Description : Maximum total strain energy theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Last Answer : (a) Ductile materials
Last Answer : (b) Brittle materials
Description : Maximum principal stress theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials (d) None
Description : Maximum shear stress theory is applicable to (a) Ductile materials (b) Brittle materials (c) Composite materials
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal Strain Theory (c) Thirdly Maximum principal strain energy theory (d) None
Last Answer : (d) None
Description : Maximum Principal Stress Theory is not good for brittle materials. a) True b) False
Last Answer : b) False
Description : A ductile material may not meet a failure if it has been tested for the theories of failure (a) Firstly Maximum Shear Stress Theory (b) Secondly Maximum Shear Strain Energy Theory (c) Both (a) & (b) (d) None
Last Answer : (c) Both (a) & (b)
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure fails (a) Firstly Maximum Principal Theory (b) Secondly Maximum Principal strain Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (c) Thirdly Maximum Principal Energy Theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum Principal stress theory (d) None
Last Answer : (c) Thirdly Maximum Principal stress theory
Description : Under complex loading, if elastic limit reaches in tension, then failure occurs due to (a) Firstly Maximum principal strain theory (b) Secondly Maximum principal theory of strain energy (c) Thirdly Maximum shear stress theory (d) None
Description : Maximum principal strain theory is also called as (a) Guest’s theory (b) Haigh theory (c) St.Venant’s theory (d) None
Last Answer : (c) St.Venant’s theory
Description : Which of the following theories of failure is most appropriate for a brittle material? (a) Maximum principal strain theory (b) Maximum principal stress theory (c) Maximum shear stress theory (d) Maximum strain energy theory
Last Answer : (b) Maximum principal stress theory
Description : In which of the following case stress concentration factor is ignored? a) Ductile material under static load b) Ductile material under fluctuating load c) Brittle material under static load
Last Answer : a) Ductile material under static load
Description : Which theory is perfect for design of shaft when it mades from brittle materials........... A. Rankine theory B. Guest's theory C. Vonmises theory D. St. Venant's theory.
Last Answer : A. Rankine theory
Description : Maximum principal strain is equal to when σ1 and σ2 are tensile (a) (σ1 –μσ2)/E (b) (σ1 + μσ2)/E (c) (–σ1 –μσ2)/E (d) None
Last Answer : (a) (σ1 –μσ2)/E
Description : Which stress strain curve is more steep (a) For a ductile material (b) For a brittle material (c) For a pure metal (d) None
Last Answer : b) For a brittle material
Description : Distortion energy theorem is not recommended for ductile materials. a) True b) False
Description : Theories of elastic failure while dealing with ductile materials consider the failure criterion as (a) Ultimate stress (b) Yield stress (c) Both ultimate and yield stress (d) None
Last Answer : (b) Yield stress
Description : Maximum total strain energy theory is also known as (a) Huber theory (b) Rankine theory (c) St.Venant’s theory (d) None
Last Answer : (a) Huber theory
Description : Maximum total strain energy theory is also known as (a) Guest’s theory (b) Haigh theory (c) St.Venant’s theory (d) None
Last Answer : (b) Haigh theory
Description : Theories of elastic failure while dealing with brittle materials consider the failure criterion as (a) Ultimate stress (b) Yield stress (c) Both ultimate and yield stress (d) None
Last Answer : (a) Ultimate stress
Description : Which theories of failure are used for (a) ductile materials, and (B) brittle materials ?
Last Answer : For ductile materials, theories of failure used are maximum shear stress theory, and maximum energy of distortion theory; while for brittle materials, theory of maximum principal stress, and maximum strain are used.
Description : A dense structure of grinding wheel is not used for the (A) Ductile material (B) Hard materials (C) Brittle materials (D) Finishing cuts
Last Answer : A) Ductile material
Description : The materials which fracture even at small strains are termed as brittle, while those materials which exhibit an appreciable deformation before failure are termed as (A) Rigid (B) Tough (C) Ductile (D) Plastic
Last Answer : Option C
Description : Which Theories Of Failure Are Used For? (a) Ductile Materials (b) Brittle Materials?
Last Answer : For ductile materials, theories of failure used are maximum shear stress theory and maximum energy of distortion theory; For brittle materials, the theory of maximum principal stress and maximum strain are used.
