Reynold's analogy states that (where, St = Stanton number f = friction factor) (A) St = f/2 (B) St = f/4 (C) St = 4f (D) St = f 1/2

Reynold's analogy states that (where, St = Stanton number f = friction

factor)

(A) St = f/2

(B) St = f/4

(C) St = 4f

(D) St = f

1/2

by

1 Answer

Answer :

(A) St = f/2

by

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