Reynold's analogy states that (A) Nst α f (B) Nst α NRe (C) NNu α f (D) NRe α f

Reynold's analogy states that

(A) Nst α f

(B) Nst α NRe

(C) NNu α f

(D) NRe α f

by

1 Answer

Answer :

(A) Nst α f

by

Related questions

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