Maximum principal stress is equal to (a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5 (b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5 (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5 (d) None

Maximum principal stress is equal to

(a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5

(b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5

(c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5

(d) None
by

1 Answer

Answer :

(c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5
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Related questions

The magnitude of maximum shear stress is (a) ± (1/2)[ ((σx –σy) 2 + 4 τ 2 )) 0.5 ] (b) ± (1/2)[ (1/2)((σx –σy) 2 + 4 τ 2 )) 0.5 ] (c) ± (1/2)[ ((1/2)(σx –σy) 2 + 4 τ 2 )) 0.5 ] (d) None

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