particle is represented by, x = Asin(wt) in which A stands for A. Amplitude B. Wavelength C. Frequency D. Damping

Description : The motion of particle is represented by, x = Asin(wt) in which A stands for A. Amplitude B. Wavelength C. Frequency D. Damping

Last Answer : A. Amplitude

Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None

Description : Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None

Last Answer : B. Acceleration due to gravity

Derive equations of motion graphically for a particle having uniform acceleration, moving along a straight line.

Description : Derive equations of motion graphically for a particle having uniform acceleration, moving along a straight line.

Last Answer : Derive equations of motion graphically for a particle having uniform acceleration, moving along a straight line.

A body is vibrating with simple harmonic motion of aplitude 5 cm frequency 10 vibrations per second. The maximum value of velocity in cm/s will be a.3.14 cm/s b.314 cm/s c.3140 cm/s d.31.4 cm/s e.31400 cm/s

Description : A body is vibrating with simple harmonic motion of aplitude 5 cm frequency 10 vibrations per second. The maximum value of velocity in cm/s will be a.3.14 cm/s b.314 cm/s c.3140 cm/s d.31.4 cm/s e.31400 cm/s

Last Answer : b. 314 cm/s

In vibration isolation system, if ω/ωn, then the phase difference between the transmitted force and the disturbing force is A 0° B 90° C 180° D 270°

Description : In vibration isolation system, if ω/ωn, then the phase difference between the transmitted force and the disturbing force is A 0° B 90° C 180° D 270°

Last Answer : C 180°

In vibration isolation system, if ω/ωn < 2, then for all values of damping factor, the transmissibility will be A less than unity B equal to unity C greater than unity D zero

Description : In vibration isolation system, if ω/ωn < 2, then for all values of damping factor, the transmissibility will be A less than unity B equal to unity C greater than unity D zero

Last Answer : C greater than unity

According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is critically damped? A x = (A + Bt) e – ωt B x = X e – ξωt (sin ω d t + Φ) C x = (A – Bt) e – ωt D x = X e – ξωt (cos ω d t + Φ)

Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... Φ) C x = (A - Bt) e - ωt D x = X e - ξωt (cos ω d t + Φ)

Last Answer : A x = (A + Bt) e – ωt

A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

Description : A shaft of diameter d carries two discs at its two ends. The lowest torsional frequency is ω n . If the diameter is doubled, then the lowest torsional frequency becomes A 4ω n B ω n /2 C ω n /4 D 4ω n

Last Answer : D 4ω n

A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Description : A shaft of length l carries two discs at its two ends. The lowest torsional frequency is ω n . If the shaft length is doubled, then the lowest torsional frequency becomes A ω n /2 B ω n /√2 C √2ω n D 2ω n

Last Answer : B ω n /√2

Calculate damping ratio if mass = 200Kg, ω = 20rad/s and damping coefficient = 800 N/m/s A. 0.03 B. 0.04 C. 0.05 D. 0.06

Description : Calculate damping ratio if mass = 200Kg, ω = 20rad/s and damping coefficient = 800 N/m/s A. 0.03 B. 0.04 C. 0.05 D. 0.06

Last Answer : A. 0.03

In vibration isolation system, if ω/ω n > 1, then the phase difference between the transmitted force and the disturbing force is A. 0° B. 90° C. 180° D. 270°

Description : In vibration isolation system, if ω/ω n > 1, then the phase difference between the transmitted force and the disturbing force is A. 0° B. 90° C. 180° D. 270°

Last Answer : C. 180°

In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if ω/ωn is A. Equal to 1 B. Equal to √2 C. Less than √2 D. Greater than √2

Description : In vibration isolation system, the transmissibility will be equal to unity, for all values of damping factor, if ω/ωn is A. Equal to 1 B. Equal to √2 C. Less than √2 D. Greater than √2

Last Answer : B. Equal to √2

In the graph shown below, the region in which frequency ratio (ω/ω n ) > √2 is known as____ A. Amplification region B. Isolation region C. Spring controlled region D. None of the above

Description : In the graph shown below, the region in which frequency ratio (ω/ω n ) > √2 is known as____ A. Amplification region B. Isolation region C. Spring controlled region D. None of the above

Last Answer : B. Isolation region

Which of the following vibro-meters have frequency ratio (ω/ω n ) << 1? A. Accelerometers B. Velometers C. Both A. and B. D. None of the above

Description : Which of the following vibro-meters have frequency ratio (ω/ω n )

Last Answer : A. Accelerometers

According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is critically damped? A. x = (A + Bt) e – ωt B. x = X e – ξωt (sin ω d t + Φ) C. x = (A – Bt) e – ωt D. x = X e – ξωt (cos ω d t + Φ

Description : According to D' Alembert's principle, m (d 2 x/ dt 2 ) + c (dx/dt) + Kx =0 is the differential equation for damped free vibrations having single degree of freedom. What will be the solution to this differential equation if the system is ... ) C. x = (A - Bt) e - ωt D. x = X e - ξωt (cos ω d t + Φ

Last Answer : A. x = (A + Bt) e – ωt

A vibrating machine of 100 kg is mounted on a rubber pad which has stiffness of 500 N/m. Determine force transmitted to the foundation if the unbalanced force 500 N acts on it. The frequency ratio (ω/ω n ) is 1.5 and ξ = 0.5 A. 461.62 N B. 400.23 N C. 450 N D. Insufficient data

Description : A vibrating machine of 100 kg is mounted on a rubber pad which has stiffness of 500 N/m. Determine force transmitted to the foundation if the unbalanced force 500 N acts on it. The frequency ratio (ω/ω n ) is 1.5 and ξ = 0.5 A. 461.62 N B. 400.23 N C. 450 N D. Insufficient data

Last Answer : A. 461.62 N

Which among the following is the fundamental equation of S.H.M.? A. x + (k / m) x =0 B. x + ω 2 x =0 C. x + (k/ m) 2 x =0 D. x 2 + ωx 2 =0

Description : Which among the following is the fundamental equation of S.H.M.? A. x + (k / m) x =0 B. x + ω 2 x =0 C. x + (k/ m) 2 x =0 D. x 2 + ωx 2 =0

Last Answer : B. x + ω 2 x =0

Consider the steady-state absolute amplitude equation shown below, if ω / ω n = √2 then amplitude ratio (X/Y) =? (X/Y) = √{1 + [ 2ξ (ω/ω n )] 2 } / √{[1 – (ω/ω n ) 2 ] 2 + {2ξ (ω/ω n ) 2 } A. 0 B. 1 C. less than 1 D. greater than 1

Description : Consider the steady-state absolute amplitude equation shown below, if ω / ω n = √2 then amplitude ratio (X/Y) =? (X/Y) = √{1 + [ 2ξ (ω/ω n )] 2 } / √{[1 – (ω/ω n ) 2 ] 2 + {2ξ (ω/ω n ) 2 } A. 0 B. 1 C. less than 1 D. greater than 1

Last Answer : B. 1

The two resonant frequency ratio (ω/ ω2) in a dynamic vibration absorber system for a mass ratio 0.2 are given by A) 0 ; 1.0 B) 0.801 ; 1.248 C) 0.458 ; 1.124 D) 0.642 ; 1.558

Description : The two resonant frequency ratio (ω/ ω2) in a dynamic vibration absorber system for a mass ratio 0.2 are given by A) 0 ; 1.0 B) 0.801 ; 1.248 C) 0.458 ; 1.124 D) 0.642 ; 1.558

Last Answer : B) 0.801 ; 1.248