If 200w, 100 w and 60 w lamps connected in series with 230V AC , which lamp glow brighter? Each lamp voltage rating is 230V.

If 200w, 100 w and 60 w lamps connected in series with 230V AC , which lamp glow brighter? Each lamp voltage rating is 230V.
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1 Answer

Answer :

 Each bulb when independently working will have currents (W/V= I)
 For 200 Watt Bulb current (I200) =200/230=0.8696 A
 For 100 Watt Bulb current (I100) =100/230=0.4348 A
 For 60 Watt Bulb current (I60) =60/230=0.2609 A
 Resistance of each bulb filament is (V/I = R)
 For 200 Watt Bulb R200= 230/0.8696= 264.5 ohms
 For 100 Watt Bulb R100= 230/0.4348 = 528.98 ohms and
 For 60 Watt Bulb R60= 230/0.2609=881.6 ohms respectively
 Now, when in series, current flowing in all bulbs will be same. The energy released will be I2R
 Thus, light output will be highest where resistance is highest. Thus, 60 watt bulb will be brightest.
 The 60W lamp as it has highest resistance & minimum current requirement.
 Highest voltage drop across it X I [which is common for all lamps] =s highest power.
 Note to remember:
 Lowest power-lamp has highest element resistance.
 And highest resistance will drop highest voltage drop across it in a Series circuit
 And highest resistance in a parallel circuit will pass minimum current through it. So minimum power dissipated across it as min current
X equal Voltage across =s min power dissipation
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