Description : The total strain energy for a unit cube subjected to three principal stresses is given by? a) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/3 b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ c) U= [(σέ) 1 + (σέ) 2+ (σέ) 3]/4 d) None of the mentioned
Last Answer : b) U= [(σ12+σ22+σ32)/2E] – (σ1σ2+σ2σ3+σ3σ1)2μ
Description : Why do we determine principal stresses? a. Failure is due to simple stress or strain b. Failure is due to complex stress or strain c. Both (a) & (b) d. None
Last Answer : a. Failure is due to simple stress or strain
Description : Shear strain energy under principal tensile stresses σ1 and σ2 is (a) (1/12E) (σ1 — σ2) 2 + σ2 2 — σ1 2 ) (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (c) (1/12K) (σ1 — σ2) 2 + σ2 2 + σ1 2 ) (d) None
Last Answer : (b) (1/12G) (σ1 — σ2) 2 + σ2 2 + σ1 2 )
Description : The principal strain due to σ1(tensile) and σ2 (Compressive ) stress is (a) Firstly (b)Secondly (c)Thirdly (d) None
Last Answer : (b)Secondly
Description : A transmission shaft subjected to pure bending moment should be designed on the basis of (A) Maximum principal stress theory (B) Maximum shear stress theory (C) Distortion energy theory (D) Goodman or Soderberg diagrams
Last Answer : (A) Maximum principal stress theory
Description : For a homogeneous & isotropic body under hydrostatic pressure, which theory of elastic failure does not fail (a) Firstly Maximum Principal Theory (b) Secondly Maximum Shear Stress Theory (c) Thirdly Maximum Principal Energy Theory (d) None
Last Answer : (a) Firstly Maximum Principal Theory
Description : Maximum principal theory is also known as (a) Beltrami Theory (b) Maximum normal stress theory (c) Saint Venant’s theory (d) None
Last Answer : (b) Maximum normal stress theory
Description : Maximum principal theory is also known as (a) Guest Theory (b) Beltrami Theory (c) Rankine Theory (d) None
Last Answer : (c) Rankine Theory
Description : Under maximum principal stress theory, maximum principal stress is equal to (a) Allowable stress in tension (b) Allowable stress in compression (c) Allowable stress in shear (d) None
Last Answer : (a) Allowable stress in tension
Description : If compressive yield stress and tensile yield stress are equivalent, then region of safety from maximum principal stress theory is of which shape? a) Rectangle b) Square c) Circle d) Ellipse
Last Answer : b) Square
Description : Shear strain energy theory is also known as (a) Coulomb’s theory (b) Distortion energy theory (c) Rankine theory (d) None
Last Answer : (b) Distortion energy theory
Description : Shear strain energy theory is also known as (a) Von Mises Theory (b) Coulomb’s theory (c) Rankine theory (d) None
Last Answer : (a) Von Mises Theory
Description : Shear strain energy theory is also known as ( a) Huber theory (b) Rankine theory (c) Mises-Hencky theory (d) None
Last Answer : (c) Mises-Hencky theory
Description : In a composite body, consisting of two different materials...........will be same in both materials. (a) Stress (b) Strain (c) Both stress and strain (d) None of these
Last Answer : (b) Strain
Description : Maximum total strain energy is equal to (a) (σ1 2 +σ2 2 )/2E (b) ( σ1 2 +σ2 2 + 2μ σ1 σ2)/2E (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E (d) None
Last Answer : (c) ( σ1 2 +σ2 2 — 2μ σ1 σ2)/2E
Description : In the Haig-Soderberg diagram, the test data for ductile material falls near the ______________ a) Soderberg line b) Goodman Line c) Gerber line d) Haig line
Last Answer : c) Gerber line
Description : In a ductile material, the strength are (a)Firstly Ultimate >yield > elastic limit (b) Secondly Ultimate > yield =elastic limit (c) Thirdly Ultimate=yield=elastic limit (d) None
Last Answer : (a)Firstly Ultimate >yield > elastic limit
Description : Manganese is added in low carbon steel to A. Make the steel tougher and harder B. Raise the yield point C. Make the steel ductile and of good bending qualities D. All of the above
Last Answer : C. Make the steel ductile and of good bending qualities
Description : Maximum principal stress is equal to (a) (σx + σy)/2 + [ (σx –σy) 2 + τ 2 ] 0.5 (b) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + τ 2 ] 0.5 (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5 (d) None
Last Answer : (c) (σx + σy)/2 + 0.5 [ (σx –σy) 2 + 4τ 2 ] 0.5
Description : In a general two dimensional stress system, planes of maximum shear stress are inclined at ___ with principal planes. a. 90 degree b. 180 degree c. 45 degree d. 60 degree
Last Answer : c. 45 degree
Description : Principal planes are those planes on which a. Normal stress is maximum b. Normal stress is minimum c. Normal stress is either maximum or minimum d. Shear stress is maximum
Last Answer : c. Normal stress is either maximum or minimum
Description : The maximum number of principal stresses is a. 1 b. 3 c. 5 d. None
Last Answer : b. 3
Description : The maximum number of principal stresses is a. 2 b. 4 c. 6 d. None
Last Answer : d. None
Description : Maximum shear stress in terms of principal stresses is a. Firstly (σ 1 +σ 2 )/2 b. Secondly (σ 1 /σ 2 ) c. Thirdly (σ 1 –σ 2 )/2 d. None
Last Answer : c. Thirdly (σ 1 –σ 2 )/2